81279 + Interview Questions in Mathematics QA in Mathematics

1.	13.If the polynomial fx) ax + bx - c is divisible by the polynomial g()+bxthen find the value of ab.
Answer» If f(x) is divisible by g(x), then the "remainder" of a long division would equal zero. The remainder after dividing f(x) by g(x) is [(ab² - ac + b)x + c(ab - 1)]/(x² + bx + c) For the numerator to equal zero, both terms in parentheses have to be equal to zero ab² - ac + b = 0 and ab - 1 = 0 ab = 1.......(i) or a=1/b ab² - ac + b = 0 ac = ab² + b ab = 1...........(from (i)) ac = b + b = 2bc=2b/ac = 2b/(1/b).......substituting value of aor c = 2b2...........

1.

13.If the polynomial fx) ax + bx - c is divisible by the polynomial g()+bxthen find the value of ab.

Answer»

If f(x) is divisible by g(x), then the "remainder" of a long division would equal zero.

The remainder after dividing f(x) by g(x) is

[(ab² - ac + b)x + c(ab - 1)]/(x² + bx + c)

For the numerator to equal zero, both terms in parentheses have to be equal to zero

ab² - ac + b = 0 and ab - 1 = 0

ab = 1.......(i)

or a=1/b

ab² - ac + b = 0

ac = ab² + b

ab = 1...........(from (i))

ac = b + b = 2bc=2b/ac = 2b/(1/b).......substituting value of aor c = 2b2...........

Discussion

2.	aber should be divide () to get (-1) ?
Answer»

Discussion

3.	\frac{\cos ^{2} \theta(1-\cos \theta)}{\sin ^{2} \theta(1-\sin \theta)}=\frac{1+\sin \theta}{1+\cos \theta}
Answer» thanks Please Solve it

3.

\frac{\cos ^{2} \theta(1-\cos \theta)}{\sin ^{2} \theta(1-\sin \theta)}=\frac{1+\sin \theta}{1+\cos \theta}

Answer»

thanks

Please Solve it

Discussion

4.	\frac { \operatorname { cos } \theta } { 1 - \operatorname { sin } \theta } + \frac { \operatorname { sin } \theta } { 1 - \operatorname { cos } \theta } + 1 = \frac { \operatorname { sin } \theta \cdot \operatorname { cos } \theta } { ( 1 - \operatorname { sin } \theta ) ( 1 - \operatorname { cos } \theta ) }
Answer»

Discussion

5.	3. What should be subtracted form7 to get 1?83
Answer»

Discussion

6.	Prove that \sqrt{\frac{\sec \theta-1}{\sec \theta+1}}+\sqrt{\frac{\sec \theta+1}{\sec \theta-1}}=2 \csc \theta
Answer»

Discussion

7.	Prove that $ \sqrt{\frac{\sec \theta-1}{\sec \theta+1}}+\sqrt{\frac{\sec \theta+1}{\sec \theta-1}}=2 \csc \theta $
Answer»

Discussion

8.	\sqrt{\frac{\sec \theta-1}{\sec \theta+1}}+\sqrt{\frac{\sec \theta+1}{\sec \theta-1}}=2 \csc \theta
Answer»

Discussion

9.	\frac { 1 \theta - \operatorname { cos } \theta + 1 } { 1 \theta + \operatorname { cos } \theta - 1 } = \frac { 1 } { \operatorname { sec } \theta . \operatorname { tan } \theta }
Answer» part 2

Discussion

10.	if you subtract 1/2 from a number and multiply the result by 1/2,you get 1/8 what is the number
Answer» Let number be xThen according to the given condition (x - 1/2) 1/2 = 1/8x - 1/2 = 2/8x - 1/2 = 1/4x = 1/4 + 1/2x = 3/4 Therefore number is 3/4

10.

if you subtract 1/2 from a number and multiply the result by 1/2,you get 1/8 what is the number

Answer»

Let number be xThen according to the given condition

(x - 1/2) 1/2 = 1/8x - 1/2 = 2/8x - 1/2 = 1/4x = 1/4 + 1/2x = 3/4

Therefore number is 3/4

Discussion

11.	- What should be subtracted fromto get 1?
Answer» -7/4 is the answer of the following a.t.q-3/4-x=1X=-3/4-1x=-7/4 solution-1-(-3/4)=1+3/4 =7/4 Answer -7/4 is the answers of this question

11.

