This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6101. |
How to eliminate the redundant rule matching attempts in the forward chaining?(a) Decremental forward chaining(b) Incremental forward chaining(c) Data complexity(d) None of the mentioned |
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Answer» Right answer is (b) Incremental forward chaining The best I can explain: We can eliminate the redundant rule matching attempts in the forward chaining by using incremental forward chaining. |
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| 6102. |
Differentiate food crops and cash crops. |
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Answer» The crops which can directly be consumed as food are called food crops. Cash crops are those having industrial and commercial significance. |
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| 6103. |
Compared to road transport, what are the advantage of rail, water, and air transport? |
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Answer» Each means of transport has its own advantage. Road transport is the best for short distances. But the other means of transport have certain advantages over road transport. Rail transport:
Water transport:
Air transport:
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| 6104. |
How many objects are available in closed classes?(a) 1(b) 2(c) 3(d) 4 |
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Answer» Correct choice is (d) 4 The explanation is: The four objects are available in closed classes are pronoun, article, preposition and conjunction. |
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| 6105. |
Agents behavior can be best described by ____________(a) Perception sequence(b) Agent function(c) Sensors and Actuators(d) Environment in which agent is performing |
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Answer» The correct option is (b) Agent function To explain I would say: An agent’s behavior is described by the agent function that maps any given percept sequence to an action, which can be implemented by agent program. The agent function is an abstract mathematical description; the agent program is a concrete implementation, running on the agent architecture. |
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| 6106. |
Which are the four types of iron ore found in India? |
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Answer» 1. Magnetite 2. Haematite 3. Limonite 4. Siderite |
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| 6107. |
What is the importance of agriculture in Indian economy? |
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| 6108. |
To eliminate the inaccuracy problem in planning problem or partial order planning problem we can use ___________________ data structure/s.(a) Stacks(b) Queue(c) BST (Binary Search Tree)(d) Planning Graphs |
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Answer» Right option is (d) Planning Graphs For explanation I would say: A planning graph can be used to give better heuristic estimates. |
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| 6109. |
India stands second in the world in jute production. a. What are the geographical factors for the cultivation of jute? b. Which is the major jute producing region in India? c. Jute products have high demand in international market. Why? |
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Answer» a. Hot and humid conditions are ideal for jute cultivation. High temperature and rainfall above 150 cm are essential for jute cultivation. Well drained alluvial soil is required. b. The Ganga - Brahmaputra delta region of West Bengal is the major jute producing region. c. Due to low cost. |
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| 6110. |
Explain the geographical factors required for rice cultivation. |
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Answer» Alluvial soil is most suitable for rice cultivation. Rice requires high temperature (24°C) and a good amount of Rainfall (more than 150cm) Rice is being cultivated on regions with less rainfall with the aid of irrigation. |
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| 6111. |
Through which mineral, the following places are known i) Neyveli ii) Jharia iii) Digboy |
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Answer» i) Lingnite ii) Coal iii) Petroleum |
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| 6112. |
Write a note on the agricultural seasons of India and the crops cultivated. |
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| 6113. |
Which food crop is cultivated in both summer and winter in India? Write the geographical conditions for its cultivation. |
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| 6114. |
What are the advantages of water transport compared to road and railways? |
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| 6115. |
The famous spare tire problem or Scheduling classes for bunch of students or Air cargo transport are the best example of ____________(a) Planning problem(b) Partial Order planning problem(c) Total order planning(d) None of the mentioned |
