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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8501. |
Square root of complex no . |
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| 8502. |
(1+tan1)(1+tan2)(1+tan3)....(1+tan45) |
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| 8503. |
(Root 5+7 oita) ( root 5 - 7 iota)^3 |
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| 8504. |
Sorry.................. Please forgive me dhama Yaar ??????????? |
| Answer» Sala... | |
| 8505. |
What is the mean of tengram |
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| 8506. |
Product of the roots of the Z^2 - z = 5 - 5i |
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| 8507. |
If (A union B) = (A union C) and (A intersection B) = (A intersection C) prove B=C |
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Answer» Tq n(A U B) = n(A U C) …….1n(A ∩ B) = n(A ∩ C)………2Expanding equation 1n(A) + n(B) — n( A ∩ B) = n(A) + n(C) — n(A∩C)…3Substituting 2 in equation 3n(A) + n(B) — n(A∩B) = n(A) + n(C) — n(A∩ B)Therefore n(B) = n(C) |
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| 8508. |
0! |
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Answer» As no of permutations for 0! Is 1 Ans is 1 |
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| 8509. |
What do you mean by PMI? |
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Answer» Principle of mathematical induction. PMI is a method of proving a mathematical statement, also known as principle of mathematical induction |
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| 8510. |
How can be prove the de morgans law theoritically |
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| 8511. |
Is best 5 marks are added in cbse class 10 result or core subjects? |
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Answer» Core subjects Best 5 |
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| 8512. |
Find the value of trigonometric ratio sin151 Pi by 6 |
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Answer» Sorry = - 1/2 =1/2Sin (151 pi)/6 = sin (144+7) pi/6 = sin (24pi + 7pi/6) = sin (12*2pi + 7pi/6) = sin 7pi/6 = sin (pi + pi/6) = -sin (pi/6) = 1/2 |
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| 8513. |
Show that cos40cos80cos160=-1/8 |
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Answer» Mujhe samajh ni aaya We havecos40°cos80°cos160°=>{(2sin40°cos40°)cos80°cos160°}/2sin40°=>{(2sin80°cos80°)cos160°}/4sin40°=>{2sin160°cos160°}/8sin40°=>sin320°/8sin40°=>sin(360°-- 40°)/8sin40°=> -- sin40°/8sin40°=> --1/8 |
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| 8514. |
Hii sandhu |
| Answer» Hlo | |
| 8515. |
Convert 57 degree 16 mintute 21 second |
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Answer» In which measure it will be converted plz determine in the question ??????? Plz subscribe YouTube channel royal fun unlimited 1 radian |
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| 8516. |
Example 11 complex no. Exercise 2b |
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| 8517. |
Cosec(-20piupon3) |
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| 8518. |
Cosec(-20piupon2) |
| Answer» Cosec(-20piupon3) | |
| 8519. |
Differentiate 1/√2 by first principle |
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| 8520. |
How to find trigonometric ratio between 0 to 180 |
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| 8521. |
Find the equation of parabola whose focus(2,5)anddirectrix is 3x-2y+4=0 |
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| 8522. |
Is zero is an even no. Or odd no.? |
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Answer» Neither even nor odd ZERO IS NITHER EVEN NOR ODD |
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| 8523. |
Cos 29°+sin29°/cos29°-sin29°= tan74° |
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| 8524. |
Prove that sin 3 alpha/ sin alpha + cos 3 alpha /cos alpha |
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| 8525. |
Convert 40° 20\' into radian measure. |
| Answer» We know that 180° = π radian.40° 20\' = 40 1/3 degree = π /180 × 121/3 radian = 121π /540radianTherefore 40° 20′ = 121π/540 radian. | |
