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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
find the volume of the cylinder which form by rolling a rectangular piece of paper along its length,if length of paper 76 cm and width is 30 cm. |
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Answer» Length will be equal to the circumstance of baseand width will be equal to height of cylinder. So, circumference =2πr76cm=2(22/7)rr=12.1cm Height=30cm Volume of cylinder=πr²h=(22/7)(12.1)²(30)=13798.8cm³ |
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| 2. |
Example 15: Rajesh bought a motorcycle for727,000 and bought some accessories for it tomake it look good. He sold the bike at a profit o10% and at a selling price of 33,000. How mudid he spend on the accessories? |
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Answer» 3300033000*100/110 = 30000Spend money for accessories30000-27000 = 3000 |
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| 3. |
เคนเค. = /, /o 7% xo!22/o- g7y L % |
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Answer» ((0.325*0.325)-(0.125*0.125))/0.2=(0.105625-0.015625)/0.2=0.09/0.2=0.045 |
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| 4. |
' . -अअ] oWW - kJZ wty=p ली 2% ol ‘ XO 3. |
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Answer» 3x² - k√2x + 4 = 0 When roots are equal then discrimanat is 0. D = (-k√2)² - 4 × 3 × 4 = 0 2k² = 48 k² = 24 k = √(24) k = 2√6 or - 2√6 |
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| 5. |
.4In the figure find the value of xo.2560° |
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Answer» how easy this is. Can't you solve this question?😀 angle ECD=35°+25°=60° (ext angle property)x=60°+60°= 120° (ext angle property) |
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| 6. |
8) A worker makes 23 paper bags in anhour. How much time will he take tomake 161 bags? |
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Answer» Number of paper bags made in 1 hour = 23Time taken to make 1 bag = 1/23 hoursTime taken to make 161 bags = (1/23) × 161 = 7 hours 7 hours he will take number of paper bags made in 1 hour=23time taken to make 1bag= 1/23 hourstime taken to make 161 bags=(1/23)×161 =7 hours paper bags in 1 hour = 23 time taken for 161 bags = 161/23 = 7 therefore 7 hours taken for 161 bags 70 hours he will take Please like my answer and accept it as best please😓 sorry 70 not 70 please like my both answer 😭 please don't spam ok 🙏🏻🙏🏻 161 papers bag made in 7 hours🙏🙏🙏 We have, 23 pages are made in 1 hour i.e. 60 mins. So, 1 page is made in6023mins.Hence, 161 pages will me made in6023×161=60×16123=60×7=420mins=7hour paper bags in 1 hour= 24time taken for 161 bags= 161/ 23= 7therefore7 hours taken for 161 bags |
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| 7. |
(c)5 502 |
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Answer» 2x/(-5) = 1/50 x = (-5)/2×(50) x = -5/100 x = -1/20 |
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| 8. |
The cost of 5 pencils is equal to the cost of 2 ballpoints. Write a linear equation in twovariables to represent this statement |
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Answer» Let cost of one pencil be xLet cost of one ball point be y Then,As per given condition5x = 2y5x - 2y = 0 |
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| 9. |
LINEAR EQUATIONS IN Two VARIABLES75If the work done by a body on application of a constant force is directly proportionalto the distance travelled by the body, express this in the form of an equation in twovariables and draw the graph of the same by taking the constant force as 5 units. Alsoread from the graph the work done when the distance travelled by the body is6.(i) 2 units(ii) 0 unit |
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| 10. |
Q. 1 When the integers 10, 0, 5, -5, -7 are arranged in descendingascending order, then find out which of the following integers alwremains in the middle of the arrangement.(a) O(b) 5(c) â 7(d) - 5 |
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Answer» the answer is (a) 0 when the integers are arranged in descending order:10, 5, 0, -5, -7 when the integers are arranged in ascending order:-7, -5, 0, 5, 10 so zero always remains in I middle answer is ' a)0 ' Answer is zero. 0 is the answer because there are two negative and two positive integers the answer 10, 0,-5,-7 the arrangements is a option is c) 5 |
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| 11. |
Prove that21+tan A tan B)+(tan A-tan B)sec2 A sec BS |
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| 12. |
