14.Evaluatev5 + 2V6+ v8- 2y15.

1.	14.Evaluatev5 + 2V6+ v8- 2y15.
Answer» √(5+2√6)=√(3+2+2√3.√2)=√{(√3)²+2.√3.√2+(√2)²}=√(√3+√2)²=√3+√2 (neglecting the negative sign)√(8-2√15)=√(5+3-2.√5.√3)=√{(√5)²-2.√5.√3+(√3)²}=√(√5-√3)²=√5-√3 (neglecting the negative sign)∴,√(5+2√6)+√(8-2√15)=√3+√2+√5-√3=√2+√5 Ans. HIT LIKE BUTTON ✔️👍

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√(5+2√6)=√(3+2+2√3.√2)=√{(√3)²+2.√3.√2+(√2)²}=√(√3+√2)²=√3+√2 (neglecting the negative sign)√(8-2√15)=√(5+3-2.√5.√3)=√{(√5)²-2.√5.√3+(√3)²}=√(√5-√3)²=√5-√3 (neglecting the negative sign)∴,√(5+2√6)+√(8-2√15)=√3+√2+√5-√3=√2+√5 Ans.

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14.Evaluatev5 + 2V6+ v8- 2y15.

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