This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
23. Solve the following system of linearequations graphically3x+y-11=0 and x-y-1=0Also, find the area of the region bounded bythese lines and the Y-axis. |
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| 2. |
using the digits 3,5,2,7write all possible 4digit numbers (use a digit only once) |
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Answer» vgklplkhfdsdffhhhcdfv ans will 35275237327572357532 3527527327357352 is answer 35273275523772357532 please answer my question too 35273275523772357532 please answer my question too yessurewhy notwhatis que 3527, 3275, 5237, 7235, 7532 35273275523776325337 35273275523772357532is the right answer 352732573752327537253572 |
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| 3. |
Write all the possible 2digit numbers that can be formed by using the digits 7,8,5 If the repetition of the digit is allowed |
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Answer» 77, 78, 75, 88, 87, 85, 55, 57, 58 77,78,75,88,87,85,55,57,58 |
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| 4. |
log(-x %2B 1, 2) %2B log(-x %2B 3, 2)=3 |
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| 5. |
2) if x-3+ V8 find the value of x +170 |
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| 6. |
If x=8, find the value of V8 + x - 5. |
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Answer» 3√8+8-5as 2^3=8hence 3√8=2hence2+8-510-5=5 |
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| 7. |
Find the next term of the A.P. V8, v18,V32, |
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Answer» √8=2√2√18=3√2√32=4√2.. 2√2, 3√2, 4√2 ...so the next term is 5√25√2 =√50 Hence the next term is √50..please share the feedback and the like the solution 👍 ✔️ |
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| 8. |
14.Evaluatev5 + 2V6+ v8- 2y15. |
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Answer» √(5+2√6)=√(3+2+2√3.√2)=√{(√3)²+2.√3.√2+(√2)²}=√(√3+√2)²=√3+√2 (neglecting the negative sign)√(8-2√15)=√(5+3-2.√5.√3)=√{(√5)²-2.√5.√3+(√3)²}=√(√5-√3)²=√5-√3 (neglecting the negative sign)∴,√(5+2√6)+√(8-2√15)=√3+√2+√5-√3=√2+√5 Ans. HIT LIKE BUTTON ✔️👍 |
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| 9. |
9x 15xs_ (x-2)2 = 323. |
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| 10. |
which is equivalent to V8 |
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Answer» 3√8 = 3√2*2*2= 22 is equivalent to 3within overroot 8the multiple of 3 comes out 1 |
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| 11. |
Everything equal itself. What does it justify? |
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Answer» I hope you are talking mathematics here. Reflexive property simply states that any number isequal to itself. Reflexive property, forallreal numbers x, x = x. A numberequals itself. Two numbers are onlyequalto each other if and only if both the numbers are same. |
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| 12. |
Cards marked with numbers 3,4,5.,...,5,50 are placed in a box and and mixedthoroughly. One card is drawn at random from the box, find the probability thatthe number on thedrawn card is(i) divisible by 7 (ii) a number, which is a perfect sqaure |
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| 13. |
acos((x - 1)/(1 %2B 4)) %2B asin((x - 1)/(x %2B 1)) |
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Answer» pi/2. sin inverse X+ cos inverse X= pi /2 the answer will be π/2 |
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| 14. |
Solve graphically the system:3x +4y < 12, x-y < 1, x >=20, y >=20. |
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Answer» 3x+4y<12x-y<1 so 4x-4y<43x+4y+4x-4y<12+47x<16so x<16/748/7+4y<12so 4y<12-48/7so 4y<36/7so y<9/7 |
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| 15. |
y=x^2 %2B asin(x) %2B log(x, e) |
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| 16. |
y=acos(x) %2B asin(x) |
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| 17. |
acos(x) %2B asin(x)=pi/2 |
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Answer» Let sin^-1 x = Ax = sin A = cos(pi/2 - A)cos^-1x = pi/2 - Acos^-1x = pi/2 - sin^-1xsin^-1x + cos^-1x = pi/2 |
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| 18. |
lim x--->1 (x^2-9x-20)/(x^3-6x+5) |
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| 19. |
-48 \times 20 x-1 x-5 |
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Answer» -4800 4800 by basic multiplication-960×5=-4800 |
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| 20. |
( 1 ) x ^ { 2 } + 9 x + 20 |
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Answer» thanks |
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| 21. |
44. xs_ (20-1) x + (b2-b-20) |
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Answer» x²−(2b−1)x+(b²−b−20)=0 ComparingtheaboveequationwithAx^2+Bx+C=0 ,Weget, A=1B=−(2b−1)C=b²−b−20 Now,D=B²−4AC=(2b−1)^2−4(b²−b−20)=4b^2+1−4b−4b^2+4b+80=81>0 So,theaboveequationhas2realanddistinctrootsgivenby,x=−B+D√2Aorx=−B−D√2A⇒x=2b−1+92orx=2b−1−92⇒x=b+4orx=b−5 Like my answer if you find it useful! |
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| 22. |
20) if x 3+ v8 find the value of x+120 |
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| 23. |
Write all the possible numbers using digits 0,8,4,3,9,5,1,2 and 6.Write their predecessor and successor. |
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Answer» 2 ki power n where n=no. of digits ans=256 |
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| 24. |
e/ If ome angle of a triange is equal to the sum of other two, show that the triangle is a rightangle. |
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| 25. |
26. Cards marked with numbers 3,4,5,.......,50 are placed in a box and and mixedthoroughly. One card is drawn at random from the box, find the probability thatthe number on thedrawn card is(i) divisible by 7 (ii) a number, which is a perfect sqaure |
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| 26. |
x^3 %2B 1/(x^2) %2B 1/x %2B 1 |
