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Let Alpha be the one zero of the given polynomial.

Then the other will be 1/Alpha

P(X) = 5X²+13X+K

Here,

A = 5 , B = 13 and C= K

Product of zeros = C/A

Alpha × 1/Alpha = K/5

1 = K/5

K = 5.

CP of inverter=10800profit percent=10%profit=(10/100)*10800=1080SP=CP+profit=10800+1080=11880

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answer is 18 I am wright

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I want

oye isme points milte hai wo kaise

Let his original salary be ₹ X. Then, (100+10)/100 * X = 154000=> X = 154000*(10/11)=> X = ₹ 140000.

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70 is the correct answer

70ia the correct answer

70 is the right answer

right answer is 70 because we know that the sum of Angeles of triangle is 180.

angle C =70 degree is the correct answer

(10r²+3r) - (5r²+11r)

= 5r²-8r

Given quadratic equation =√3x² - 8x + 4√3 = 0We should factorize the equation first. =√3x²-6x-2x+4√3 = 0 =√3x(x-2√3)-2(x-2√3) = 0 = (√3x-2) (x-2√3) = 0 = (√3x-2) = 0 , (x-2√3) = 0 = x = 2/√3 , x = 2√3.

Let us assume that Mohan’s salary before the raise was x

Then they gave him a 8% raise on his salary of x

Then his current salary = original salary + the raise

151200 = x + 0.08x

151200 = 1.08x

==> x = 151200 / 1.08

= 140000

Formula : area=l*ba)Given : area=204 m sq; b = 12m204=l*12l=204/12=17Therefore length=17 mb)given: area=450cm sq ; b=18 cm450=l*18l=450/18=25Therefore length= 25 cm

Let the equation be : y= mx+cSince, angle made with x-axis is 60° , slope(m)= tan 60°= √3

Also, distance of this line from (0,0), which is center of circle ,is radius=2.

So, c²=a²(1+m²) c²= 4(1+3)c= 4So, equation is : y= √3x + 4

8x - x² - 15

First we find zeroes

-x² + 8x - 15 = 0

-x² + 3x + 5x - 15 = 0

-x ( x - 3) + 5 ( x - 3) = 0

(5 - x) ( x - 3) = 0

So, x = 3 and 5

Therefore, when x

---------------------------------------- - | + | - 3 5

So, 8x - x² - 15 is negitive when x < 3 and x > 5

A) option

Given:area triangle ABC =64 cm and and area PQR =120 cmthen:since both triangles are similarso,64/121=(BC/QR)^264/121=(BC/15)^28/11=BC/15BC=8×15/11=10.909cm

please explain

this is a similar ques.the only change you have to make is in the first step where instead of 11, draw a line segment of 9.5cm

the water for a factory stored in a hemisphere tank whose internal diameter is 14m.the tank contains 50kilolitres of water. water is pumped in the tank to fill it's capacity calculate the volume of water pumped into the tank.

p^2x^2-( p^2-q^2)x-q^2= 0, p^2x^2-p^2x-q^2x-q^2=0, p^2x(x+1)-q^2( x+1)=0, (p^2x-q^2)(x+1)=0; p^2x=q^2; x=q^2/p^2; x=-1

Take H.C.F. of 156, 208 and 260.

=> HCF of 156 and 208

P.F. of 156 = 2×2×3×13P.F. of 208 = 2×2×2×2×13Therefore, H.C.F. of 156 and 208 = 2×2×13 = 52

=> Now , H.C.F. of 52 and 260

P.F. of 52 = 2×2×13P.F. of 260 = 2×2×5×13H.C.F. = 2×2×13 = 52

●Max. number of students per bus = 52

●Total number of students = 156+208+260 = 624 students.

●No. of buses = 624/52 = 12 buses.

3(2x-4)=-4x+286x-12=-4x+2810x=40x=40/10x=4

I m not satisfied

1) geometric mean of 4 and 25 = (4*25)^2 = (100)^2 = 10

2) x + y = 5..... (1) x - y = 7..... (2)

Add eq(1) and eq(2)2x = 12x = 6

Value of x = 6

Part 1

Part 2

HJ

Slope m = 1 and -1By comparison to y = mx+c

We will write the equation x+y=0 as y=-x+0 Now comparing it with y=mx+c we will get m=-1Similarly for second equation m=1

According to Question m = 1 and -1 slope

x+y=0this is in form of ax×x+bx+c=0a=1,b=1 m=-a/b=-1/1=1x-y=0this is in form of ax×x+bx+c=0a=1,b=-1 m=-1/-1=1

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