1.

2 tan 30°1 + tan2 30°(A) sin 60°1- tan 45°1 + tan2 45°(A) tan 90°

Answer»

tan30° = 1/√3

so, 2tan30/(1+tan²30) = 2*(1/√3)/(1+(1/√3)²) = (2/√3)/(4/3) = √3/2 = sin(60°)

tan45° = 1

so, (1-tan²45°)/(1+tan²45°) = (1-1)/(1+1) = 0= tan0° = sin0° = cos90°



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