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x is an integer. So,it is of the form 3k,3k+1 or 3k+2 where k is an integer.

If x=3k,then

x+1=3k+1,not divisible by 3

x+2=3k+2,not divisible by 3

If x=3k+1(not divisible by 3),then

x+1=3k+2,not divisible by 3

x+2=3k+3=3(k+1), divisible by 3

If x=3k+2(not divisible by 3),then

x+1=3k+3=3(k+1),divisible by 3

x+2=3k+4=3(k+1)+1,not divisible by 3

Hence by seeing all the above cases,we can safely say that:out of x,x+1 and x+2,only one is divisible by 3.

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We are looking for a new number which is 748 more than 66443.We will get the new number by adding 748 to 66443.We write it down as:66443+748=67191

66443 more then numbers

I want equation in one variable😅

Let the tens digit be x and the units digit be y.

So the number=10x+y

A.q.=>x=2y(equation 1)

After interchanging the digits we get10y+x

Also,=>(10x+y)+(10y+x)=66

=>10x+y+10y+x=66

=>11y+11x=66

=>11(y+x)=66

=>y+x=66/11

=>y+x=6

From equation 1 x=2y

So, y+2y=6

=>3y=6

=>y=6/3

=>y=2

And x=2(2)=4

Hence the number is 42.

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A. us right answer

A is the correct answer 1st si is 360 and second principal+ si then 405 difference is 45

B) is correct answer

option C ) is the correct answer

By using prime factorisation 33 = 3*11 44= 2*2*1166= 2*3*11

so, in all these only 11 is common.. so the answer is 11.

Let the two digit number be (10a+b)According to the question(10a+b)+(10b+a)=66; 11a+11b=66;a+b=6;And also it is given that a=5b or b=5aIf a=5b then put in the above equation 6b=6; then b=1 then a=5...then the number is 51 and if a=1 then b=5 then the number is 15

In mathematics, a real-valued function is a function whose values are real numbers. In other words, it is a function that assigns a real number to each member of its domain. Many important function spaces are defined to consist of real-valued functions

Domain (1/2 to infinity) and range (0 to infinity)

12 boys are there in the classthis is the correct answer for this question Thank you sir

this is the crispy snacks

deep river is a snacks.

12 boys are there in the class

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deep river is the snacks...

12 boys are there in class

Total students =40no. of girls= 70% of 40 =70/100*40 =28therefore number of boys= 40-28=12

12 is the correct answer for this question

first think then act is the right answer

25+31+27+29+32+28+25=190/15=12.667

25+31+27+32+28+25=190/15=12.667

12.667 is the correct answer

12.667 is the. correct. answer

(a) Let the per cent be a. 600 x a /100 = 60 600a = 60 x100 a = 60 x 100/600 a = 10 % similarly you can do every question. But, for their unit should be sameLike in (c) convert 8hrs to day by dividing by 24 and in

3+√2/4√2*4√2/4√2=12√2+8/32=3/8√2+1/4

Let, speed of faster car = x km/hSpeed ofslowercar = y km/h

Relative speed when both cartravelsinsame direction= x - yIf the cars travel in thesame directionat different speeds, they meet in 5 hoursSpeed = distance/ timeTotal distance= 100 kmSpeed, x – y = 100/5x – y = 20x = 20 + y................…(1)

Relative speed when both cartravelsin opposite direction = x + yIf they travel towards each other, they meet in 1 hour.Speed = distance/ timeTotal distance= 100 kmSpeed, x+ y = 100/1

Put the value of x from eq(1)We get, 20 + y + y = 1002y = 80y = 40

Put the value of y in eq(1)we get,x= 20 + 40x = 60

Hence speeds are 40 km/h and 60 km/h

Explanation : 5*5th term = 8*8th term 5(a + 4d) = 8(a + 7d) 5a + 20d = 8a + 56d 3a = -36d a = -12d a + 12d = 0 13th term = a + 12d = 0 13th term is 0.

