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pH of a solution of a strong acid is 3.0. What will be the pH of the solution obtained after diluting the given solution 100 times? |
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Answer» We have given, pH at strong acid = 3.0 ∴ -log [H+] = 3 [H+] = 10-3M Concentration of H+ ion After diluting 100 times = 10-3/100 = 10-5 M Therefore, the pH of final solution = - log 10-5 = 5 Hence, the pH of solution, After dilution, 100 times, will becomes 5. |
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