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8951.

Who penned the famous patriotic song ‘Sore Jahan Se Accha, Hindustan Hamara’? (A) Prem Chand(B) Altaf Hussain Hali (C) Muhammad Iqbal

Answer»

Correct option is (C) Muhammad Iqbal

8952.

Which is essential condition for the occurrence of dust storms in Rajasthan?1. High annual range of temperature2. High atmospheric pressure during winter season3. Convective Activity4. Low pressure conditions over Tibetan Plateau

Answer» Correct Answer - Option 3 : Convective Activity

The correct answer is Convective Activity.

  • Convective Activity in Rajasthan and the presence of western disturbance that led to the atmosphere becomes unstable.
  • This creates the essential condition for the occurrence of dust storms in Rajasthan.

 

  • In the context of climate change, we can say that in north India the temperature is increasing more compared to south India.
    • An increase in temperature means an increase in heating which means there will be more heatwave days and major reasons for the occurrence of dust storms and thunderstorms.
    • If the temperature increases then conditions become more favourable for the occurrence of dust storms.
8953.

The circular hill of Ramgarh is situated in which of the following regions?1. Shekhawati Region2. Hadoti Plateau3. Chappen Plains4. Ghaggar Plains

Answer» Correct Answer - Option 2 : Hadoti Plateau

The correct answer is Hadoti Plateau.

  • Circular hill of Ramgarh is situated in Baran, Rajasthan (Hadoti Plateau).

 

  • Ramgarh Crater in Baran, Rajasthan:
    • Ramgarh Circular hill is also known as Ramgarh crater, Ramgarh structure, Ramgarh Dome and Ramgarh astrobleme, etc.
    • Ramgarh Crater is also known as Ramgarh structure, Ramgarh Dome and Ramgarh astrobleme.
    • It is located in Ramgarh village in Mangrol Tehsil of Baran district in Rajasthan, India.
    • Rajasthan’s only terrestrial Meteorite Impact Crater (MIC) located at Ramgarh, in Baran district has been recently recognized by the Meteoritical Society, the US-based world body for meteorites.
8954.

The basic difference between the Indian President and the British Monarch is(a) A British Monarch can be questioned by the House of Lords, whereas the Indian President is not answerable to any court(b) The British Monarch IS forbidden from foreign travel whereas the Parliament is in session no such restriction ever applies to the Indian President(c) There is no age bar to the Indian President for holding the office whereas the British Monarch .automatically steps down on his attaining the age of 75 installing the Crown Prince as Monarch(d) The Indian President is elected every five years whereas the British Crown is hereditary and not elective. Whereas

Answer»

(d) The Indian President is elected every five years whereas the British Crown is hereditary and not elective. Whereas

8955.

The Chief Minister of the National Capital Territory of Delhi shall be appointed/elected by the(a) President (b) Lieutenant Governor (c) Delhi Assembly (d) Chief Administrator 

Answer»

The Chief Minister of the National Capital Territory of Delhi shall be appointed/elected by the  President

8956.

The highest position in the country an IAS officer can aspire for is(a) Governor RBI(b) Cabinet Secretary(c) Home Secretary(d) Foreign Secretary

Answer»

(b) Cabinet Secretary

8957.

He is a very ______ player. He practices for two hours every morning. A) amateur B) anxious C) excitedD) impatient E) keen

Answer»

Correct option is E) keen

8958.

Who amongst the following appoints the Chairperson of the National Human Rights Commission, India?(a) The President of India(b) The Prime Minister of India(c) The Chief Justice of India(d) The Lok Sabha(e) None of these

Answer»

(a) The President of India

8959.

As per the news which appeared in some newspapers/magazines, the police with the help of some NGOs rescued some children who had been forced in child labour illegally. Such children are protected under which of the following acts in India?(A) Juvenile Justice Act(B) Child Labour Act(C) Immoral Trafficking Act(a) Only (A)(b) Only (B)(c) Only (C)(d) All (A), (B) and (C)(e) None of these

Answer»

(b) Only (B) Child Labour Act

8960.

