A rectangular field 80m by 60m has two cross roads each measuring 10 m

1.	A rectangular field 80m by 60m has two cross roads each measuring 10 m wide running in the middle of it. Find the coat of gravelling them at the rate of 5 rs
Answer» FOR RECTANGULAR LAWN.Length, L = 80m.Breadth, B= 60m. For Vertical road:length= Breadth of rectanglelength = 60m. Breadth = 10m. Thus, Area of vertical road=length × breadth= 60m ×10m=600m². For Horizontal road:length = length of rectangle.length = 80mbreadth= 10m. Thus, area of horizontal road= length ×breadth= 800m × 10m=800m². Note: The roads overlap in the middle of rectangle and form a square having side of 10m. FOR SQUARE:Area of square = Side × SideArea of square = 10m × 10mArea of square = 100m². Therefore,Area needd of road to be gravel = Area of vertical road + area of horizontal road - area of square = 600m² + 800m² -100m²= 1300m². If the cost of gravelling for 1m² = Rs 5So, Cost of gravelking for 1300m²= 1300 ×Rs 5=Rs 6500. Ans.

A rectangular field 80m by 60m has two cross roads each measuring 10 m wide running in the middle of it. Find the coat of gravelling them at the rate of 5 rs

Answer»

FOR RECTANGULAR LAWN.Length, L = 80m.Breadth, B= 60m.

For Vertical road:length= Breadth of rectanglelength = 60m.

Breadth = 10m.

Thus, Area of vertical road=length × breadth= 60m ×10m=600m².

For Horizontal road:length = length of rectangle.length = 80mbreadth= 10m.

Thus, area of horizontal road= length ×breadth= 800m × 10m=800m².

Note: The roads overlap in the middle of rectangle and form a square having side of 10m.

FOR SQUARE:Area of square = Side × SideArea of square = 10m × 10mArea of square = 100m².

Therefore,Area needd of road to be gravel = Area of vertical road + area of horizontal road - area of square

= 600m² + 800m² -100m²= 1300m².

If the cost of gravelling for 1m² = Rs 5So, Cost of gravelking for 1300m²= 1300 ×Rs 5=Rs 6500. Ans.