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\left. \begin{array} { l } { \frac { x + 3 } { 2 } - \frac { y + 2 } { 7 } = 1 } \\ { \frac { x + 2 } { 11 } + \frac { y + 3 } { 11 } = 1 } \end{array} \right. |
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Answer» X+3/2-y+2/7=1or, {7x+21-(2y+4)}/14=1or, 7x+21-2y-4=14or, 7x-2y=14-21+4or, 7x-2y=-3.......................(i) x+2/11+y+3/11=1or, x+2+y+3/11=1or, x+y+5=11or, x+y=11-5or, x+y=6...........................(ii) Now, (i)-7×(ii).'. 7x-2y-(7x+7y)=-21-6or, 7x-2y-7x-7y=-27or, -9y=-27or, y=-27/-9=3 Now, entire the value of y in (ii)x+3=6or, x=6-3=3 .'. x=3,y=3 |
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