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The sum of two numbers is 184. If one-third of the one exceeds one-seventh of the other by 8, find the smaller number. |
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Answer» Let the numbers be x and (184 - x). Then, (X/3) - ((184 – x)/7) = 8 => 7x – 3(184 – x) = 168 => 10x = 720 => x = 72. So, the numbers are 72 and 112. Hence, smaller number = 72. |
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