Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
) If the value of tan θ=5, then the value of sec θ is34434 |
|
Answer» by using identity of trigonometri the answer is c |
|
| 2. |
A factory kept increasing its output by the same percentageevery year. Find the percentage increase, if it is known thatthe output is doubled in the last 2 years. |
| Answer» | |
| 3. |
A cone is cut by a plane parallel to the base andupper part is removed. If the C.S.A. of the remainder15isof the C.S.A. of whole cone, find the ratioof the line segments to which the cone's height isdivided by the plane.Board Term-2, 2014] |
|
Answer» very simple question solved by the teachers in 9th class |
|
| 4. |
urface Area of a Cube 6a^2 |
| Answer» | |
| 5. |
10. A circus tent is in the shape of a cylinder surmounted by a cone. The diameter of the cylindrical partis24 m and its height is 11 m. If the vertex of the tent is 16 m above the ground, find the area of the canvasCBSE Sample Paper 2004]required to make the tent. |
| Answer» | |
| 6. |
EXERCISE 2.1. Find thee remainder when x'+3x2 +3x +1 is divided byvwon: As x(iv) x+π0 x+1Find the remainder when x-ax: + 6x-a is divided by x - a.II) X-(ii) x(v).2.ill now |
|
Answer» If x+1 is the factor of the given P(x).Therefore, P-1 must be zero. P(-1) = (-1)³ + 3(-1)²+3(-1)+1 = -1 +3 -3 +1 = 0 |
|
| 7. |
メt The hypotenuse of a right triangle is 17 cm long. If one of the remaining two sides isofength 8 cm, find the length of the third side. |
| Answer» | |
| 8. |
(a) 12825. The sum of two numbers is 45. Their difference isof their sum. The(s.s.c. 200L.C.M. is:(a) 100(b) 150(c) 200(d) 250 |
|
Answer» Let the two numbers be x, y. x + y = 45 ---> EQ1.x - y = 1/9(45)x - y = 5 ---> EQ2.Solve the two equations.2x = 50x = 25Put x = 25 in EQ1.25 + y = 45y = 20 So, the two numbers are 20, 25 and their LCM is 100 why 1/9 multiplying 45 |
|
| 9. |
6. If a number is divided by 161, then theremainder is 102. When the same number isdivided by 23, then the remainder will be:(a) 7(b) 11(c) 3(d) 10(e) 18 |
|
Answer» Given, divisor = 161 , remainder = 102 the required number will be =divisor + remainder =161 + 102 = 363 363 / 161 = 102 ( remainder ) if we divide it by 23 ,then 363 / 23 = 18 ( remainder ) hence , the remainder will be 18 . therefore ,option (d) is the correct answer. Answer option (e) is the correct answer. 18 is the correct answer of the given question 18 is right answer.of this question. the right answer is 18 |
|
| 10. |
e quotient and remainder when 9x5 -19x-21x2 -30 is divided by (e-3)have to arnho dsidd |
|
Answer» remainder is 429 |
|
| 11. |
oblem set 33-ne the following mixed fractions in decimal form and read them aloud.up to (m) 100 G) 400 (4) () (6) (1) (9) 100от с опругот 53 сгусгусусретсе |
|
Answer» what is displacement |
|
| 12. |
12. 0, 2, 8, 14, ?, 34(a) 20 (6) 23(B.B.S. 2004)(d) 25(c) 24 |
|
Answer» option C 24 option c is the correct answer of this question option (a) 20 is the right answer. plz like my answer 20 is the right answer c is the correct answer for this question 24 is the right option... 0, 2, 8, 14, ?, 34 a) 20 b) 23 c) 24. d) 25. ... Examveda Team). The pattern is + 2, + 6, + 6, + 10, + 10,..... So, missing term = 14 + 10 = 24. |
