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1-sin?30° cos®60°+ cos®30°xS ~sin 60° tan 30°1+sin’45° cosec?90°—cot”90° |
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Answer» (1-sin30*sin30)/(1+sin45*sin45) × (cos60*cos60+cos30*cos30)/(cosec90*cosec90-cot90*cot90) ÷ sin60*tan30 = (1-1/2*1/2)/(1+1/2) × (1/2*1/2 + 3/4)/(1*1-0*0) ÷ (√3/2 × 1/√3) = (1-1/4)/(3/2) × (1/4+3/4)/(1) ÷ 1/2 = (3/4)/(3/2) × (4/4)/(1) × 2 = 2/4 × 1 × 2 = 4/4 = 1 If you find this answer helpful then like it. Good effort vai.... |
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