| 8526. |
Write the set A={x:xEZ, 4 |
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| 8527. |
If A and B are two sets that n(A)=2 and n(B)=3 find the no. of relations from A to B |
| Answer» A relation from a set A to another set B by definition is a subset of the Cartesian product of the two sets A and B i.e.( A x B ) . If A has 2\xa0elements and B has 3\xa0elements then (A x B ) has (2\xa0x 3\xa0) = 6\xa0elements in it.Therefore no. of subsets of (A x B) = 2^(6) = 64 ; that are the required numbers of relations from A to B. | |
| 8528. |
Find tan13π/12 |
| Answer» tan(13π/12)\xa0= tan(4π/3 - π/4),= [tan(4π/3) - tan(π/4)]/[1 + tan(4π/3)tan(π/4)]= (-1 + √3)/(1 + √3)\xa0= -(1 - √3)/(1 + √3)\xa0= -(1 - √3)^2/[(1 + √3)(1 - √3)],\xa0= -(1 - √3)^2/(1 - 3)= (1/2)(1 - √3)^2\xa0= (1/2)(1 - 2√3 + 3)\xa0= (1/2)(4 - 2√3)\xa0= 2 - √3. | |
| 8529. |
Find derivative of (x-a)(x-b) |
| Answer» Here f (x) = (x - a)(x - b){tex}\\therefore \\;f{\\text{\'}}(x) = \\frac{d}{{dx}}(x - a)(x - b){/tex}{tex} = (x - a)\\frac{d}{{dx}}(x - b) + (x - b)\\frac{d}{{dx}}(x - a){/tex}= (x - a) × 1 + (x - b) × 1= x - a + x - b = 2x - a - b | |
| 8530. |
Prove that 3tan^2x + 2 root3 tanx -3=0 |
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| 8531. |
If R is a relation from a finite set A having n elements then the no. Of relation on A=? |
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Answer» Mennu Ba Hi |
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| 8532. |
prove that 1 + tan A into tan A/2 is equal to sec A is equal to tan A cot A/2 minus one |
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| 8533. |
Find HP whose 3rd and 14th terms are respectively 6/7and 1/3 |
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| 8534. |
SinA÷CosA |
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Answer» TanA Answer is Tan A TanA |
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| 8535. |
Find the value of the following angles cos 1445° |
| Answer» Cos 0degree =1 | |
| 8536. |
,is (A – B) ∩ (C – B) = (A ∩ C) – B? |
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| 8537. |
X2+1/X2-1 find range |
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| 8538. |
Prove that 4sinx.sin2x.sin4x =sin3x |
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| 8539. |
Formula of a.p |
| Answer» a+(n - 1)d | |
| 8540. |
Express (-root 3+ root-2)(2root 3-iota) |
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| 8541. |
Harmonic conjugate of2,3 with respect to line joining 1,2 and -1,3 |
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| 8542. |
Cosπ/7+cos2π/7+cos3π/7+cos4π/7+cos5π/7+cos6π/7+cos7π/7=? |
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| 8543. |
these year test same like last year |
| Answer» Last year test book & thise year test book are same | |
| 8544. |
Prove that 1/sin(x-a)sin(x-b)=cot(x-a) -cot(x-b) /sin(a-b) |
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| 8545. |
Draw the diagram of the solution set of the linear equations 1. 3x+4y≥12‚y≥1‚x≥0 |
| Answer» Give me answer | |
| 8546. |
Cos(A+B).COS(A-B) |
| Answer» 2cosAcosB | |
| 8547. |
ABCD is a cyclic quadrilateral then prove that CosA+cosB+CosC+cosD=0 |
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Answer» As abcd is a cyclic quadA+C=180°B+D=180°A=180°-CB=180°-DCos(180-C)+cos(180-D)+cosC+cosD-cosc-CosD+cosC+cosD=0Hence proved As |
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| 8548. |
Trignometry 3.4 exercise solution |
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Answer» Visit ncert solutions from this app 3.4 exercise solution |
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| 8549. |
1puc trignometric 3.4exercise solution |
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| 8550. |
If the set A has 3 elements then what is the number of proper subsets of A |
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Answer» But this is for degree anthe for puc our sir said to find proper subsets of any set we should do 2n-1 The set will have 8 subsets in totalOut of 8 ,2are improper subsets while the rest 8-2=6 subsets are proper subsets.Hope this is helpful |
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