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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
) There are 260 persons with a skin disorder. If150 had been exposed to the chemical A, 74to the chemical B, and 36 to both chemicals Aand B, find the number of persons exposed ti) Chemical A but not Chemical Bii) Chemical B but not Chemical Aii) Chemical A or Chemical Bl doun set of all poss |
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| 2. |
25.When these two magnets are kept close as shown, there will be?N SS Na) Rotationb) No changeepulsiond) Attraction |
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Answer» since like poles repel each other the magnets when brought close with both their south poles together will cause repulsion. hence, option (c) is correct |
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| 3. |
find derivation of cost by Abhitio method or by first principle method |
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| 4. |
chemical change is |
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Answer» chemical changes is a irreversible |
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| 5. |
D.lABola with vertex at the origin and the directrix, y2.Find the equation of the parabola whose focus is (5, 2) and havingThe cable of a uniformly loaded suspension bridge hangs in theroadway which is horizontal and 100 m long is supported by vertical wires attached to trecable, the longest wire being 30 m and the shortest wire being 6 m. Find the length ot aupporting wire attached to the roadway 18 m from the middle.form of a parabola. TheINCERT |
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| 6. |
Find the addition 5/6 and -1/6 |
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| 7. |
x-7y=9 & 2x+3y=5 solve by addition and substraction method |
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| 8. |
(1) If AB 7 cm, BP 4 cm, AP 5.4 cm, compare the segments. |
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| 9. |
2 id6. Write the following integers in ascending and descending order(iv)-5,4,-1,24.5 Addition ofintegersGame oftamarind seeds. |
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Answer» i) ascending order= -7 , -3 , 3 , 5descending order=5 , 3 , -3 , -7ii) ascending order=-2 , -1 , 0 ,3descending order= 3 , 0 , -1 , -2iii) ascending order=-6 , 1 ,3descending order=3 , 1 -6iv) ascending order=-5 , -1 , 2 , 4descending order=4 , 2 , -1 , -5 |
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| 10. |
EXERCISE TA1. Write the numeral for each of the following numbers:Nine thousand eighteennd seventy-three |
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| 11. |
\begin{array} { l } { \text { For what value of } k , 2 x + 3 y = 4 \text { and } ( k + 2 ) x + } \\ { 6 y = 3 k + 2 \text { will have infinitely many solutions? } } \end{array} |
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Answer» do ur self from here thank you |
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| 12. |
For what values of m and n the following system of linear equations has infinitelymany solutions.3x + 4y 12(m + n) x 2 (m -n) y 5m-1 |
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Answer» Answer: m = 5 & n = 1 Step-by-step explanation: Find the value of m and n 3x+4y=12(m+n)x+2(m-n)Y=5m-1 complete question is find values of m&n for infinite solution to have infinite solutions both equation should be same (m+n)x + 2(m-n)y = 5m-1 should be equivalent to 3x + 4y = 12 => k*3x + k*4y = k*12 where k is any variable => (m+n)/3 = 2(m-n)/4 = (5m-1)/12 = k Multiplying each with 12 => 4m + 4n = 6m - 6n = 5m -1 = 12k taking 1st 2 equations 4m + 4n = 6m - 6n => 10n = 2m => m = 5n - eq A taking 1st & 3rd 4m + 4n = 5m-1 => m = 4n + 1 - eq B equating value of m from eq A & eq B 5n = 4n + 1 => n = 1 putting value of n in eq A m = 5*1 = 5 Hence value of m = 5 & n = 1 |
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| 13. |
5. Find the value of mand n for which the following system of linear equations has infinitely manysolution3x + 4y = 12(m + n)x + 2(m n )y = 5m - 1 |
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Answer» If equations3x + 4y = 12(m+n)x + 2(m-n)y = 5m - 1 Have infinitely many solutionsThen,3/(m+n) = 4/2(m-n) = 12/(5m-1) 6(m - n) = 4(m + n)6m - 4m = 4n + 6n2m = 10nm = 5n.......(1) 3(5m-1) = 12(m+n)5m - 1 = 4m + 4n5m - 4m = 4n + 1m = 4n + 1......(2) Put value of m from eq(1) in eq(2)5n = 4n + 15n - 4n = 1n = 1 m = 4*1 + 1 = 5 Therefore, Value of m = 5, n = 1 |
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| 14. |
For what values of m and n the following system of linear equations has infinitelymany solutions.3x+4y = 12(n + n) x + 2 (m-n) y = 5m-1 |
