100525 + Interview Questions in GENERAL QA IN GENERAL AWARENESS Page 67 InterviewSolution

3301.	A metallic element exists as simple cubic lattice. Each edge of the unit cell is 3Å. The density of the metal is `9 "g cm"^(–3)`. How many number of unit cells will be present in 100 g of the metal :-A. 6.85 × 102B. 4.12 × 1023C. 4.37 × 105D. 2.12 × 106
Answer» Correct Answer - B `C.D.=(ZxxM_W)/(VxxN_A) = (ZxxM_0)/(VxxN_0)` Number of unit cell present in 100 g of the metal `M_0/(V xx C.D.) = 100/((3xx10^(-8))^3) xx9` = 4.12 × 1023

Discussion

3302.	(A) `-NO_(2),-CN,-CNO` act as ambident nucleophles. (R) These consist atoms of same period.A. If both (A) and (R) are correct and (R) is the correct explanation of (A).B. If both (A) and (R) are correct but (R) is not the correct explanation of (A).C. If (A) is correct but (R) is incorrect.D. IF (A) is incorrect but (R) is correct.
Answer» Correct Answer - A

Discussion

3303.	Rate constant for first order reaction is `5.78xx10^(-5)S^(-1)`. What percentage of initial reactant will react in 10 hours ?A. `12. 5%`B. `25%`C. `87. 5%`D. `75%`
Answer» Correct Answer - C `5.78xx10^(-5)=(2.303)/(10xx3600)xx"log"(A_(0)/(A_(t)))` ` A_(0)=8ArArr=8ArArrA_(t)=(A_(0))/(8)=12.5%(A_(0))`

Discussion

3304.	Your friend,Shivam Malik, has invited you to attend the wedding of his sister,Soniya Singh. You find that you have an important paper of pre-board examination on the day of the wedding. Thus, you cannot attend the event. Write a formal reply to the invitation expressing your regret. You are Pooja Vij, M-114,fort road, Chennai.
Answer» M-114 fort a road Chennai 26 October 2020 House no 4 Suhas colony Laxmi Nagar Delhi 110092 Dear friend, subject :regret regarding the wedding invitation My warm wishes to you and your family . Hope you are fine and busy in the wedding planning. I very regret fully wish to inform you that I would not be able to attend the wedding of your sister. This is because I have my boards this year and my pre board exams are going to start soon . one of my exam is on the day of the wedding . so it would not be possible for me to attend the wedding . I'll miss all that fun but cannot place my exams in delay so please forgive me .I am sending a small gift for Sonia.. please hand it over to her and congratulate her for the wedding ..give my warm wishes to Sonia for her happy married life and also to all the family members. hope you will forgive me . yours faithfully Pooja

3304.

Your friend,Shivam Malik, has invited you to attend the wedding of his sister,Soniya Singh. You find that you have an important paper of pre-board examination on the day of the wedding. Thus, you cannot attend the event. Write a formal reply to the invitation expressing your regret. You are Pooja Vij, M-114,fort road, Chennai.

Answer»

M-114

fort a road

Chennai

26 October 2020

House no 4

Suhas colony

Laxmi Nagar

Delhi 110092

Dear friend,

subject :regret regarding the wedding invitation

My warm wishes to you and your family . Hope you are fine and busy in the wedding planning. I very regret fully wish to inform you that I would not be able to attend the wedding of your sister. This is because I have my boards this year and my pre board exams are going to start soon . one of my exam is on the day of the wedding . so it would not be possible for me to attend the wedding . I'll miss all that fun but cannot place my exams in delay so please forgive me .I am sending a small gift for Sonia.. please hand it over to her and congratulate her for the wedding ..give my warm wishes to Sonia for her happy married life and also to all the family members.

hope you will forgive me .

yours faithfully

Pooja

Discussion

3305.	For the decomposition, `N_(2)O_(5)(g) rarr N_(2)O_(4)(g) + 1//2O_(2)(g)`, the initial pressure of `N_(2)O_(5)` is `114 mm` and after `20 sec`, the pressure of reaction mixture becomes `133 mm`. Calculate the rate of reaction in terms of : (a) change in pressure `sec^(-1)` and (b) change in molarity `sec^(-1)`. Given that reaction is carried out at `127^(@)C`.A. `1.25xx10^(-3) atm sec^(-1)`B. `2.5xx10^(-3) atm sec^(-1)`C. `9.5xx10^(-1) atm sec^(-1)`D. `4.75xx10^(-1) atm sec^(-1)`
Answer» Correct Answer - B `{:(N_(2)O_(5),to,N_(2)O_(4),+,(1)/(2)O_(2)),(114.p,,p,,(1)/(2)p):}` `P_(T)=114+(P)/(2)=133rArrp=38` `K=(2.303)/(20)"log"((114)/(76))` `K(Pt)=2.07xx10^(-3)`at m `sec^(-1)`

Discussion

3306.	I used to speak French _____, but I’ve forgotten it now. A) successfully B) fluently C) honestly D) carefully
Answer» Correct option is B) fluently

Discussion

3307.	Could you give me a ________? I’ve forgotten my matches. A) flame B) light C) fire D) illumination E) flare
Answer» Correct option is B) light

Discussion

3308.	For the reaction `N_(2)O_(5)(g)toN_(2)O_(4)(g)+1//2O_(2)(g)` initial pressure is 114 mm and after 20 seconds the pressure of reaction mixture becomes 133 mm then the average rate of reaction will beA. `1.9 atm S^(-1)`B. `8.75xx10^(-3) atm S^(-1)`C. `2.5xx10^(-3)atmS^(-1)`D. `6.65atmS^(-1)`
Answer» Correct Answer - C `{:(,N_(2)O_(5),to,N_(2)O_(4)+,(1)/(2)O_(2),,),(t=0,,11MM,O,O,,),(t=20s,114-x,,x,(x)/(2),,):}` `:.114+(x)/(2)=133rArrx=38 mm` `r=(x)/(t)=(38)/(20)` `r=1.9mmsec^(-1)` `r=(1.9)/(760)=2.5xx10^(-3)atmsec^(-1)`

Discussion

3309.	Paraphrase the interjection used in the following dialogue. A: I’ve forgotten to tell John about the party. B: Eh? A) What did you say?B) Really? C) How come?
Answer» Correct option is A) What did you say?

Discussion

3310.	Statement (I) : First law of thermodynamics analyses the problem quantitatively whereas second law of thermodynamics analyses the problem qualitatively. Statement (II) : Throttling process is reversible process(a) Both Statement (I) and Statement (II) are individually true and Statement (II) is the correct explanation of Statement (I) (b) Both statement (I) and Statement (II) are individually true but Statement (II) is NOT the correct explanation of Statement (I) (c) Statement (I) is true but Statement (II) is false (d) Statement (I) is false but Statement (II) is true
Answer» (c) Statement (I) is true but Statement (II) is false Throttling process is a irreversible process as the entropy of the fluid increases during the process. The first law of thermodynamics only gives a quantitative estimate of the heat and work interaction between the system and surroundings, however, it does not state about quality of energy. It is the second law of thermodynamics which deals with the low grade and high grade energy and concepts of availability.