- What should be subtracted fromto get 1?

Answer»

-7/4 is the answer of the following

a.t.q-3/4-x=1X=-3/4-1x=-7/4

solution-1-(-3/4)=1+3/4 =7/4 Answer

-7/4 is the answers of this question

Discussion

12.	UuY+5. Find the cost of 3 metres of cloth at 2 632 per metre.
Answer» 216.75 rs is the correct answer of the given question Rs 216.75 is the right answer Rs.216.75 is the correct answer the correct answer is 216.75 216•75 is the right answer 216.75 is correct answer 216.75 is the right answer

12.

UuY+5. Find the cost of 3 metres of cloth at 2 632 per metre.

Answer»

216.75 rs is the correct answer of the given question

Rs 216.75 is the right answer

Rs.216.75 is the correct answer

the correct answer is 216.75

216•75 is the right answer

216.75 is correct answer

216.75 is the right answer

Discussion

13.	What should be subtracted fromto get -1?
Answer» Let the number be x-5/7-x=-1x=-5/7+1=(-5+7)/7=2/7

Discussion

14.	If one zero of the polynomial ax^2 +bx + c is double the other prove that2 b^{2}=9 a c
Answer» Letα,β are the two zeros of the polynomial ax²+bx+cThen,α+β=-b/a andαβ=c/aBy the given condition,β=2α∴,α+2α=-b/aor, 3α=-b/aor,α=-b/3a -------(1) andα.2α=c/aor, 2α²=c/aor,α²=c/2aor, (-b/3a)²=c/2a [using (1)]or, b²/9a²=c/2aor, b²/9a=c/2or, 2b²=9ac (Proved) Tq u

14.

If one zero of the polynomial ax^2 +bx + c is double the other prove that2 b^{2}=9 a c

Answer»

Letα,β are the two zeros of the polynomial ax²+bx+cThen,α+β=-b/a andαβ=c/aBy the given condition,β=2α∴,α+2α=-b/aor, 3α=-b/aor,α=-b/3a -------(1) andα.2α=c/aor, 2α²=c/aor,α²=c/2aor, (-b/3a)²=c/2a [using (1)]or, b²/9a²=c/2aor, b²/9a=c/2or, 2b²=9ac (Proved)

Tq u

Discussion

15.	If α and ß are zeroes of a quadratic polynomial then find ax^2-bx-c then find α^2-b^2
Answer»

Discussion

16.	uwa and B are two zeros of the quadratic polynomial ax2+bx+c, then find the value of(ac+b)?(a3 +b)
Answer»

Discussion

17.	2222If the sum of zeroes of polynomial - ax + 6 be 5, find the value o, a2
Answer»

Discussion

18.	If one zero of the polynomial ax' +bxtc is double the other prove that2 b^{2}=9 a c.
Answer» Letα,β are the two zeros of the polynomial ax²+bx+cThen,α+β=-b/a andαβ=c/aBy the given condition,β=2α∴,α+2α=-b/aor, 3α=-b/aor,α=-b/3a -------(1) andα.2α=c/aor, 2α²=c/aor,α²=c/2aor, (-b/3a)²=c/2a [using (1)]or, b²/9a²=c/2aor, b²/9a=c/2or, 2b²=9ac (Proved)

Discussion

19.	b. 1Maximum nos of zeros in polynomial ax? +bx + cb. 1a. 2c. 4d. 3a. 2c. 4d. 3
Answer» अधिकतम संख्या 2 हैक्योंकि यह क्वाड्रेटिक equation है

Discussion

20.	2What should be added toto get-1?9
Answer»

Discussion

21.	By selling a toy for Rs 25, a man gains 25%Find the C.P. of the toy.
Answer» SP = 25Gain% = 25 let CP be x So, we have equation, x + 25% of x = 25 x + 25/100 × x = 25 x + x/4 = 25 5x/4 = 25 x = 100/5 x = 20 So, cost price is Rs 20

21.

