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Three boys A, B and C got different number of pens. If A gives 3 pens to C, then the ratio of the number of pens of A and C becomes 19 ∶ 28. If B gives 2 pens to C, then the ratio of the number of pens of B and C will be 7 ∶ 11. The number of pens with B is 37. Find the number of pens with A.1. 532. 333. 414. 55 |
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Answer» Correct Answer - Option 3 : 41 Given: If A gives 3 pens to C, ratio becomes = 19 ∶ 28. If B gives 2 pens to c, ratio becomes = 7 ∶ 11 The number of pens with B = 37 Calculation: Let the pens with A, B and C be a, b and c respectively. If B gives 2 pens to c, ratio becomes = 7 ∶ 11 ⇒ (b – 2)/(c + 2) = 7/11 ⇒ (37 – 2)/(c + 2) = 7/11 ⇒ 385 = 7(c + 2) ⇒ c = 53 Now, If A gives 3 pens to C, ratio becomes = 19 ∶ 28 ⇒ (a – 3)/(c + 3) = 19/28 ⇒ (a – 3)/(53 + 3) = 19/28 ⇒ a = 38 + 3 ⇒ a = 41 ∴ The number of pens with A is 41. |
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