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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
In frogs, body proportions do not change with their growth. A frog that is twice as long as another will be heavier by approximatelyA. Two-foldB. Six-foldC. Four-foldD. Eight-fold |
| Answer» Correct Answer - A | |
| 352. |
In frogs, body proportions do not change with their growth. A frog that is twice as long as another will be heavier by approximately (A) Two-fold (B) Six-fold (C) Four-fold(D) Eight-fold |
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Answer» Correct Option :- (A) Two-fold |
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| 353. |
The molar mass of CaCO3 is 100 g. The maximum amount of carbon dioxide that can be liberated on heating 25 g of CaCO3 is - (A) 11 g (B) 55 g (C) 22 g (D) 2.2 g |
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Answer» Correct Option :- (A) 11 g Explanation :- 25g CaCO3 ⇒ 100 25/100 = 1/4 mole of CaCO3 CaCO3 → CaO + CO2 ∴ 1 mole CaCO3 produce 1 mole CO2 ∴ 1/4 mole CaCO3 produce 1/4 mole CO2 and 1/4 mole CO2 = 1/4 × 44 g of CO2 = 11 g
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| 354. |
The atomic radii of the elements across the second period of the periodic table -A. decrease due to increase in atomic numberB. decrease due to increase in effective nuclear chargeC. decrease due to increase in atomic weightsD. decrease due to increase in effective nuclear charge |
| Answer» Correct Answer - B | |
| 355. |
The correct electronic configuration for the ground state of silicon (atomic number 14) is -A. `1s^(2)2s^(2)2p^(6)3s^(2)3p^(2)`B. `1s^(2)2s^(2)2p^(4)3s^(2)3p^(4)`C. `1s^(2)2s^(2)2p^(6)3s^(2)3p^(4)`D. `1s^(2)2s^(2)2p^(6)3s^(1)3p^(2)` |
| Answer» Correct Answer - A | |
| 356. |
Vitamin A deficiency leads to night-blindness. Which of the following is the reason for the disease ? (A) rod cells are not converted to cone cells (B) rhodopsin pigment of rod cells is defective (C) melanin pigment is not synthesized in cone cells (D) cornea of eye gets dried |
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Answer» Correct :- (B) rhodopsin pigment of rod cells is defective Explanation :- Aldehyde form of vitamin A (Retinal) is required for synthesis of rhodopsin pigments of rod cells. deficiency of vitamin A will lead to defective formation of rhodopsin. |
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| 357. |
In Dengue virus infection, patients often develop haemorrhagic fever due to internal bleeding. This happens due to the reduction of – (A) platelets (B) RBCs (C) WBCs (D) lymphocytes |
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Answer» Correct :- (A) platelets Explanation :- Dengue fever also known as break bone fever is an infections tropical disease caused by dengue virus. This results in bleeding, low levels of blood platelets and blood plams leakage. |
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| 358. |
If the sequence of bases in sense strand of DNA is 5'-GTTCATCG-3', then the sequence of bases in its RNA transcript would be – (A) 5'-GTTCATCG-3' (B) 5'-GUUCAUCG-3' (C) 5'-CAAGTAGC-3' (D) 5'-CAAGUAGC-3' |
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Answer» Correct :- (B) 5'-GUUCAUCG-3' Explanation :- The direction of RNA sequence is also from 5'-3'. The sequence of sense strand is - 5'-GTTCATCG-3' We know the sequence of m-RNA is similar to sense strand. Only uracil is present instead of Thymine. Hence the m-RNA sequence will be - 5'-GUUCAUCG-3' |
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| 359. |
The mutation of a purine to a pyrimidine is known asA. TransitionB. fram shiftC. nonsenseD. transversion |
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Answer» Correct Answer - D Mutationh of a purine to a pyrimidine is known as transversion. 8 possible transversion can occurs. |
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| 360. |
The oxoacdi of phosphrous having the strongest reducing property isA. `H_(3)PO_(3)`B. `H_(3)PO_(2)`C. `H_(3)PO_(4)`D. `H_(4)P_(2)O_(7)` |
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Answer» Correct Answer - B `H_(3)PO_(3)` is has strong reducing property because of smaller oxidation state = +1 and due to 2 P-H bond. |
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| 361. |
Among C, S and P the element (s) that produces (s) `SO_(2)` on reaction with hot conc. `H_(2)SO_(4)` is /areA. only SB. only C and SC. only S and PD. C, S and P |
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Answer» Correct Answer - D `C+H_(2)SO_(4) to CO_(2)SO_(2)+H_(2)O` `S+ H_(2)SO_(4) to SO_(2)+H_(2)O` `P_(4)+to H_(2)SO_(4)+SO_(2)+H_(2)O` |
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| 362. |
The oxoacid of phosphorus having the strongest reducing property is : (A) H3PO3 (B) H3PO2 (C) H3PO4 (D) H4P2O7 |
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Answer» Correct option (B) H3PO2 Explanation: In H3PO2 2 reducing hydrogen atom are present. |
