In a two digit number, digit at the ten's place is twice the digitplac

1.	In a two digit number, digit at the ten's place is twice the digitplace. If the number obtained by interchanging the digits is addedoriginal number, the sum is 66. Find the number
Answer» Let the tens digit be x and the units digit be y. So the number=10x+y A.q.=>x=2y(equation 1) After interchanging the digits we get10y+x Also,=>(10x+y)+(10y+x)=66 =>10x+y+10y+x=66 =>11y+11x=66 =>11(y+x)=66 =>y+x=66/11 =>y+x=6 From equation 1 x=2y So, y+2y=6 =>3y=6 =>y=6/3 =>y=2 And x=2(2)=4 Hence the number is 42. Like my answer if you find it useful!

In a two digit number, digit at the ten's place is twice the digitplace. If the number obtained by interchanging the digits is addedoriginal number, the sum is 66. Find the number

Answer»

Let the tens digit be x and the units digit be y.

So the number=10x+y

A.q.=>x=2y(equation 1)

After interchanging the digits we get10y+x

Also,=>(10x+y)+(10y+x)=66

=>10x+y+10y+x=66

=>11y+11x=66

=>11(y+x)=66

=>y+x=66/11

=>y+x=6

From equation 1 x=2y

So, y+2y=6

=>3y=6

=>y=6/3

=>y=2

And x=2(2)=4

Hence the number is 42.

Like my answer if you find it useful!