This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
\frac 1 3 x %2B y = \frac 10 3 ; 2 x %2B \frac 1 4 y = \frac 11 4 |
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| 2. |
the electricity bill and the telephone bill of a family for month of June were in the ratio 6:16 if R 800 more was paid for the telephone than for the electricity how much was paid for each? |
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Answer» Let X be the common multiple of the ratios As per the given, 6x + 800 = 16x 800 = 16x - 6x 10x = 800 x = 800/10 = 80 The charges of electricity bill = 6x = 6 * 80 = 480The charges of telephone bill = 6x + 800 = 480 + 800 = 1280 Like my answer if you find it useful! |
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| 3. |
( c ^ { - 2 } ) ^ { 2 / 3 } \times c ^ { 3 / 2 } \div c ^ { - 3 } |
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| 4. |
if a + b + c= 5, ab + bc + ca= 10, Prove that :-a3+ b3 + сз-abc=-252 |
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Answer» We know , a³ + b³ + c³ -3abc = (a + b + c )(a² + b² + c² -ab -bc-ca) now , a + b + c = 5 ab + bc + ca = 10 (a + b + c)² = a² + b² + c² +2(ab + bc+ca)(5)² -2×10 = a² + b² + c² a² + b² + c² =5 hence , a³ + b³ +c³ -3abc = ( a + b + c )(a² + b² + c² -ab- bc-ca) =( 5)( 5 - 10) = 5 × (-5) = -25 hence proved// |
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| 5. |
13 J C -८ -८-२ ॥17. यदि 3559 तथा 5 : ८ = 9, 10, तो ab: C को ज्ञात कीजिए।- -2/ 25 नो ... को बात की । |
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Answer» a:b:c = 5:9:10As the ratio of b is same in both of the ratios hence we show it like that. a:b:c = 5:9:10this is your answer |
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| 6. |
13. 20+/)+3 (1+1/). terms, equals-(B) n2(D) of these |
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| 7. |
first three terms of an AP respectively are 3-1, 3y + 5 and 5y +1,Theny equalsB) 4(C), 5(D) 22 |
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Answer» Thank you |
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| 8. |
If a^b = b^c = ab, then b + c always equals |
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| 9. |
If a bab, then b + c always equals |
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| 10. |
PERIMETER AND AREFind the missing values:Base Height Area of Triangle15 cm87 cm2 |
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Answer» Area of triangle = b×h/287=15×h /2174=15×h h=174/15 =11.6 cm |
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| 11. |
(2) Find the radius of a sphere having surface area1256 cm2. (T 3.14)Ans. |
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Answer» Surface area = 4πr^2 1256 cm^2 = 4(3.14)r^2 r^2 = 100cm^2 r = 10 cm |
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| 12. |
35 11 17 351 20, a which is the smallest fraction ?11.111)(4) 16되었58 |
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Answer» the smallest fraction is 35÷64 option(1) 17/32is the best answer option (3) is the best 5/8 option a is correct answer according to your question answer 117/32 is the correct answer 17/32 is correct answer. option (1) 17/32 is the right answer according to your question |
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| 13. |
14.The price of carrots is twice that of potatoes. Rajbought 3 kg carrots and 2 kg potatoes for160. Find the per kg price of carrots andpotatoes. |
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| 14. |
( - 3 a ^ { 2 } b ^ { 3 } c ) \times ( - 5 a b c ) |
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Answer» (-3a²b³c)*(-5abc) = 15a³b⁴c² |
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| 15. |
(-1)*(-11) %2B (-10)*(-11) |
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Answer» 121 is the right answer ok 121 is the right answer ok 121 is the right now 121 is the right answer |
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| 16. |
) Frame a word problem using the given clues:-(1) Town, Men, Women, 5037, 3927. Total population(2) Anil, Shirt, Rs. 2000, Jeans, Rs.3499, Altogether |
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Answer» Men=5037women=3927 Total population is ,5037+3927=8964 Anil shirt =2000and jeans 3499 altogether, 2000+3499=5499 |
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| 17. |
1. लुप्त संख्या ढूंढना-5/31/8137 ? 728(A).97 (B).87 (C). 82 (D). 45 |