3310.

Statement (I) : First law of thermodynamics analyses the problem quantitatively whereas second law of thermodynamics analyses the problem qualitatively. Statement (II) : Throttling process is reversible process(a) Both Statement (I) and Statement (II) are individually true and Statement (II) is the correct explanation of Statement (I) (b) Both statement (I) and Statement (II) are individually true but Statement (II) is NOT the correct explanation of Statement (I) (c) Statement (I) is true but Statement (II) is false (d) Statement (I) is false but Statement (II) is true

Answer»

(c) Statement (I) is true but Statement (II) is false

Throttling process is a irreversible process as the entropy of the fluid increases during the process. The first law of thermodynamics only gives a quantitative estimate of the heat and work interaction between the system and surroundings, however, it does not state about quality of energy. It is the second law of thermodynamics which deals with the low grade and high grade energy and concepts of availability.

Discussion

3311.	The cost price of 20 articles is the same as the selling price of x article. If the profit is 25%, then the value of x is-1. 252. 183. 164. 15
Answer» Correct Answer - Option 3 : 16 Given: CP of 20 articles = SP of x articles Profit = 25% Formula Used: %Profit = [(SP – CP)/CP] × 100 Calculation: Let the CP of each article be a And the SP of each article be b So, the CP of 20 articles = 20a Also, the SP of x articles = bx According to the question, 20a = bx ----(i) Now, the equation for profit percentage becomes: 25 = [(b – a)/a] × 100 ⇒ b = 1.25a ----(ii) On substituting the value of equation (ii) into equation (i), we get: 20a = 1.25a × x ⇒ x = 16 ∴ The required value of x is 16

3311.

The cost price of 20 articles is the same as the selling price of x article. If the profit is 25%, then the value of x is-1. 252. 183. 164. 15

Answer» Correct Answer - Option 3 : 16

Given:

CP of 20 articles = SP of x articles

Profit = 25%

Formula Used:

%Profit = [(SP – CP)/CP] × 100

Calculation:

Let the CP of each article be a

And the SP of each article be b

So, the CP of 20 articles = 20a

Also, the SP of x articles = bx

According to the question,

20a = bx ----(i)

Now, the equation for profit percentage becomes:

25 = [(b – a)/a] × 100

⇒ b = 1.25a ----(ii)

On substituting the value of equation (ii) into equation (i), we get:

20a = 1.25a × x

⇒ x = 16

∴ The required value of x is 16

Discussion

3312.	Ram invested 20% more than Raja. Raja invested 20% less than Rana. If the total sum of their investment is Rs. 5244, how much amount did Rana invest?1. Rs. 18902. Rs. 91003. Rs. 81004. Rs. 18005. Rs. 1900
Answer» Correct Answer - Option 5 : Rs. 1900 Given∶ Ram invested 20% more than Raja. Raja invested 20% less than Rana. Total investment = Rs. 5244 Formula Used∶ Basic knowledge of addition, multiplication and division Calculation∶ Let money invested by Rana = Rs x Then, money invested by Raja = 4x/5 = 0.8x Money invested by Ram = 4x/5 × 120/100 = 0.96x Also, x + 0.8x + 0.96x = 5244 2.76x = 5244 x = 5244/2.76 = 1900 ∴ Amount invested by Rana is Rs. 1900.

3312.

Ram invested 20% more than Raja. Raja invested 20% less than Rana. If the total sum of their investment is Rs. 5244, how much amount did Rana invest?1. Rs. 18902. Rs. 91003. Rs. 81004. Rs. 18005. Rs. 1900

Answer» Correct Answer - Option 5 : Rs. 1900

Given∶

Ram invested 20% more than Raja.

Raja invested 20% less than Rana.

Total investment = Rs. 5244

Formula Used∶

Basic knowledge of addition, multiplication and division

Calculation∶

Let money invested by Rana = Rs x

Then, money invested by Raja = 4x/5 = 0.8x

Money invested by Ram = 4x/5 × 120/100 = 0.96x

Also, x + 0.8x + 0.96x = 5244

2.76x = 5244

x = 5244/2.76 = 1900

∴ Amount invested by Rana is Rs. 1900.

Discussion

3313.	Find the cost price of an article, if profit percentage is 14% and selling price of an articles is Rs 31,920.1. Rs 28,0002. Rs 14,0003. Rs.35,0004. Rs.23,000
Answer» Correct Answer - Option 1 : Rs 28,000 Given selling price = Rs.31,920 Profit% = 14 Concept If selling price and profit% is given, then the formula for finding the cost price is as follows: Cost price = [100/(100 + profit%)] × Selling price Calculation Cost price = [100/(100 + 14)] × 31,920 ⇒ Rs.28,000 ∴ The cost price is Rs 28,000.

3313.

Find the cost price of an article, if profit percentage is 14% and selling price of an articles is Rs 31,920.1. Rs 28,0002. Rs 14,0003. Rs.35,0004. Rs.23,000

Answer» Correct Answer - Option 1 : Rs 28,000

Given

selling price = Rs.31,920

Profit% = 14

Concept

If selling price and profit% is given, then the formula for finding the cost price is as follows:

Cost price = [100/(100 + profit%)] × Selling price

Calculation

Cost price = [100/(100 + 14)] × 31,920

⇒ Rs.28,000

∴ The cost price is Rs 28,000.

Discussion

3314.	The higher a mountaineer climbs, ____. A) the thinner the air will become. B) there will be thinner air C) the air will become thinner D) thinner the air will become
Answer» Correct option is A) the thinner the air will become.

Discussion

3315.	Did Alice really ____ to live in this small town? A) used B) use C) used to D) ever
Answer» Correct option is B) use

Discussion

3316.	A: I wonder who took my alarm clock. B: It _____ Julia. She _____ supposed to get up early. A) might be / is B) could be / is C) had to be / was D) must have been / was
Answer» Correct option is D) must have been / was

Discussion

3317.	I hate to hear a clock ________ when I’m trying to go to sleep. A) clicking B) sounding C) humming D) ticking E) ringing
Answer» Correct option is D) ticking

Discussion

3318.	Alok sold a car to Brijesh at a profit of 8% and Brijesh sold the same to Mr. chander at a profit of 14%. Find the cost price of car for Mr. Chander If the cost price of car for Alok is Rs. 75,000.1. Rs. 923402. Rs. 134253. Rs. 865904. Rs. 78900
Answer» Correct Answer - Option 1 : Rs. 92340 Given∶ Profit% for Alok = 8% Profit percent for Brijesh = 14% Cost price of car for Alok = Rs. 75,000 Formula Used: CP of car for Mr. Chander = CP for Alok × [(100 + profit₁%)/100] × [(100 + profit₂%)/100] Calculation ∶ Cost price of car for Mr.Chander = CP for Alok × [(100 + profit1%)/100] × [(100 + profit2%)/100] ⇒ 75000 × (108/100) × (114/100) ⇒ Rs. 92,340 ∴ The CP of car for Mr. Chander is Rs. 92,340.

