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x-4/2 - x-3/4=1/6; 4( x-4)-2(x-3)=4/6; 4x-16-2x+6=2/3; 4x-2x-16+6=2/3; 2x-10=2/3; 2x=2/3×10=20/3; x=20/3 × 2=10/3

x-4/2 - x-3/4; 4( x-4)-( x-3)/4,; 4x-16-x+3/4; 4x-x-13=4/6; 3x-13=4/6; 3x-13=2/3; 3x=2+13/5; 3x=15/5=3;; x=3/3=1

3x-13=2/3; 3x=2+13/3=15/3; 3x=5; x=5/3

answer is 20x = -102

a ka answer x-3/6 ho ga

12m^2-7m^2-9m+5m-7m+10=5m^2-11m+10

(9m-5m/3)^2=[(27m-5m) /3]^2=(22m/3)^2=(7.3m)^2=49.9m ans

{(27m-5m/3)}²(22m/3)²49.9 mis the correct answer

2m^+7m+62m^+4m+3m+62m(m+2)+3(m+2)2m+3=0 or m+2=0m=-3/2 or m=-2

5m=60m=60/5m=12 is the answer

5m=60m=60/5 m=12 is your answer bro

First, we'll assume that √p + √q is rational, where p and q are distinct primes√p + √q = x, where x is rational

Rational numbers are closed under multiplication, so if we square both sides, we still get rational numbers on both sides.

(√p + √q)² = x²p + 2√(pq) + q = x²2√(pq) = x² - p - q

√(pq) = (x² - p - q) / 2

Now x, x², p, q and 2 are all rational, and rational numbers are closed under subtraction and division. So (x² - p - q) / 2 is rational.

But since p and q are both primes, then pq is not a perfect square and therefore √(pq) is not rational. But this is a contradiction. Original assumption must be wrong.

So √p + √q is irrational, where p and q are distinct primes

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We can also show that √p + √q is irrational, where p and q are non-distinct primes, i.e. p = q

We use same method: Assume √p + √q is rational.√p + √q = x, where x is rational√p + √p = x2√p = x√p = x/2

Since both x and 2 are rational, and rational numbers are closed under division, then x/2 is rational. But since p is not a perfect square, then √p is not rational. But this is a contradiction. Original assumption must be wrong.

So √p + √q is irrational, where p and q are non-distinct primes

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∴ √p + √q is irrational, where p and q are primes

The answer is (ii) 1/5

(i)-1/13 (ii)5 (iii)-1 (iv)2/3 (v)6/5

here is a similar question.

solution for your question-

Put in first equationhence2(2)+5(1)=4+5=9hence it's a solutionPut in secondhence2+1+4=7 hence it isn't a solution

answer my last question

5/2*(2)+3(1)=5+3=8 not equal to 14

Hence not a solution

No it's not a multiple of (2t+3)😊

let g(t) be 2t+3=02t=-3t=-3/2

now, p(-3/2)=2*(-3/2)³+3*(-3/2)²+3*(-3/2)+18=2*(-27/8)+3*9/4-9/2+18=-27/4+27/4-9/2+18=0-9/2+18=18-9/2=(36-9)/2=27/2=13.5

therefore, g(t) is not a multiple of p(t).

So,by integral test, the series is divergent.

since by comparison taste summation of (1/n)^p is convergent iff p)>1 here p=1

series ia divergent.

1 convergence it is true answer

2nd is correct answer

nPk = n!/(n-k)! nP4/(n-1)P4 = 5/3 (n!/(n-4)!)/((n-1)!/(n-1-4)!) = 5/3 (n(n-1)!/((n-4)(n-5)!))/((n-1)!/(n-5)!) = 5/3 n/(n-4) = 5/3 3n = 5n - 20 20 = 5n - 3n 2n = 20 n = 10

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4x^2y+8xy=4xy(x+2)is the factorie form

=4xy(x+2) is the factories form

4xy(x+2)is the factories from

4x^2y+8xy=4xy(x+2)is the fector

4xy(x+2) this is a answer of factor

4x^2y+8xy4x^2y: 2*2*X*y8xy: 2*2*2*X*y2,xand y are commonso,2xy(2x+4)

4x^2y+8xy=4xy(x+2) is the sector.

1) 7m + (-2m) + (-5m) = 7m - 7m = 0

2) (2y-2) + (3y+4) + (-5y-8) = (2+3-5)y + (-2+4-8) = - 6

3) (3x-5)+(-2x) + (-4x) +(5-6x) = (3-2-4-6)x + (-5 +5) = - 9x

Let x be any integer

Then x = 5m or x = 5m+1 or x = 5m+4 for integer x.

a. If x = 5m, x2= (5m)2= 25m2= 5(5m2) = 5n (where n = 5m2)

b. If x = 5m+1, x2= (5m+1)2= 25m2+10m+1 = 5(5m2+2m)+1 = 5n+1 (where n = 5m2+2m )

c. If x = 5m+4, x2= (5m+4)2= 25m2+40m+16 = 5(5m2+8m+3)+1 = 5n+1 (where n = 5m2+8m+3 )

Thus in each of three cases x2is either of the form 5n or 5n+1 for integer n.

5m to 10km isse ratio mai nikalo

then 1/X=1/3+2√2=(3-2√2)/(3+2√2)(3-2√2)=3-2√2/9-8=3-2√2hence X+1/X=3+2√2+3-2√2=3+3=6..hence it is rationao

Two numbers, x & yy=3x-4x + y + 5 = 25x + 3x - 4 + 5 = 254x +1 = 254x = 24x = 6, So one of the numbers is 6, now solve for yy = 3x-4 = 3(6)-4 = 14

1/2 z - 2 = 26z/2 = 26 + 2z = 28*2z = 56

VerifyLHS: z/2 - 2 = 56/2 - 2= 28 - 2= 26= RHS

pata nhi

answer is may be -7 not very sure

7 is the correct answer

7 is the correct answer of the given question

∆ABC and ∆ PQR by SSS rule

Add 4 and 54+5=9The result is 9

thank you sir

it's wrong mam

thanks

6 = 2 × 320 = 2 × 2 × 5lcm = 2 × 2 × 5 × 3 = 60HCF = 2

5m ( 3 - m) + 6m² - 13m

15m - 5m² + 6m² - 13m

m² + 2m

400

d²y7 ------- = [ 1 + (dy/dx)²]⅔ dx²

Cubing both sides

343 (d²y/dx²)³ = [1 + (dy/dx)²]²

Order of differential equation is 2

Degree of differential equation is 3

very easy

Answer

1. order of the matrix = 3*4

2. number of elements = 12

3. a13 = 19 a21 = 35 a33 = -5 a24 = 12 a23 = 5/2

1

Both are composite numbers because one of them has 11 as a factor other than itself and 1 another has 7 as a factor other than itself and 1.

X=4/5(X+10)5x=4x+40X=40