Getting through a day without being touched by the press would be difficult. We have daily morning and evening newspapers and weekly news magazines. _____ What we eat, what we buy, what we do, what we think is influenced by the press. A) The power of the press upon us is really enormous. B) One should not start the day without reading a newspaper. C) Newspaper sales are less than magazine sales. D) The effect of the press on the public is not so important as some people like to suggest. E) The number of newspaper readers is decreasing day by day.

Answer»

Correct option is A) The power of the press upon us is really enormous

8961.

Thieves _____ two pictures from the museum last night. A) have stolen B) stole C) was stolen D) had stolen

Answer»

Correct option is B) stole

B) Stole 
8962.

It’s time we _____ working. A) start B) will start C) started D) had started

Answer»

Correct option is C) started

8963.

Stable nuclei generally: A. have a greater number of protons than neutrons B. have low mass numbers C. have high mass numbers D. are beta emitters E. none of the above

Answer»

E. none of the above 

8964.

They discovered that the files ____ stolen while they were the other room. A) is B) will be C) had been D) was been

Answer»

Correct option is C) had been

8965.

Now that I’ve bought a car, I _____ take the bus to work. A) needn’t B) must C) mustn’t D) hadn’t

Answer»

Correct option is A) needn’t

8966.

Robert reads sports magazines. He wants ______ them now. A) reads B) is reading C) read D) to read

Answer»

Correct option is D) to read

8967.

The boy told his teacher a lie to avoid ____. A) be punished B) to be punished C) being punished D) punishing

Answer»

Correct option is C) being punished

8968.

I asked you to get some white cheese! You ____ bought this! A) shouldn’t have B) hadn’t to have C) mustn’t have D) wouldn’t have

Answer»

Correct option is A) shouldn’t have

8969.

It is not necessary for him _____ every page. A) reading B) read C) to read D) reads

Answer»

Correct option is C) to read

8970.

I _____ a book about astrology these days. A) am reading B) read C) am reads D) reading

Answer»

Correct option is A) am reading

8971.

here is nothing _____. A) to do B) doing C) did D) do

Answer»

Correct option is A) to do

8972.

I’m fond of ___ in the river. A) have swum B) swam C) swim D) swimming E) having swum

Answer»

Correct option is D) swimming

8973.

I always enjoyed ____ in that lake in summer. A) to have swum B) been swimming C) to swimming D) swimming

Answer»

Correct option is D) swimming

8974.

Have you got anything _____? A) reading B) to read C) read D) reads

Answer»

Correct option is B) to read

8975.

She is good at _____. A) to swim B) swimming C) swims D) swum

Answer»

Correct option is B) swimming

8976.

`A` and `B` are two fixed spots in a river in which water has a steady sped `v_(w)`. A person who can swim with a speed `v` relative to water swims from `A` to `B` and back to `A` alomg shortest path. If the water is still, the person will take a time `30` minute in swimming from `A` to `B` and back to `A` along the shortes path. But we know that water is acually not still. The person also knows the technique of just flowing with water without exerting his own effort. Using this technique, i.e., just being carried with water, he takes a time `20` minute in moving from `A` to `B`. As shown, `X` and `Y` are two places directly oppsite to each other on oppsite banks. Assuming that width of the river is the same as the distance `A` and `B`, answer these questions. (assume `v gt v_(w)`) Choose the correct option(s) :A. Time taken by the person to swim from `B` to `A` (in running water) is `60` minB. Time taken by the person to swim from `B` to `A` (in running water) is `45` minC. Time taken by the person to swim from `B` to `A` (in running water) is `(60)/(7)` minD. Time taken by the person to swim from `B` to `A` (in running water) is `10` min

Answer» Correct Answer - A::C
Let `L =` distance `A` and `B` which is also equal to that between `X` and `Y`
From `A` and `B` back to `A`
`2L = V 30`
`V = L/15`, When river flowing then from A to B
`V_(W) = (L)/(20)`
Time from `B` to `A = (L)/(V - V_(W)) = (L)/((L)/(15) - (L)/(20)) = 60` min.
8977.