|
| 13. |
Q14X'If α and β are zeroes of a quadratic polynomial 4x2 + 4x + 1, then form a quadraticIAns. 2x 1polynomial whose zeroes are 2α and 2β |
|
Answer» Like if you find it useful |
|
| 14. |
Example 9. Find the arca of smaller region bounded by the2+ y_ =169x y4 31 and the straight line-+-=1.,lipseICBSE Sample Paper 2004 |
| Answer» | |
| 15. |
3. A shuttle cockused for playing badminton has the shape of a frustum of a conemounted on a hemisphere. The external diameters of the frustum are 5 cm anrespectively and height of the entire shuttle cock is 7 cm. Find its total externalurface area |
|
Answer» Given:r1= 1 cm,r2= 2.5 cm,h= 6 cml = √h² + (r2-r1)²= √(6)² + (2.5-1)² cm= √36 + 2.25 cm= √38.25 cm= 6.18cmSo,External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)= 22/7(r1+r2)l +2.22/7.r1= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²= 22/7 (3.5 × 6.18 +2) cm²= 22/7 (21.63+2) cm²= 22/7 × 23.63 cm²= 519.86/7 cm²= 74.26 cm² wrong answer answer is 74.5 cm2 |
|
| 16. |
Shuttle cock is a combination of |
|
Answer» Ans :- SHUTTLECOCK is a combination of HEMISPHERE and FRUSTUM. |
|
| 17. |
A hollow cone is cut by a plane parallelto the base and the upper portion isremoved. If the curved surface of theremainder is 8/9th of the curved surfaceof the whole cone, find the ratio of theline segments into which the cone'saltitude is divided by the plane. |
| Answer» | |
| 18. |
27 A hollow cone is cut by a plane paraliel to the base and the upper portion is removed. If the curved surfacethe remainder is of the curved surface of the whole cone, find the ratio of the line- segment into whicone's altitude is divided by the plane.,B''L |
| Answer» | |
| 19. |
Construct the tangents fromA Ocone is cut by a plane parallel to the baseand the upper portion is removed. If thesurface of the isoofe remainder isof the curved surface, find the ratio of the line segmentsinto which the cone's altitude is divided by the plane.the whole cone2 |
| Answer» | |
| 20. |
A hollow cone is cut by a plane parallel to the base and the upperportion is removed. If the curved surface of the remainder is 8/9 ofthe curved surface of the whole cone, find the ratio of the lineICBSE 2004, '04Csegments into which the altitude of the cone is divided by the plane. |
| Answer» | |
| 21. |
11 + sine i1-sin θ-2see&Prove that |
| Answer» | |
| 22. |
N (x+4)(x+10) |
| Answer» | |
| 23. |
Height of the seciuTA hollow cone is cut by a plane parallel to the base and the upperportion is removed. If the curved surface of the remainder is 8/9 ofthe curved surface of the whole cone, find the ratio of the linesegments into which the altitude of the cone is divided by the plane.0ICBSE 2004. 04C] |
| Answer» | |
| 24. |
Prove that : (1 + tan20) (1+sine) (1-sin6)- 1 |
|
Answer» (1+tan ^2 theta)(1-sin^2 theta)1+(sin^2/cos^2)(1-sin^2 theta)(cos^2+sin^2)/(cos^2 theeta)*(cos^2 theeta) = 1RHS |
|
| 25. |
4. The ne term of a sequence is 3n-2. Is the sequence an A.P.? If so find the 10" term. |
| Answer» | |
| 26. |