followig.githeent of length 76 cm and divide it in the ratio 5 : 8. Measure t |
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Answer» let xbethe common multiplehence5x and 8x=7.65x+8x=7.613x=7.6x=0.58cmhence 5x=2.92cmand 8x=4.64cm |
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| 13. |
Water is leaking from a conical funnel at the rate of 5 ent/sec If the radius of the base of thetunnel is 10 cmand altitude is 20 cm. Find the rate at which water level is dropping when it is 5cm from top.wlond kent vertical the petrol is leaking at the rate of |
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Answer» dV/dt = 5 cm^3/sec radius(funnel) = 10 cm height(funnel) = 20 cm dh/dt = ? at the point when the water level is dropping 5 cm from the best.volume = π/3(radius)^2(height) 1.) discover the proportion wager. the water and the cone shaped pipe. radius(funnel)/height(funnel) = radius(water)/height(water) give r a chance to be the radius(water) and h be height(water) 10cm/20cm = r/h 1/2(h) = r 2.) the volume of the water is the same as the volume of the conelike pipe. volume = π/3(radius)^2(height) substitute 1/2(h) to the range volume = π/3(1/2*h)^2(height) volume = π/3(1/4*h^2)(h) volume = πh^3/12 3.) separate the new eq'n shaped as for time. give V a chance to be the volume d/dV(V)dV/dt = d/dh(πh^3/12)dh/dt dV/dt = (πh^2/4)dh/dt connect to the water level, w/c is 15cm (since the water level is dropping when it is 5cm from the best) and the rate of the spilling of the water from the cone shaped channel 5 cm^3/sec = (π*(15 cm)^2/4)(dh/dt) 5 cm^3/sec = 176.7145868 cm^2(dh/dt) - 0.028 cm/sec = dh/dt - > last answer (negative implies that the water is spilling) |
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| 14. |
3. Find the successor and the predecessor of the following integersa) -32 |
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Answer» successor = -31predecessor = -33 |
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| 15. |
2 Dlooks the following integers on a number ten0 5 -2 I -13 |
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| 16. |
Why does a lump of cotton wool shrink in water? |
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Answer» Alump of cottonwoolshrinkswhen immersed inwater. This is because air present in thecottonwool escapes. Thus, the volume of thecottonwool decreases. |
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| 17. |
2.f(x) =xo(x + C) is increasing inis increasing in |
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Answer» when f'(x) greater than or equal to zero |
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| 18. |
The average age of a husband and wife is 23 years at thebeginning of their marriage. After five years they have a oneyear old child. The average age of the family of three, whentheir child was born is: |
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Answer» 28 years of three persons average age is 18 years of three person |
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| 19. |
I Which of the following is an instructional objective of mathematics?(A) To develop in the child the power of thinking and reasoning(B) To perform computations with speed and accuracy(C)(D) To make reasonably good approximations and estimate measurements.To identify even and odd numbers of three digits. |
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Answer» option A. |
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| 20. |
PAIR OF LINEAR EQUATIONS IN TWO VARIABLES52. Form the pair of linear equations in the following proble(if they exist) by the elimination method:(i) If we add I to the numerator and subtract from the denomlons in the following problems, and find their solutionsract from the denominator, a fraction reducesto 1. It becomesif we only add I to the denoWe only add I to the denominator. What is the fraction?(ii) Five years ago, Nuri was thrice as old as Sonu. Ten yearswas thrice as old as Sonu. Ten years later, Nuri will be twice asold as Sonu. How old are Nuri and Sonu?Yui) The sum of the digits of a two-digit number is 9. AlsoTa two-digit number is 9. Also, nine times this number isnumber obtained by reversing the order of the digits. Find the number.(iv) Meena went to a bank to withdraw 32000. She asked the cashier to giveand 100 notes only. Meena got 25 notes in all. Find how many notes of350 and 100 she received.(Vy A lending library has a fixed charge for the first three days and an additional chargefor each day thereafter. Saritha paid 27 for a book kept for seven days, while Susypaid 21 for the book she kept for five days. Find the fixed charge and the chargefor each extra day. |