By selling a toy for Rs 25, a man gains 25%Find the C.P. of the toy.

Answer»

SP = 25Gain% = 25

let CP be x

So, we have equation,

x + 25% of x = 25

x + 25/100 × x = 25

x + x/4 = 25

5x/4 = 25

x = 100/5

x = 20

So, cost price is Rs 20

Discussion

22.	3. What should be subtracted form7 to get 1?
Answer» 13/24 is the correct answer of the given question

Discussion

23.	By selling an article for rs 34.40, a man gains 7and1/2 %.. what is its cost price?
Answer»

Discussion

24.	By what number should 2be multiplied to get 1?
Answer»

Discussion

25.	\begin{array} { l } { \text { Prove that: } } \\ { \frac { \tan \theta } { 1 - \cot \theta } + \frac { \cot \theta } { 1 - \tan \theta } = 1 + \tan \theta + \cot \theta } \end{array}
Answer»

Discussion

26.	\frac \tan \theta 1 - \cot \theta %2B \frac \cot \theta 1 - \tan \theta = \tan \theta %2B \cot \theta %2B 1
Answer» Let theta = x LHS:tanx/1−cotx + cotx/1 - tanx = tan^2 x/(tanx - 1) + 1/tanx( 1 - tanx) = tan^3 x - 1/tanx(tanx - 1) = tan^2 x + tanx + 1/tanx = tanx + 1 + 1/tanx = tanx + cotx + = RHS Hence proved

26.

\frac \tan \theta 1 - \cot \theta %2B \frac \cot \theta 1 - \tan \theta = \tan \theta %2B \cot \theta %2B 1

Answer»

Let theta = x

LHS:tanx/1−cotx + cotx/1 - tanx

= tan^2 x/(tanx - 1) + 1/tanx( 1 - tanx)

= tan^3 x - 1/tanx(tanx - 1)

= tan^2 x + tanx + 1/tanx

= tanx + 1 + 1/tanx

= tanx + cotx +

= RHS

Hence proved

Discussion

27.	\lim _{n \rightarrow \infty} \frac{1+\frac{1}{2}+\frac{1}{2^{2}}+\ldots+\frac{1}{2^{n}}}{1+\frac{1}{3}+\frac{1}{3^{2}}+\ldots \ldots+\frac{1}{3^{n}}}
Answer»

Discussion

28.	乖(1 + tan 1°)(1 + tan 2)(1 + tan 45°) = 2",
Answer» =(1+tan 0o)(1 + tan1°) (1 + tan2°) (1 + tan3°) ………. (1 + tan 45°) {Since , tan 0o= 0} Now , we know thattan(A + B) = [ tan(A) + tan(B) ] / [ 1 - tan(A) tan(B) ]And tan(45) = 1 Sotan(45) = [ tan1 + tan44 ] / [ 1 - tan1 tan44 ]tan(45) = [ tan2 + tan43 ] / [ 1 - tan2 tan43 ]...tan(45) = [ tan22 + tan23 ] / [ 1 - tan22 tan23 ] So we have ,tan1 + tan44 = tan(45) [ 1 - tan1 tan44 ]tan2 + tan43 = tan(45) [ 1 - tan2 tan43 ]...tan22 + tan23 = tan(45) [ 1 - tan22 tan23 ] So finally we have , (1 + tan1) (1 + tan2) (1 + tan3) ... (1 + tan44) (1 + tan45) = (1 + tan1) (1 + tan2) (1 + tan3) ... (1 + tan44) (1 + 1) = 2 (1 + tan1) (1 + tan2) (1 + tan3) ... (1 + tan44) = 2 (1 + tan1) (1 + tan44) * (1 + tan2) (1 + tan43) * (1 + tan3) (1 + tan42) * ... * (1 + tan22) (1 + tan23) = 2 (tan1 + tan44 + tan1 tan44 + 1) (tan2 + tan43 + tan2 tan43 + 1) ... (tan22 + tan23 + tan22 tan23 + 1) = 2 ((tan45)(1 - tan1 tan44) + tan1 tan44 + 1) ((tan45)(1 - tan2 tan43) + tan2 tan43 + 1) ... ((tan45)(1 - tan22 tan23) + tan22 tan23 + 1) = 2 (1 - tan1 tan44 + tan1 tan44 + 1) (1 - tan2 tan43 + tan2 tan43 + 1) ... (1 - tan22 tan23 + tan22 tan23 + 1) = 2 (2) (2) ... (2) = 2 (2^22) = 2^23 hence n=23