A certain simple harmonic vibrator of mass 0.1 kg has a total energy of 101. its displacement from the man position is 1 cm when it has equal kinetic and potential energies. the amplitude and frequency of vibration of the vibrator are.

Answer»

For any SHM 

KE when particle is at X from mean position = 1/2 mw2(A-x2) and 

Potential energy = 1/2 mw2x2

KE=PE when  X= A/√2 =0.707 A 

A= amplitude

At X=1 cm KE and PE are equal mean

A= X.√2= 1.414 cm

Total energy E=1/2mw2A2 

W2= 2E/(mA2)=2×101/0.1x0.01m)

W2= 202000

W= 449.3 /s

w

W​​​​

w​​​​​

8978.

A small square loop of wire of side l is placed inside a large square loop of wire of side `L(Lgtgtl)`. The loops are co-planer and their centres coincide. The mutual inductance of the system is proportional toA. `(l)/(L)`B. `(l^(2))/(L)`C. `(L)/(l)`D. `(L^(2))/(l)`

Answer» Correct Answer - B
The magnetic flux that links the larger loop with the smaller loop of side `l(lltltL)` is `f_(12)=Bl^(2)=(2sqrt(2)mu_(0)Il^(2))/(piL)`
`therefore` Mutual inductance `M_(12)=(phi_(12))/(I)=(2sqrt(2)mu_(0))/(pi)((l^(2))/(L))`
`i.eM_(12)prop(l^(2))/(L)`
`therefore (b)`
8979.

In the given (Fig.) all the symbols have their usual meanings. At `t = 0`, key `K` is closed. Now answer the following questions. At `t rarr oo`, the equivalent resistance between `A` and `B` isA. `R_(1)+R_(2)+R_(3)`B. `R_(1)+R_(2)`C. `R_(1)+R_(3)`D. indeterminate

Answer» At `t=0`, capacitor will behave like a short circuit and the inductor as open circuit but as `t to oo`, the nature is just opposite.
8980.

In the given (Fig.) all the symbols have their usual meanings. At `t = 0`, key `K` is closed. Now answer the following questions. At `t = 0`, the equivalent resistance between `A` and `B` is A. `R_(1)+R_(2)+R_(3)`B. `R_(1)+R_(2)`C. `R_(1)+R_(3)`D. indeterminate

Answer» At `t=0`, capacitor will behave like a short circuit and the inductor as open circuit but as `t to oo`, the nature is just opposite.
8981.

Consider the following reaction `x MnO_(4)^(-) + C_(2)O_(4)^(2-) + zH^(+) rarr x Mn^(2+) + 2y CO_(2) + (z)/(2)H_(2)O` The value of x, y and z in the reaction are respectivelyA. 2,5 and 16B. 5, 2 and 8C. 5,2 and 16D. 2,5 and 8

Answer» Correct Answer - A
`2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to2Mn^(2+)+10CO_(2)+8H_(2)O`
8982.

For the reaction `2NO_(2)rarrN_(2)O_(3)+O_(2)`, rate expression is as follows `:` `-(d[NO_(2)])/(dt)=K[NO_(2)]^(n)`, where `K=3xx10^(-3)mol^(-1)L sec^(-1)` If rate of formation of oxygen is `1.5xx10^(-4)mol L^(-1)sec^(-1)` then the molar concentration of `NO_(2)`in mole `L^(-1)` is `:`A. `1.5xx10^(-4)`B. `0.0151`C. `0.214`D. `0.316`

Answer» Correct Answer - 4
From the unit of k, it is evident that it is second order reaction.
`-(1)/(2)=(d[NO_(2)])/(dt)=(d[O_(2)])/(dt)`
`:." "-(d[NO_(2)])/(dt)=2xx(d[O_(2)])/(dt)=2xx1.5xx10^(-4)=3xx10^(-4)`
`3xx10^(-4)=K[NO_(2)]^(2)=3xx10^(-3)[NO_(2)]^(2)`
`:. " "[NO_(2)]=0.316`
8983.