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Answer» To have infinite solutions both equation should be same (m+n)x + 2(m-n)y = 5m-1should be equivalent to 3x + 4y = 12 => k*3x + k*4y = k*12 where k is any variable => (m+n)/3 = 2(m-n)/4 = (5m-1)/12 = k Multiplying each with 12=> 4m + 4n = 6m - 6n = 5m -1 = 12k taking 1st 2 equations 4m + 4n = 6m - 6n=> 10n = 2m=> m = 5n - eq A taking 1st & 3rd4m + 4n = 5m-1=> m = 4n + 1 - eq B equating value of m from eq A & eq B5n = 4n + 1=> n = 1 putting value of n in eq Am = 5*1 = 5 Hence value of m = 5 & n = 1 |
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| 15. |
Group A 1 IANY1. What is the number of solutions of the pair of linear equations x + 2y - 8 = 0 and 2x + 4y = 16?(C.B.S.E. 2010) |
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Answer» What are you doing of this paper which is of 2010 there will be no solution for these equations as 1/2=1/2 isnot equal to 0 There will be no solutions for these equations as:1/2 = 1/2 ≠ 0 |
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| 16. |
हिरण 18:1358 +113, आधार =100प्रथम खण्ड | मध्य खण्ड तृतीयभाजक = 1 1 3 | 1 3 । | 58विचलन = 1 3 | -11-3 -परिवर्तित अंक = -1-3-2 -61 2 | 0 2त: (i) मध्य खण्ड का 1 लिखा नीचे योग के स्थान पर |
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Answer» the answer is ,प्रथम खंडभाजक =1 1 3 विचलन। = 1 3 परिवर्तीत अंक = -1 -3 --------- 1 1 6 |
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| 17. |
\left. \begin{array} { l } { \frac { x + 3 } { 2 } - \frac { y + 2 } { 7 } = 1 } \\ { \frac { x + 2 } { 11 } + \frac { y + 3 } { 11 } = 1 } \end{array} \right. |
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Answer» X+3/2-y+2/7=1or, {7x+21-(2y+4)}/14=1or, 7x+21-2y-4=14or, 7x-2y=14-21+4or, 7x-2y=-3.......................(i) x+2/11+y+3/11=1or, x+2+y+3/11=1or, x+y+5=11or, x+y=11-5or, x+y=6...........................(ii) Now, (i)-7×(ii).'. 7x-2y-(7x+7y)=-21-6or, 7x-2y-7x-7y=-27or, -9y=-27or, y=-27/-9=3 Now, entire the value of y in (ii)x+3=6or, x=6-3=3 .'. x=3,y=3 |
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| 18. |
AFind the largest four-digits number which when divided by 4,7 and 13leaves a remainder of 3 in each case. |
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Answer» this is not the correct answer answer is 9831 |
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| 19. |
14. Find the largest four-digits number which when divided by 4,7 and 13leaves a remainder of 3 in each case. |
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Answer» LCM ( 4,7,13) = 364 Largest 4 digit number = 9999 On dividng 9999 by 364 we get reaminder as 171 So 9999 - 171 = 9828 + 3 = 9831 Therefore 9831 is the number. |
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| 20. |
18. Write two conditions that will make the adjoining figure asquare254Concise MATHEMATICS Middle School |
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Answer» Conditions for constructing square:1. angles must be 90 degree.2.all sides are equal.3. opposite sides are parallel |
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| 21. |
Draw number lines and locate the points on the(a) 54 4 |
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| 22. |
EXERCISE 72Drawnumber lines and locate the i1341237Express the following as mixel frus20 |
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| 23. |
The number of solutions of the equation5^{x}+5^{-x}=\log _{10} 25, xe R is :(a) zero(b) 1(d) infinitely many2 |
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| 24. |
write all the conditions between two triangles that they may congruence to each other |
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Answer» the triangle are congruent between each other has 4 condition= side Angle side,angle side angle,side side side, rhs,cpct |
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| 25. |
\frac 3 4 ( 8 a - 24 ) = 4 a %2B 7 |
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Answer» 3/4*8a-3/4*24=4a+7=3*2a-3*6=4a+76a-18=4a+72a=25a=25/2 |
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| 26. |
The number of solutions of the pair of linear equations x + 2y-8-0 and 2x + 4y-16 isAns1,Infinitely manyX4. 1 |
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Answer» thnx |
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| 27. |
23: If (p-1 +q-3+(r-Sy+(s-e, then pqrs+16is equal to:af (p-1)+A: 52C: 112B: 92D: 12 |
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| 28. |
SECTIONUsing Euclid's algorithm, find H.C.F of 240 and 228.0 (a 0), the1. |
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| 29. |
For the following matrices A and B, verify (AB)? = BAT,I11where a= 1-4, B=1-1 2 113 |
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| 30. |
\sqrt{2401} \times \sqrt{3249}=? |
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| 31. |
[ ( 2401 ) ^ { - \frac { 1 } { 2 } } ] ^ { - \frac { 1 } { 4 } } ] ^ { 2 } |
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| 32. |
Draw number lines to show thefractionsA. 1/4B. 1/2C. 3/4 |
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| 33. |
