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25+\left[20-\left\{2-\left(20 \frac{1}{5} \div \frac{1}{8} \times \frac{1}{16}-8\right)\right\}\right] |
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Answer» 25+[20-{2-(20 of 1/5 ÷ 1/8 ×1/16 -8)}]=25+[20-{2-(20/5 ÷ 1/8 ×1/16-8)}]=25+[20-{2-(4÷1/8 ×1/16-8)}]=25+[20-{2-(32/16-8)}]=25+[20-{2-(2-8)}]=25+[20-(2+6)}]=25+[20-8]=25+12=37 |
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