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The radius of a nucleus is given by `r_(0) A^(1//3)` where `r_(0) = 1.3xx 10^(-15)` m and A is the mass number of the nucleus, the Lead nucleus has A = 206. the electrostatic force between two protons in this nucleus is approximatelyA. `10^(2)` NB. `10^(7)` NC. `10^(12)` ND. `10^(17)` N

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