This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 8951. |
Who penned the famous patriotic song ‘Sore Jahan Se Accha, Hindustan Hamara’? (A) Prem Chand(B) Altaf Hussain Hali (C) Muhammad Iqbal |
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Answer» Correct option is (C) Muhammad Iqbal |
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| 8952. |
Which is essential condition for the occurrence of dust storms in Rajasthan?1. High annual range of temperature2. High atmospheric pressure during winter season3. Convective Activity4. Low pressure conditions over Tibetan Plateau |
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Answer» Correct Answer - Option 3 : Convective Activity The correct answer is Convective Activity.
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| 8953. |
The circular hill of Ramgarh is situated in which of the following regions?1. Shekhawati Region2. Hadoti Plateau3. Chappen Plains4. Ghaggar Plains |
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Answer» Correct Answer - Option 2 : Hadoti Plateau The correct answer is Hadoti Plateau.
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| 8954. |
The basic difference between the Indian President and the British Monarch is(a) A British Monarch can be questioned by the House of Lords, whereas the Indian President is not answerable to any court(b) The British Monarch IS forbidden from foreign travel whereas the Parliament is in session no such restriction ever applies to the Indian President(c) There is no age bar to the Indian President for holding the office whereas the British Monarch .automatically steps down on his attaining the age of 75 installing the Crown Prince as Monarch(d) The Indian President is elected every five years whereas the British Crown is hereditary and not elective. Whereas |
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Answer» (d) The Indian President is elected every five years whereas the British Crown is hereditary and not elective. Whereas |
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| 8955. |
The Chief Minister of the National Capital Territory of Delhi shall be appointed/elected by the(a) President (b) Lieutenant Governor (c) Delhi Assembly (d) Chief Administrator |
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Answer» The Chief Minister of the National Capital Territory of Delhi shall be appointed/elected by the President |
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| 8956. |
The highest position in the country an IAS officer can aspire for is(a) Governor RBI(b) Cabinet Secretary(c) Home Secretary(d) Foreign Secretary |
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Answer» (b) Cabinet Secretary |
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| 8957. |
He is a very ______ player. He practices for two hours every morning. A) amateur B) anxious C) excitedD) impatient E) keen |
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Answer» Correct option is E) keen |
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| 8958. |
Who amongst the following appoints the Chairperson of the National Human Rights Commission, India?(a) The President of India(b) The Prime Minister of India(c) The Chief Justice of India(d) The Lok Sabha(e) None of these |
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Answer» (a) The President of India |
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| 8959. |
As per the news which appeared in some newspapers/magazines, the police with the help of some NGOs rescued some children who had been forced in child labour illegally. Such children are protected under which of the following acts in India?(A) Juvenile Justice Act(B) Child Labour Act(C) Immoral Trafficking Act(a) Only (A)(b) Only (B)(c) Only (C)(d) All (A), (B) and (C)(e) None of these |
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Answer» (b) Only (B) Child Labour Act |
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| 8960. |
Getting through a day without being touched by the press would be difficult. We have daily morning and evening newspapers and weekly news magazines. _____ What we eat, what we buy, what we do, what we think is influenced by the press. A) The power of the press upon us is really enormous. B) One should not start the day without reading a newspaper. C) Newspaper sales are less than magazine sales. D) The effect of the press on the public is not so important as some people like to suggest. E) The number of newspaper readers is decreasing day by day. |
