Saved Bookmarks
| 1. |
A particle `A` of mass `m` is situated at highest point of wedge `B` of mass `2m` is released from rest. Then distance travelled by wedge `B (` with respect to ground `)` when particle `A` reaches at lowest position. Assume all surfaces are smooth. A. `4//3cm`B. `8//3cm`C. `2//3cm`D. none of these |
|
Answer» Correct Answer - A `SigmamDeltar_(cm)=m_(1)Deltar_(1)+m_(2)Deltar_(2)` `=(m+2m)(0)=m(x-4)+2m(x)` `rArr x=(4)/(3)cm` |
|