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Vegetable matter is changed into compost by micro- organisms using decomposition reactions. The complex organic material of which vegetable matter is made up of is broken down into simpler molecules during this process.

The reaction for the formation of ammonia is N₂​+3H₂ ​⇔ 2NH₃​.

1 mole (28 g) of nitrogen will react with 3 moles (6g) of hydrogen to form 2 moles (34g) of ammonia if the reaction is 100% completed.

But only 17 g of ammonia are actually formed.

Hence, the reaction is 50% complete.

Hence, 0.5 mole (14 g) of nitrogen and 3 moles (3g) of hydrogen will remain unreacted at equilibrium.

Given AP is 5, 8, 11, 14, ….. 

First term of given AP is a = 5. 

Common difference of given A.P is d = a₂ – a₁ = 8 – 5 = 3. 

We know that sum of first n terms of AP whose first term is a and common difference is d is given by S_n = \(\frac{n}{2}\) [2 + ( − 1)]. 

Therefore, the sum of first 24 terms of the given AP is S₂₄ = \(\frac{24}{2}\) [2 × 5 + (24 − 1)3] 

= 12[10 + 23 × 3] = 12(10 + 69) = 12 × 79 = 948. (∵ a = 5, d = 3, n = 24) 

Hence, the sum of first 24 term of given AP is 948.

Plastic is a poor conductor of heat because conduction of heat and electricity requires free electrons. Plastics, whose molecules are made from long combinations of carbon and hydrogen atoms, have few or no free electrons.

Assume that 2 +√3 is a rational number, therefore it can be write in \(\frac{p}{q}\) form, where q ≠ 0 and p & q have no common factor other than 1. 

Therefore, 2 + √3 = \(\frac{p}{q}\) . 

⇒ √3 = \(\frac{p}{q}\) – 2 = \(\frac{ p− 2q}{q}\), q ≠ 0. 

But √3 is an irrational number and \(\frac{ p− 2q}{q}\) is a rational number. 

(∵ p − 2q, q ∈ I & q ≠ 0, ∴ \(\frac{ p− 2q}{q}\) is a rational number. ) 

It mean rational = irrational which is not possible. (contradiction) 

Hence, our assumption is wrong.

Therefore, 2 +√3 is an irrational number.

Let us assume that 2+√3 is a rational number.
A rational number can be written in the form of p/q.
2+√3=p/q
√3=p/q-2
√3=(p-2q)/q
p,q are integers then (p-2q)/q is a rational number.
But this contradicts the fact that √3 is an irrational number.
So,our assumption is false.
Therefore,2+√3 is an irrational number.
Hence proved.

‘फ़्लाइंग सिख’ के नाम से मिल्खा सिंह को जाना जाता है ।

भारत में अंग्रेजी शिक्षा  लार्ड मैकाले ने शुरू की थी ।

Statement I: False

• In memory-mapped I/O, devices cannot be accessed using IN and OUT instructions
• IN and OUT both are 2-byte instructions in 8085 processor

Example:

IN – port address DB (Hexadecimal)

OUT-port address D3 (Hexadecimal)

So statement 1 is False

Statement II: True

In memory-mapped I/O, arithmetic and logic operations can be directly performed with the I/O data.

The correct answer is "option 3".

CONCEPT:

The ping measure Round-trip time for the messages, that are echoed back to the source, sent from source host to destination host.

Ping is used to test the reachability of any host on an Internet protocol(IP) network.

Ping works by sending Internet Control Message Protocol(ICMP) echo request packet & waits for ICMP echo reply by the target host.

When ping encounters any error, ICMP sends the error messages & some of them are:

• Destination Host Unreachable
• Request timed out
• Ping request could not find a host

Hence, the statement "If PING encounters an error condition, an ICMP message is not returned" is false.

Given equation is x³ + x² - 2x - 1 = 0

Since only one time sign changes from going left side to right side.

So, only one real root is possible.

\(\because\) f(0) = -1 & f(-1) = -1 + 1 + 2 - 1 = 1 > 0, where f(x) = x³ + x² - 2x - 1

\(\therefore\) f(0) f(-1) < 0

\(\therefore\) Root lies between 0 and -1.

Given equation is x³ - 3x² + 4 = 0

\(\because\) x = -1 satisfies the equation.

(Because, (-1)³ - 3(-1)² + 4 = -1 - 3 + 4 = -4 + 4 = 0)

\(\therefore \) (x + 1) is a factor of x³ - 3x² + 4.

Now,

since x³ - 3x² + 4 = 0

⇒ (x + 1) (x² - 4x + 4) = 0

⇒ (x + 1) (x - 2)² = 0

⇒ x = -1, 2, 2

Hence, roots of given equation are -1, 2, 2.

(c) The value of vector A . vector B is 0.

Concept:

Page offset length = log₂ (Page size)

Physical Page length = Physical Address length – Page offset length.

Virtual page length = virtual address length – page offset length

Calculation:

Page offset length = log₂ (8 kB)

= log₂ (2³ × 2¹⁰) = log₂ 2¹³

= 13 bits

Virtual page length (VPN) = 64 – 13 = 51 bits

Physical page length (PPN) = 43 – 13 = 30 bits

Concept:

Average total time is defined as the sum of:

Average seek + Average Rotational Delay + Transfer time

Let us first read the first track:

Average seek time = 4 ms

Average Rotational Delay = 2 ms

Reading 500 sectors per track is also given

The rotational speed is 15000 rpm, i.e.

The time taken in 15000 revolution = 1 min = 60 sec

The time taken in 1 revolution will be:

\(\frac{1}{{15000}} \times 60\;sec\) 

Now, Reading 500 sectors = Time for 1 Revolution = 4 msec

The above is the complete track reading time.

Hence the time required to read the first track will be:

4 ms(average seek) + 2 ms (average rotational delay) + 4 ms (Reading 500 sector) = 10 msec

Now, it is given that sequential organization is followed and no seek time is required for further reading of the remaining 4 tracks.

But the remaining 4 tracks will have a rotational delay and reading time of tracks, i.e.

= 4 × (2 + 4) msec

4  = No. of remaining tracks

2 ms = rotational delay

4 ms = reading time of 500 sectors or 1 track

= 4 × 6 = 24 sec

∴ The total time will be:

= 10 + 24 = 34 msec

 = 0.034 sec

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The center of mass of a uniform disc shape would be at its center. Sometimes the center of mass doesn't fall anywhere on the object. The center of mass of a ring for example is located at its center, where there isn't any material.

The angle of banking depends on the speed of the vehicle, the radius of the curved road and the acceleration due to gravity g at that place.

As above, apply rotational equilibrium + (300) (30cm) – X(20cm) – (200) (40cm) = 0

Friction is a good example of a nonconservative force.

B. the energy per unit mass absorbed as heat during a phase transformation 

Electric field at distance r ⇒E= λ/2πrϵ₀ ​ 

Flux through Gaussian cylinder 

ϕ=E.2πrL 

ϕ=​ λL/ϵ₀ ​

According to question, If we set up 3 or more identical cube around it, to cover its area then we get flux equal to that of cylindrical Gaussian surface i.e. λL/ϵ₀ ​

But as we are covered with only 1/4 ​ of area thus 

Flux would be = λL/4ϵ₀ ​

D. melt 1 g of ice

1. Gymnosperms 

2. Ovule

Non-elongated sclerenchyma(sclereids)