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Answer» Correct option is A) The power of the press upon us is really enormous |
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| 8961. |
Thieves _____ two pictures from the museum last night. A) have stolen B) stole C) was stolen D) had stolen |
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Answer» Correct option is B) stole B) Stole
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| 8962. |
It’s time we _____ working. A) start B) will start C) started D) had started |
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Answer» Correct option is C) started |
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| 8963. |
Stable nuclei generally: A. have a greater number of protons than neutrons B. have low mass numbers C. have high mass numbers D. are beta emitters E. none of the above |
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Answer» E. none of the above |
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| 8964. |
They discovered that the files ____ stolen while they were the other room. A) is B) will be C) had been D) was been |
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Answer» Correct option is C) had been |
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| 8965. |
Now that I’ve bought a car, I _____ take the bus to work. A) needn’t B) must C) mustn’t D) hadn’t |
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Answer» Correct option is A) needn’t |
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| 8966. |
Robert reads sports magazines. He wants ______ them now. A) reads B) is reading C) read D) to read |
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Answer» Correct option is D) to read |
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| 8967. |
The boy told his teacher a lie to avoid ____. A) be punished B) to be punished C) being punished D) punishing |
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Answer» Correct option is C) being punished |
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| 8968. |
I asked you to get some white cheese! You ____ bought this! A) shouldn’t have B) hadn’t to have C) mustn’t have D) wouldn’t have |
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Answer» Correct option is A) shouldn’t have |
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| 8969. |
It is not necessary for him _____ every page. A) reading B) read C) to read D) reads |
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Answer» Correct option is C) to read |
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| 8970. |
I _____ a book about astrology these days. A) am reading B) read C) am reads D) reading |
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Answer» Correct option is A) am reading |
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| 8971. |
here is nothing _____. A) to do B) doing C) did D) do |
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Answer» Correct option is A) to do |
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| 8972. |
I’m fond of ___ in the river. A) have swum B) swam C) swim D) swimming E) having swum |
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Answer» Correct option is D) swimming |
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| 8973. |
I always enjoyed ____ in that lake in summer. A) to have swum B) been swimming C) to swimming D) swimming |
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Answer» Correct option is D) swimming |
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| 8974. |
Have you got anything _____? A) reading B) to read C) read D) reads |
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Answer» Correct option is B) to read |
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| 8975. |
She is good at _____. A) to swim B) swimming C) swims D) swum |
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Answer» Correct option is B) swimming |
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| 8976. |