3318.

Alok sold a car to Brijesh at a profit of 8% and Brijesh sold the same to Mr. chander at a profit of 14%. Find the cost price of car for Mr. Chander If the cost price of car for Alok is Rs. 75,000.1. Rs. 923402. Rs. 134253. Rs. 865904. Rs. 78900

Answer» Correct Answer - Option 1 : Rs. 92340

Given∶

Profit% for Alok = 8%

Profit percent for Brijesh = 14%

Cost price of car for Alok = Rs. 75,000

Formula Used:

CP of car for Mr. Chander = CP for Alok × [(100 + profit₁%)/100] × [(100 + profit₂%)/100]

Calculation ∶

Cost price of car for Mr.Chander = CP for Alok × [(100 + profit1%)/100] × [(100 + profit2%)/100]

⇒ 75000 × (108/100) × (114/100)

⇒ Rs. 92,340

∴ The CP of car for Mr. Chander is Rs. 92,340.

Discussion

3319.	The alarm clock is ringing. It ____ be time to get up. A) must B) can’t C) will D) should
Answer» Correct option is A) must

Discussion

3320.	2C4H10 + 13O2 → 8CO2 + 10H2O This is the equation of ignition of cooking gas butane.Calculate the volume of CO2 in STP during the complete ignition of 14 kg of cooking gas.
Answer» Mass of Butane (C₄H₁₀) = 14 kg = 1400g GMM of C₄H₁₀ = 4 × 12 + 10 × 1 = 58 g ∴ Number of moles in molecules = \(\frac{1400}{58}\) = 241.38 Amount of CO₂ when 2 moles of C₄H₁₀ ignites = 8 moles of C₄H₁₀ ignites = \(\frac{8}{2}\)× 965.52 moles ∴ Volume of CO₂ formed in STP = 965.52 × 22.4 L = 21627.65 L

3320.

2C4H10 + 13O2 → 8CO2 + 10H2O This is the equation of ignition of cooking gas butane.Calculate the volume of CO2 in STP during the complete ignition of 14 kg of cooking gas.

Answer»

Mass of Butane (C₄H₁₀) = 14 kg = 1400g

GMM of C₄H₁₀ = 4 × 12 + 10 × 1 = 58 g

∴ Number of moles in molecules = \(\frac{1400}{58}\) = 241.38

Amount of CO₂ when 2 moles of C₄H₁₀ ignites = 8 moles of C₄H₁₀ ignites = \(\frac{8}{2}\)× 965.52 moles

∴ Volume of CO₂ formed in STP

= 965.52 × 22.4 L = 21627.65 L

Discussion

3321.	How much heat ( in kcal ) will be required at constant pressure to form 1.28 kg of `CaC_(2)` from CaO(s) & C(s) ? Given: `Delta_(f)H^(@)(CaO,s)=-152 kcal/mol. ` `DeltaH_(f)(CaC_(2),s)=-14 kcal/mol` `DeltaH_(f)(CO,g)=-26 kcal/mol`
Answer» [2240] `CaO(s)+3C(s) to CaC_(2)(s)+CO_(g)` `Delta_(f)H^(@)=(-14-26)-(-152)=+112 kcal//mol` Total heat required `=((1280)/(64))xx112implies 2240 kcal`

Discussion

3322.	If among 54 students each contributes Rs.60, the amount to buy new books for the library can be collected . If 9 students drop out how much additional amount does each student have to pay ?(a) Rs.18 (b) Rs.10(c) Rs.12 (d) Cannot be determined(e) None of these
Answer» (c) Sum to be collected from 54 students = 60×54 = Rs.3240 Sum collected from 45 students = 60 × 45 = Rs.2700 Difference = 3240 - 2700 = Rs.540 Additional amount to be paid by each student = 540/45 = Rs.12

Discussion

3323.	The cost of 5 chairs and 8 tables is Rs.6,574. What is the cost of 10 chairs and 16 tables?(a) Rs.15674 (b) Rs.16435(c) Rs.13148 (d) Cannot be determined(e) None of these
Answer» (c) 5 chairs + 8 tables = Rs.6574 10 chairs + 16 tables = 6574 × 2 = Rs.13148

Discussion

3324.	a `A_((g)) + bB_((g)) rarr cC_((g)) + d D_((g))` Reaction is taking place at constant Temperature, Pressure & Volume, then correct statement(s) is/are:A. `a + b = c + d`B. `M_(avg.)` may increase or decrease depeding upon limiting reagent.C. Vapour density of mixture will remain same throughout the course of reaction.D. Total molar will change with progress of reaction.
Answer» Correct Answer - A::C According to `PV = nRT`

Discussion

3325.	pH of a solution of a strong acid is 3.0. What will be the pH of the solution obtained after diluting the given solution 100 times?
Answer» We have given, pH at strong acid = 3.0 ∴ -log [H⁺] = 3 [H⁺] = 10^-3M Concentration of H⁺ ion After diluting 100 times = 10^-3/100 = 10^-5 M Therefore, the pH of final solution = - log 10^-5 = 5 Hence, the pH of solution, After dilution, 100 times, will becomes 5.

3325.

pH of a solution of a strong acid is 3.0. What will be the pH of the solution obtained after diluting the given solution 100 times?

Answer»

We have given,

pH at strong acid = 3.0

∴ -log [H⁺] = 3

[H⁺] = 10^-3M

Concentration of H⁺ ion After diluting 100 times

= 10^-3/100

= 10^-5 M

Therefore, the pH of final solution

= - log 10^-5

= 5

Hence, the pH of solution, After dilution, 100 times, will becomes 5.

Discussion

3326.	Hydrazine reacts with `KIO_(3)` in presence of `HCl` as `:` `N_(2)H_(4)+IO_(3)^(-)+2H^(+)+Cl^(-) rarrICI+N_(2)+3H_(2)O` The equivalent masses of `N_(2)H_(4)` and `KIO_(3)` respectively are `:`A. 8 and 53.5B. 16 and 53.5C. 8 and 35.6D. 8 and 87
Answer» Correct Answer - A Eq. wt. of `N_(2)H_(4)=("molar mass")/(4)` Eq. wt. of `IO_(3)^(-)=("molar mass")/(4)`

Discussion

3327.	0.1M solution of KI reacts with excess of `H_(2)SO_(4)` and `KIO_(3)` solutions, according to equation `5I^(-)+IO_(3)^(-)+6H^(+)to3I^(2)+3H_(2)O`, which of the following statements is /are correct:A. 400 ml of the KI solution react with 0.004 mole of `KIO_3`B. 100 ml of the KI solution reacts with 0.006 mole of `H_2SO_4`C. 0.5 litre of the KI solution produced 0.005 mole of `I_2`D. Equivalent weight of `KIO_3` is equal to `(("Molecular Weight")/5)`
Answer» Correct Answer - B,D `5I^(-) + IO_3^(-) +6H^(+)to3I_2 + 3H_2O` `("moles of" KI "used")/("moles of" KIO_3 "used")=5` valency factor of `KIO_3=5` `:. E_(KIO_3)=("mol. Wt.")/5`