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Answer» Correct choice is (a) Planning problem Easiest explanation: None. |
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| 6116. |
What is the basis for the classification of railways in India as broad gauge, metre gauge and narrow gauge? Which rail gauge has the maximum length in India? Which guage tracks are replaced and how? |
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| 6117. |
What is the advantage of railways? |
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Answer» Rail transport is equally important for cargo as well as passenger transport. |
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| 6118. |
What is the significance of non-conventional sources of energy in the modern period? Which are the non-conventional energy sources in India? |
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| 6119. |
Prepare a note on any three cash crops cultivated in India, its geographical requirements and the states where it is cultivated. |
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Answer» Cotton: Forest free growing seasons, 200 to 30°C temperature small amount of rainfall. Black soil in the best soil. Jute: Hot and humid conditions. High temperature and rainfall above 150cm is essential well drained alluvial soil is suitable. Sugareane: 4 tropical crop, requires hot and humid climate. Black soil and alluvial soil are ideal. |
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| 6120. |
Write the favorable geographical factors required for the cultivation of major cash crops – cotton and jute and the states in which they are cultivated. |
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Answer» Cotton — Jute 1. Frost-free growing season — Hot and humid conditions 2. 20°C to 30°C temperature — High temperature 3. Black soil — Rainfall above 150cm 4. Gujrat Maharastra — Well drained alluvial soil 5. Andrapradesh, Tamilnadu — West Bengal, |
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| 6121. |
Reforms have been implemented from time to time in Indian railways which is important for cargo as well as passenger transport. Write any three such reforms. |
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| 6122. |
The presence of mineral resources has made some regions industrial centre. Substantiate this statement based on any three iron and steel industrial centre of India. |
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Answer» 1. Bokaro Steel Plant, Jharkhand : The factors responsible for this industrial centre are iron ore and manganese from Singhbhum and coal from sharia. 2. Rourkela Steel Plant, Odisha : The factors are iron ore and manganese from Sundargarh and Mayurbhanj. 3. Visweswarayya Iron and Steel Ltd., Bhadravathi, Karnataka : The factors are iron ore and manganese deposits from Bellary, Chikmagalur and Shimoga in Karnataka. |
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| 6123. |
Presence of mineral resources has made some regions industrial centers. Substantiate this statement based on two industrial centers and the factors responsible for it. |
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Answer» Iron and steel industry, Aluminium industry availability of raw materials, transport facilities. |
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| 6124. |
A distance of \(\dfrac{1}{2}\) centimetre on a map represents 200 kilometre on the ground. If two cities are 1800 kilometre apart on the ground, then their distance on the map will be1. nine centimetre2. three and a half centimetre3. four and a half centimetre4. six centimetre |
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Answer» Correct Answer - Option 3 : four and a half centimetre Given : 1/2 cm on map = 200 km on ground Calculation 1/2 cm on map = 200 km on ground ⇒ 1 cm on map = 400 km on ground or 1 km in ground = 1/400 cm on map ∴ 1800 km on ground = 1800 ÷ 400 = 4.5 cm on map. So, the correct answer is option 3) four and a half-centimeter. |
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| 6125. |
Complete the table as column A should indicate different types of minerals and column B their examples.ABFerrous metalsa...........b.........Silverc.........Petroleum |
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Answer» a. Iron ore b. Non – ferrous metals c. Mineral fuels |
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| 6126. |
Answer the questions based on minerals in India.a. Where are most of the mineral resources of India found? b. Shimoga in Karnataka, Singhbhum in Jharkhand and Mayurbhanj in Odisha are the mining centers of a major metallic mineral. Which is that metallic mineral? c. Manganese is a metallic mineral largely used in the iron and steel industry. Write another use of manganese. |
