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(x + 4) ( x + 10)

x² + 10x + 4x + 40

x² + 14x + 40

aUb is set -2,-3,2,3. A intersection B is an empty set. there are not equal set . there are equivalent set because both set a and B as 2 no of sets

sets are equal A-(2,3) B-(2,3) roots are 2,3 of QE

The answer is 2 as the first number is always given on /-axis

The ans for P(2,3) is 2

the distance from x-axis of the point p (2,3) by the formula distance from x-axis=the value of yd

distance from x-axis =value of y=3

i)4 pi r²

= 4 × 3.14 × (10.5)²

= 1,384.74 cm²

ii)

4 pi r²

= 4 × 3.14 × (5.6)²

= 393.8816 cm²

x^2-3x+2=0(x-1)(x-2)=0range is [1,2]domain is (-infinity,1]U[2, infinity)

3/5 of 5/8 is greater

(3/5 of 5/8) > (2/7 of 3/4 ) .

x-3/8=1/4x=1/4+3/8x=5/8option d is a correct answer

X=1/4+3/8X=5/8 answer

x-3/8=1/4x=1/4+3/8x=5/8option d is correct answer.

correct answer is 5/8

x=5/8 is the right answer

x - 3/8 = 1/4; x =1/4 +3/8 = 2+3/8=5/8

x=5/8 is the right answer

x =5/8 is the right answer

×-3/8=1/4×=1/4=3/8×=5/8😨😨😈😈😠😠😠😤

X=1/4+3/8X=5/8 answer

x-3/8=1/4x=1/4+3/8x=5/8option d is correct answer

5/8 is the right answer

question nhi ayga paper mai

a^2+16+8a-5ab-20b-6b^2

A: B:C:D=16:24:30:25

The height of the aeroplane can be AB

and C and D be the position of 2 ships.

Let ∠ ABC = 60° and ∠ADB = 30°

Let BC = xm, CD = y m

in triangle ABC,

tan 60° = AB/BC

√3 = 1200/x

x = 1200/√3 = √3/√3

= 400√3 m

In triangle ABD

tan 30° = AB/BD

= 1/√3 = 1200/ x + y

y = 1200/√3 - 400√3 = 800√3

The final answer for this question is 800√3

170.5

9/2 is correct answer

Area swept in 2 hrs= 2*pi*r*r

r = 3.5 cmArea swept = 2*22/7*3.5*3.5 = 44*.5*3.5 = 22*3.5 = 77 cm^2

thanks friend

9/2 this is 100persent right answer

15 1/2 - [12/5 * 5/8 + (7 ÷ 1 3/4)] * 2

= 31/2 - [3/2 + (7 ÷ 7/4)]*2

= 31/2 - [3/2 + (7 * 4/7)]*2

= 31/2 - [3/2 + 4]*2

= 31/2 - [(3 + 8)/2]*2

= 31/2 - 11

= (31 - 22)/2

= 9/2

= 4 1/2

9/2 is correct answer.

9/2 is correct answer

Like my answer if you find it useful!

31/2-[12/5*5/8+(7÷7/4)]*231/2-[3/2+4]*231/2-11/2*231/2-1131-22/29/2

is carcat answer 9/2

31/2 -[3/2 +(7 ÷ 7/4)]×231/2 -[3/2 + 4]×231/2 -[11]=9/2

2500 + 200 -12

= 2700 - 12

= 2688

thanks

2500+200-12

2700-12

2688

A (-3,6) is the midpoint of DE , B(0,7) is the midpoint of EF and C(1,9) is the midpoint of FD.

Let D = (x1, y1) , E = (x2 , y2) and F = (x3 , y3)

so, A is the midpoint of DE so, (-3, 6) = {(x1 + x2)/2, (y1 + y2)/2} x1 + x2 = -6y1 + y2 = 12

Similarly, B is the midpoint of EF so, x2 + x3 = 0y2 + y3 = 14

and C is the midpoint of FD so, x3 + x1 = 2 y1 + y3 = 18

now, solving equations, x1 = (x1 + x2 + x3) - (x2 + x3) =-2 + 0 = -2 x2 = (x1 + x2 + x3) - (x1 + x3) = -2 -2 = -4 x3 = (x1 + x2 + x3) - (x1 + x2)= -2 - 6 = -8

Similarly, y1 = (y1 + y2 + y3)- (y2 + y3)= 22 - 14 = 8 y2 = (y1 + y2 + y3) - (y1 + y3) = 22 - 18 = 4 y3 = (y1 + y2 + y3) - (y1 + y2) = 22 - 12 = 10

hence, D(-2,8) , E(-4, 4) and F(-8, 10)

now, we have to show that ABCD is a parallelogram.

we know, diagonals of parallelogram intersect at midpoint. e.g., midpoint of diagonal AC = midpoint of diagonal BD.

midpoint of AC = {(-3+1)/2, (6+9)/2} = (-1,15/2)midpoint of BD = {(0-2)/2, (7+8)/2} = (-1,15/2)

hence, it is clear that, ABCD is a parallelogram.

