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The molar mass of CaCO3 is 100 g. The maximum amount of carbon dioxide that can be liberated on heating 25 g of CaCO3 is - (A) 11 g (B) 55 g (C) 22 g (D) 2.2 g |
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Answer» Correct Option :- (A) 11 g Explanation :- 25g CaCO3 ⇒ 100 25/100 = 1/4 mole of CaCO3 CaCO3 → CaO + CO2 ∴ 1 mole CaCO3 produce 1 mole CO2 ∴ 1/4 mole CaCO3 produce 1/4 mole CO2 and 1/4 mole CO2 = 1/4 × 44 g of CO2 = 11 g
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