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Answer» a. Most of the mineral resources of India are found in the igneous and metamorphic rocks of the Peninsular plateau. b. Iron ore. c. Manganese is also used Jo make ferroalloys. |
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| 6127. |
Classify and write the Characteristics of Mineral Fuels Coal:1. The major Thermal energy source in India2. ………3. ………4. ………5. ………Petroleum and Natural gas:1. Main energy source of Bus, Rail and Air transport2. ……3. ……4. ……Non – Conventional energy source:1. Comparatively cheap2. ………3. ……… |
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Answer» Coal: 1. Coal is a major industrial fuel 2. Most of coal of fund in India is of medium grade of bituminous type. 3. West Bengal, Jharkhand, Odisha, Chattisgarh are the major states producing coal. 4. The largest coalfield in India is Jharia in Jharkhand. 5. The less energy-efficient coal is lignite. Petroleum and Natural gas: 1. Other than petrol and diesel etc. numerous by-products are also obtained. 2. Petroleum mining in India started at Digboi in Assam. 3. Petroleum producing states in India are Assam Gujrat and Maharashtra. 4. Natural gas is the fuel obtained along with petroleum. Non – Conventional energy source: 1. Environment-friendly 2. Renewable |
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| 6128. |
Choose the correct order related to the National waterways in India.ABI. National Waterway 1Allahabad to HaldiaII. National Waterway 2Kakinada to PuducherryIII National Waterway 3Sadia to DubaiIV. National Waterway 5Brahmani- Mahanadi river systemHints : A. I and II are correct B. I and III are correct C. I and IV are correct D. II and III are correct |
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Answer» Option : (C). I and IV are correct. |
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| 6129. |
Complete the table about the major Minerals in India, Uses, and the major state that produce these minerals. |
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| 6130. |
Complete the following flow chart about the major Minerals in India. |
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Answer» a) Ferrous metals b) Non-ferrous metals c) Other minerals d) Iron ore manganese e) Gold silver copper f) Coal, Petroleum g) Mica |
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| 6131. |
Where are the plantation of spices concentrated in Kerala? Why? |
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| 6132. |
How many terms of an A.P. must be taken for their sum to be equal to 200 if its third term is 16 and the difference between the 6th and the 1st term is 30? (a) 6 (b) 9 (c) 7 (d) 8 |
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Answer» Correct option (d) 8 Explanation: If the difference between the 6th and the 1st term is 30, it means that the common difference is equal to 6. Since, the third term is 16, the AP would be 4, 10, 16, 22, 28, 34, 40, 46 and the sum to 8 terms for this AP would be 200. |
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| 6133. |
Find the sum of all three-digit whole numbers less than 500 that leave a remainder of 2 when they are divided by 3.(a) 49637 (b) 39767 (c) 49634 (d) 39770 |
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Answer» Correct option (b) 39767 Explanation: We need the sum of the AP: 101, 104,107,…497 = 133 × 299 = 39767. |
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| 6134. |
Which are the major nuclear minerals and where are they found? Also write the names of nuclear power plants located in South India. |
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| 6135. |
Write the names of the nuclear power plants in the states of Rajasthan and Gujarat. |
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| 6136. |
How many 625 ml bottles can be filled with water from a container of 2.5 L capacity? (Bottles should be filled completely) 1. 3 bottles2. 4 bottles3. 5 bottles4. 6 bottles |
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Answer» Correct Answer - Option 2 : 4 bottles Given: Capacity of a container = 2500ml Capacity of a bottle = 625 ml Calculation: Capacity of a container = 2500ml Capacity of a bottle = 625 ml ⇒ Numbers of bottles can be filled = 2500 ÷ 625 = 4 ∴ 4 bottles can be filled completely. The correct option is 2 i.e. 4 bottles |
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| 6137. |
If a be the arithmetic mean and b,c be the two geometric means between any two positive numbers, then (b3 + c3) /abc equals (a) (ab)1/2/c (b) 1 (c) a2c/b (d) None of these |
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Answer» Correct option (d) None of these Explanation: Solve by taking values and checking with the options. If we take the numbers as 1 and 8, we would get a = 4.5 and b and c as 2 and 4 respectively. Then (b3 + c3)/abc =2. None of the first three options gives us a value equal to 2. |
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| 6138. |
In which state is Narora Nuclear Power Plant located?(a).Gujarat (b).Karnataka (c).Uttar Pradesh (d).Rajasthan |
