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ABCD is a cyclic quadrilateral then prove that CosA+cosB+CosC+cosD=0 |
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Answer» As abcd is a cyclic quadA+C=180°B+D=180°A=180°-CB=180°-DCos(180-C)+cos(180-D)+cosC+cosD-cosc-CosD+cosC+cosD=0Hence proved As |
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