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x*x + 5x + 6 = x*x + 2x + 3x + 6 = x(x+2)+3(x+2) = (x+2)(x+3)

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L H S=1+3+3^2+3^3=1+3+3^2+3^3=1+3+9+27=40; RHS=3^4-1/2=81-1/2=80/2=40; LHS = RHS

2) is correct answer

2) is the right answer of the following

x^2+5x+6hencex^2+2x+3x+6x(X+2)+3(X+2)(x+2)(X+3)

X+y=2xy. -------1equationx-y=6xy. ---------2equation

2x=8xy

2x/8x=y

1/4=y

Put the. Value of y in 1equation

x+1/4=x*2*1/4

(4x+1)/4=x/2

8x+2=4x

8x-4x=-2

4x=-2

x=-1/2

(sin5x-2sin3x+sinx)/(cos5x-cosx)

=[{2sin(5x+x)/2cos(5x-x)/2}-2sin3x]/{2sin(5x+x)/2sin(x-5x)/2}

=(2sin3xcos2x-2sin3x)/{2sin3xsin(-2x)}

={2sin3x(cos2x-1)}/{-2sin3xsin2x}=-(cos2x-1)/sin2x

=(1-cos2x)/sin2x

=2sin²x/2sinxcosx=sinx/cosx

=tanx (Proved)

The question is incomplete. Please post the clear question

A regulatory substance produced in an organism and transported in tissue fluids such as blood or sap to stimulate specific cells or tissues into action.

A synthetic substance with a similar effect to that of an animal or plant hormone.

i. Thyroxine is the main hormone secreted into the bloodstream by thethyroid gland. It plays vital roles in digestion, heart and muscle function, brain development and maintenance of bones.

ii. Oxytocin is a peptide hormone and neuropeptide. Oxytocin is normally produced by the paraventricular nucleus of the hypothalamus and released by the posterior pituitary. It plays a role in social bonding, sexual reproduction, childbirth, and the period after childbirth

iii. Testosterone is the primary male sex hormone and an anabolic steroid. In male humans, testosterone plays a key role in the development of male reproductive tissues such as testes andprostate, as well as promoting secondary sexual characteristics such as increased muscle and bone mass, and thegrowthofbodyhair.

iv. The hormone acts mainly in the functional unit of the kidneys to aid in the conservation of sodium, secretion of potassium, water retention and to stabilize blood pressure.

We observe the following properties ofS.

Reflexivity:LetabeanarbitraryelementofR.Then,a∈R⇒a2+a2≠1∀a∈R⇒(a,a)∉SSo,SisnotreflexiveonR.Symmetry:Let(a,b)∈R⇒a2+b2=1⇒b2+a2=1⇒(b,a)∈Sforalla,b∈RSo,SissymmetriconR.Transitivity:Let(a,b)and(b,c)∈S⇒a2+b2=1andb2+c2=1Addingtheabovetwo,wegeta2+c2=2−2b2≠1foralla,b,c∈RSo,SisnottransitiveonR.Reflexivity:LetabeanarbitraryelementofR.Then,a∈R⇒a2+a2≠1∀a∈R⇒a,a∉SSo,SisnotreflexiveonR.Symmetry:Leta,b∈R⇒a2+b2=1⇒b2+a2=1⇒b,a∈Sforalla,b∈RSo,SissymmetriconR.Transitivity:Leta,bandb,c∈S⇒a2+b2=1andb2+c2=1Addingtheabovetwo,wegeta2+c2=2-2b2≠1foralla,b,c∈RSo,SisnottransitiveonR.

Hence,Sis not an equivalence relation onR.

3x^2-8x-3=03x^2-9x+x-3=03x(x-3)+1(x-3)=0(x-3)(3x+1)=0x-3=0; x=33x+1=0; x=-1/3

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step wise aaya na aaish

2 sin square x/2 /2 cos square x/2= tan square x/2

Given : f(x) = x³

Lt f(x) = f(2) = 2³ = 8x--> 2

f(2) = 2³ = 8

Sn = n(n+1) 420 = n(n+1) 21×20 = n(n+1) n = 20

is it worth for 3marks

3x/5 - 2x - 1/3 > 1

(9x - 10x + 5) > 15

- x + 5 > 15

- x > 10

x < - 10

Therefore,Solution set is (-infinity, - 10)

Denominator of given function is √(2)+√(7)-√(5)

(7+√3)²+(7-√3)²=49+14√3+3+49+3-14√3=104

Even natural no:s form an A.P :-

2,4,6,8 .....

a = 2 , d = 2 , Sn = 420

Sn = n/2 [ 2a + (n-1)d]420 = n/2 [ 4 + 2n - 2 ]840 = n [ 2 + 2n ]

2n²+ 2n = 840

2 [ n² + n ] = 840

n² + n = 420

n² + n - 420 = 0 ------------n = -b±√ b² - 4ac / 2a = -1±√1 - 4 x 1 x -420 = 2 = -1±√1681 / 2 = -1± 41 /2 = -1 + 41/2 = 40/2 = 20

n = 20

right answer

maximum value of cos can be 1

.maximum value of sin can be 1

5*1+12*1+12=5+12+12=5+24=29

The maximum value acos∅+bsin∅ = √a²+b² ao, for 5cosA +12sinA , it will be √12²+5² = √169 = 13

now maximum value of 5cosA +12sinA +12 = 13+12 = 25

the above answer 29 provided by the fellow is wrong.. he doesn't know.. that sinA and CosA can't be 1 , at same time and same value of A

ca n you tell the ans .

25 is the answer . i have solved above

Anything multiplied by zero is zero. So, the answer is zero.

56×11=56×(10+1)=560+56=616

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x^2-4x+1; ; 2+V3;;; (2+V3)^2-(2+V3)+1; (4+3+4V3-2-V3)= (7-2+3V3)=(5+3V3)

-1<=3x-2<=1add 21<=3x<=3divide by 31/3<=x<=1