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5Find the value of n such that 114 n> 49.m-1p3 |
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Answer» nPk = n!/(n-k)! nP4/(n-1)P4 = 5/3 (n!/(n-4)!)/((n-1)!/(n-1-4)!) = 5/3 (n(n-1)!/((n-4)(n-5)!))/((n-1)!/(n-5)!) = 5/3 n/(n-4) = 5/3 3n = 5n - 20 20 = 5n - 3n 2n = 20 n = 10 If you find this answer helpful then like it. |
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