Discussion

3328.	Predict which of the following reactions have positive entropy changes. `(a)` `NH_(3(g))+HCl_((g))rarrNH_(4)Cl_((s))` `(b)` `Cu_((aq))^(+2)+S_((aq))^(-2)rarrCuS_((s))` `(c )` `NH_(2)COONH_(4(s))rarr2NH_(3(g))+CO_(2(g))` `(d)` Condensation of waterA. `b` and `c`B. `c` and `d`C. `c`D. `a`
Answer» Correct Answer - C

Discussion

3329.	Predict which of the following reaction(s) has a positive entropy change?I. Ag+ (aq) + Cl– (aq) → AgCl(s)II. NH4Cl(s) → NH3(g) + HCl(g)III. 2NH3(g) → N2(g) + 3H2(g)(a) I and II (b) III (c) II and III (d) II
Answer» Correct option (c) II and III Δng is +ve

3329.

Predict which of the following reaction(s) has a positive entropy change?I. Ag+ (aq) + Cl– (aq) → AgCl(s)II. NH4Cl(s) → NH3(g) + HCl(g)III. 2NH3(g) → N2(g) + 3H2(g)(a) I and II (b) III (c) II and III (d) II

Answer»

Correct option (c) II and III

Δng is +ve

Discussion

3330.	1. Write the full form of LPG, what is its main constituent? 2. Why is ethyl mercaptan added to LPG? 3. Which element is the main component of coal? 4. Name the different types of coal? 5. Name the process by which the components of coal are separated? 6. Write the products obtained by the distillation of coal.
Answer» 1. Liquefied Petroleum Gas, Butane 2. To identify the leak of LPG. 3. Carbon 4. Peat, Lignite, Anthracite and Bituminous coal. 5. Distillation 6. Ammonia, Coal gas, Coal tar, and Coke.

3330.

1. Write the full form of LPG, what is its main constituent? 2. Why is ethyl mercaptan added to LPG? 3. Which element is the main component of coal? 4. Name the different types of coal? 5. Name the process by which the components of coal are separated? 6. Write the products obtained by the distillation of coal.

Answer»

1. Liquefied Petroleum Gas, Butane

2. To identify the leak of LPG.

3. Carbon

4. Peat, Lignite, Anthracite and Bituminous coal.

5. Distillation

6. Ammonia, Coal gas, Coal tar, and Coke.

Discussion

3331.	The following Fairs and Festivals organised by the Department of Rajasthan Tourism - (A) Desert Festival, Jaisalmer (B) Elephant Festival, Jaipur(C) Camel Festival, Bikaner(D) Summer Festival, Mount AbuTheir chronological order according to the calendar year is -1. (A), (C), (B), (D)2. (B), (A), (C), (D)3. (C), (A), (D), (B)4. (C), (A), (B), (D)
Answer» Correct Answer - Option 4 : (C), (A), (B), (D) The correct answer is (C), (A), (B), (D). Camel Festival, Bikaner (January) Desert Festival, Jaisalmer (Jan-Feb.) Elephant Festival, Jaipur (March–April) Summer Festival, Mt. Abu (June) Department of Tourism of Rajasthan Government organizes multiple fairs & festivals during the year. These festivals & fairs are great tourist attractions. Fairs organized in Rajasthan include: Camel Festival, Bikaner (January) Nagaur Fair, Nagaur (Jan-Feb.) Kite Festival (held on 14th Jan of every year) Desert Festival, Jaisalmer (Jan-Feb.) Baneshwar Fair, Baneshwar (Jan-Feb.) Gangaur Festival, Jaipur (March–April) Mewar Festival, Udaipur (March–April) Elephant Festival, Jaipur (March–April) Urs Ajmer Sharif, Ajmer (According to Lunar Calendar) Summer Festival, Mt. Abu (June) Teej Festival, Jaipur (July–August) Kajli Teej, Bundi (July–August) Dussehra Festival, Kota (October) Marwar Festival, Jodhpur (October) Pushkar Fair, Ajmer (November)

3331.

The following Fairs and Festivals organised by the Department of Rajasthan Tourism - (A) Desert Festival, Jaisalmer (B) Elephant Festival, Jaipur(C) Camel Festival, Bikaner(D) Summer Festival, Mount AbuTheir chronological order according to the calendar year is -1. (A), (C), (B), (D)2. (B), (A), (C), (D)3. (C), (A), (D), (B)4. (C), (A), (B), (D)

Answer» Correct Answer - Option 4 : (C), (A), (B), (D)

The correct answer is (C), (A), (B), (D).

Camel Festival, Bikaner (January)
Desert Festival, Jaisalmer (Jan-Feb.)
Elephant Festival, Jaipur (March–April)
Summer Festival, Mt. Abu (June)

Department of Tourism of Rajasthan Government organizes multiple fairs & festivals during the year.
- These festivals & fairs are great tourist attractions. Fairs organized in Rajasthan include:
- Camel Festival, Bikaner (January)
- Nagaur Fair, Nagaur (Jan-Feb.)
- Kite Festival (held on 14th Jan of every year)
- Desert Festival, Jaisalmer (Jan-Feb.)
- Baneshwar Fair, Baneshwar (Jan-Feb.)
- Gangaur Festival, Jaipur (March–April)
- Mewar Festival, Udaipur (March–April)
- Elephant Festival, Jaipur (March–April)
- Urs Ajmer Sharif, Ajmer (According to Lunar Calendar)
- Summer Festival, Mt. Abu (June)
- Teej Festival, Jaipur (July–August)
- Kajli Teej, Bundi (July–August)
- Dussehra Festival, Kota (October)
- Marwar Festival, Jodhpur (October)
- Pushkar Fair, Ajmer (November)

Discussion

3332.	“Mundiyar ri Khyat” is about -1. Chauhans of Siroht2. Hadas of Bundi3. Sisodias of Mewar4. Rathores of Marwar
Answer» Correct Answer - Option 4 : Rathores of Marwar The correct answer is Rathores of Marwar “Mundiyar ri Khyat” is about - Rathores of Marwar. Mundiyar Ri Khait or Dayaladas Reh It is significant for the early history of Jodhpur. By the orders of Maharaja Ratan Singh, Dayaldas wrote the history of the throne of the earliest kings of Bikaner state. He wrote the history of Rathore of Marwar.

3332.

“Mundiyar ri Khyat” is about -1. Chauhans of Siroht2. Hadas of Bundi3. Sisodias of Mewar4. Rathores of Marwar

Answer» Correct Answer - Option 4 : Rathores of Marwar

The correct answer is Rathores of Marwar

“Mundiyar ri Khyat” is about - Rathores of Marwar.