29. A shuttle cock used for playing badmintonas the shape of a frustum of a conemounted on a hemi-sphere as shown inthe figure below. The external diameters ofthe frustum are 6 cm and 2 cm; and theheight of the entire shuttle cock is 7 cm.Find its external surface area. |
|
Answer» Given:r1= 1 cm,r2= 2.5 cm,h= 6 cml = √h² + (r2-r1)²= √(6)² + (2.5-1)² cm= √36 + 2.25 cm= √38.25 cm= 6.18cmSo,External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)= 22/7(r1+r2)l +2.22/7.r1= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²= 22/7 (3.5 × 6.18 +2) cm²= 22/7 (21.63+2) cm²= 22/7 × 23.63 cm²= 519.86/7 cm²= 74.26 cm² |
|
| 27. |
s cmot A shuttlecock used for playing badminton has the shapea frustum of a cone mounted on a hemisphere as shownthe figure. The external diameters of the frustum are 5 em andcm and the height of the entire shuttlecock is 7 cm. Finexternal surface area.1 cmICBSE Sample Paperl iAns. 74.26 cm2approx.) |
|
Answer» Given:r1= 1 cm,r2= 2.5 cm,h= 6 cml = √h² + (r2-r1)²= √(6)² + (2.5-1)² cm= √36 + 2.25 cm= √38.25 cm= 6.18cmSo,External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)= 22/7(r1+r2)l +2.22/7.r1= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²= 22/7 (3.5 × 6.18 +2) cm²= 22/7 (21.63+2) cm²= 22/7 × 23.63 cm²= 519.86/7 cm²= 74.26 cm² |
|
| 28. |
Write down the next three natural numbers after 10999.1001 |
| Answer» | |
| 29. |
Use Euclid's Algorithm to find the HCF of 1001 and 385 |
|
Answer» 1001=385*2+231385=231*1+154231=154*1+77154=77*2+0HCF=2 |
|
| 30. |
A hollow cone is cut by a plane parallel to the base and the upperportion is removed. If the curved surface of the remainder is 2 of thecurved surface of whole cone, find the ratio of the line segments intowhich the cone's altitude is divided by the plane. |
| Answer» | |
| 31. |
33)/ State and Prove Sine formula by Vector method |
|
Answer» Like if you find it useful |
|
| 32. |
Write the product of prime factors of 2556ă |
|
Answer» 255 = 3 × 5 × 17 |
|
| 33. |
A sequence (an) is given by the formula an 10-3n, Prove that it is an A.P |
|
Answer» An = 10 - 3n Putting value of n, Let n = 1 , Then, A1 = 10 - 3 *1 A1 = 7 For n = 2, A2 = 10 - 3 *2 A2 = 10 - 6 = 4 For n = 3 , A3 = 10 - 3 * 3 A3 = 10 - 9 = 1 Now, A2 - A1 = 4 - 7 = - 3 = d A3 - A2 = 1 - 4 = - 3 = d Since, Difference is common. So, Common difference is same. Hence, The given sequence is in A. P. hmmm |
|
| 34. |
A Shuttle cock used for playing badminton has the shape of frustrum ofa cone mounted on the hemisphere. The external diameters of thetum are 5cm and 2cm and height of the entire shuttle cock is 7 cm. Findthe external surface areafrus- |
|
Answer» Given:r1= 1 cm,r2= 2.5 cm,h= 6 cml = √h² + (r2-r1)²= √(6)² + (2.5-1)² cm= √36 + 2.25 cm= √38.25 cm= 6.18cmSo,External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)= 22/7(r1+r2)l +2.22/7.r1= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²= 22/7 (3.5 × 6.18 +2) cm²= 22/7 (21.63+2) cm²= 22/7 × 23.63 cm²= 519.86/7 cm²= 74.26 cm² thanks |
|
| 35. |
1. Write 98 as product of its prime factors. |
|
Answer» On doing prime factorization, we get as:98 = 2 * 7 * 798 = 2 *7^298 = 2 * 49 |
|
| 36. |
5016 x 1001 -333x77+22=2x 11 |
|
Answer» 5016*1001 - 333*77 + 22 =? + 11 5021016 - 25641 + 22 = ? + 115021038 - 25641 = ? + 114995397 - 11 = ?? = 4995986 No. Ans is 454127 |