`A` and `B` are two fixed spots in a river in which water has a steady sped `v_(w)`. A person who can swim with a speed `v` relative to water swims from `A` to `B` and back to `A` alomg shortest path. If the water is still, the person will take a time `30` minute in swimming from `A` to `B` and back to `A` along the shortes path. But we know that water is acually not still. The person also knows the technique of just flowing with water without exerting his own effort. Using this technique, i.e., just being carried with water, he takes a time `20` minute in moving from `A` to `B`. As shown, `X` and `Y` are two places directly oppsite to each other on oppsite banks. Assuming that width of the river is the same as the distance `A` and `B`, answer these questions. (assume `v gt v_(w)`) Choose the correct option(s) :A. Time taken by the person to swim from `B` to `A` (in running water) is `60` minB. Time taken by the person to swim from `B` to `A` (in running water) is `45` minC. Time taken by the person to swim from `B` to `A` (in running water) is `(60)/(7)` minD. Time taken by the person to swim from `B` to `A` (in running water) is `10` min |
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Answer» Correct Answer - A::C Let `L =` distance `A` and `B` which is also equal to that between `X` and `Y` From `A` and `B` back to `A` `2L = V 30` `V = L/15`, When river flowing then from A to B `V_(W) = (L)/(20)` Time from `B` to `A = (L)/(V - V_(W)) = (L)/((L)/(15) - (L)/(20)) = 60` min. |
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| 8977. |
A certain simple harmonic vibrator of mass 0.1 kg has a total energy of 101. its displacement from the man position is 1 cm when it has equal kinetic and potential energies. the amplitude and frequency of vibration of the vibrator are. |
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Answer» For any SHM KE when particle is at X from mean position = 1/2 mw2(A2 -x2) and Potential energy = 1/2 mw2x2 KE=PE when X= A/√2 =0.707 A A= amplitude At X=1 cm KE and PE are equal mean A= X.√2= 1.414 cm Total energy E=1/2mw2A2 W2= 2E/(mA2)=2×101/0.1x0.01m) W2= 202000 W= 449.3 /s w W w |
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| 8978. |
A small square loop of wire of side l is placed inside a large square loop of wire of side `L(Lgtgtl)`. The loops are co-planer and their centres coincide. The mutual inductance of the system is proportional toA. `(l)/(L)`B. `(l^(2))/(L)`C. `(L)/(l)`D. `(L^(2))/(l)` |
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Answer» Correct Answer - B The magnetic flux that links the larger loop with the smaller loop of side `l(lltltL)` is `f_(12)=Bl^(2)=(2sqrt(2)mu_(0)Il^(2))/(piL)` `therefore` Mutual inductance `M_(12)=(phi_(12))/(I)=(2sqrt(2)mu_(0))/(pi)((l^(2))/(L))` `i.eM_(12)prop(l^(2))/(L)` `therefore (b)` |
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| 8979. |
In the given (Fig.) all the symbols have their usual meanings. At `t = 0`, key `K` is closed. Now answer the following questions. At `t rarr oo`, the equivalent resistance between `A` and `B` isA. `R_(1)+R_(2)+R_(3)`B. `R_(1)+R_(2)`C. `R_(1)+R_(3)`D. indeterminate |
| Answer» At `t=0`, capacitor will behave like a short circuit and the inductor as open circuit but as `t to oo`, the nature is just opposite. | |
| 8980. |
In the given (Fig.) all the symbols have their usual meanings. At `t = 0`, key `K` is closed. Now answer the following questions. At `t = 0`, the equivalent resistance between `A` and `B` is A. `R_(1)+R_(2)+R_(3)`B. `R_(1)+R_(2)`C. `R_(1)+R_(3)`D. indeterminate |
| Answer» At `t=0`, capacitor will behave like a short circuit and the inductor as open circuit but as `t to oo`, the nature is just opposite. | |
| 8981. |
Consider the following reaction `x MnO_(4)^(-) + C_(2)O_(4)^(2-) + zH^(+) rarr x Mn^(2+) + 2y CO_(2) + (z)/(2)H_(2)O` The value of x, y and z in the reaction are respectivelyA. 2,5 and 16B. 5, 2 and 8C. 5,2 and 16D. 2,5 and 8 |
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Answer» Correct Answer - A `2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to2Mn^(2+)+10CO_(2)+8H_(2)O` |
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| 8982. |