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Answer» the correct answer is d 45 45 is the correct answer The correct answer is 45. 45 is the right answer. plz like my answer 45 is the right answer d 45 I think so........ . correct answer is 45 49 is a correct answer 45 is the right answer option (d) ,45 is the right answer 45 is the right answer 45 is correct answer |
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| 18. |
(5) Frame a word problem using the given clues:-(1) Town, Men, Women, 5037, 3927, Total population(2) Anil, Shirt, Rs. 2000, Jeans, Rs.3499. Altogether |
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Answer» 1. What is the total population of the men and women in the town2. What। is the cost of anil's shirt and jeans there are 5037 women and 3927 men in a town. what is the total population? Anil brought a shirt for ₹2000 and jeans for ₹3499 what is the total cost altogether? 1: In a town there are numbers of men and women are 5037,3927.find the total population 2: Anil went to market and bought a shirt which cost him 2,000 and jeans 3,499 altogether how much amount did he had to pay |
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| 19. |
\left. \begin{array} { c } { 3000 } \\ { \times 5 } \end{array} \right. |
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Answer» The answer to 3000 x 5 = 15000 |
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| 20. |
Simplify:\left(\frac{5 c^{4} b^{3}}{a^{2}}\right)^{3} \times\left(\frac{a^{2}}{4 b^{2} c^{5}}\right)^{2} |
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| 21. |
(C) 145.960, A certain sum of money triplesitself in 5 years at simpleinterest. In how many years itwill be five times?/5肓爽响ㄒㄧㄒ司可TZTt? \ |
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Answer» Let the Principal be Rs.100amount=300 SI=p*r*t/100200=100*r*5/100200=5r200/5=r40=r the rate of interest is 40% required amount=500required interest=400 400=100*40*t/100400=40t400/40=t10=t it will take 10 years to be 5 times. Like my answer if you find it useful! |
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| 22. |
(a)28. If 4-4 24, then (2x) equalsb) 5(c) 25/5 |
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| 23. |
04 20002000न. «आन |
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Answer» thanks |
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| 24. |
B-9.a The angle between the two tangents from the origin to the circle (x-7) (y1)25 equals42 |
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Answer» The distance between origin(0,0) and center of circle(7,-1) is √(7²+(-1)²) = 5√2.So, we can construct a circle of radius 5√2 and concentric to given circle. radius of given circle is 5 The newly constructed circle has radius is √2 times radius of given circle and concentric with given circle. So, the new circle is director circle of given circle. So, the angle between tangents must be π/2 |
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| 25. |
कीजिए।2हल 2 का मान ज्ञातदा l0g,(2000)° ' log,(2000)° |
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| 26. |
3^2x+4 + 1 = 2*3^x+2. Find x? |
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Answer» 3^2x+4 + 1 = 2.3^x+2 3^2(x+2) + 1 = 2.3^x+2 Let 3^(x+2) = A => A² + 1 = 2A=> A² - 2A + 1 = 0=>(A-1)² = 0=> A = 1=> 3^(x+2) = 3^0=> x + 2 = 0=> x = -2 Therefore the value of x is -2 |
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| 27. |
x ^ { 2 } + 1 / x ^ { 2 } = 27 \text { then find } x ^ { 3 } + 1 / x ^ { 3 } \text { and } x |
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Answer» hi hi hi hi hi hi hi are you sure hey hey |
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| 28. |
x = \frac { \sqrt { 3 } + 1 } { 2 } , \text { find the value of } 4 x ^ { 3 } + 2 x ^ { 2 } - 8 x + 7 |
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| 29. |
\left. \begin{array} { l } { \text { If } x = 3 - 2 \sqrt { 2 } , \text { Find } x ^ { 2 } + \frac { 1 } { x ^ { 2 } } } \\ { \text { If } a = 1 - \sqrt { 3 } , \text { find the value of } ( a - \frac { 1 } { a } ) ^ { 3 } } \end{array} \right. |
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| 30. |
3. If total software exports in 2000 - 2001 were expected to be Rs10,000 crore and the growth of Infosys is the same as it was in 1999 -2000, what would have been Infosys' share of exports of these 12companies in 2000 - 2001?A. 15% |