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| 363. |
The complex that can exhibit linkage isomerism is (A) [Co(NH3)5(H2O)]Cl3 (B) [Co(NH3)5(NO2)]Cl2 (C) [Co(NH3)5(NO3)](NO3)2 (D) [Co(NH3)5Cl]SO4 |
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Answer» Correct option (B) [Co(NH3)5(NO2)]Cl2 Explanation: NO2 is an ambidonate ligand so can show linkage isomerism. |
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| 364. |
The correct representation of wavelength-intensity relationship of an ideal blackbody radiation at two different temperatures T1 and T2 is : |
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Answer» Correct option (A) Explanation: λ max ∝ 1/T So on increasing temp. Maximum wavelength shifts to left side. |
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| 365. |
Consider the following statements about Langmuir isotherm : (i) The free gas and adsorbed gas are in dynamic equilibrium (ii) All adsorption sites are equivalent (iii) The initially adsorbed layer can act as a substrate for further adsorption (iv) The ability of a molecule to get adsorbed at a given site is independent of the occupation of neighboring sites The correct statements are (A) (i), (ii), (iii) and (iv) (B) only (i), (ii) and (iv) (C) only (i), (iii), and (iv) (D) only (i), (ii) and (iii) |
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Answer» The Correct option is (B) only (i), (ii) and (iv) |
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| 366. |
Among the following, the plot that correctly represents the conductometric titration of 0.05 M H2SO4 with 0.1M NH4OH is :- |
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Answer» Correct option (B) Explanation: Initially H+ ions are present due to complete dissociation of H2SO4. Upon addition of NH4OH, H+ ions decreases so conductivity decreases & becomes constant after salt formation. |
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| 367. |
Which of the following is NOT an enzyme? (A) Lipase (B) Amylase (C) Trypsin (D) Bilirubin |
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Answer» Correct Option :- (D) Bilirubin Explanation :- Lipase = Enzyme [Lipid digesting] Amylase = Enzyme [Starch digesting] Trypsin = Enzyme [Endopeptidase] Bilirubin = Bile pigment |
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| 368. |
Among the following , the plot that correctly represents the conductometric titration of 0.05 M `H_(2)SO_(4)` with 0.1 M `NH_(4)OH` isA. B. C. D. |
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Answer» Correct Answer - B On adding `NH_(4)OH` (A) Initially the fast moving `H^(+)` ion get neutralized as `H_(2)O` and is replaced by slow moving `NH_(4)^(+)` ion upto neutralisation point. (B) After neutralisation point, weak electrolyte `NH_(4)OH` is added gradually, which does not effect the conductance. |
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| 369. |
The complex that can exhibit linkage isomerism isA. `[Co(NH_(3))_(5)(H_(2)O)]Cl_(3)`B. `[Co(NH_(3))_(5)(NO_(2))]Cl_(2)`C. `[Co(NH_(3))_(5)(NO_(3))](NO_(3))_(2)`D. `[Co(NH_(3))_(5)Cl]SO_(4)` |
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Answer» Correct Answer - B `-NO_(2)` is ambidentate ligand as it connect with metal by N or O atom. |
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| 370. |
Consider the following statement about Langmuir isotherm : (i) The free gas and adsorbed gas are in dynamic equilibrium (ii) All adsorption sites are equivalent (iii) The initially adsorbed layer can act as a substrate for further adsorption. (iv) The ability of a molecule to get adsorbed at a given site is independent of the occuption of neighbouring sites The correct statement areA. (i),(ii),(iii) and (iv)B. only (i),(ii) and (iv)C. only (i),(iii) and (iv)D. only (i),(ii) and (iii) |
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Answer» Correct Answer - C Factually incorrect. The initially adsorbed layer cannot act as a sunstarte for further adsorption. |
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| 371. |
The Diptheria, Pertussis ,Tetanus (DPT) vaccine consists of (A) live attenuated strains of Diptheria, Pertussis, Tetanus (B) toxoid of Diptheria, Tetanus , and heat killed whole cells of Pertussis (C) whole cell lysate of Diptheria, Pertussis, Tetanus (D) heat killed strains of Diptheria, Pertussis, Tetanus |
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Answer» Correct Option :- (B) toxoid of Diptheria, Tetanus , and heat killed whole cells of Pertussis Explanation :- Vaccine of Diphtheria, Pertussis and Tetanus (DPT) consist of ………. (i) Toxoid of Diptherian and Tetanus (ii) Heat killed cells of Pertussis |
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| 372. |
What is the length of human DNA containing 6.6 x 109 bp? (A) 22 nm (B) 0.22 mm (C) 2.2 m (D) 22 m |
