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15 is negative:(C) x = 0, x = 513. The value of x when the value of 8r x(A) x < 3, x25(B) x > 3, x < 5(D) x = 3, x = 5 |
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Answer» 8x - x² - 15 First we find zeroes -x² + 8x - 15 = 0 -x² + 3x + 5x - 15 = 0 -x ( x - 3) + 5 ( x - 3) = 0 (5 - x) ( x - 3) = 0 So, x = 3 and 5 Therefore, when x ---------------------------------------- - | + | - 3 5 So, 8x - x² - 15 is negitive when x < 3 and x > 5 A) option |
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