44. xs_ (20-1) x + (b2-b-20)

1.	44. xs_ (20-1) x + (b2-b-20)
Answer» x²−(2b−1)x+(b²−b−20)=0 ComparingtheaboveequationwithAx^2+Bx+C=0 ,Weget, A=1B=−(2b−1)C=b²−b−20 Now,D=B²−4AC=(2b−1)^2−4(b²−b−20)=4b^2+1−4b−4b^2+4b+80=81>0 So,theaboveequationhas2realanddistinctrootsgivenby,x=−B+D√2Aorx=−B−D√2A⇒x=2b−1+92orx=2b−1−92⇒x=b+4orx=b−5 Like my answer if you find it useful!

Answer»

x²−(2b−1)x+(b²−b−20)=0

ComparingtheaboveequationwithAx^2+Bx+C=0

,Weget,

A=1B=−(2b−1)C=b²−b−20

Now,D=B²−4AC=(2b−1)^2−4(b²−b−20)=4b^2+1−4b−4b^2+4b+80=81>0

So,theaboveequationhas2realanddistinctrootsgivenby,x=−B+D√2Aorx=−B−D√2A⇒x=2b−1+92orx=2b−1−92⇒x=b+4orx=b−5

Like my answer if you find it useful!

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