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Correct answer is (ii) Dashrath Manjhi 

Correct answer is (i) Social Science 

Correct option is: (B) Chitinase

Cellulase enzyme is used to treat plant cells .

Anthrax is a rare but serious illness caused by a spore-forming bacterium, Bacillus anthracis. Anthrax mainly affects livestock and wild game. Humans can become infected through direct or indirect contact with sick animals.

Ranikhet disease, also known in the West as Newcastle disease is a contagious and highly fatal daises of flows. In spite of the notable work done towards its control, this disease still ranks as one of the most serious virus diseases of poultry.

Oligochaeta is a subclass of animals in the phylum Annelida, which is made up of many types of aquatic and terrestrial worms, including all of the various earthworms.  

Polychaetes (bristleworms) are marine annelids with parapodia bearing numerous setae in distinct fascicles. They are dioecious and multi-segmented. They have simple exit ducts from the gonads. Most of them live in soft or rocky environment on sea floor from intertidal to depth.

Difference between Polychaeta and Oligochaeta :

Alpha diversity is the number of species found in a small and homogeneous area (very tiny area up to about 1,000 hectares or 2,500 acres). It is the same as species richness for a local community.  

Beta diversity entails comparing one small and homogeneous community with another in the same general area. It is the number of species unique to each community in the pair of communities being compared. The greater the beta diversity between the pair of communities in comparison with the alpha diversity of each community, the greater the distinctiveness of the two communities.  

Gamma diversity is kind of like alpha diversity, only at a larger geographical scale. It is the total species richness of all the patches or communities within a larger area, say, 1,000 hectares or 2,500 acres up to maybe 1,000,000 hectares or 2,500,000 acres.

World environment day is observed on  5^th June.

Blue body syndrome is due to Methaemoglobin.

Cardiovascular fitness—also known as cardiorespiratory fitness, is the ability of the heart, lungs, and vascular system to deliver oxygen-rich blood to working muscles during sustained physical activity. Muscular strength—the amount of force a muscle or muscle group can exert against a resistance.

People engaged in quinary activities is termed as Golden Collar worker. 

(b) decrease the largest reserve of fresh water on Earth. 

(c) chicken and hog farms 

Correct option is B. Male 16, Female 32

Correct option is D. (ii) and (iv)

The correct answer is CV Raman.

• The Nobel Prize in Physics 1930 was awarded to Sir Chandrasekhara Venkata Raman "for his work on the scattering of light and for the discovery of the effect named after him."
  • Chandrasekhara Venkata Raman was an Indian physicist known mainly for his work in the field of light scattering.
  • With his student K. S. Krishnan, he discovered that when light traverses a transparent material, some of the deflected light changes wavelength and amplitude.
  • He was the first Asian person to receive a Nobel Prize in any branch of science.

• Meghnad Saha was an Indian astrophysicist who developed the Saha ionization equation, used to describe chemical and physical conditions in stars.
  • His work allowed astronomers to accurately relate the spectral classes of stars to their actual temperatures.
  • He was elected to the Parliament of India in 1952.
• Satyendra Nath Bose was an Indian mathematician and physicist specialising in theoretical physics.
  • He is best known for his work on quantum mechanics in the early 1920s, collaboration with Albert Einstein in developing the foundation for Bose-Einstein statistics and the theory of the Bose-Einstein condensate.
• Birbal Sahni was an Indian paleobotanist who studied the fossils of the Indian subcontinent.
  • He also took an interest in geology and archaeology.
  • He founded what is now the Birbal Sahni Institute of Palaeobotany at Lucknow in 1946.

Calculation:

a/3 = b/4 = c/7 = k (let)

⇒ a = 3k, b = 4k, c = 7k

⇒ (a + b + c)/c = (3k + 4k + 7k)/7k = 2

∴ The required answer is 2.

Given:

⇒ One pipe's 1 hours work = 1/1.8

⇒ Second pipe's 1 hours work = 1/3

⇒ Third pipe's 1 hours work = 1/x

Calculation:

⇒ All three pipes opened simultaneously = 1/1.8 + 1/3 - 1/x

⇒ 1/2.25 = 1/1.8 + 1/3 - 1/x

⇒ 1/x = 1/2.25

Third pipe can empty tank in 2.25 hours.