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Answer» Let the fixed charge be xLet the additional charge be yA. T. Q.Condition---1 x+4y=27 --1 Condition--2x+2y=21 ---2Now, by elimination method x+4y=27 x+2y=21 – – –-------------------- 2y=6 y=6/2 y=3put y in eq. 1 x+4*3=27x+12=27 x=27–12 x=15fixed charge is ₹15 additional charge is ₹3 the height of ram is 1/2/3m and that of that of shyam is 1/1/3m.who is taller and by how much? |
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| 21. |
(डा) 36 Swo+ (056 न पथ evaluate (teno(oto)हल |
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Answer» Like if you find it useful |
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| 22. |
(1) A student of class IV starts doing his/her home work at 6:47 p.m and finishes at8.57 p.m. How much time is taken by the student to complete the home work? |
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Answer» The student has taken 2 hours and 10 minutes. 2:10 time is taken by the students to complete the home work |
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| 23. |
If sin θ-cos θthen find the value ofsin θ + coOrIf A, B, C are interior angles of AABC, show that:e(B2C)-tan2tan2 1.-1cose |
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| 24. |
3. Mark the following integers on a number line(1) -5(ii) -2(v) -13Mathematics for Class(iv) 74. Which number is larger in each of the(i) 0, -2 |
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| 25. |
dyах3. Ifx- a sec2 0, y b tan2 0, then find |
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| 26. |
l + tan2 A1-tan A1 +cot2A1 cot A= tan2 A |
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Answer» L.H.S1+tan^2A/1+cot^2A=(1+sin^2A/cos2A)/(1+cos^2A/sin^2A)=((cos^2A+sin^2A)/cos^2A)/(sin^2A+cos^2A)/sin^2A=(1/cos^2A)/(1/sin^2A)=1/cos^2A*sin^2A/1=sin^2A/cos^2A=tan^2A M.H.S(1-tanA/1-cotA)^2=(1+tan^2A-2tanA)/(1+cot^2-2cotA)=(sec^2A-2tanA)/(cosec^2A-2cosA/sinA)=(sec^2A-2*sinA/cos A)/(cosec^2A-2cosA/sinA)=(1/cos^2A-2sinA/cosA)/(1/sin^2A-2cosA/sinA)=[(1-2sinAcosA)/cos^2A]/[(1-2cosAsinA)sin^2A]=(1-2sinAcosA)/cos^2A*sin^2A/(1-2sinAcosA)=sin^2A/cos^2A=tan^2A R.H.S=tan^2A Hence L.H.S=M.H.S=R.H.S |
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| 27. |
b 2 '8 20, 1 â 2510â0 =2 |
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| 28. |
VR's family having three child , swo gids oregirls. So, the probability of each is V/4. Is this correca ? Justify your answerInren, there may be no girl, one girre |
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Answer» 3 children given. let ‘s b denote boy and g denote girl. bbb, bbg, bgb, gbb, ggg, ggb, gbg, bgg total 8 possibilities. (1) Probability of no girl Possibility = 1(bbb) So, probability = 1/8 (2) Probability of one girlPossibilities = 3 (bbg, bgb, gbb) So, probability = 3/8 (3) Probability of two girlsPossibilities = 2 (bgg, ggb) So, probability = 2/8 = 1/4 (4) Probability of three girlsPossibilities = 1 (ggg) So, probability = 1/8 Therefore, probability = 1/4 is true for only one condition when there are two girls. |
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| 29. |
In a fraction when 3 is addedto its numerator and denom45inator it becomesand itbecomeswhen 2 is sub-2tracted from both the numer-ator and denominator. Findthe fraction. |
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| 30. |
A student of class IV starts doing his/her home work at 6:47 p.m and finishes at 8.57 p.m. How much time is taken by the student to complete the home work? |
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Answer» Total time taken is 8:57 - 6:47 as both is in pm conversion not neededso 8:57 - 6:47 = 2 : 10 hours are required by the student. |
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| 31. |
25+\left[20-\left\{2-\left(20 \frac{1}{5} \div \frac{1}{8} \times \frac{1}{16}-8\right)\right\}\right] |
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Answer» 25+[20-{2-(20 of 1/5 ÷ 1/8 ×1/16 -8)}]=25+[20-{2-(20/5 ÷ 1/8 ×1/16-8)}]=25+[20-{2-(4÷1/8 ×1/16-8)}]=25+[20-{2-(32/16-8)}]=25+[20-{2-(2-8)}]=25+[20-(2+6)}]=25+[20-8]=25+12=37 |
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| 32. |
Finá e point an the purabela y-(-3, where the tangent is parallel tthe chand jnining (3., 0) nz (4, 1)ICBSE 2000C) |
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| 33. |
) A student of class IV starts doing his/her home work at 6:47 p.m and finishes at8.57 p.m. How much time is taken by the student to completethe home work? |
