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Data is the quantities, characters, or symbols on which operations are performed by a computer, which may be stored and transmitted in the form of electrical signals and recorded on magnetic, optical, or mechanical recording media.

24 banyan tree and 30 of mango tree

rationalise and then solve

(3+root3)(3-root3)=3^(2)-root3^(2)=9-3=6

6 is the answer of this question

(3+√3)(3-√3)solving using the formulae (a-b)(a+b)=(a²-b²)= (3-√3)²=(3)²-(√3)²=(9-3)=6

(a+b)(a-b)=(a^2-b^2)=(3)^2-(√3)^2 =9-3 =6 Ans

Let the radius and height of the right circular cone be 'r' and 'h' respectively.Now, it is given thatr/h = 3/4h = 4r/3Volume of the cone =301.44 cu cm (given)Volume of the cone = 1/3πr²h⇒301.44= 1/3*22/7*r²*4r/3⇒ r³ = 863.214⇒ r³ = 863⇒ r =∛863⇒ r = 9.5 cmSo, h = (4*9.5)/3h = 12.6cm = Now, let the slant height of the cone be 'l'.we know that,l² = r² + h²l² = 9.5² + 12.6²l² = 90.25+ 158.76l² = 249.01l =√249.01l = 15.8cm

Primary data:Datacollected by the investigator himself/ herself for a specific purpose. Examples:Datacollected by a student for his/her thesis or research project.

Secondary data:Datacollected by someone else for some other purpose (but being utilized by the investigator for another purpose).

cost of 1 L oil is ₹324so cost of 13.51 L is ₹324× 13.51 = ₹4,377.24

each litre cost of oil=324 rs.cost of 13.5 l oil=13.5×324 =4374rs. ans

Please post complete question

3+4y=-54y=-5-34y=-8y=-8/4y=-2

thanks

sinA = bsinB....(1)

tanA= atanB

(sinA/cosA) = a(sinB/cosB)....(2)

substuting sinB value from equation (1)

cosB = (a/b) cosA......(3)

sin2A = b2sin2B

1-cos2A = b2(1-cos2B)

substituting equation (3)

1-cos2A = b2[1 – ((a2/b2)cos2A)]

1 – cos2A = b2– a2cos2A

a2cos2A – cos2A = b2– 1

cos2A = (b2– 1)/(a2– 1)

Crossbreeding method is commonly used for improving cattle breeds.Cross breeding between two good varieties of cattle will produce a new improved variety.

x=4 put in the equation then both the equation solved easily

and:- 4 solved both equations

x=4 solved the equation

Yes x=4 it's right answer....

this question right answer x = 4.

X=5 solved the question

X=4 is the correct answer

right the correct answer =x=4

6x/7+14+ 4x/5+20=4x+6/3

×=solve the equation

x=4 solved the equation

X = 4 is the correct answer

right answer is x = 4

हल करने से अच्छा है कि उत्तर ही बता दें इसका उत्तर यह है। x=4 करेक्ट है

4 is the right answer II for this equation

let 1/x=u4u +3y=8.......(1)6u -4y=-5........(2)(1)×4; 16u +12y =32.....(3)(2)×3; 18u -12y =-15......(4)(3)+(4); 34u=17u=1/2 then y=2(putting the value of u in (1))if u=1/x=1/2then x=2

3x²+x-7=4x3x²+x-4x-7=03x²-3x-7=0x=-b+/-√(b²-4ac)/2a Here a=3;b=-3; c=-7

x=3+/-√(9+84) ----------------- 6x=3+/-√93 -------- 6

12x+1=×/9+112x+1=×/9+9/9

same base so 4 is six times therefore 4^(6)

FOR RECTANGULAR LAWN.Length, L = 80m.Breadth, B= 60m.

For Vertical road:length= Breadth of rectanglelength = 60m.

Breadth = 10m.

Thus, Area of vertical road=length × breadth= 60m ×10m=600m².

For Horizontal road:length = length of rectangle.length = 80mbreadth= 10m.

Thus, area of horizontal road= length ×breadth= 800m × 10m=800m².

Note: The roads overlap in the middle of rectangle and form a square having side of 10m.

FOR SQUARE:Area of square = Side × SideArea of square = 10m × 10mArea of square = 100m².

Therefore,Area needd of road to be gravel = Area of vertical road + area of horizontal road - area of square

= 600m² + 800m² -100m²= 1300m².

If the cost of gravelling for 1m² = Rs 5So, Cost of gravelking for 1300m²= 1300 ×Rs 5=Rs 6500. Ans.

500000 answers are there answers

500000 Is The Right Answer

21+1/18 is the best answer

2261/72 is the right answer

2261/72 is the best answer

The ratio for the problem is 2:1

(a+b)(a-b)(25)^2-5^2625-25620

Volume of the cylindrical can=πr²h=3.14×(7.7)²×56=10425.5536 cm³=10.425 litres

3.5 +25-12.5-10+20=25

3.5+25-13.5-10+20=25

4 is the answer because...64 have to come

Given,Outer diameter of the hemisphere 2r =17cm

r=17/2

Its Inner diameter 2r=15cm

r=15/2

[Note:- C.S.A:-Curved Surface Area]

Therfore outer C.S.A = 2*22/7*17/2*17/2

=454.142sq cm

Its inner C.S.A= 2*22/7*15/2*15/2

=343.571sq cm

Then 454.142+343.571=797.7134

Rate of painting it=25 paise=Rs. 0.25

Therefore, 797.7134*0.25=Rs.199.4275

Hence the cost of polishing the hemispherical bowl is Rs. 199.43 .

x=3/2 is the correct answer.

Use Heron's formula with

sides a,b and c

s=a+b+c/2

Area=√s(s−a)(s−b)(s−c)

Then, s = (120 + 160 + 200)/2 = 480/2 = 240

Area of triangle = √240(240−120)(240-160)(240−200)= √240*120*80*40= 12*8*100= 9600 sq m

Therefore, Cost of ploughing a field = 9600 *.25= Rs 2400

15)The dimensions are 3x : 2x : x

The volume is { 6x }^{ 3 }=10368.

So, x is { 6x }^{ 3 }=10368

therefore x = 12

So, the dimensions are 36cm, 24cm and 12 cm respectively.

The surface area is 2(36 ×24+ 24× 12+ 12×36)=3168 cm^2

Total cost is 3168×0.02=Rs. 63.36