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Answer» Option : (c).Uttar Pradesh |
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| 6139. |
If all the angles of a quadrilateral are in G.P. and all the angles and the common ratio are natural numbers. Exactly two angles are acute and two are obtuse then find the largest angle |
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Answer» Let the angles are x, xr, xr2 , xr3 x + xr + xr2 + xr3 = 360°. The angles are 24°, 48°, 96°,192°, Largest angle =192° |
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| 6140. |
In Narora nuclear power plant a technician is allowed an interval of maximum 100 minutes. A timer with a bell rings at specific intervals of time such that the minutes when the timer rings are not divisible by 2, 3, 5 and 7. The last alarm rings with a buzzer to give time for decontamination of the technician. How many times will the bell ring within these 100 minutes and what is the value of the last minute when the bell rings for the last time in a 100 minute shift? |
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Answer» In order to find how many times the alarm rings we need to find the number of numbers below 100, which are not divisible by 2, 3, 5 or 7. This can be found by: 100 — (numbers divisible by 2) – (numbers divisible by 3 but not by 2) — (numbers divisible by 5 but not by 2 or 3) — (numbers divisible by 7 but not by 2 or 3 or 5). Numbers divisible by 2 up to 100 would be represented by the series 2, 4, 6, 8, 10…100 → A total of 50 numbers. Numbers divisible by 3 but not by 2 up to 100 would be represented by the series 3, 9, 15, 21...99 → A total of 17 numbers. Note use short cut for finding the number of number in this series : [(last term — first term)/ common difference] + 1 = [(99 — 3)/6] + 1 = 16 + 1 = 17. Numbers divisible by 5 but not by 2 or 3: Numbers divisible by 5 but not by 2 up to 100 would be represented by the series 5, 15, 25, 35...95 → A total of 10 numbers. But from these numbers, the numbers 15, 45 and 75 are also divisible by 3. Thus, we are left with 10 — 3 = 7 new numbers which are Divisible by 5 but not by 2 and 3. Numbers divisible by 7, but not by 2, 3 or 5: numbers divisible by 7 but not by 2 upto 100 would be represented by the series 7, 21, 35, 49, 63, 77, 91 → A total of 7 numbers. But from these numbers we should not count 21, 35 and 63 as they are divisible by either 3 or 5. Thus a total of 7 — 3 = 4 numbers are divisible by 7 but not by 2, 3 or 5. Thus we get a total of 100 − 78 = 22 times. Also, the last time the bell would ring would be in the 97th minute (as 98, 99 and 100 are divisible by at least one of the numbers). |
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| 6141. |
The internal angles of a plane polygon are in AP. The smallest angle is 100° and the common difference is 10°. Find the number of sides of the polygon. |
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Answer» Smallest interior angle = 100, largest exterior angle= 180 − 100 =80 Similarly other exterior angles are 70, 60, 50, …. Sum of all the exterior angles = 360 So n(2.80 +(n-1)(-10))/2 = 360 or n(17 − n) = 72 We can see that the above equation is true for both n = 8, 9. But for n = 9, the 9th exterior angle must be 0 which is not possible so only 8 is possible. |
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| 6142. |
The sum of the squares of 3 natural numbers is 261, and they are in the proportion 2 : 3 : 4. The difference between greatest number and smallest number is:1. 62. 93. 54. 4 |
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Answer» Correct Answer - Option 1 : 6 Calculation: Let the numbers be 2y, 3y and 4y respectively. ⇒ (2y)2 + (3y)2 + (4y)2 = 261 ⇒ 29y2 = 261 ⇒ y2 = 9 ⇒ y = 3 Greatest number = 4y = 12 Smallest number = 2y = 6 ∴ The difference between greatest number and smallest number is 6.
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| 6143. |
A man purchases some mangoes at the rate of 24 mangoes for Rs 1. How many mangoes did he sell for a rupee to gain 20% profit?1. 202. 213. 184. 22 |
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Answer» Correct Answer - Option 1 : 20 GIVEN: A man purchases some mangoes at the rate of 24 mangoes for Rs. 1. CONCEPT: FORMULA USED: SP = CP × [1 + Profit/100] CALCULATION: Given, CP of 24 mangoes is Rs. 1. ⇒ CP per mango = Rs 1/24 Also, Profit = 20 % of CP = 1/5 CP So, SP = CP + Profit = 6/5 CP. ⇒ SP per mango = Rs 6/5 × 1/24 = 1/20 Since, SP of 1 mango = Rs 1/20 ⇒ No. of Mangoes sold for Rs. 1 = 20 |
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| 6144. |
Elaborate about a staple food, two unique ingredients, two sweet dishes and five main dishes of Bengali cuisine. |
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Answer» Bengali Cuisine A staple food Rice Two unique ingredients Fish Mustard paste Two sweet dishes Rasgulla Chamcham Five main dishes Bhaja Doimach Chingrimalai curry Aloo Posto Chorchori |
