Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The angle of elevation of cloud from point ‘h’ m above surface of lake is θ and the angle of depression of its reflection in lake is ɸ. Prove that height of cloud from lake is h[(tanɸ + tanθ)/(tanɸ-tanθ)]

Answer»
2.

yS0o -y s07O R ARGV uisz-yusपश्पा ग*०्य्त LT

Answer»

(sinθ- 2 sin^3θ)/(2cos^3θ-cosθ)

=sinθ(1-2sin^2θ)/cosθ(2cos^2 θ-1)

= sin θ [1- 2(1- cos^2 θ)/cos θ(2cos ^2 θ -1)

= sin θ [1-2+ 2cos ^2 θ]/ cos θ (2 cos^2θ -1)

= sin θ(2cos^2 θ -1)/ cos θ(2 cos ^2θ-1)

= sin θ/ cos θ

= tanθ

3.

ⓒ Compare the(リ3.anel

Answer»

3*5/4*5 and 4*4/5*4=15/20 and 16/20=hence 16/20>15/20

4.

4 सु e penie) BRE 2 0 QSR धन T

Answer»

कालीबंगा राजस्थान के हनुमानगढ़ ज़िले में घग्घर नदी के बाएं तट पर स्थित है। खुदाई 1953 में 'बी.बी. लाल' एवं 'बी. के. थापड़' द्वारा करायी गयी। यहाँ पर प्राक् हड़प्पा एवं हड़प्पाकालीन संस्कृति के अवशेष मिले हैं। यह प्राचीन समय में चूडियों के लिए प्रसिद्ध था। ये चूडियाँ पत्‍थरों की बनी होती थी

5.

12.8 cm28. From a cubical piece of wood of side 21 cm, a hemisphere is carved ouin such a way that the diameter of the hemisphere is equal to the side othe cubical piece. Find the surface area and volume of the remainingpiece.20 A

Answer»

Cubical volume =21*21*21=9261cm3cubical surface area =6*21*21=2646cm2diameter = side of cubical piece radius =diameter/2r=21/2=10.5cmvolume of new side =10.5*10.5*10.5=1157.625cm3surface area of new side =6*10.5*10.5=661.5cm2 volume of remaining piece =9261-1157.625=8103.375cm2surface area remaining piece 2646-661.5=1984.5cm2

6.

An article was purchased for Rs.1239 including GST of 18%. Find the price of the article before added the GST.

Answer»

Cost with gst included = rupees 1239

Cost with out gst = x rupees

gst = 18%

If we take this into equation -

x + ( ( 18 ÷ 100 ) × x ) = 1239

cost before gst + gst = cost with gst

x + ( 9x ÷ 50 ) = 1239

( 50x + 9x ) ÷ 50 = 1239

59x ÷ 50 = 1239

59x = 1239 × 50

59x = 61950

x = 61950 ÷ 59

x = 1050

Price before GST = 1050 rupees

7.

EXERCISE 1B1. Represent each of the following numbers on the number line:(iii) 15

Answer»

plz explain carefully

8.

EXERCISE 1B1. Represent each of the following numbers on the number line:(iii) 1 -(iv) 2(v) 3(vi) 5(vii) 4(viii) 8

Answer»

eska ans ky hoga

9.

cimal7. Rahul attempted in of the total numberof questions in an examination. If of theanswers were wrong, what fraction of theattempted questions did he answer correctly?

Answer»

He attempted 9/10*100= 90 percentagequestionnowwrngt answers = 3/8*100300/8= 150/4= 75/2= 37.5 percentageso remainin= 90-37.552.5 percentage he attempted right

he attempted 9/10*100=90percentagequestionnowwrngt answer=3/8*100300/8=150/4=75/2=37.5percentageso remain=90-37.552.5percentage he attempted right

10.

51. 8963-5413-2869=?(1) 861 (2) 663(5) इनमें से कोई नहीं(3) 681(4) 654

Answer»

8963-5413-2869=8963-(5413+2869)=8963-8282=681Therefore option 3 is the correct answer.

8963-5413-2869= 8963-(5413+2869= 8963-8282=681c is correct

11.

b61 The solution of differential equationdy-ex-y + x²e-Y isdx36813Y+C

Answer»
12.

vatives so that the order of difterentiation is immaterial.10.Prove that dicurlA=0,i.ะต.,โ–ฝ-(TXA)-2-Romhav 681

Answer»

Part 1

Part 2

13.