Mundiyar Ri Khait or Dayaladas Reh
- It is significant for the early history of Jodhpur.
- By the orders of Maharaja Ratan Singh, Dayaldas wrote the history of the throne of the earliest kings of Bikaner state.
- He wrote the history of Rathore of Marwar.

Discussion

3333.	The Martial Arts Academy of Madhya Pradesh is located at -1. Indore2. Jabalpur3. Bhopal4. Umaria
Answer» Correct Answer - Option 3 : Bhopal The correct answer is Bhopal. The Martial Arts Academy of Madhya Pradesh is located at Bhopal. It is an academy for learning Martial Arts and self - defense. Bhopal city is situated in the fertile plain of the Malwa Plateau, the city lies just north of the Vindhya Range, along the slopes of a sandstone ridge. Bhopal was formerly a part of Bhopal princely state, which was founded in 1723 by Dost Moḥammad Khan, an Afghan adventurer. Bhopal was constituted as a municipality in 1903. In 1952, the Nawab’s absolute rule was abolished, and a chief commissioner’s state was established. It merged with Madhya Pradesh in 1956, and Bhopal replaced Nagpur as the state capital. Indore is the most populous and the largest city in the Indian state of Madhya Pradesh. Jabalpur is known for the Dhuandhar Falls and the White Marble Rocks at Bhedaghat. It is the third largest city of Madhya Pradesh. As of 2011, Umaria is the second least populous district of Madhya Pradesh (out of 50).

3333.

The Martial Arts Academy of Madhya Pradesh is located at -1. Indore2. Jabalpur3. Bhopal4. Umaria

Answer» Correct Answer - Option 3 : Bhopal

The correct answer is Bhopal.

The Martial Arts Academy of Madhya Pradesh is located at Bhopal.
It is an academy for learning Martial Arts and self - defense.

Bhopal city is situated in the fertile plain of the Malwa Plateau, the city lies just north of the Vindhya Range, along the slopes of a sandstone ridge.
Bhopal was formerly a part of Bhopal princely state, which was founded in 1723 by Dost Moḥammad Khan, an Afghan adventurer.
Bhopal was constituted as a municipality in 1903.
In 1952, the Nawab’s absolute rule was abolished, and a chief commissioner’s state was established.
It merged with Madhya Pradesh in 1956, and Bhopal replaced Nagpur as the state capital.

Indore is the most populous and the largest city in the Indian state of Madhya Pradesh.
Jabalpur is known for the Dhuandhar Falls and the White Marble Rocks at Bhedaghat. It is the third largest city of Madhya Pradesh.
As of 2011, Umaria is the second least populous district of Madhya Pradesh (out of 50).

Discussion

3334.	The compound that does NOT liberate CO2, on treatment with aqueous sodium bicarbonate solution, is (A) Benzoic acid (B) Benzenesulphonic acid (C) Salicylic acid (D) Carbolic acid (Phenol)
Answer» (D) Carbolic acid (Phenol) pK_a of PhOH (carbolic acid) is 9.98 and that of carbonic acid (H₂CO₃) is 6.63 thus phenol does not give effervescence with HCO\(^-_3\) ion.

3334.

The compound that does NOT liberate CO2, on treatment with aqueous sodium bicarbonate solution, is (A) Benzoic acid (B) Benzenesulphonic acid (C) Salicylic acid (D) Carbolic acid (Phenol)

Answer»

(D) Carbolic acid (Phenol)

pK_a of PhOH (carbolic acid) is 9.98 and that of carbonic acid (H₂CO₃) is 6.63 thus phenol does not give effervescence with HCO\(^-_3\) ion.

Discussion

3335.	Give examples of paramagnetic oxide of chlorine.
Answer» Paramagnetic oxides of chlorine: `ClO_2` and`ClO_3`.

Discussion

3336.	Concentrated nitric acid, upon long standing, turns yellow–brown due to the formation of(A) NO (B) NO2 (C) N2O (D) N2O4
Answer» (B) NO₂ 4HNO₃ → 2H₂ O + 4NO₂ + O₂ NO₂ remains dissolved in nitric acid colouring it yellow or even red at higher temperature.

3336.

Concentrated nitric acid, upon long standing, turns yellow–brown due to the formation of(A) NO (B) NO2 (C) N2O (D) N2O4

Answer»

(B) NO₂

4HNO₃ → 2H₂ O + 4NO₂ + O₂

NO₂ remains dissolved in nitric acid colouring it yellow or even red at higher temperature.

Discussion

3337.	Consider the following statements and arrange in the order of true/false as given in the codes. `S_1`:Interstitial compounds have high melting points, higher than those of pure metals. `S_2`:Permagnate titrations in presence of hydrochloric acid are unsatisfactory. `S_3`:`KMnO_4` does not act an oxidising agent in strong alkaline medium. `S_4`:For `1^(st)` transition serise, the `E^()` value for `M^(2+)//M` indicate a decreasing tendency to form cation across the series.
Answer» Correct Answer - A `S_1`:Due to strong interatomic forces. `S_2`:Hydrochloric acid is oxidised to chlorine. `S_3`:`MnO_4^(-)overset(OH^-)toMnO_4^(2-)` `S_4:M^(2+)//M (E^(theta)//V)`-negative value decreases across the series.

Discussion

3338.	Consider the following statements and arrange in the order of true/false as given in the codes . `S_1`:Colour of a colloidal solution depends upon the size and shape of sol particles. `S_2`:Bromnian motion is due to continuous bombardment of sol particles by molecules of disperson medium. `S_3`:When negatively charged smoke comes in contact with positively charged clouds.rain fall takes place. `S_4`:For a positive sol, flocculation values are in the order. `NaClgtK_2SO_4gtNa_3PO_4gtK_4[Fe(CN)_6]`A. TTTTB. TTFFC. TFTFD. FFFF
Answer» Correct Answer - A `S_1`:different sized colloidal particles have different colour. `S_2`:Brownian movement is due to collision between D.P. particles and D.M. particles `S_3`:It is because of coagulation of mist particle in air `S_4`:Flocculation value `prop 1/("Charge on effective ion")`

Discussion

3339.	Which of the following are correct statementsA. Spontaneous adsorption of gases on solid surface is an exothermic process as entropy decrease during adsorptionB. Formation of micelles takes place when temperature is below Kraft Temperature `(T_k)` and concentration is above critical micelle concentration (CMC)C. A colloid of `Fe(OH)_3` is prepared by adding a little excess (required to completely precipitate `Fe^(3+)` ions as `Fe(OH)_3` ) of NaOH in `FeCl_3` solution the particles of this sol will move towards cathode during electrophoresis.D. According to Hardy-Schuize rules the coagulation (flocculating) value of `Fe^(3+)` ion will be more than `Ba^(2+)` or `Na^(+)`
Answer» Correct Answer - A,C (A)`DeltaG=DeltaH-TDeltaSltO " " as " " DeltaSltO " " so DeltaH` has to be negative (B)micelles formation will take place above `T_k` and above CMC ( C)`Fe(OH)_3` sol prepared by the hydrolysis of `FeCl_3` solution adsorbs `Fe^(3+)` and this is positively charged. `FeCl_3 +3H_2O hArrFe(OH_3)+3HCl , " " Fe(OH)_3+FeCl_3 tounderset("Fixed part.")(Fe(OH)_3)\|Fe^(3+), " " underset("Diffused part.")(3Cl^(-))` Positive charge on colloidal sol is due to adsorption of `Fe^(3+)` ion (common ion between `Fe(OH)_3` and `FeCl_3`) (D)`Fe^(3+)` ions will have greater flocculatibility power so smaller flocculating value.