For the reaction `2NO_(2)rarrN_(2)O_(3)+O_(2)`, rate expression is as follows `:` `-(d[NO_(2)])/(dt)=K[NO_(2)]^(n)`, where `K=3xx10^(-3)mol^(-1)L sec^(-1)` If rate of formation of oxygen is `1.5xx10^(-4)mol L^(-1)sec^(-1)` then the molar concentration of `NO_(2)`in mole `L^(-1)` is `:`A. `1.5xx10^(-4)`B. `0.0151`C. `0.214`D. `0.316` |
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Answer» Correct Answer - 4 From the unit of k, it is evident that it is second order reaction. `-(1)/(2)=(d[NO_(2)])/(dt)=(d[O_(2)])/(dt)` `:." "-(d[NO_(2)])/(dt)=2xx(d[O_(2)])/(dt)=2xx1.5xx10^(-4)=3xx10^(-4)` `3xx10^(-4)=K[NO_(2)]^(2)=3xx10^(-3)[NO_(2)]^(2)` `:. " "[NO_(2)]=0.316` |
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| 8983. |
Which of the following compounds is NOT prepared by the action of alcoholic NH3 on alkyl halide? (A) CH3 - NH2 (B) CH3 – CH2 – NH2 (C) CH3 – CH2 – CH2 – NH2 (D) (CH3)3C – NH2 |
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Answer» (D) (CH3)3C – NH2 Tertiary alkyl halides on treatment with alcoholic base undergo elimination in preference to substitution. |
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| 8984. |
The products obtained when benzyl phenyl ether is heated with HI in the mole rate `1:1` are. (1) Phenol. (2) benzyl alcohol, (3) benzyl,iodide, (4)IodobenzeneA. 1and 3onlyB. 3 and 4 onlyC. 1 and 4 only 2and 4 onlyD. |
| Answer» Correct Answer - A | |
| 8985. |
Metal (M) crystallizes in a cubic unit cell with density 3.2 g/cc. Edge-length of the unit cell is `4.37Å` picometre (pm) The number of nearest neighbours of a Ca atom areA. 4B. 6C. 8D. 12 |
| Answer» Correct Answer - D | |
| 8986. |
`FeO` crystal has a simple cubic structure and each edge of the unit cell is `5 A^(@)`. Taking density of crystal as `5gm//"cc"` the number of `Fe^(2+)` and `O^(2-)` ions present in each unit cell are:A. `4Fe^(2+)` and `4O^(2-)`B. `6Fe^(2+)` and `6O^(2-)`C. `2Fe^(2+)` and `2O^(2-)`D. `1Fe^(2+)` and `1O^(2-)` |
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Answer» Correct Answer - A Volume of unit cell `=1.25xx10^(-22)"cc"` Mass of unit cell `=1.25xx10^(-22)xx4` `=5xx10^(-22)` gm For one molecle `=72/(6.022xx10^(23))=1.195xx10^(-22)g` Hence number of `FeO` molecules per unit cell `=(5xx10^(-22))/(1.195xx10^(-22))=4.19~~4` Hence there are `4Fe^(2+)` and `4O^(2-)` in each unit cell. |
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| 8987. |
`K_("sp")` of `PbBr_(2)` (Molar mass `=367`) is `3.2xx10^(-5)`. If the salt is `80%` dissociated in solution, caculate the solubility of salt in `g` per `litre`. |
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Answer» Correct Answer - `00009.175` `00009.175` Let solubility of `PbBr_(2)` is `S` mol `"litre"^(-1)` `PbBr_(2)(s)+"Aq" hArr PbBr_(2)("aq")hArr underset ((Sxx80)/100)(Pb^(2))+underset((2Sxx80)/100)(2Br^(-)` Since, `PbBr_(2)` ionises to `80%` only. Now `K_("sp")=[Pb^(2+)][Br^(-)]^(2)` or `3.2xx10^(-5)=[(Sxx80)/100][(2Sxx80)/100]^(2)` `S=0.025 "mol litre"^(-1)` `=0.025xx367g "litre"^(-1)` `=19.175g "litre"^(-1)` |
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| 8988. |
A 100 ml mixture of CO and `CO_2` is passed through a tube containing red hot charcoal. The volume becomes 160 ml.The volumes are measured under the same conditions of temperature and pressure Amongst the following , select the correct statement(s).A. Mole percent of `CO_2` in the mixture is 60B. Mole fraction of CO in the mixture is 0.40C. The mixture contains 40 ml of `CO_2`D. The mixture contains 40 ml of CO |
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Answer» Correct Answer - A,B,D When mixture is passed through hot graphite the following reaction will occur. `underset(x ml)(CO_(2))(g)+C(s)tounderset("2x mi will formed")(2CO(g))` `:.` Total volume of mixture =160 100-x+2x=160 volume of CO=100-x=40 ml |
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| 8989. |
functional isomer of an ether |
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Answer» functinal isomer of ether will be alcohol |
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| 8990. |
A crystalline salt on being rendered anhydrous loses 45.6% of its weight. The composition of anhydrous salt is: Al= 10.5%, K= 15.1 % , S=24.8 % and 0=49.6% Calculate the formula of anhydrous salt and crystalline salt. |