\frac { 1 } { \operatorname { log } _ { 4 } ( b c ) + 1 } + \frac { 1 } { \operatorname { log } _ { h } ( c a ) + 1 } + \frac { 1 } { \operatorname { log } _ { c } ( a b ) + 1 } = 1 |
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| 34. |
SECTIONthe following briefly: [2 marks each]ะก.d. of 735 and 85 by using Euclid's |
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Answer» Like if you find it useful |
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| 35. |
w number lines and locate the points on them:Dra,1, 1, 3, 4(b) 1, 2, 3,7te, 2, 324 4 48 8' 8s |
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| 36. |
Find the values of a and b for which the followingsystem of linear equations has an infinitely numberofsolutions : 2x + 3y = 7 ; (a + b + 1)x + (a + 2b + 2)y4a + b) + 1(B) a=3,b=2(D) a 4, b 3(A) a=1,b=2(C)a-3, b = 4 |
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| 37. |
10010020accident what is the probability that he is a scooter driverSECTION-C-12A-3 2find A, Using A-1 Solve the following sy23rindA", Using A-, S Ivethe following2x-3y + 5z # 11Solve tan"Yo + 1) + tan-1(x-1)tan-:-<. |
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| 38. |
14 Find the largest four-digits number which when divided by 4,7 and 13leaves a remainder of 3 in each case. |
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Answer» So LCM ( 4,7,13) = 364 Largest 4 digit number = 9999 On dividng 9999 by 364 we get reaminder as 171 So 9999 - 171 = 9828 + 3 = 9831 Therefore 9831 is the number. |
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| 39. |
24 and 3614. Find the largest four-digits number which when divided by 4,7 and 13leaves a remainder of 3 in each case.beddedbe 2401 babu |
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Answer» largest 4 digit number = 9999 we have toFind the largest 4 digit number which when divided by 4 , 7 and 13 leaves a remainder 3 in each case =>let us find the lcm of 4,7 and 13 = >prime factoristion of 4 = 2*2 =>prime factoristion of 7 = 7*1 =>prime factoristion of 13 = 13*1 => 2 *7*13 *2 =>364 now let us divide 9999/364 =>27.4697............... =>27 [approx] =>27* 364 =>9828 now let us add 3 to it =>9828 +3 = 9831 Therefore 9831 is the number. |
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| 40. |
Using section formula, show that the points A (2, -3, 4),B (-1,C| 02 | are collinear.3 |
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| 41. |
Using section formula, show that the points A (2, -3, 4), B (-1, 2, 1) andC 0,2 are collinear |
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| 42. |
| प्रश्न–१ 6250 का 18 जनवरी, 2017 से 13 जून 2017 तक 4 प्रतिशत कीदर से ब्याज बताइये। |
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Answer» 99.315 is the correct answer of the given question this question answer is 💯 not for 99.135ok |
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| 43. |
nylDuls as explained7. Derive the formula for the volume of the frustum of a cone, given to you in Section 13susing the symbols as explained. |
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| 44. |
Related to EX: 6.2lf PQ 11 Rs, LEF-120°, BHS-100° then find the value of x.12D7. In the fig PR is the andle Ibi |
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| 45. |
14. Find the largest four-digits number which when divided by 4,7 and 13leaves a remainder of 3 in each case.bedded 2017 |
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Answer» So LCM ( 4,7,13) = 364 Largest 4 digit number = 9999 On dividng 9999 by 364 we get reaminder as 171 So 9999 - 171 = 9828 + 3 = 9831 Therefore 9831 is the number. |
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| 46. |
any value of x. Thus,EXERCISE 42true, and whyLhich one of the folowing opitioms is true5 has(i) only two solutions.for each of the following o9i) infinitely manyquatons(i) a unique solution,venty shLet us1 Ev |
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Answer» 1. iii)have infinitely many solution as y and x are not fixed so for each x we get a y. |
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| 47. |
Itseį totsdt gts togso +2856based 298567 gasit ass} + toed |
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Answer» i^582 + i^580 + i^588 + i^586+i^584// i^582 + i^580+i^578+i^576+i^574= i^2920/i^2890=i^30 |
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| 48. |
Example & Using section formula, prove that the three points (4,6, 10), (2,4,5)and (14, 0,-2) are collinear. |
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| 49. |
0=A~4py +xg[=£-X¢ (B)B |
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Answer» Like if you find it useful |
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| 50. |
xe (!m)x (IIE-x ) |
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Answer» Answer is [x+8] (ii).Given: p(X)=p(-8)putting the value of X in all the equations...Case I,-8-3=-11. [×] Case II,-8+8=0. [✓] Case III,3×-8=-24. [×] |
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