Which of the following compounds is NOT prepared by the action of alcoholic NH3 on alkyl halide? (A) CH3 - NH2 (B) CH3 – CH2 – NH2 (C) CH3 – CH2 – CH2 – NH2 (D) (CH3)3C – NH2

Answer»

(D) (CH3)3C – NH2

Tertiary alkyl halides on treatment with alcoholic base undergo elimination in preference to substitution.

8984.

The products obtained when benzyl phenyl ether is heated with HI in the mole rate `1:1` are. (1) Phenol. (2) benzyl alcohol, (3) benzyl,iodide, (4)IodobenzeneA. 1and 3onlyB. 3 and 4 onlyC. 1 and 4 only 2and 4 onlyD.

Answer» Correct Answer - A
8985.

Metal (M) crystallizes in a cubic unit cell with density 3.2 g/cc. Edge-length of the unit cell is `4.37Å` picometre (pm) The number of nearest neighbours of a Ca atom areA. 4B. 6C. 8D. 12

Answer» Correct Answer - D
8986.

`FeO` crystal has a simple cubic structure and each edge of the unit cell is `5 A^(@)`. Taking density of crystal as `5gm//"cc"` the number of `Fe^(2+)` and `O^(2-)` ions present in each unit cell are:A. `4Fe^(2+)` and `4O^(2-)`B. `6Fe^(2+)` and `6O^(2-)`C. `2Fe^(2+)` and `2O^(2-)`D. `1Fe^(2+)` and `1O^(2-)`

Answer» Correct Answer - A
Volume of unit cell `=1.25xx10^(-22)"cc"`
Mass of unit cell `=1.25xx10^(-22)xx4`
`=5xx10^(-22)` gm
For one molecle `=72/(6.022xx10^(23))=1.195xx10^(-22)g`
Hence number of `FeO` molecules per unit cell `=(5xx10^(-22))/(1.195xx10^(-22))=4.19~~4`
Hence there are `4Fe^(2+)` and `4O^(2-)` in each unit cell.
8987.

`K_("sp")` of `PbBr_(2)` (Molar mass `=367`) is `3.2xx10^(-5)`. If the salt is `80%` dissociated in solution, caculate the solubility of salt in `g` per `litre`.

Answer» Correct Answer - `00009.175`
`00009.175`
Let solubility of `PbBr_(2)` is `S` mol `"litre"^(-1)`
`PbBr_(2)(s)+"Aq" hArr PbBr_(2)("aq")hArr underset ((Sxx80)/100)(Pb^(2))+underset((2Sxx80)/100)(2Br^(-)`
Since, `PbBr_(2)` ionises to `80%` only.
Now `K_("sp")=[Pb^(2+)][Br^(-)]^(2)`
or `3.2xx10^(-5)=[(Sxx80)/100][(2Sxx80)/100]^(2)`
`S=0.025 "mol litre"^(-1)`
`=0.025xx367g "litre"^(-1)`
`=19.175g "litre"^(-1)`
8988.

A 100 ml mixture of CO and `CO_2` is passed through a tube containing red hot charcoal. The volume becomes 160 ml.The volumes are measured under the same conditions of temperature and pressure Amongst the following , select the correct statement(s).A. Mole percent of `CO_2` in the mixture is 60B. Mole fraction of CO in the mixture is 0.40C. The mixture contains 40 ml of `CO_2`D. The mixture contains 40 ml of CO

Answer» Correct Answer - A,B,D
When mixture is passed through hot graphite the following reaction will occur.
`underset(x ml)(CO_(2))(g)+C(s)tounderset("2x mi will formed")(2CO(g))`
`:.` Total volume of mixture =160
100-x+2x=160
volume of CO=100-x=40 ml
8989.

functional isomer of an ether

Answer»
functinal isomer of ether will be alcohol 

8990.

A crystalline salt on being rendered anhydrous loses 45.6% of its weight. The composition of anhydrous salt is: Al= 10.5%, K= 15.1 % , S=24.8 % and 0=49.6% Calculate the formula of anhydrous salt and crystalline salt.