7. What is an earthquake?

Answer»

Anearthquake(also known as aquake,tremorortemblor) is the shaking of the surface of the Earth, resulting from the sudden release of energy in theEarth'slithospherethat createsseismic waves. Earthquakes can range in size from those that are so weak that they cannot be felt to those violent enough to toss people around and destroy whole cities. Theseismicity, orseismic activity,of an area is the frequency, type and size of earthquakes experienced over a period of time. The wordtremoris also used fornon-earthquake seismic rumbling.

14.

Which visual fraction model correctly shows the shaded region for theexpression?

Answer»
15.

3Saran is 4 times as old as his bon.After 16 years, he will be twice as oldas his son find his son's present age.

Answer»

let son age =x yearsfather age = 4x16 years after son age = x+16father age= 4x +16A/S4x+16=2(x+16)4x+16= 2x+324x-2x= 32 -162x= 16x= 16/2=8so son present age= 8 yearsfather present age= 4x= 4×8=32 years

16.

Evaluate:cosec? (90° - 0) न tanzfi-o4(cos? 48° + cos? 42°)2 tan? 30°.sec* 52°.sin” 38sec? 70° — cot~ 20°

Answer»
17.

42. If sin θ2x and x cos θ-2, 0°< θ < 90°, then the value of 2 | x2 +-11 is :

Answer»
18.

EXERCISE 8.1t.) The angles of quadrilateral are in the ratio 3 5: 9 13. Find all the angles ofquadrilateral.bon how tbat it is a rectang

Answer»
19.

If 0 < S 90°, solve for 'e' wherecos? - 3 cos + 2 = 2 sin? O.A)60°B)45°C)90°D)30°

Answer»

option C ) 90° is correct answer

20.

(a)40(6)10(c)9044. यदि 3:436 :: है, तो . का क्या मान होगा -

Answer»

x= 8 is the correct answer of the given question

3/4=6/x3x=6×43x=24x=8

3/4=6/x3x=6×43x=24x=8answer

correct answer for this question is 8

8 is correct answer.

Q - 3 : 4 = 6 : x 3 /4 = 6 / x 3x =24 x = 8

21.

Evaluate \frac{\sec 17^{0}}{\csc 73^{0}}+\frac{4}{3} \tan ^{2} 60^{\circ}+\cos ^{2} 44^{\circ}+\cos ^{2} 46-8 \cos ^{3} 60^{\circ}

Answer»
22.

(3) 60(4)9015. सदिश A तथा B इस प्रकार हैं कि A + B = |A-B सदिशA तथा B के मध्य कोण होगा -[RPMT 1999, AIPMT 2006](1) 90 (2) 60 (3) 75 (4) 45

Answer»

90°square of both side we will get cos theta= 0 means angle 90

90° will be the best ans

4:(45)is the correct answer.

45 is the correct answer

45 is correct option

45 is correct answer

45 is the right answer

23.

A box contains 90 disc, numbered from 2 to 90. If one disc is drawn at random from the box, the probability that it bears a prime number less than 23 is

Answer»

The given box contains disc numbered as 1 to 90. The number of elements in the sample space is n(S) = 90.The prime numbers less than 23 are 2, 3, 5, 7, 11, 13, 17, 19So there are 8 prime numbers. If E denotes the set of these prime numbers then n(E) = 8Therefore probability of getting a prime number less than 23= n(E)/n(S) = 8/90 =4/45

24.

hox contains 90 dises which are numbered from I to 90. If one disc is drawn at randomthe box, find the probability that it bears (i) a two-digit number (ii) a perfecquare number (ii) a number divisible by 5

Answer»
25.

\begin{array}{l}{\frac{4 \sin ^{2} 60+\sec ^{2} 60+4 \sin ^{2} 45+3 \cos ^{2} 90}{\sec 60+\cos \operatorname{ec} 30^{\circ}-\sin 90}} \\ {\text { (a) } 0}\end{array}

Answer»

sin60=√3/2 sec60=2 sin45=1/√2 cos90=0cosec30=2 sin90=1put in equation4*3/4+4+4/2+3*0/2+2-13+4+2/4-19/3=3

26.

A box contains 90 discs ,numbered from 1 to 90.If one disc is drawn at random from the box,find the probability that it bears a prime number less than 23.