28.

乖(1 + tan 1°)(1 + tan 2)(1 + tan 45°) = 2",

Answer»

=(1+tan 0o)(1 + tan1°) (1 + tan2°) (1 + tan3°) ………. (1 + tan 45°) {Since , tan 0o= 0}

Now , we know thattan(A + B) = [ tan(A) + tan(B) ] / [ 1 - tan(A) tan(B) ]And tan(45) = 1

Sotan(45) = [ tan1 + tan44 ] / [ 1 - tan1 tan44 ]tan(45) = [ tan2 + tan43 ] / [ 1 - tan2 tan43 ]...tan(45) = [ tan22 + tan23 ] / [ 1 - tan22 tan23 ]

So we have ,tan1 + tan44 = tan(45) [ 1 - tan1 tan44 ]tan2 + tan43 = tan(45) [ 1 - tan2 tan43 ]...tan22 + tan23 = tan(45) [ 1 - tan22 tan23 ]

So finally we have ,

(1 + tan1) (1 + tan2) (1 + tan3) ... (1 + tan44) (1 + tan45)

= (1 + tan1) (1 + tan2) (1 + tan3) ... (1 + tan44) (1 + 1)

= 2 (1 + tan1) (1 + tan2) (1 + tan3) ... (1 + tan44)

= 2 (1 + tan1) (1 + tan44) * (1 + tan2) (1 + tan43) * (1 + tan3) (1 + tan42) * ... * (1 + tan22) (1 + tan23)

= 2 (tan1 + tan44 + tan1 tan44 + 1) (tan2 + tan43 + tan2 tan43 + 1) ... (tan22 + tan23 + tan22 tan23 + 1)

= 2 ((tan45)(1 - tan1 tan44) + tan1 tan44 + 1) ((tan45)(1 - tan2 tan43) + tan2 tan43 + 1) ... ((tan45)(1 - tan22 tan23) + tan22 tan23 + 1)

= 2 (1 - tan1 tan44 + tan1 tan44 + 1) (1 - tan2 tan43 + tan2 tan43 + 1) ... (1 - tan22 tan23 + tan22 tan23 + 1)

= 2 (2) (2) ... (2)

= 2 (2^22)

= 2^23

hence n=23

Discussion

29.	\frac { 1 } { 2 } - ( \frac { 1 } { 3 } - \frac { 1 } { 5 } ) \neq ( \frac { 1 } { 2 } - \frac { 1 } { 3 } ) - \frac { 1 } { 5 }
Answer» 1/2-(1/3-1/5)=1/2-2/15=11/30(1/2-1/3)-1/5=1/6-1/5=-1/30so both are different

Discussion

30.	( \text { iil } ) \frac { \operatorname { tan } \theta } { 1 - \operatorname { cot } \theta } + \frac { \operatorname { cot } \theta } { 1 - \operatorname { tan } \theta } = 1 + \operatorname { sec } \theta \operatorname { cosec } \theta = 1 + \operatorname { tan } \theta + \operatorname { cot } \theta
Answer»