Discussion

3340.	Amphoterism Amphoteric oxides, such as aluminium oxide, are soluble both in strongly acidic and in strongly base solutions : In acid:`Al_2O_3(s)+6H_3O^(+)(aq)hArr2Al^(3+)(aq)+9H_2O(l)` In base:`Al(OH)_3(s)+OH^(-)(aq)hArr Al(OH)_4^(-)(aq)` Dissolution of `Al(OH)_3` in excess base is just a special case of the effect of complex-ion formation on solubility.`Al(OH)_3` dissolves because excess `OH^(-)` ions convert it to the soluble complex ion `Al(OH)_4^(-)`(aluminate ion)The effect of pH on the solubility of `Al(OH)_3` is shown in figure. Other examples of amphoteric hydroxides include `Zn(OH)_2,Cr(OH)_3,Sn(OH)_2 and Pb(OH)_2`, which react with excess `OH^(-)` ions to form the soluble complex ion `Zn(OH)_4^(2-)`(zincate ion),`Cr(OH)_4^(-)`(chromite ion),`Sn(OH)_3^(-)` , `Fe(OH)_2 and Fe(OH)_3` , dissolve in strong acid but not in strong base. Which of the following curves best represents the variation of solubility of ferrous hydroxide `Fe(OH)_2` with the concentration of `[H^(+)]` ions in the solution:A. B. C. D.
Answer» Correct Answer - A On increasing concentration of `[H^+]` ions the solubility of basic hydroxide `Fe(OH)_2` will increase.

Discussion

3341.	Amphoterism Amphoteric oxides, such as aluminium oxide, are soluble both in strongly acidic and in strongly base solutions : In acid:`Al_2O_3(s)+6H_3O^(+)(aq)hArr2Al^(3+)(aq)+9H_2O(l)` In base:`Al(OH)_3(s)+OH^(-)(aq)hArr Al(OH)_4^(-)(aq)` Dissolution of `Al(OH)_3` in excess base is just a special case of the effect of complex-ion formation on solubility.`Al(OH)_3` dissolves because excess `OH^(-)` ions convert it to the soluble complex ion `Al(OH)_4^(-)`(aluminate ion)The effect of pH on the solubility of `Al(OH)_3` is shown in figure. Other examples of amphoteric hydroxides include `Zn(OH)_2,Cr(OH)_3,Sn(OH)_2 and Pb(OH)_2`, which react with excess `OH^(-)` ions to form the soluble complex ion `Zn(OH)_4^(2-)`(zincate ion),`Cr(OH)_4^(-)`(chromite ion),`Sn(OH)_3^(-)` , `Fe(OH)_2 and Fe(OH)_3` , dissolve in strong acid but not in strong base. `Zn(OH)_2` is a amphoteric hydroxide and is involved in the following two equilbria in aqueous solutions `Zn(OH)_2(s)hArrZn^(2+)(aq)+2OH^(-)(aq),K_(sp)=1.2xx10^(-17)` `Zn(OH)_2(s)+2OH^(-)(aq)hArr[Zn(OH)_4]^(2-)(aq),K_(@)=0.12` At what pH the solubility of `Zn(OH)_2` be minimum ?A. 4B. 10C. 6D. 8
Answer» Correct Answer - B Let solubility of `Zn(OH)_2`=s, some of will go in `Zn^(2+)` form and some in complex `[Zn(OH)_4]^(2-)`, of `[OH^(Theta)]=10^(-x)M`, then `S_1(10^(-14)/10^(-x))^2=1.2xx10^(-17) `...(i) `S_2/(10^(-14)/10^(-x))^2=0.12` [`S_1+S_2`=total solubility] So , `S_1S_2=1.2xx1.2 10^(-18)` Now we want `S=S_1+S_2` to be minimum we will have `S_1=S_2` So, `S_1=S_2=1.2xx10^(-9)M` Hence from `1^(st)` equation we get `(10^(-14)/10^(-x))^2=(1.2xx10^(-17)) /(1.2xx10^(-3))=10^(-10)` Hence, x=10

Discussion

3342.	Which of the following statements are true for physisoption?A. Extent of adsorption increases with increase in pressureB. It needs activation energyC. It can be reversed easilyD. It occurs at high temperature
Answer» Correct Answer - A,C From the properties of physisorption it can be seen that extent of adsorption increases with increases in pressure and it can be reversed easily.

Discussion

3343.	State the Reactions in Non-aqueous solvents.
Answer» Reactions in Non-aqueous solvents : (i) Solvents like C₆H₆, CCl₄ , THF (Tetrahydrofuran), DMF (N, N-dimethyl formamide) etc. are used in organic chemistry. In inorganic chemistry reactions are generally studied in water. However a large number of non– aqueous solvents (such as Glacial acetic acid, Hydrogen halides, SO₂ etc.) have been introduced in inorganic chemistry. (ii) The physical properties of a solvent such as M.P., B.P., Dipole moment and Dielectric constant are of importance in deciding its behaviour.

3343.

State the Reactions in Non-aqueous solvents.

Answer»

Reactions in Non-aqueous solvents :

(i) Solvents like C₆H₆, CCl₄ , THF (Tetrahydrofuran), DMF (N, N-dimethyl formamide) etc. are used in organic chemistry. In inorganic chemistry reactions are generally studied in water. However a large number of non– aqueous solvents (such as Glacial acetic acid, Hydrogen halides, SO₂ etc.) have been introduced in inorganic chemistry.

(ii) The physical properties of a solvent such as M.P., B.P., Dipole moment and Dielectric constant are of importance in deciding its behaviour.

Discussion

3344.	My father’s brother is my ______. A) brother B) grandfather C) uncle D) aunt
Answer» Correct option is C) uncle

Discussion

3345.	lim(x-->0) (3x-2x/4x-3x) is equal to
Answer» It continues to be 0/0, so we will apply L-Hospital rule lim_(x-->0) (3^x-2^x/4^x-3^x) = lim_(x-->0) (3^xln3 - 2^x ln2 / 4^xln4 - 3^x ln3) apply limit = ln3 - ln2 / ln4 - ln3 = ln(3/2) x ln (3/4)

3345.

lim(x-->0) (3x-2x/4x-3x) is equal to

Answer»

It continues to be 0/0, so we will apply L-Hospital rule

lim_(x-->0) (3^x-2^x/4^x-3^x)

= lim_(x-->0) (3^xln3 - 2^x ln2 / 4^xln4 - 3^x ln3)

apply limit

= ln3 - ln2 / ln4 - ln3

= ln(3/2) x ln (3/4)

Discussion

3346.	A point on the parabola y2 = 18x at which the ordinate increases at twice the rate of the abscissa is
Answer» Refers to the below link http://bit.ly/2D8EDXE

3346.