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Answer» Correct Option :- (C) 2.2 m Explanation :- The distance between 2 nucleotides / nitrogen bases is 3.4 Å and human DNA containing 6.6 × 109 bp multiplied by this distance gives a length of 2.2 meters |
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| 373. |
The adsorption isotherm for a gas is given by the relation `x=ap//(1+bp)` where x is mole of gas adsorbed per gram of the adsorbent, p is the pressure of the gas, and a and b are constants. Then xA. increases with pB. remains unchanged with pC. decreases with pD. increases with p at low pressures and then remains the same at high pressure |
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Answer» Correct Answer - D According to Lagmuir curve `x=(ap)/(1+bp)` `p rarr oo" "x=a/b` `p rarr 0" "x prop p` |
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| 374. |
What is the length of human DNA containing `6.6 xx 10^(9)` bp ?A. 22 nmB. 0.22 mmC. 2.2 mD. 22 m |
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Answer» Correct Answer - c The distance between 2 nucleotides / nitrogen bases is 3.4 A and human DNA containing `6.6 xx 10^(9)` bp multiplied by this distance gives a length of 2.2 meters. |
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| 375. |
Children suffering from phenylketonuria are given food low in phenylalanine and supplemented with tyrosine. This is because theyA. are unable to utilize phenylalanineB. do not require phenylalanineC. have increased tyrosine anabolismD. have increased tyrosine catabolism |
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Answer» Correct Answer - A Phenyl Ketonuria is an autosomal recessive disorder with mutation in geme for emzyme phenyl alanine hydroxylase (PAH), rendering it non functional `"Phenyl alanine"underset(X)overset(PAH)to"Turosin"` `to`Such person cannot metabolise the above reaction leading to accumulation of Phenyl alanine. So, are given food low in (Phe) and supplemented with (tyr). |
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| 376. |
Leyding cells synthesizeA. insulinB. growth hormoneC. testosteroneD. estrogen |
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Answer» Correct Answer - C Also know as interstitial cells present in testies between somniferous tubule. |
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| 377. |
Glucagon increases the blood glucose concentration byA. promoting glycogenolysisB. increasing the concentration of fructose 2,-6-bisphosphateC. increasing the concentration of pyruvate kinaseD. inhibiting gluconeogenesis |
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Answer» Correct Answer - A Promote breakdown og Glycogen in liver. |
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| 378. |
Which ONE of the following is NOT essential for Polymerase Chain Reaction (PCR) ?A. Restriction enzymesB. Denaturation of DNAC. PrimersD. DNA polymerase |
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Answer» Correct Answer - A RE is not required in PCR |
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| 379. |
Concentration of `Na^(+)` ions outside a nerve cell is `~100` times more than inside. The concentration of `K^(+)` ions is more inside the cells. The levels of `Na^(+)` ions and `K^(+)` ions are maintained byA. free diffusion of `Na^(+)` ions and pumping of `K^(+)` ions across the membrane.B. `Na^(+) " and " K^(+)` pumps in the membrane.C. free diffusion of `K^(+)` ions and pumping of `Na^(+)` ions across the membraneD. water channels fomed by lipids in the membrane. |
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Answer» Correct Answer - B Energy derived pumps are present in plasma membrane. |
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| 380. |
The following sequence contains the open reading frame of a polypeptide. How many amino acids will the polypeptide consists of ? 5' AGCATATGATCGTTTCTCTGCTTTGAACT-3' (A) 4 (B) 2 (C) 10 (D) 7 |
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Answer» Correct Option :-(B) 2 Explanation :- Given sequence is 5'- AGCATATGATCGTTTCTCTGCTTTGAACT-3' After Transcription the m-RNA sequence will be- 5'- AGCAUAUGAUCGUUUCUCUGCUUUGAACU-3' UGA is the stop codon. Hence, only 2 amino acids will be formed. |
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| 381. |
The two components of autonomous nervous system have antagonistic actions. But in certain cases their effects are mutually helpful. Which of the following statement is correct ?A. At rest, the control of heart beat is not by the vagus nerveB. During exercise the sympathetic control decreasesC. During exercise the parasymphathetic control decreasesD. Stimulation of sympathetic system results in constriction of the pupil |
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Answer» Correct Answer - C Parasy mpathetic control decreased during exercise. |
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| 382. |