Answer»
ElementPercentage Atomic massrelative numbered molessimple ratio
Al10.52710.5/27 = 0.3891
K15.13915.1/39 = 0.3871
S24.963224.96/32 = 0.782
O49.216\(\frac{49.2}{16}\) = 3.088

Therefore, The simples formula of anhydrous  = KAlS2O8

molecular weight for anhydrous = 258 g/mole.

Let say molecular weight of crystalline = x g/mol.

∴ \(\frac{(x-258)}x\times100=45.6\)

⇒ (x - 258) = 0.456 x

⇒ 0.544 x = 258

x = 474.26 f/mol

∴ Number of water molecular in crystalline = \(\frac{474.26-258}{12}=12\)

Thus, crystalline contains 12 molecule of water.

Therefore, The formula of crystalline will be

KAlS2O8.12H2O

Or KAlH24S2O20

Hence, The formula of crystalline and anhydrous will be KAlS2O8.12H2O and KAlS2O8 respectively.

8991.

500 ml of a gaseous hydrocarbon when burnt in excess of `O_(2)` gave 2.0litres of `CO_(2)` and 2.5 litres of water vapours under same conditions. molecular formula of the hydrocarbon is:-A. `C_(4)H_(8)`B. `C_(4)H_(10)`C. `C_(5)H_(10)`D. `C_(5)H_(12)`

Answer» Correct Answer - B
`{:(C_(x)H_(y)+(x+(y)/(4))O_(2),to,xCO_(2)+,(y)/(2)H_(2)O,),(1mL,,2mL,(y)/(2)mL,),(500mL,,500mL,250ymL,),("Hence,and",,,,),(500x=2000,,250y,=2500mL,),(x=4,,y=10mL,,),(":. formula = C_(4)H_(10),,,,):}`
8992.

Q how many moles of electrons are exchanged during the formation of 3 moles of MgO a)3 b)5 c)6 d)10Pls explain the answer to me

Answer»

Correct option is (C) 6 moles.

Explanation : During the for formation of MgO each Mg loses 2 electrons to form Mg2+ and oxygen gains those 2 electrons to form oxide ion O2- .  Hence in 1 mole of MgO, there is an exhange of 2 moles of electrons.

Therefore in 3 mole of MgO , there will an exchange of 3x2 = 6 moles of electrons.

8993.

A 0.02 M solution of pyridinium hydrochloride has pH = 3.44. Calculate the ionization constant of pyridine.

Answer»

Pyridinium hydrochloride is a salt of a weak base (pyridine) and a strong acid (HCl). The pH of an aqueous solution of this salt is given by the relation:

pH = \(\frac{1}{2}\) [pKw - pKb - logC]

3.44 = \(\frac{1}{2}\) [14+logkb - log (0.02)]

6.88 = 14 + log Kb + 1.7

log Kb = -8.82

∴Kb = antilog(-8.82) = 1.514 x 10-9

8994.

1°, 2° and 3° alcohols are distinguished by(a) Oxidation method(b) Lucos test(c) Victor Mayer test(d) All 

Answer»

(d) All of these

8995.

Vitamin ‘C’ is–(a) Maleic acid(b) Ascorbic acid(c) Paracetamo(d) Lactic acid

Answer»

Vitamin ‘C’ is Ascorbic acid.

8996.

Vitamine C is–(i) Citric acid(b) Lactic acid(c) Ascorbic acid(d) Paracitamol

Answer»

Vitamine C is Ascorbic acid

8997.

Vitamine A is called- (a) Ascorbic acid(b) Retinol(c) Calciferol(d) Tocopherol

Answer»

Vitamine A is called  Retinol

8998.

Oxygen atom in ether is- (a) Very active(b) Replaceable (c) Active (d) Comparatively inert

Answer»

Oxygen atom in ether is Replaceabl

8999.

Which of the following is a disaccharide- (a) Lactose (b) Starch (c) Cellulose (d) Fructose 

Answer»

Lactose is a disaccharide.

9000.

Rhizome of ginger is like the roots of other plants that grows underground. Despite this fact ginger is a stem and not a root. Justify.

Answer»

Because it possess nodes and internodes, buds, scale leaf, and adventitious roots. Hence these are stem characters.