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Answer» Total time taken is 8:57 - 6:47 as both is in pm conversion not neededso 8:57 - 6:47 = 2 : 10 hours are required by the student. |
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| 34. |
9. The cost of a theatre ticket is increased by 40% for a special movie. What is the new price,normal price was F 160? |
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Answer» The new price is 224Because160 × 40% = 64Then,New price is160 + 64 = 224 |
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| 35. |
1) A student of class IV starts doing his/her home work at 6:47 p.m and finishes a8.57 p.m. How much time was taken by the student to complete the home work |
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| 36. |
the cost of a theatre ticket is increased by 40% for a special movie what is new price if normal price was rupees 160 |
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| 37. |
Rohan watches a movie from 6.30 p.m. to 9.30 p.m. How long does hewatch the movie? |
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Answer» He watched the movie for total 3 hours |
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| 38. |
Prove that:\tan ^{2} A \sec ^{2} B-\sec ^{2} A \tan ^{2} B=\tan ^{2} A-\tan ^{2} B |
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| 39. |
IF8809-6, 7111 = 02172 = 0 , 6666 = 40000 = 4 , 3333-0THEN,2581 = ? |
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| 40. |
A certain sum of money at compound interest becomes7,396 in two years and7,950.70 in three years. Find the rate of interest. |
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| 41. |
fromQL what should be swo tracted28 toget -11 |
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Answer» let the sub. no. be xthen -5/6-x=-11/9-5/6+11/9=X-15/18+22/18=Xx=7/18 ansIf u satisfied with the ans then like or cmmt ✌️ 7/18 is the correct answer of the given question 7/18 is the correct answer 7/18 is the correct answer of the given question |
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| 42. |
from5.What should be subtracted- 32to get - ?43toget |
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Answer» -17/12 ok likh looooooo -19 by 12 Is equal x |
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| 43. |
Rationalize the DenominatorProblemsWork Space2Answer: |
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| 44. |
28, , 272-8202S. CHAND |
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Answer» (x^27+x^28+x^29) / (x^30+x^28+x^29) = [x^27 * ( 1 + x + x^2 ) ] / [ (1+ x+ x^2)* x^28]= 1/x PEASE HIT THE LIKE BUTTON sorry it is wrong |
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| 45. |
2 tan 30°1 + tan2 30°(A) sin 60°1- tan 45°1 + tan2 45°(A) tan 90° |
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Answer» tan30° = 1/√3 so, 2tan30/(1+tan²30) = 2*(1/√3)/(1+(1/√3)²) = (2/√3)/(4/3) = √3/2 = sin(60°) tan45° = 1 so, (1-tan²45°)/(1+tan²45°) = (1-1)/(1+1) = 0= tan0° = sin0° = cos90° |
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| 46. |
halkaclassWORK SHEETwhichIdentify the National numberis different from theother there Explain your areasonltiplicat |
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Answer» -1/2 is different from all others because if we solve it that is if we divide -1 by 2 it will give us -0.5 that is it is non repeating and terminating rational number but all other will not be divided like that they will repeat after dividing that's why they are repeating and non terminating rational number |
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| 47. |
21 + tan2 A(-tan A1 +cot A 1 cot A= tan, A |
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| 48. |
If tanθ + sinθ=m and tanθ-sinθ=n, show that m^2-n^2=4√mn |
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Answer» Tanθ+sinθ=mtanθ-sinθ=n∴, m+n=tanθ+sinθ+tanθ-sinθ=2tanθm-n=tanθ+sinθ-tanθ+sinθ=2sinθmn=(tanθ+sinθ)(tanθ-sinθ) =tan²θ-sin²θ∴, m²-n²=(m+n)(m-n)=2tanθ.2sinθ=4sinθtanθ4√mn=4√(tan²θ-sin²θ)=4√(sin²θ/cos²θ-sin²θ)=4√sin²θ(1/cos²θ-1)=4sinθ√(1-cos²θ)/cos²θ=4sinθ/cosθ√sin²θ [∵,sin²θ+cos²θ=1]=4sinθtanθ∴, LHS=RHS (proved) |
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| 49. |
on 5%, find the selling price of the articlewere spent on its repairs. If itisCR and TV were bought for 8,000 each. The shopkeeper made aof 4% on the VCR and a profit of 8% on the TV. Find the gain or loss4ent on the whole transaction. |
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| 50. |
21 + tan2 A 1-tan A1 + cot 2 A (1-cot A= tan 2 A |
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Answer» 1 is not equal to RHS |
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