Two independent experiments related to photosynthesis were conducted-one with `^(18)O`- labelled water (experiment P ) and the other with `^(14)C`- labelled `CO_(2)` (experiment Q) . Which ONE of the following options lists the first labelled products in experiments P and Q respectively ?A. `P : O_(2) " " Q : 3-` phosphoglycerateB. `P: 3 -` Phosphoglycerate `" "` Q : NADPHC. `P : O_(2) " " Q : ATP`D. `P : 3- ` Phosphoglycerate `" " ` Q : 3- phosphoglycerate |
| Answer» Correct Answer - A | |
| 383. |
Where is the third ventricle of the brain located?A. CerebrumB. CerebellumC. Pons varoliD. Diencephalon |
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Answer» Correct Answer - D Cavity of Diancephelon is called as diocoel or third ventricle. |
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| 384. |
Concentration (%) of NaCl isotonic to human blood is (A) 0.085 – 0.09% (B) 1.7 – 1.8% (C) 3.4 – 3.6% (D) 0.85 – 0.9% |
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Answer» Correct option (B) 1.7 – 1.8% Explanation: 0.9% NaCl solution is isotonic for human blood cell. |
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| 385. |
Which ONE of the pair of amino-acids contains two chiral centres ?A. Isoleucine and threonineB. Leucine and valineC. Valine and isoleucineD. Theronine and leucine |
| Answer» Correct Answer - A | |
| 386. |
A girl brings a positively charged rod near a thin neutral stream of water from a tap. She observes that the water stream bends towards her. Instead, if she were to bring a negatively charged rod near to the steam, it will–A. Bend in the same directionB. Bend in the opposite directionC. Not bend at allD. Bend in the opposite direction above and below and rod |
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Answer» Correct Answer - A |
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| 387. |
Which statements about the Rutherford model of the atom is NOT true ? (A) There is a positively charged center in an atom called the nucleus (B) Nearly all the mass of an atom resides in the nucleus (C) Size of the nucleus is completely to the atom (D) Electrons occupy the space surrounding the nucleus |
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Answer» Correct option (C) Size of the nucleus is completely to the atom Explanation: Size of the nucleus is completely to the atom |
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| 388. |
A girl brings a positively charged rod near a thin neutral stream of water from a tap. She observes that the water stream bends towards her. Instead, if she were to bring a negatively charged rod near to the steam, it will– (A) Bend in the same direction (B) Bend in the opposite direction (C) Not bend at all (D) Bend in the opposite direction above and below and rod |
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Answer» Correct option (A) Bend in the same direction Explanation: Due to induction, bend in same direction |
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| 389. |
The sum of (12 – 1 + 1)(1!) + (22 – 2 + 1)(2!) + …. + (n2 – n + 1)(n!) is - (A) (n + 2)! (B) (n – 1)((n + 1)!) + 1 (C) (n + 2)! – 1 (D) n((n + 1)!) – 1 |
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Answer» Correct Option :- (B) (n – 1)((n + 1)!) + 1 Explanation :- Tn = (n2 – n + 1) n! = (n2 – 1) n! – (n – 2) n! Tn = (n – 1) (n + 1) ! – (n – 2) n! Sum = 1 + (n – 1) (n + 1) ! |
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| 390. |
The radius of a nucleus is given by `r_(0) A^(1//3)` where `r_(0) = 1.3xx 10^(-15)` m and A is the mass number of the nucleus, the Lead nucleus has A = 206. the electrostatic force between two protons in this nucleus is approximatelyA. `10^(2)` NB. `10^(7)` NC. `10^(12)` ND. `10^(17)` N |
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Answer» Correct Answer - A |
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| 391. |
Among the following, the correct statements isA. pH decreases when solid ammonium chloride is added toa a dilute aqueous soplution of `NH_(3)`B. pH decreases when solid sodium acetate is added to a dilute aqueous solution of acetic acid.C. pH decreases when solid NaCl is added to a dilute aqueous solution of NaOHD. pH decreases when solid sodium oxalate is added to a dilute aqueous solution of oxalic acid |
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Answer» Correct Answer - A Dil aqueous Solutionof `NH_(3)" is "NH_(4)OH` solution `NH_(3)OHhArrNH_(4)^(+)+overset(-)OH` On adding solid ammonium chloride `NH_(4)rarrNH_(4)^(+)+Cl^(-)` The reaction moves backward due to common ion effect. The concentration of `OH^(-)` decreases and pH decressess. |
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| 392. |
The solubility of `BaSO_(4)` in pure water (in g `L^(-1)`) is closest to [Given: `K_(sp)" for "BaSO_(4)" is " 1.0xx10^(-10)" at "25^(@)C`. Molecular weight of `BaSO_(4)" is "233g mol^(-1)`]A. `1.0xx10^(-5)`B. `1.0xx10^(-3)`C. `2.3xx^(-5)`D. `2.3xx10^(-3)` |