Discussion

31.	. The sides of a rectangular park are in the ratio 4: 3. If its area is 2028 sq. m, find the cost of fencingit at ?3 per metre.
Answer»

Discussion

32.	2 tan 30°1-tan2 30°, 1s equal to :(i) cos 60 (i) tan 60°(111)sin 60°(iv) sin 30°
Answer»

Discussion

33.	1 + tan1 - tan A1+ cot A 1 - cot Atan?A
Answer»

Discussion

34.	4, 3991 1992 4993ÂĽ/ 7 799 + 992 + 992T 7 v1s equal to() 603 B) 600(C) 598 D) 597
Answer»

Discussion

35.	(4) 120°. 60le) 60,0Find the angle which is equal to itswhich is equal to its supplement1s its supplementary angle gre
Answer»

Discussion

36.	If the sum and product of zeroes of the polynomial ax 2-5x + C 1S equal to10 each, find the value of a and c.
Answer» retry

Discussion

37.	415What nmımber should be added to 7 to get 4number should be added to to get7.12
Answer» thanks didi thank you is the right answer i know in my copy i covered my mistake

37.

415What nmımber should be added to 7 to get 4number should be added to to get7.12

Answer»

thanks didi

thank you

is the right answer

i know in my copy i covered my mistake

Discussion

38.	to get15. What should be subtracted from
Answer» Let X be subtractedhence5/9-x=9/5X=5/9-9/5=25-81/45=-56/45

Discussion

39.	2. What should be added to 6 to get 15?
Answer» 42/5 is the correct answer of the given 42/5 is the right answer 42/5 is the correct answer 45/5 42/5. is the correct one 42/5 is the correct answer of the following question 42/5 is the answer of it

39.

2. What should be added to 6 to get 15?

Answer»

42/5 is the correct answer of the given

42/5 is the right answer

42/5 is the correct answer

45/5

42/5. is the correct one

42/5 is the correct answer of the following question

42/5 is the answer of it

Discussion

40.	By selling an article for336, a man gains36. In how many rupees should he sell thearticle to get 15% profit ?
Answer»

Discussion

41.	What should be added 7 by 15 to get 1
Answer»

Discussion

42.	2. What should be added to 7to get 82?15
Answer» 15/15 is a good one it is a mixed fraction

Discussion

43.	15Tly what rational number should we multiply me to get56?
Answer»

Discussion

44.	( \frac 1 %2B \sin \theta - \cos \theta 1 %2B \sin \theta %2B \cos \theta ) ^ 2 = \frac 1 - \cos \theta 1 %2B \cos \theta
Answer» LHS = [(1+sinA-cosA )/(1+sinA+cosA)]² =[ (1+sin²A+cos²A+2sinA-2sinAcosA-2cosA)/(1+sin²A+cos²A+2sinA+2sinAcosA+2cosA) ]² = [( 1+1+2sinA-2sinAcosA-2cosA)/(1+1+2sinA+2sinAcosA+2cosA)]² = { ( 2(1+sinA) -2cosA(sinA+1) / [ 2(1+sinA) + 2cosA(sinA +1 ) ]}² = { (2(1+sinA)[1 - cosA] /[2(1+sinA )(1 + cosA )] }² = [ ( 1 - cosA ) / ( 1 + cosA ) ]² = RHS

44.

( \frac 1 %2B \sin \theta - \cos \theta 1 %2B \sin \theta %2B \cos \theta ) ^ 2 = \frac 1 - \cos \theta 1 %2B \cos \theta

Answer»

LHS = [(1+sinA-cosA )/(1+sinA+cosA)]²

=[ (1+sin²A+cos²A+2sinA-2sinAcosA-2cosA)/(1+sin²A+cos²A+2sinA+2sinAcosA+2cosA) ]²