Answer»
27.

cost of 5 wristwatches of the same type is6250. What is the cost of 16 such wristwatches?Solution:

Answer»

5 are of 6250 so 16 are of 6250×16/5 = 20000 Rs.

28.

A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at randomfrom the box, find the probability that it bears () a two-digit number (i) a perfectsquare number (ii) a number divisible by 5.18.

Answer»
29.

市刌市可Tat

Answer»
30.

factorise by the following.ů) a3_63+ gab tat

Answer»
31.

77す礻肖き9528.1282, Tat'at

Answer»

wrong

32.

Isimplity = 55 +13Egr-Sn-tat

Answer»
33.

न शभलैसक- ७ Sec = 0Fhoiapyoke tat bew = P+ L

Answer»
34.

5. Find three rational numbers between - 2 and - 1.TAT.

Answer»

-2*5/1*5, - 1*5/1*5-10/5, - 5/5Three rational numbers between - 2and -1 are-6/5, - 7/5, - 8/5

35.

가나 largest- Syaane that Canchiawncliam etrrLe.nt tんe whe tat

Answer»
36.

рди | 2NN= =

Answer»

x + 2 7-------- = ------x - 2 3

3( x + 2) = 7 ( x - 2)

3x + 6 = 7x - 14

7x - 3x = 20

4x = 20

x = 5

Thanks

37.

कि हजNNi~

Answer»
38.

that the drawn card is(1)neitherĂkinghĂśraqueet()redqueelCalu10. A box contains 90 discs, numbered from 1 to 90. If one disc is drawn at random from the box.find the probability that it bears () a prime-number less than 23 (i) a perfect square number.

Answer»

Total Numbers=90No. of prime numbers less than 23=8 (2,3,5,7,11,13,17,19)(i)Probability=8/90=4/45No. of perfect square numbers=9(1,4,9,16,25,36,49,64,81)(ii) Probability=9/90=1/10

39.

Deduct 2 from 7and Add 1to it.Answer will be

Answer»

deduction of 2 from 7 = 7-2 = 5

addition of 1 to it= 5+1 = 66 will be the answer.

40.

!! бы The-ratio of the present ages of Abha and her: 5. At the time of Abha's birth, heronsmother is 2ber mothers age was 27 years. Find the present ages ofrseAbha and her mother.

Answer»

Let the present age of Abha be x yearsHence the age of her mother is x + 27 years.

Given:

x/(x + 27) = 2/5

5x = 2 (x + 27)

5x = 2x + 54

3x = 54

x = 18 years

Answer - The present age of Abha is 18 years and her mother's age is (18 + 27 = 45 years)

41.

a right triangle has hypotenuse of length p cm and one side of length q cm. if p-q=1, find the length of the third side of the triangle

Answer»
42.

Fimel the enton and correct the Satament axb=, |asb are the multiples of where as cia the factorof a and be

Answer»

axb=c//c-a=b;;c-b=a.

yes it the correct answer is a*b=c//c-a=b::c=a

acb=c//c-a=b;;c-b=a is anwer

a*b=c//c-a=b::c=a is the correct answer

a*b=c//c-a=b::c=a is the answer of the following

axb=c-a=b;c-b=a. is the correct answer

43.

— (Al(A1) ०0६ ०9800 + ,0¢ 205पा= (m

Answer»

Like my answer if you find it useful!

44.

find the AP 7,13,19,.......205

Answer»

FindAP 18,15_1/2,13,. ....,-47

45.

The sum of the ages of a mother and a daughter is 50years. Also, 5 years ago, the mother's age was 7 timesthe age of the daughter. The present ages of the motherand the daughter respectively are:

Answer»

The age of mother is 40 and daughter is 10

46.

From a point Q. the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is

Answer»
47.

a point Q, the length of the tangent to a circle is 24 cm and the distance of Q froncentre is 25 cm. The radius of the circle is

Answer»
48.

1. From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q fromthe centre is 25 cm. The radius of the circle is

Answer»
49.

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q fromthe centre is 25 cm. The radius of the circle is

Answer»
50.

The present age of girl is two fifth the age ofher father.' Express the above statement as alinear equation in two variables. Also find:(a) the age of the girl when father is 40years.(b) the age of the father when the girl is 22(CBSE 2012)years.

Answer»

Thnk u