A point on the parabola y2 = 18x at which the ordinate increases at twice the rate of the abscissa is

Answer»

Refers to the below link

http://bit.ly/2D8EDXE

Discussion

3347.	If the day before yesterday was Friday, what will be the third day after the day after tomorrow?1. Friday2. Saturday3. Thursday4. Wednesday
Answer» Correct Answer - Option 1 : Friday The day before yesterday was Friday. Therefore, today is Sunday. The day after tomorrow will be Tuesday. Tuesday + 3 = Friday Hence, Friday is the correct answer.

3347.

If the day before yesterday was Friday, what will be the third day after the day after tomorrow?1. Friday2. Saturday3. Thursday4. Wednesday

Answer» Correct Answer - Option 1 : Friday

The day before yesterday was Friday.

Therefore, today is Sunday.

The day after tomorrow will be Tuesday.

Tuesday + 3 = Friday

Hence, Friday is the correct answer.

Discussion

3348.	If `f(x)=(1-s in2x+cos2x)/(2cos2x)`, then the value of `f(16^0)dotf(29^0)`is`1/2``1/4``1``3/4`A. `1/2`B. `1/4`C. `1`D. `3/4`
Answer» Correct Answer - A

Discussion

3349.	In the Expansion of\( \left(2 x^{2}+r x+1\right)^{6} \), where \( r \) is a number and\( x \) is a variable, the coefficient of \( x^{2} \) and\( x^{4} \) are 27 and \( -192 \) respectively findThe possible value of \( r \)
Answer» Given expression:- (2x² + rx + 1)⁶ The general term of this expression = 6!/ (p! q! r!) × 1^p × rx^q × (2x²)^r = 6!/ (p! q! r!) × r^q × 2^r × (x^{q + 2r}) Case1:- x^q^+2r= x² q + 2r = 2 Also, p + q + r = 6, The possible values of p, q, r are (4,2,0) and (5,0,1) The coefficient of x² = 27(given) [{6! / (4! 2! 1!)} × r² × 2⁰] + [{6! / (5! 0! 1!)} × r⁰ × 2¹] = 27 [{6! / (4! 2!)} × r²] + [{6! / (5! 1!)} × 2] = 27 15r² + 12 = 27 15r² = 15 ∴r = ±1 .... (1) Case2:- x^q^{+ 2r} = x¹¹ q + 2r = 11 Also, p + q + r = 6 The only possible value of p, q, r is (0,1,5) The coefficient of x¹¹ = -192 {6! / (0! 1! 5!)} × r¹ × 2⁵ = -192 {6! / 5!} × r × 32 = -192 6r = -6 r = -1 .... (2) From (1) and (2), r = -1

3349.

In the Expansion of\( \left(2 x^{2}+r x+1\right)^{6} \), where \( r \) is a number and\( x \) is a variable, the coefficient of \( x^{2} \) and\( x^{4} \) are 27 and \( -192 \) respectively findThe possible value of \( r \)

Answer»

Given expression:- (2x² + rx + 1)⁶

The general term of this expression = 6!/ (p! q! r!) × 1^p × rx^q × (2x²)^r

= 6!/ (p! q! r!) × r^q × 2^r × (x^{q + 2r})

Case1:-

x^q^+2r= x²

q + 2r = 2

Also, p + q + r = 6,

The possible values of p, q, r are (4,2,0) and (5,0,1)

The coefficient of x² = 27(given)

[{6! / (4! 2! 1!)} × r² × 2⁰] + [{6! / (5! 0! 1!)} × r⁰ × 2¹] = 27

[{6! / (4! 2!)} × r²] + [{6! / (5! 1!)} × 2] = 27

15r² + 12 = 27

15r² = 15 ∴r = ±1 .... (1)

Case2:-

x^q^{+ 2r} = x¹¹

q + 2r = 11

Also, p + q + r = 6

The only possible value of p, q, r is (0,1,5)

The coefficient of x¹¹ = -192

{6! / (0! 1! 5!)} × r¹ × 2⁵ = -192

{6! / 5!} × r × 32 = -192

6r = -6

r = -1 .... (2)

From (1) and (2), r = -1

Discussion

3350.	The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case is1. 252. 183. 154. None of the above
Answer» Correct Answer - Option 3 : 15 Concept The greatest number by which dividing a, b and c leaves the same remainder in each case = HCF of (a - b) and (b - c) Calculation The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case = HCF of (138 - 63) and (228 - 138) ⇒ HCF of 75 and 90 [138 - 63 = 75 and 228 - 138 = 90] ⇒ 15 Hence, the greatest number is 15.

3350.

The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case is1. 252. 183. 154. None of the above

Answer» Correct Answer - Option 3 : 15

Concept

The greatest number by which dividing a, b and c leaves the same remainder in each case = HCF of (a - b) and (b - c)

Calculation

The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case = HCF of (138 - 63) and (228 - 138)

⇒ HCF of 75 and 90 [138 - 63 = 75 and 228 - 138 = 90]

⇒ 15

Hence, the greatest number is 15.

Discussion

Explore topic-wise InterviewSolutions in .

A metallic element exists as simple cubic lattice. Each edge of the unit cell is 3Å. The density of the metal is `9 "g cm"^(–3)`. How many number of unit cells will be present in 100 g of the metal :-A. 6.85 × 102B. 4.12 × 1023C. 4.37 × 105D. 2.12 × 106

Rate constant for first order reaction is `5.78xx10^(-5)S^(-1)`. What percentage of initial reactant will react in 10 hours ?A. `12. 5%`B. `25%`C. `87. 5%`D. `75%`

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Give examples of paramagnetic oxide of chlorine.

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State the Reactions in Non-aqueous solvents.

My father’s brother is my ______. A) brother B) grandfather C) uncle D) aunt

lim(x-->0) (3x-2x/4x-3x) is equal to

A point on the parabola y2 = 18x at which the ordinate increases at twice the rate of the abscissa is

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In the Expansion of\( \left(2 x^{2}+r x+1\right)^{6} \), where \( r \) is a number and\( x \) is a variable, the coefficient of \( x^{2} \) and\( x^{4} \) are 27 and \( -192 \) respectively findThe possible value of \( r \)

The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case is1. 252. 183. 154. None of the above

Explore topic-wise InterviewSolutions in .