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Answer» Correct Answer - D Given Ksp `=10^(-10)` For `BaSO_(4)," Ksp "=S^(2)` `S=10^(-5)" mol/L "rArr2.33xx10^(-3)" g/L"` |
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| 393. |
Among the following, the INCORRECT statement isA. No two electrons in an atom can have same have the same set of four quantum numbers.B. The maximum number of electron in the shell with principal quantum numbers is nC. Electrons in an orbital must have opposite spin.D. In the ground state, atomic orbitals are filled in the order of their increasing energies. |
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Answer» Correct Answer - B The maximum number of electrons in the `n^(th)" shell is "2n^(2)`. |
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| 394. |
The correct statement about the following compounds is (A) both are chiral (B) both are achiral (C)X is chiral and Y is achiral (D) X is achiral and Y is chiral |
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Answer» Correct option (C)X is chiral and Y is achiral Explanation: ‘X’ is chiral molecule because it has chiral centre or asymmetric C atom but ‘Y’ is achiral because it does not have chiral centre. |
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| 395. |
Remote sensing satellites move in an orbit that is at an average height of about `500 km` from the surface of the earth. the camera onboard one such satellite has a screen of area `A` on which the images captured by it are formed. If the focal length of the camera lens is `50 cm`, then the terrestrial area that can be observed from the satellite is close toA. `2xx10^(3)A`B. `10^(6)A`C. `10^(12)A`D. `4xx10^(12)A` |
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Answer» Correct Answer - C |
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| 396. |
Among the following, the INCORRECT statement is (A) No two electrons in an atom can have the same set of four quantum numbers (B) The maximum number of electrons in the shell with principal quantum number, n, is equal to n2 +2 (C) Electrons in an orbital must have opposite spin (D) In the ground state, atomic orbitals are filled in the order of their increasing energies |
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Answer» Correct option (B) The maximum number of electrons in the shell with principal quantum number, n, is equal to n2 +2 Explanation: The maximum number of e– in the shell with principal quantum number n, is equal to 2n2 (not n2 + 2) |
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| 397. |
Letters A, B, C and D are written on a cardboard as shown in the picture. The cardboard is kept at a suitable distance behind a transparent empty glass of cylindrical shape. If the glass is now filled with water, one sees an inverted image of the pattern on the cardboard when looking through the glass. Ignoring magnification effects, the image would appear as. |
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Answer» The Correct option is (D) |
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| 398. |
A steady current `I` is set up in a wire whose cross-sectional area decreases in the direction of the flow of the current. Then, as we examine the narrowing regionA. the current density decreases in value.B. the magnitude of the electric field increases.C. the current density remains constant.D. the average speed of the moving charges remains constant. |
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Answer» Correct Answer - B |
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| 399. |
Many exoplanets have been discovered by the transit method, wherein one monitors a dip in the intensity of the parent star as the exoplanet moves in front of it. The exoplanet has a radius `R` and the parent star has radius `100R`. If `I_(0)` is the intensity observed on earth due to the parent star, then as the exoplanet transits,A. The minimum observed intensity of the parent star is `0.9I_(0)`B. The minimum observed intensity of the parent star is `0.99I_(0)`C. The minimum observed intensity of the parent star is `0.999 I_(0)`D. The minimum observed intensity of the parent star is `0.9999 I_(0)` |
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Answer» Correct Answer - D |
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| 400. |
Which of the following is NOT true about the total lunar eclipse? (A) A lunar eclipse can occur on a new moon and full moon day. (B) The lunar eclipse would occur roughly every month if the orbits of earth and moon were perfectly coplanar (C) The moon appear red during the eclipse because the blue light is absorbed in earth’s atmosphere and red is transmitted. (D) A lunar eclipse can occur only on a full moon day |
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Answer» (A) A lunar eclipse can occur on a new moon and full moon day. |
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