∴ The value of x is 2.25

Given:

Ratio of present age of father and son = 5 : 2

Ratio of their age before 4 years = 3 : 1

Calculation:

Let the present age of father and son be 5x and 2x respectively

Age of father 4 years ago = 5x – 4

Age of son 4 years ago = 2x – 4

Now, according to question

(5x – 4)/(2x – 4) = 3 : 1

⇒ 5x – 4 = 6x – 12

⇒ x = 8

Age of father after 6 years = 5x + 6

⇒ (5 × 8 + 6) years

⇒ 46 years

Age of son after 6 years = 2x + 6

⇒ (2 × 8 + 6) years

⇒ 22 years

Required ratio = 46 years : 22 years

⇒ 23 : 11

∴ The ratio of their ages after 6 years is 23 : 11

Given:

Two years ago, the ratio between the age of Ram and Sham is 4 : 9. After 5 years, the ratio will be 3 : 5

Calculation:

Let present age of Ram and Sham be a years and b years respectively.

⇒ (a - 2) : (b - 2) = 4 : 9

⇒ 9a - 18 = 4b - 8

⇒ 9a - 4b = 10

Then,

⇒ (a + 5) : (b + 5) = 3 : 5

⇒ 5a + 25 = 3b + 15

⇒ 3b - 5a = 10

After solving, we get

a = 10 years and b = 20 years

Total age of Ram and Sham = 10 + 20 = 30 years

Required average = 30/2 = 15 years

∴ The average age of Ram and Sham is 15 years.

Nepenthes grow in nitrogen-deficient soils so these trap, digest and absorb amino acids from the insects supplementing their nitrogen supply

This is an interesting problem of biological evolution. The most accepted hypothesis asserts that the more simple cell, the prokaryotic cell, appeared earlier in evolution than the more complex eukaryotic cell. The endosymbiotic hypothesis, for example, affirms that aerobic eukaryotic cells appeared from the mutualist ecological interaction between aerobic prokaryotes and primitive anaerobic eukaryotes.

The nuclear membrane is also called karyotheca. The nuclear membrane is continuous to the endoplasmic reticulum membrane.

If the data either in statement I alone or in statement II alone is sufficient to answer the question.

Calculation:

Let the ages of A and B be 2x and 5x respectively.

From statement I

Ages of A and B after 10 years will be (2x + 10) years and (5x + 10) years respectively.

Then, (2x + 10)/(5x + 10) = 4/7

⇒ 14x + 70 = 20x + 40

⇒ 20x – 14x = 70 – 40

⇒ 6x = 30

⇒ x = 5

A’s present age = 2 × 5

⇒ 10 years

B’s present age = 5 × 5

⇒ 25 years

So, the statement I alone is sufficient to answer the question.

From statement II

Ages of A and B 4 years ago were (2x – 4) years and (5x – 4) years respectively.

Then, (2x – 4)/(5x – 4) = 2/7

⇒ 14x – 28 = 10x – 8

⇒ 14x – 10x = 28 – 8

⇒ 4x = 20

⇒ x = 5

A’s present age = 2 × 5

⇒ 10 years

B’s present age = 5 × 5

⇒ 25 years

So, the statement II alone is sufficient to answer the question.

∴ Either statement I alone or statement II alone is sufficient to answer the question.

Calculation:

Let the salary of Mohit and Rohit be Rs. 3x and Rs. 4x respectively.

From statement I

Saving of Mohit is not given. We cannot determine the ratio of saving of Mohit and Rohit.

So, the Statement I alone is not sufficient to answer the question.

From statement II

Saving of Rohit is not given. We cannot determine the ratio of saving of Mohit and Rohit.

So, the statement II alone is not sufficient to answer the question

From statement III

Saving of Rohit and Mohit is not given. We cannot determine the ratio of saving of Mohit and Rohit.

So, the statement III alone is not sufficient to answer the question.

From statement I, statement II and statement III together

Let the expenditure of Mahit and Rohit be Rs 5y and 6y respectively.

Then, 4x – 6y = 4x × (20/100)

⇒ 4x – 6y = 4x/5

⇒ 20x – 30y = 4x

⇒ 20x – 4x = 30y

⇒ 16x = 30y

⇒ y = 8x/15

Saving of Mohit = 3x – 5(8x/15) = 2000

⇒ 3x – (40x/15) = 2000

⇒ 45x – 40x = 30000

⇒ 5x = 30000

⇒ x = 6000

Salary of Mohit = 3 × 6000

⇒ 18000

Salary of Rohit = 4 × 6000

⇒ 24000

Saving of Mohit = 2000

Saving of Rohit = 24000 × (20/100)

⇒ 4800

Sum of saving of Mohit and Rohit = 2000 + 4800

⇒ 6800

So, statement I, statement II and statement III together are sufficient to answer the question.

