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A metallic element exists as simple cubic lattice. Each edge of the unit cell is 3Å. The density of the metal is `9 "g cm"^(–3)`. How many number of unit cells will be present in 100 g of the metal :-A. 6.85 × 102B. 4.12 × 1023C. 4.37 × 105D. 2.12 × 106 |
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Answer» Correct Answer - B `C.D.=(ZxxM_W)/(VxxN_A) = (ZxxM_0)/(VxxN_0)` Number of unit cell present in 100 g of the metal `M_0/(V xx C.D.) = 100/((3xx10^(-8))^3) xx9` = 4.12 × 1023 |
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