4500+3000+2500+2500 = 4500+3000+5000= 12500.

sum of 4500+3000+2500+2500=12500

005754 this is right answer

माना R को एक्स भाग मिलाsoQ will get x/4P will get3x/20nowx+3x/20+x/4= 80x+12x+20x/4= 5600112x= 5600*4x= 200P will get = 3*200/20= = 30

Sin73° = cos17=and cos 37° = sin 53°so we know that sin^2+cos^2= 1then sin^2(73)+cos^2(73)/cos^2(37+sin^2 (37}1/1= 1 Answer

sinjskwkakskkskskwkskwkwkw sjjwjsjsjwjwkwkwo

thank you very much

3/4(7x-1) - (2x - (1-x)/2) = x + 3/221x/4 - 3/4 - 2x + 1/2 - x/2 = x + 3/221x/4 - 3x - x/2 = 3/2 + 3/4 - 1/2(21x - 12x - 2x)/4 = (6 + 3 - 2)/47x = 7x = 7/7 = 1

Value of x = 1

1/x + 5/y = 2........(1)3/x + 10/y = 3......(2)

Multiply eq(1) by 33/x + 15/y = 6...... (3)

Subtract eq(2) from eq(3)15/y - 10/y = 6 - 35/y = 3y = 5/3

Put value of y in eq(1)1/x + 5/(5/3) = 21/x = 2 - 31/x = - 1x = - 1

tan^2x - sec^2x = 1

As we know the above formula,

x = 42 1/2

Like my answer if you find it useful!

the answer is 2706.0804

Given- (a+b)= 5 and ab=6

(1/a +1/b)= (a+b)/ab = 5/6

(1/a+1/b)=(a+b)/ab=5/6

(1/a+1/b)=(a+b)ab=5/6

Given-(a+b)=5 and ab=6

(1/a+1/b)= 5(a+b)/ab=6

=5/6

given (a+b)=5 and ab=6. (1/a+1/b)=(a+b)/ab. =5/6

given,a+b=5 and ab=6

1/a + 1/b= a+b/ab =5/6

1/5

Given that , a+b =5ab=6 then (1/a+1/b) = a+b/ab = 5/6 ORLet , a=3 and b=2 then put these value in these equation then answer is 5/6

1/a+1b = 1/(a) + 1(b)... (one and one cancelled)= a+b =5

if a+b=5 also ab =6then 1/a + 1/b =a+b/ab=5/6=8.33

given (a+b)=5and ab=6(1/a+1/b)=(a+b)ab=5/6

your answer is this -5/6

(1/a+1/b)=(b+a)/ab5/6

a+b=5,ab=61/a +1/ba+b/ab=5/6

5/6 is the solution to the above question

Given ( a + b ) = 5 and ab = 6 ( 1 / a + 1 / b ) = ( a + b ) / ab = 5 / 6

if, a=3, b=2a+b=53+2=5 (as,a=3 & b=2)ab= 63*2=6 (as, a=3 & b=2)so, 1/a+1b1/3+1*2=2*1/3

i dont know it is difficult

If a+b=5 an=6then 1\a+1b1\2+1×31\2+31+3\24\2=2that is your ansI hope it will help you

to prove :1/a+1/b=b+a/ab=a+b/ab=5/6

1/a+1/b=(a+b)/ab = 5/6

(1/a+1/b)=(a+b)/ab=5/6

(1/a+1/b)=5 (a+b)/ab=6=5/6

(1/a+1/b)=(a+b)ab=5/6

a+b=5a=5-bab=6b=6/anow1/5-b+6/aa/11-b

1/a+1/b(a+b)/aba+b=5;ab=6so, 5/6

a+b=5 and ab=6 By observation value of a and b are 3 and 2So nxt 1/a and 1/b=?1/3+1/2 =2+3/6this implies that the value is 5/6

if a+b =5 ab=6 then 1/a+1b?

given that,a+b=5andab=6 now, (1/a+1/b)=(a+b)/ab=5/6

1/a+1b=1/2+1/3=5/6(a=2 and=3

given (a+b)=5 and ab=6(1/a+1/b)=a+b)/ab= =5/6

(1/a+1/b) =(a+b)/ab =5/6

1 2 4 8 161 2^1 2^2 2^3 2^(n-1)a a2^1 a 2^2 ....geometric sequence witha = 1r = 2n = number of days

2^59 = area

2^x = 2^59/2x = n-1 = 58 so 59 dayswhich we could have said right offbecause if you cover the whole lake in 60 days then the day before you must have half the lake covered.

It is givenPerimeter =28m4*side=28mSIDE=28/4SIDE=7 CMANOW According to the question AREA=BASE*ALTITUDE

63m^2=7*ALTITUDE ALTITUDE=63/7m

Let AO=HCD=OB=60mA'B=AB=(60+H)m

In triangke AOD,tan30'=AO/OD=H/OD

H=OD/√3OD=√3 H

Now, in triangle A'OD,tan60'=OA'/OD=(OB+BA')/OD√3=(60+60+H)/√3 H =(120+H)/√3 H=>120+H=3H 2H=120 H=60m

Thus, height of the cloud above the lake = AB+A'B =(60+60) = 120m

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Self respect self confidence self-reliance how can you show to others that you have these qualities give some examples

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