∴ Statement I, II, and III together are sufficient to answer the question.

Given:

I was 8 years and my brother’s age was half of my age.

Calculation

I was 8 years and my brother’s age half of my age.

My brother’s age = 8/2 = 4

The Age gap of my and my brothers = 8 – 4 = 4

Then my age = 80

My brothers age = 80 - 4 = 76 years

∴ When my age is 80 years at that time My brother’s age is 76 years 

Given:

Three numbers are 25% and 125% and 250%

Formula used

Ratio = first numbers: second numbers: third numbers

Calculation

Let the fourth number be X

And first three number a, b, and c

Then according to question,

a = 1.25X, b = 2.25X and c = 3.50X

a ∶ b ∶ c = 1.25X ∶ 2.25X ∶ 3.50X

a ∶ b ∶ c = 5 ∶ 9 ∶ 14

∴ a ∶ b ∶ c is 5 ∶ 9 ∶ 14

(B) intensity of incident radiation

(C) higher orbit to the second orbit

Answer is:

 (A) \(\frac{S}{S+G}\)

(B) 4.5mV

e = vlb

= 54 x \(\frac{5}{18}\) x 1 x 3 x 10^-4 

= 45 x 10^-4 = 4.5mV

Let us assume contrary that (5 – √3) is a rational number. 

∴ 5 – √3 = \(\frac{p}{q}\), 

q ≠ 0 & p, q ∈ I 

(Because every rational number can be written in \(\frac{p}{q}\) form where q ≠0 & p, q ∈ I )

⇒ 5 − \(\frac{p}{q}\) = √3.

⇒ \(\frac{5q-p}{q}\) = √3 … (1)

L.H.S = \(\frac{5q-p}{q}\), 

(q ≠ 0 & , 5q − p ∈ I) is a rational number.

(Because, every number which can be written in \(\frac{p}{q}\) form is a rational number)

R.H.S = √3 is an irrational number. 

(∵\(\sqrt{prime \,number}\) is always a irrational number) 

But rational ≠ irrational which is contradiction of equation (1). 

Hence, 

Our assumption is wrong. 

∴ (5 – √3) is an irrational number.

Correct option is: C. two

Correct option is: B. 20 m³/h

B. Both (A) and (R) are true but (R) is not the correct explanation of the (A).

Correct option is: C. 18

Let the number be x and y. Then, 

x – y = 11 ----(i) and 1/5 (x + y) = 9 => x + y = 45 ----(ii) 

Adding (i) and (ii), we get: 

2x = 56 or x = 28. 

Putting x = 28 in (i), we get: 

y = 17. 

Hence, the numbers are 28 and 17.

Let the numbers be x and (184 - x). 

Then, (X/3) - ((184 – x)/7) = 8 

=> 7x – 3(184 – x) = 168 

=> 10x = 720 

=> x = 72. 

So, the numbers are 72 and 112. 

Hence, smaller number = 72.

Answer :
3(x – 1) ≤ 2(x – 3)
⇒ 3x – 3 ≤ 2x – 6
⇒ 3x – 3 + 3 ≤ 2x – 6 + 3
⇒ 3x ≤ 2x – 3
⇒ 3x – 2x ≤ 2x – 3 – 2x
⇒ x ≤ – 3
Thus, all real numbers x, which are less than or equal to –3, are the solutions of the given inequality.
Hence, the solution set of the given inequality is (–∞, –3].

Let Rajeev's present age be x years. 

Then, Rajeev's age after 15 years = (x + 15) years. 

Rajeev's age 5 years back = (x - 5) years. 

∴ x + 15 = 5 (x - 5)

x + 15 = 5x - 25 

4x = 40 

x = 10. 

Hence, Rajeev's present age = 10 years.

A light-year is a unit of distance. It is the distance that light can travel in one year. 

Light moves at a velocity of about 300,000 kilometers (km) each second. So in one year, it can travel about 10 trillion km. More precisely, one light-year is equal to 9,500,000,000,000 kilometers.

Conservation of Charge is the principle that the total electric charge in an isolated system never changes. The net quantity of electric charge, the amount of positive charge minus the amount of negative charge in the universe, is always conserved.