he sum of two numbers is 80 and the greater number exceeds twiceFind t – InterviewSolution

1.

he sum of two numbers is 80 and the greater number exceeds twiceFind the numbers.

Answer»

Let smaller number be nThen greater number = 2n + 11

Given,n + 2n + 11 = 803n = 80 - 11 = 693n = 69n = 69/3 = 23

Smaller number = 23Greater number = 2*x + 11 = 2*23 + 11 = 46 +11 = 57

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