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Answer» the answer is 15% is correct happy environment day 15% is the correct answer |
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| 31. |
LOGARITHM:238.The value of expression+-\frac{2}{\log _{4}(2000)^{6}}+\frac{3}{\log _{5}(2000)^{6}}sequalto |
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| 32. |
Draw a pie diagram to represent the following population in a townWomenGirlsBoysMen4200180020002000Total10000 |
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| 33. |
. If the surface area of a spherical ball is 1256 cm2, then find the volume of ssphere. (Take T-3.14) |
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Answer» surface area of sphere ball is 4×pi×r²4 × 3.14 × r² = 1256r² = 1256/(4×3.14) = 100r = √100r = 10so volume of sphere is 4/3 ×pi× r³4/3 × 3.14 × 10³ = 4,186.67 cm³ |
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| 34. |
: ‘J xa“‘fl |
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Answer» (a-b)²+(a+b)²=a²+b²-2ab+a²+b²+2ab=2(a²+b²) |
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| 35. |
Base Helght Area of Triangle87 cm31 A mm1256m22 om |
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| 36. |
an inch equals 25.4 mm. express 3 miles in terms of Km. correct to 2Assam H.S '85, 87 1IAns. 4.83 km]4. Ifdecimal places. |
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Answer» thanks 🙂 |
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| 37. |
3 c ^ { 7 } \times 5 c ^ { 0 } \times 2 c ^ { - 6 } |
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Answer» 3c^7*5c^0*2c^-6=3c^7*5*2c^-6=30c^7-6=30c thanx |
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| 38. |
If xa = у, уь = z and zCzx, then prove that abc= 1. |
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| 39. |
2. Simplify the following:(1) ao x at xas xa |
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Answer» 21 a^6×a⁴×a^-5×a^0=a^{6+4-5+0)=a^5 a to the power5 is the right answer |
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| 40. |
xa + yb + zcya + zb + xcza + xb + yeéĄ 1a+b+c |
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| 41. |
2 31 2find x, y so that A2 xA + yl.32 If A- |
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| 42. |
के.xa + xb + ya +yb |
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Answer» 6+5-7-4+2+1-6-6+7+7+6+4-8-9 |
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| 43. |
(D)2b+c-a23(A)xa+b-c(B)x(C) 1(D) 0 |
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| 44. |
The angle of elevation of the top of a tower from a point on the samelevel as the foot of the tower is 30. On advancing 150 m towards thefoot of the tower, the angle of elevation becomes 60°. Show that theheight of the tower is 129.9 metres. [Given /3 -1.732.] [CBSE 20osc) |
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| 45. |
2000...o XA |
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Answer» 2000/60 ×(3×40)=33.333×3×40=4000 |
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| 46. |
BaseHeight Area of Triangle87 cm21256 mm170.5 cm15 cm31.4 mm22 cm |
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Answer» Area=1/2*base*height1) height=(2*area)/base=(2*87)/15=11.62) base=(2*area)/height=(2*1256)/31.4=803) height=(2*area)/base=(2*170.5)/22=15.5 |
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| 47. |
the missing values:Base Height Area of Triangle87 cm1256 mm170.5 cm15 cm31.4 mm22 cm |
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| 48. |
PERIMETER AND A4.Find the missing values:Base Height Area of Triangle87 cm21256 mm2170.5 cm15 cm31.4 mm5. PORS is |
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| 49. |
26.The angle of elevation of the top of a tower from a point on the samelevel as the foot of the tower is 30, On advancing 150 m towards thefoot of the tower, the angle of elevation becomes 60°. Show that theheight of the tower is 129.9 metres. [Given 3 1.732.] caSE 2008 |
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| 50. |
4. The angle of elevation of a tower from a point on the same level as the foot of the tower is30° Onadvancing 150 metres towards the foot of the tower, the angle of elevation of thetower becomes 60°. Show that the height of the tower is 129.9 metres (Use 3 1.732).[CBSE 2006] |
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