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let first term be a and common difference be daccording to given question5 × a(5) = 8 × a(8)5(a + 4d) = = 8(a + 7d)5a + 20d = 8a + 56d3a + 36d = 0a + 12d = 0a = -12dso,a(13) = a + 12d = -12d + 12d = 0

(1+cot A -cosec A)(1+ tan A + sec A)

Lhs

=(1 +cos A/sin A - 1/sin A)(1 + sin A/cos A +1/cos A)

=(sin A+cos A -1/sin A)(cos A +sin A+1/cos A)

=(sin A+cos A-1)(sin A+cos A+1)/sin Acos A

=[(sin A+cos A)^2-(1)^2]/sin Acos A

=[sin^2A+cos^2A +2sin Acos A- 1]/sin Acos A

=[1-1+2sin Acos A]/sin Acos A

=2sin Acos A/sin Acos A

=2 =Rhs

Interest = 3000- 2500= 500.INTEREST = PRT/100=> R = (500*100)/(2500*5)=> R = 4 %

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am=1/na+(m-1)d=1/n--------(1)

an=1/ma+(n-1)d=1/m---------(2)

(1)-(2)(m-n)d=1/n - 1/md=1/mn

put in eq(1)a+(m-1)/mn=1/na=1/n - (m-1)/mna=1/mn

amn=a+(mn-1)damn=1/mn+(mn-1)/mnamn=1

Therangeof an even indexed radical starts at its startingpoint(1,0)(1,0)and extends toinfinity.

[0,∞)[0,∞)

{y|y≥0}

Domain:[1,∞),{x|x≥1}

If the sum doubles (x2) in 15 years.

Then it to become 2*2*2 = 8 times as large it should double three times.

so three 15 years time period are needed, which is 3*15 = 45 years.

So the answer is 45

10100100010000100000100000010000000sab ke sab live wise answer hai isliye Ab Mujhe like karo, jawab mat khao a b c d e f g h s s i number likhe Hain

a. 10000b. 100000Yeh Hai Nabi Ka answer Ab Mujhe like karo please

Let smaller number be nThen greater number = 2n + 11

Given,n + 2n + 11 = 803n = 80 - 11 = 693n = 69n = 69/3 = 23

Smaller number = 23Greater number = 2*x + 11 = 2*23 + 11 = 46 +11 = 57

thankyou

plants whose stem we eat

plants whose stem we eat

Let the numbers be x and y where x>y so,

x^2 - y^2 = 120.....(1)

y^2 = 2 x.....(2)

Putting (2) in (1), we get

x^2 - 2x = 120

x^2 - 2x - 120 = 0

x^2 - 12x + 10x - 120 = 0

x(x -12) +10(x - 12) = 0

(x-12)(x+10) = 0

So x can be 12 or -10, but we are given that the square of smaller number is twice the larger number, therefore the square of any number cant be negative,

Thus x cant take value of -10

So x = 12, so y^2 = 2 (12)

y^2 = 24

So y = √24 or - √24

y = 2√6 or -2√6

Hence the numbers are 12 and 2√6 or 12 and -2√6

Let the numbers be x and y where x>y so,

x^2 - y^2 = 120.....(1)

y^2 = 2 x.....(2)

Putting (2) in (1), we get

x^2 - 2x = 120

x^2 - 2x - 120 = 0

x^2 - 12x + 10x - 120 = 0

x(x -12) +10(x - 12) = 0

(x-12)(x+10) = 0

So x can be 12 or -10, but we are given that the square of smaller number is twice the larger number, therefore the square of any number cant be negative,

Thus x cant take value of -10

So x = 12, so y^2 = 2 (12)

y^2 = 24

So y = √24 or - √24

y = 2√6 or -2√6

Hence the numbers are 12 and 2√6 or 12 and -2√6

The answer to your question is 40%

(4/5) of 50 is (4/5) x 50 =40

thx

Let the ratio be x so,

A, B, C will get x, 3x, 5x parts

According to questionx + 3x + 5x = 1500

9x = 1500

x = 1500/9 = 500/3

So, B will get 3x = 3 × 500/3 = ₹ 500