|
| 37. |
(d) 9| (c) 8(a) 4143156 * 942 में लुप्त अंक ज्ञात करें जिससे यह संख्या 11 से पूर्णतया विभक्त हो ?(b) 7(एस०एस०सी०। नातिभत हो ? |
|
Answer» hi friend I don't know the answer and please also like my answer sorry bro I didn't know the of this question |
|
| 38. |
d) 63Find the mean of: 8,11,6,14,17 and 13.a) 11.510.b) 11.611. If the arithmetic mean of hoc)11.7d) 11.8 |
|
Answer» mean = (8+11+6+14+17+13)/6 = 69/6 = 11.5 |
|
| 39. |
state and prove Pascal's formula for combination |
| Answer» | |
| 40. |
11. Express 156 as a product prime factors. |
|
Answer» how many two digits number are divisible by 3 |
|
| 41. |
123X 1001 Shou withCanclationConslea |
| Answer» | |
| 42. |
- 156 * 942 में लुप्त अंक ज्ञात करें जिससे यह संख्या 11 से पूर्णतया विभक्त हो? |
|
Answer» 9 is the correct answer of this question 9 is the correct answer of this question 9 is the right ans of this question 9,is the right answer of question |
|
| 43. |
owing distribution gives the state-wise teacher-stu0elly schools of India, Find the mode and mean of this data. Interpret tt ratio imber of students per teacherNumber of states / U .Т.15-2020-2525-3030-3535-4040-4545-5050-55102 |
| Answer» | |
| 44. |
Average weight of 24 students of a class is32 kg. A teacher is also included and thusthe average is increased by 2 kg. What isthe weight of that teacher ? |
|
Answer» average is 32so total weight=32×24=768now after adding teacher average will be 34so total weight=34×25=850so weight of teacher = 850-768=82 kg |
|
| 45. |
926 यात्रा पर गया एक आदमी पहले 120 km, 600 की गति से और अगले 120 ।ताए, 80ता की गति से तय करता है। यात्रा कीऔसत गति क्या हैं?(A) 70 km/h (B) 68.57 km/h(C) 71.11 km/h \)/69(]3'23 km/h |
|
Answer» answer is A = 70 km/h |
|
| 46. |
omplify the15611 7 |
|
Answer» 15/11-6/7nowLCMof 11 and 7= 77105-66/7739/77thanks What is mobile................. |
|
| 47. |
Themid point ofT-926) iG A and B.the live joining (2294) and(2, 2012) Find the values |
|
Answer» Let P (2, 2a + 2) is mid point of line joining (3a, 4) and (-2, 2b) Then,2 = (3a - 2)/24 = 3a - 23a = 6a = 6/3 = 2...... (1) 2a + 2 = (4 + 2b)/2Put value of a from eq(1)2*2 + 2 = 2 + b6 - 2 = bb = 4 Therefore, value of a = 2 and b = 4 |
|
| 48. |
: MATÍThe following distribution gives the state-wise teacher-student ratio in highsecondary schools of India. Find the mode and mean of this data. Interpret the tmeasuresNumber of students per teacherNumber of states /U.T.15-2020-2525-3030-3535-4040-4545-5050-5510 |
| Answer» | |
| 49. |
16. State the formula for the area of rhombus. |
|
Answer» To find theareaof arhombus, multiply the lengths of the two diagonals and divide by 2 (same as multiplying by 1/2): The sides and angles of a rhombus: The sides of arhombusare all congruent (the same length.) Opposite angles of arhombusare congruent (the same size and measure.) the area of rhombus=1/2× measure of diagnol 1× measure of diagonal 2 |
|
| 50. |
4. The following distribution gives the state-vsecondary schools of India. Find the mode and mean ofthis datameasures.nt ratio in higher. Interpret the twoNumber of students per teacherNumberofstates/ U.T15-2020-2525-3030-3535-4040-4545-5050-5510 |
| Answer» | |