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| 6145. |
Shashank had candies and chewing gums in his sweet box in the ratio 7 ∶ 13. After he has eaten 9 candies and 11 chewing gums the ratio became 1 ∶ 2. How many candies does he have now?1. 442. 423. 414. 40 |
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Answer» Correct Answer - Option 4 : 40 Given: Shashank had candies and chewing gums in his sweet box in the ratio 7 ∶ 13. Calculations: Let the number of candies be 7x and the number of chewing gums be 13x. According to the question, (7x – 9)/(13x – 11) = 1/2 ⇒ 14x – 18 = 13x – 11 ⇒ 14x – 13x = 18 – 11 ⇒ x = 7 Number of remaining candies = 7x – 9 = (7 × 7) – 9 = 49 – 9 = 40 ∴ Number of remaining candies is 40 |
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| 6146. |
The ratio of three numbers A, B and C is 8 ∶ 11 ∶ 15, and ratio of A and D is 4 ∶ 11. The number C is equal to the average of the number A and D. Find the number B.1. 332. 243. 454. Cannot be determined |
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Answer» Correct Answer - Option 4 : Cannot be determined Given: The ratio of three numbers A, B and C = 8 ∶ 11 ∶ 15 The ratio of A and D = 4 ∶ 11 The number C = The average of the numbers A and D. Formula: If the ratio of A and B is a ∶ b, assume A = ak and B = bk where k is a constant. Calculation: Let the numbers A, B, C and D be 8x, 11x, 15x and 22x respectively. The number C = The average of the numbers A and D. ⇒ 15x = (8x + 22x)/2 ⇒ 30x – 8x = 22x ⇒ 22x = 22x ∴ The value of x cannot be determined. A : B : C = 8 : 11 : 15 A : D = 4 : 11 To make A same in both the ratios , we have to multiply 2 with (A : D) |
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| 6147. |
Three boys A, B and C got different number of pens. If A gives 3 pens to C, then the ratio of the number of pens of A and C becomes 19 ∶ 28. If B gives 2 pens to C, then the ratio of the number of pens of B and C will be 7 ∶ 11. The number of pens with B is 37. Find the number of pens with A.1. 532. 333. 414. 55 |
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Answer» Correct Answer - Option 3 : 41 Given: If A gives 3 pens to C, ratio becomes = 19 ∶ 28. If B gives 2 pens to c, ratio becomes = 7 ∶ 11 The number of pens with B = 37 Calculation: Let the pens with A, B and C be a, b and c respectively. If B gives 2 pens to c, ratio becomes = 7 ∶ 11 ⇒ (b – 2)/(c + 2) = 7/11 ⇒ (37 – 2)/(c + 2) = 7/11 ⇒ 385 = 7(c + 2) ⇒ c = 53 Now, If A gives 3 pens to C, ratio becomes = 19 ∶ 28 ⇒ (a – 3)/(c + 3) = 19/28 ⇒ (a – 3)/(53 + 3) = 19/28 ⇒ a = 38 + 3 ⇒ a = 41 ∴ The number of pens with A is 41. |
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| 6148. |
Amit covers from A to B and back to A by train in 16 hour. If the ratio of speed from A to B and back from B to A is 5 : 3. Find the speed of the train in the onward journey from A to B if the distance between A and B is 300 kilometres.1. 50 km/hr2. 30 km/hr3. 25 km/hr4. 45 km/hr5. 15 km/hr |
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Answer» Correct Answer - Option 1 : 50 km/hr Given: Total time = 16 hours Total distance = 600 km The ratio of speed of onward journey and return journey is 5 : 3 . Formula used : Average speed = Total distance/Total time taken Average speed = 2 x y/x + y Where, x and y are speeds of onward journey and return journey respectively . Calculations : Let speed of onward journey and return journey be 5x and 3x respectively. Average speed = 600/16 ----(1) Also, Average speed = 2 × 5x × 3x/(5x +3x) ----(2) On equating equation (1) and (2) we get , ⇒ 2 × 5x × 3x/(5x +3x) = 600/16 ⇒ 30x2/8x = 600/16 ⇒ x = 10 ⇒ speed of onward journey is 5x = 5 × 10 = 50 km/hr ∴ The speed of train in onward journey from A to B is 50 km/hr. |
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| 6149. |
If the ratio of principal and the simple interest of 5 years is 10:3, them the rate of interest is:(यदि मूल धन और 5 वर्षो के ब्याज का अनुपात 10 : 3 है, तो ब्याज की दर क्या है ? )A. 0.06B. 0.08C. 0.03D. 0.05 |
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Answer» (a) `(P)/(S.I)=(10)/(3)` Let Principal(मूलधन)=10 S.I for 5years=3 S.I for 1years =0.6 `"Rate"=(SI)/(Principal)xx100 =(0.6)/(10)xx100=6%` |
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| 6150. |
Ramesh deposited 15600 in a fixed deposit at the rate of 10% per annu simple interest, After every second year, he adds his interest earning to the principal. The interest at the end of fourth year is (रमेश ने 15600 साधारण बियाज की 10 % वार्षिक दर वाले एक सावधि खाते में जमा कराये बियाज से हुई आय को वह प्रति दूसरे वर्ष मूलधन में मिला देता है उसका चौथे वर्ष के अंत में मिलने वला बियाज क्या होगा )A. 1716B. 1560C. 3744D. 1872 |
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Answer» (c ) Principal=15600 Rate%=10% `SI=(15600xx10xx2)/(100)=3120` Now, the principal for next two years(अगले दो वर्षो के लिए नया मूलधन)=15600+3120=18720 `Now SI=(18720xx10xx2)/(100)=3744` Hence Required SI=3744 |
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