1.

Check whetherp(t) 6t+3t+3t+ 18 is a multiple of (2t+3)

Answer»

No it's not a multiple of (2t+3)😊

let g(t) be 2t+3=02t=-3t=-3/2

now, p(-3/2)=2*(-3/2)³+3*(-3/2)²+3*(-3/2)+18=2*(-27/8)+3*9/4-9/2+18=-27/4+27/4-9/2+18=0-9/2+18=18-9/2=(36-9)/2=27/2=13.5

therefore, g(t) is not a multiple of p(t).


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