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Answer»
Therefore, The simples formula of anhydrous = KAlS2O8 molecular weight for anhydrous = 258 g/mole. Let say molecular weight of crystalline = x g/mol. ∴ \(\frac{(x-258)}x\times100=45.6\) ⇒ (x - 258) = 0.456 x ⇒ 0.544 x = 258 x = 474.26 f/mol ∴ Number of water molecular in crystalline = \(\frac{474.26-258}{12}=12\) Thus, crystalline contains 12 molecule of water. Therefore, The formula of crystalline will be KAlS2O8.12H2O Or KAlH24S2O20 Hence, The formula of crystalline and anhydrous will be KAlS2O8.12H2O and KAlS2O8 respectively. |
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| 8991. |
500 ml of a gaseous hydrocarbon when burnt in excess of `O_(2)` gave 2.0litres of `CO_(2)` and 2.5 litres of water vapours under same conditions. molecular formula of the hydrocarbon is:-A. `C_(4)H_(8)`B. `C_(4)H_(10)`C. `C_(5)H_(10)`D. `C_(5)H_(12)` |
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Answer» Correct Answer - B `{:(C_(x)H_(y)+(x+(y)/(4))O_(2),to,xCO_(2)+,(y)/(2)H_(2)O,),(1mL,,2mL,(y)/(2)mL,),(500mL,,500mL,250ymL,),("Hence,and",,,,),(500x=2000,,250y,=2500mL,),(x=4,,y=10mL,,),(":. formula = C_(4)H_(10),,,,):}` |
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| 8992. |
Q how many moles of electrons are exchanged during the formation of 3 moles of MgO a)3 b)5 c)6 d)10Pls explain the answer to me |
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Answer» Correct option is (C) 6 moles. Explanation : During the for formation of MgO each Mg loses 2 electrons to form Mg2+ and oxygen gains those 2 electrons to form oxide ion O2- . Hence in 1 mole of MgO, there is an exhange of 2 moles of electrons. Therefore in 3 mole of MgO , there will an exchange of 3x2 = 6 moles of electrons. |
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| 8993. |
A 0.02 M solution of pyridinium hydrochloride has pH = 3.44. Calculate the ionization constant of pyridine. |
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Answer» Pyridinium hydrochloride is a salt of a weak base (pyridine) and a strong acid (HCl). The pH of an aqueous solution of this salt is given by the relation: pH = \(\frac{1}{2}\) [pKw - pKb - logC] 3.44 = \(\frac{1}{2}\) [14+logkb - log (0.02)] 6.88 = 14 + log Kb + 1.7 log Kb = -8.82 ∴Kb = antilog(-8.82) = 1.514 x 10-9 |
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| 8994. |
1°, 2° and 3° alcohols are distinguished by(a) Oxidation method(b) Lucos test(c) Victor Mayer test(d) All |
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Answer» (d) All of these |
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| 8995. |
Vitamin ‘C’ is–(a) Maleic acid(b) Ascorbic acid(c) Paracetamo(d) Lactic acid |
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Answer» Vitamin ‘C’ is Ascorbic acid. |
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| 8996. |
Vitamine C is–(i) Citric acid(b) Lactic acid(c) Ascorbic acid(d) Paracitamol |
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Answer» Vitamine C is Ascorbic acid |
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| 8997. |
Vitamine A is called- (a) Ascorbic acid(b) Retinol(c) Calciferol(d) Tocopherol |
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Answer» Vitamine A is called Retinol |
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| 8998. |
Oxygen atom in ether is- (a) Very active(b) Replaceable (c) Active (d) Comparatively inert |
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Answer» Oxygen atom in ether is Replaceable |
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| 8999. |
Which of the following is a disaccharide- (a) Lactose (b) Starch (c) Cellulose (d) Fructose |
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Answer» Lactose is a disaccharide. |
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| 9000. |
Rhizome of ginger is like the roots of other plants that grows underground. Despite this fact ginger is a stem and not a root. Justify. |
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Answer» Because it possess nodes and internodes, buds, scale leaf, and adventitious roots. Hence these are stem characters. |
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