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A box contains 90 disc, numbered from 2 to 90. If one disc is drawn at random from the box, the probability that it bears a prime number less than 23 is |
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Answer» The given box contains disc numbered as 1 to 90. The number of elements in the sample space is n(S) = 90.The prime numbers less than 23 are 2, 3, 5, 7, 11, 13, 17, 19So there are 8 prime numbers. If E denotes the set of these prime numbers then n(E) = 8Therefore probability of getting a prime number less than 23= n(E)/n(S) = 8/90 =4/45 |
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