= [( 1+1+2sinA-2sinAcosA-2cosA)/(1+1+2sinA+2sinAcosA+2cosA)]²

= { ( 2(1+sinA) -2cosA(sinA+1) / [ 2(1+sinA) + 2cosA(sinA +1 ) ]}²

= { (2(1+sinA)[1 - cosA] /[2(1+sinA )(1 + cosA )] }²

= [ ( 1 - cosA ) / ( 1 + cosA ) ]²

= RHS

Discussion

45.	(cos(theta) %2B 1 %2B sin(theta))/(-cos(theta) %2B 1 %2B sin(theta))=cot(theta/2)
Answer»

Discussion

46.	4. P.T. Usha runs around a circular path of area 754600 sq metre. How long will she take to nun20 rounds at the speed of 16 km/hr.
Answer» Area of a circle = 754600 m^222/7 × r^2 = 754600r^2 = (754600×7)/22 = 34300×7r = √(34300*7)=49×10= 490mcircumference of circular path = 22/7 × 2 × 490= 1760 mdistace covered in 20 rounds = 1760 × 20 m= 53.2 kmspeed = 16 km/htime taken = 53.2/16 = 3.325 h Like my answer if you find it useful!

46.

4. P.T. Usha runs around a circular path of area 754600 sq metre. How long will she take to nun20 rounds at the speed of 16 km/hr.

Answer»

Area of a circle = 754600 m^222/7 × r^2 = 754600r^2 = (754600×7)/22 = 34300×7r = √(34300*7)=49×10= 490mcircumference of circular path = 22/7 × 2 × 490= 1760 mdistace covered in 20 rounds = 1760 × 20 m= 53.2 kmspeed = 16 km/htime taken = 53.2/16 = 3.325 h

Like my answer if you find it useful!

Discussion

47.	(sin(theta) - cos(theta) %2B 1)/(sin(theta) %2B cos(theta) - 1)=1/(-tan(theta) %2B sec(theta))
Answer»

Discussion

48.	explain why 7×11×13+13and7×6×5×4×3×2×1+5are composite number
Answer» A composite number is a positive integer that has a factor other than 1 and itself.1) 7×11×13+13=13[(711)+1]=13(77+1)=13(78)Thus 13 and 78 is also a factor hence it a composite number2) 7×6×5×4×3×2×1+5 = 5[(7643*2)+1]=5(1008+1)=5(1009)Thus 5 and 1009 are factors of above numberThus the both numbers are compositeLike if you find it useful

Discussion

49.	If[9 + 110-111, the x 1s equal to10(b) 11(c) 121(d) 9.
Answer»

Discussion

50.	(x³+2x²-5ax-7)÷x+1
Answer» x^3 + 2x^2-5ax-7÷ x+1; x=-1, (-1)^3+2(-1)^2-5a(-1)-7; -1+2+5a-7=0; 5a=8-2; 5a=6; a=6/5

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

13.If the polynomial fx) ax + bx - c is divisible by the polynomial g()+bxthen find the value of ab.

aber should be divide () to get (-1) ?

\frac{\cos ^{2} \theta(1-\cos \theta)}{\sin ^{2} \theta(1-\sin \theta)}=\frac{1+\sin \theta}{1+\cos \theta}

3. What should be subtracted form7 to get 1?83

Prove that \sqrt{\frac{\sec \theta-1}{\sec \theta+1}}+\sqrt{\frac{\sec \theta+1}{\sec \theta-1}}=2 \csc \theta

Prove that $ \sqrt{\frac{\sec \theta-1}{\sec \theta+1}}+\sqrt{\frac{\sec \theta+1}{\sec \theta-1}}=2 \csc \theta $

\sqrt{\frac{\sec \theta-1}{\sec \theta+1}}+\sqrt{\frac{\sec \theta+1}{\sec \theta-1}}=2 \csc \theta

\frac { 1 \theta - \operatorname { cos } \theta + 1 } { 1 \theta + \operatorname { cos } \theta - 1 } = \frac { 1 } { \operatorname { sec } \theta . \operatorname { tan } \theta }

if you subtract 1/2 from a number and multiply the result by 1/2,you get 1/8 what is the number

- What should be subtracted fromto get 1?

UuY+5. Find the cost of 3 metres of cloth at 2 632 per metre.