A metallic element exists as simple cubic lattice. Each edge of the unit cell is 3Å. The density of the metal is `9 "g cm"^(–3)`. How many number of unit cells will be present in 100 g of the metal :-A. 6.85 × 102B. 4.12 × 1023C. 4.37 × 105D. 2.12 × 106

Rate constant for first order reaction is `5.78xx10^(-5)S^(-1)`. What percentage of initial reactant will react in 10 hours ?A. `12. 5%`B. `25%`C. `87. 5%`D. `75%`

I used to speak French _____, but I’ve forgotten it now. A) successfully B) fluently C) honestly D) carefully

Could you give me a ________? I’ve forgotten my matches. A) flame B) light C) fire D) illumination E) flare

For the reaction `N_(2)O_(5)(g)toN_(2)O_(4)(g)+1//2O_(2)(g)` initial pressure is 114 mm and after 20 seconds the pressure of reaction mixture becomes 133 mm then the average rate of reaction will beA. `1.9 atm S^(-1)`B. `8.75xx10^(-3) atm S^(-1)`C. `2.5xx10^(-3)atmS^(-1)`D. `6.65atmS^(-1)`

Paraphrase the interjection used in the following dialogue. A: I’ve forgotten to tell John about the party. B: Eh? A) What did you say?B) Really? C) How come?

The cost price of 20 articles is the same as the selling price of x article. If the profit is 25%, then the value of x is-1. 252. 183. 164. 15

Ram invested 20% more than Raja. Raja invested 20% less than Rana. If the total sum of their investment is Rs. 5244, how much amount did Rana invest?1. Rs. 18902. Rs. 91003. Rs. 81004. Rs. 18005. Rs. 1900

Find the cost price of an article, if profit percentage is 14% and selling price of an articles is Rs 31,920.1. Rs 28,0002. Rs 14,0003. Rs.35,0004. Rs.23,000

The higher a mountaineer climbs, ____. A) the thinner the air will become. B) there will be thinner air C) the air will become thinner D) thinner the air will become

Did Alice really ____ to live in this small town? A) used B) use C) used to D) ever

A: I wonder who took my alarm clock. B: It _____ Julia. She _____ supposed to get up early. A) might be / is B) could be / is C) had to be / was D) must have been / was

I hate to hear a clock ________ when I’m trying to go to sleep. A) clicking B) sounding C) humming D) ticking E) ringing

Alok sold a car to Brijesh at a profit of 8% and Brijesh sold the same to Mr. chander at a profit of 14%. Find the cost price of car for Mr. Chander If the cost price of car for Alok is Rs. 75,000.1. Rs. 923402. Rs. 134253. Rs. 865904. Rs. 78900

The alarm clock is ringing. It ____ be time to get up. A) must B) can’t C) will D) should

2C4H10 + 13O2 → 8CO2 + 10H2O This is the equation of ignition of cooking gas butane.Calculate the volume of CO2 in STP during the complete ignition of 14 kg of cooking gas.

How much heat ( in kcal ) will be required at constant pressure to form 1.28 kg of `CaC_(2)` from CaO(s) & C(s) ? Given: `Delta_(f)H^(@)(CaO,s)=-152 kcal/mol. ` `DeltaH_(f)(CaC_(2),s)=-14 kcal/mol` `DeltaH_(f)(CO,g)=-26 kcal/mol`

If among 54 students each contributes Rs.60, the amount to buy new books for the library can be collected . If 9 students drop out how much additional amount does each student have to pay ?(a) Rs.18 (b) Rs.10(c) Rs.12 (d) Cannot be determined(e) None of these

The cost of 5 chairs and 8 tables is Rs.6,574. What is the cost of 10 chairs and 16 tables?(a) Rs.15674 (b) Rs.16435(c) Rs.13148 (d) Cannot be determined(e) None of these

pH of a solution of a strong acid is 3.0. What will be the pH of the solution obtained after diluting the given solution 100 times?

Hydrazine reacts with `KIO_(3)` in presence of `HCl` as `:` `N_(2)H_(4)+IO_(3)^(-)+2H^(+)+Cl^(-) rarrICI+N_(2)+3H_(2)O` The equivalent masses of `N_(2)H_(4)` and `KIO_(3)` respectively are `:`A. 8 and 53.5B. 16 and 53.5C. 8 and 35.6D. 8 and 87

Predict which of the following reactions have positive entropy changes. `(a)` `NH_(3(g))+HCl_((g))rarrNH_(4)Cl_((s))` `(b)` `Cu_((aq))^(+2)+S_((aq))^(-2)rarrCuS_((s))` `(c )` `NH_(2)COONH_(4(s))rarr2NH_(3(g))+CO_(2(g))` `(d)` Condensation of waterA. `b` and `c`B. `c` and `d`C. `c`D. `a`

Predict which of the following reaction(s) has a positive entropy change?I. Ag+ (aq) + Cl– (aq) → AgCl(s)II. NH4Cl(s) → NH3(g) + HCl(g)III. 2NH3(g) → N2(g) + 3H2(g)(a) I and II (b) III (c) II and III (d) II

“Mundiyar ri Khyat” is about -1. Chauhans of Siroht2. Hadas of Bundi3. Sisodias of Mewar4. Rathores of Marwar

The Martial Arts Academy of Madhya Pradesh is located at ­-1. Indore2. Jabalpur3. Bhopal4. Umaria

The compound that does NOT liberate CO2, on treatment with aqueous sodium bicarbonate solution, is (A) Benzoic acid (B) Benzenesulphonic acid (C) Salicylic acid (D) Carbolic acid (Phenol)

Give examples of paramagnetic oxide of chlorine.

Concentrated nitric acid, upon long standing, turns yellow–brown due to the formation of(A) NO (B) NO2 (C) N2O (D) N2O4

Which of the following statements are true for physisoption?A. Extent of adsorption increases with increase in pressureB. It needs activation energyC. It can be reversed easilyD. It occurs at high temperature

State the Reactions in Non-aqueous solvents.

My father’s brother is my ______. A) brother B) grandfather C) uncle D) aunt

lim(x--&gt;0) (3x-2x/4x-3x) is equal to

A point on the parabola y2 = 18x at which the ordinate increases at twice the rate of the abscissa is

If the day before yesterday was Friday, what will be the third day after the day after tomorrow?1. Friday2. Saturday3. Thursday4. Wednesday

If `f(x)=(1-s in2x+cos2x)/(2cos2x)`, then the value of `f(16^0)dotf(29^0)`is`1/2``1/4``1``3/4`A. `1/2`B. `1/4`C. `1`D. `3/4`

In the Expansion of\( \left(2 x^{2}+r x+1\right)^{6} \), where \( r \) is a number and\( x \) is a variable, the coefficient of \( x^{2} \) and\( x^{4} \) are 27 and \( -192 \) respectively findThe possible value of \( r \)

The greatest number by which dividing 63, 138 and 228 leaves the same remainder in each case is1. 252. 183. 154. None of the above

A: I wonder who took my alarm clock. B: It _ Julia. She _ supposed to get up early. A) might be / is B) could be / is C) had to be / was D) must have been / was

The Martial Arts Academy of Madhya Pradesh is located at -1. Indore2. Jabalpur3. Bhopal4. Umaria

lim(x-->0) (3x-2x/4x-3x) is equal to