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| 27. |
(((x %2B 2)*(x %2B 3))*x(x %2B 1))/x(x %2B 1) |
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Answer» (X+2)(X+3) is the correct answer of the given question =(x+2)(x+3)is answer |
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| 28. |
y=asec((x %2B 1)/(x - 1)) %2B asin((x - 1)/(x %2B 1)) |
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| 29. |
(x %2B 1/x)*(x^4 %2B 1/(x^4)) |
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| 30. |
Change the Voice1. I am trying a new method.2. My parents love me. |
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Answer» 1, A new method is being tried by me2. I am loved by my parents |
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| 31. |
Why had Jerome to unpack the bags? How many times did he do so? |
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| 32. |
(dc +xp) (ds—xp) ७9) |
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Answer» (a-b)(a+b)=a²-b² (4x-5y)(4x+5y)=(4x)²-(5y)²=16x²-25y² |
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| 33. |
\ds)(1 + x)sin?(x-âŹ%) |
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| 34. |
Find the value of){x(1-x)”ds |
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| 35. |
3/15 %2B 1/14 %2B 2/7 |
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Answer» 117/210 is the correct answer 117/210 is correct answer 117/210 is the correct answer of the given question 117/210 is the right answer....... (f) 1/14 +2/7 +3/15=15 + 60 + 42=117/210=39/70 answer 117/210 is the best answer The right answer is 117/210.... 117/210 is the correct ans 117/210 is the correct answer 117/210 is the correct answer 117/210 is the answer of the following |
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| 36. |
-9*(x %2B 1/x) %2B 2*(x^2 %2B 1/(x^2)) %2B 14=0 |
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| 37. |
v सत्यापित HHTC: (i) 12 + 99 = (x+y) (2e xy + yz< Ry |
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| 38. |
the 4 urn of a Inc segu t re ten ry s an A- eInd dhea o 」 |
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Answer» TYSM |
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| 39. |
= 2R Ry "*"a“5 e - 20512228 RE 05 | RRK) isA s दे दे जा अ o o ool |
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| 40. |
RY THIS40°Extend AB to E. Find ZCBE. What dyou notice. What kind of angles aZABC and ZCBE? |
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Answer» as AD and BC are parallel hence angle DAB and angle CBE are corresponding angleshence they will be equalhence angle bce =40° |
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| 41. |
1, Cost price 600, selling pricăŚ2800. |
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| 42. |
e pric306. Find its original price.e of a garment has been reduced by 15% in a sale to |
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Answer» Let original price=xReduced percentage = d = 15 % S.P of the garment = S.P = Rs 306S.P = original price × ( 100 - d ) / 100Original price = ( s.p × 100 ) / ( 100 - d )x = (306 × 100 ) / ( 100 - 15 )x = ( 306 × 100 ) / 85x = 360 |
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| 43. |
ds |
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Answer» it will be simplified as2x^53x^5 |
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| 44. |
4650. The shopkeeper offers an off-sanThe marked price of a water cooler is 46-it Find its selling price. |
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| 45. |
Original pricNew price =60h01 Calculate the value of the given per cent.a 30% of?'300 Sd 75% of400 mangoesg 100% of 7.20Find |
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Answer» a) 30% of ₹ 300 30/100 × ₹300 = ₹ 90 b) 75% of 400 75/100 × 400 75 × 4 300 g) 100 % of 7.20 100/100 × ₹ 7.20 ₹7.20 |
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| 46. |
The marked price of a water coolers?4650. The shopkeeper offers an off season discount of 18% on it. Findits selling price.8. |
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Answer» yes you are right |
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| 47. |
A die is thrown once. Find the probability of getting (i) a compositenumber, (ii) a prime number. |
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Answer» There are total 6 possibilitiesfor a composite number there are 4,6hence probability will.be 2/6=1/3For a prime number 2,5,3=3/6=1/2 Total number of die = 6 1. Composition Number are 4 and 5 = 2 The probability of composition number = 2/6 = 1/3 2. Prime Number are 2, 4 and 6 = 3 The probability of prime number = 3/6 = 1/2 |
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| 48. |
20. A childhasa block in the shape of a cube with one letter/number written on each face as shown bel2 3 5 7 A BThe cube is thrown once. Find the probability of(a) getting an alphabet.(c) getting a consonant.(b) getting a prime number |
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Answer» Probability = possible outcomes /total outcomes Here,Total outcomes = 6 (a) Probability of getting an alphabet = 2/6 = 1/3 (b) Probability of getting a consonant = 1/6 (c) Probability of getting a prime number = 4/6 = 2/3 answer is (b)getting a prime numbet |
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| 49. |
Find the mean, mode and median of following data:8, 12, 16, 18, 19, 20, 12, 10, 5, 15. |
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Answer» Explanation : Numbers in ascending order 5,8,10,12,12,15,16,18,19,20 Mean = (5+8+10+12+12+15+16+18+19+20)/10 = 135/10 = 13.5 Median = (5th term + 6th term)/10 = (12+15)/2 = 27/2 = 13.5 Mode = Most repeated element = 12 Solution : Mean = 13.5 Median = 13.5 Mode = 12 If you find this answer helpful then like it |
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| 50. |
13. A die is thrown once. Find the probability of getting(0) a prime number, (ii) a number lying between 2 and 6;((iii) an odd number. |
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