What should be subtracted fromto get -1?

If one zero of the polynomial ax^2 +bx + c is double the other prove that2 b^{2}=9 a c

If α and ß are zeroes of a quadratic polynomial then find ax^2-bx-c then find α^2-b^2

uwa and B are two zeros of the quadratic polynomial ax2+bx+c, then find the value of(ac+b)?(a3 +b)

2222If the sum of zeroes of polynomial - ax + 6 be 5, find the value o, a2

If one zero of the polynomial ax' +bxtc is double the other prove that2 b^{2}=9 a c.

b. 1Maximum nos of zeros in polynomial ax? +bx + cb. 1a. 2c. 4d. 3a. 2c. 4d. 3

2What should be added toto get-1?9

By selling a toy for Rs 25, a man gains 25%Find the C.P. of the toy.

3. What should be subtracted form7 to get 1?

By selling an article for rs 34.40, a man gains 7and1/2 %.. what is its cost price?

By what number should 2be multiplied to get 1?

\begin{array} { l } { \text { Prove that: } } \\ { \frac { \tan \theta } { 1 - \cot \theta } + \frac { \cot \theta } { 1 - \tan \theta } = 1 + \tan \theta + \cot \theta } \end{array}

\frac \tan \theta 1 - \cot \theta %2B \frac \cot \theta 1 - \tan \theta = \tan \theta %2B \cot \theta %2B 1

\lim _{n \rightarrow \infty} \frac{1+\frac{1}{2}+\frac{1}{2^{2}}+\ldots+\frac{1}{2^{n}}}{1+\frac{1}{3}+\frac{1}{3^{2}}+\ldots \ldots+\frac{1}{3^{n}}}

乖(1 + tan 1°)(1 + tan 2)(1 + tan 45°) = 2",

\frac { 1 } { 2 } - ( \frac { 1 } { 3 } - \frac { 1 } { 5 } ) \neq ( \frac { 1 } { 2 } - \frac { 1 } { 3 } ) - \frac { 1 } { 5 }

. The sides of a rectangular park are in the ratio 4: 3. If its area is 2028 sq. m, find the cost of fencingit at ?3 per metre.

2 tan 30°1-tan2 30°, 1s equal to :(i) cos 60 (i) tan 60°(111)sin 60°(iv) sin 30°

1 + tan1 - tan A1+ cot A 1 - cot Atan?A

4, 3991 1992 4993ÂĽ/ 7 799 + 992 + 992T 7 v1s equal to() 603 B) 600(C) 598 D) 597

(4) 120°. 60le) 60,0Find the angle which is equal to itswhich is equal to its supplement1s its supplementary angle gre

If the sum and product of zeroes of the polynomial ax 2-5x + C 1S equal to10 each, find the value of a and c.

415What nmımber should be added to 7 to get 4number should be added to to get7.12

to get15. What should be subtracted from

2. What should be added to 6 to get 15?

By selling an article for336, a man gains36. In how many rupees should he sell thearticle to get 15% profit ?

What should be added 7 by 15 to get 1

2. What should be added to 7to get 82?15

15Tly what rational number should we multiply me to get56?

( \frac 1 %2B \sin \theta - \cos \theta 1 %2B \sin \theta %2B \cos \theta ) ^ 2 = \frac 1 - \cos \theta 1 %2B \cos \theta

(cos(theta) %2B 1 %2B sin(theta))/(-cos(theta) %2B 1 %2B sin(theta))=cot(theta/2)

4. P.T. Usha runs around a circular path of area 754600 sq metre. How long will she take to nun20 rounds at the speed of 16 km/hr.

(sin(theta) - cos(theta) %2B 1)/(sin(theta) %2B cos(theta) - 1)=1/(-tan(theta) %2B sec(theta))

explain why 7×11×13+13and7×6×5×4×3×2×1+5are composite number

If[9 + 110-111, the x 1s equal to10(b) 11(c) 121(d) 9.

(x³+2x²-5ax-7)÷x+1