Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Salicylic acid is prepared from phenol by the reaction known as

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WURTZ reaction
Williamson reaction
Kolbes-Schmidt reaction
esterification

Answer :C
2.

Salicylic acid is obtained by using

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ANSWER :A::B
3.

Sal volatile is:

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`NH_4Cl`
`(NH_4)_2SO_4`
`(NH_4)_2SO_3`
`(NH_4)_2CO_3`

ANSWER :C
4.

Salicylic acid can be prepared using Reimer-Tiemann's reaction by treating phenol with

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methyl CHLORIDE in the presence of anhydrous ALUMINIUM chloride.
carbon dioxide under pressure in SODIUM hydroxide solution.
carbon TETRACHLORIDE and concentrated sodium hydroxide.
sodium nitrite and a few drops of concentrated sulphuric acid.

Answer :C
5.

Salicyldehyde can be prepared by .......

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FITTING reaction
REIMER - Tiemann reaction
Fries rearrangement reaction
KOLBE - SCHMITT reaction

Solution : Reimer - Tiemann reaction
6.

Salicylaldehyde can be separated from the mixture of salicyladehyde and p - hydroxy benzaladehyde by

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DISTILLATION
FRACTIONAL distillation
SOLVENT extraction
All of these

Answer :B
7.

Saccharine contains

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C and H
C, H, N andO
C,H,N, O & S
C,O and H

Solution :
8.

Give the structure of the Saccharinand write its one use.

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HEXOSE
REDUCING sugar
Glucoside
None

ANSWER :D
9.

Saccharin is a/an________.

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ANALGESIC
SWEETENING agent
antioxidant
food preservative

Answer :B
10.

Saccharin, butyl hydroxy toluene, aspartane, sucralose, alitame.

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Solution :BUTYL hydroxy TOLUENE. It is an ANTIOXIDANT where as others are artificial sweetening AGENTS.
11.

Saccharin, an artificial sweetner, is manufacturing from:

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Cellulose
TOLUENE
CYCLOHEXANE
STARCH

ANSWER :B
12.

Saccharin, an artificial sweetener is manufactured from

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CELLULOSE
TOLUENE
cyclohexene
starch

Solution :toluene
13.

Saccharin , an artificial sweetener , is manufactured from

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CELLULOSE
TOLUENE
CYCLOHEXANE
STARCH

ANSWER :B
14.

Saccharin, an artificial sweetener, is manufactured from

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Cellulose
Toluene
Cyclohexane
STARCH

ANSWER :B
15.

Saccharification is the process of conversion of :

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SUGAR SOLUTION into alcohol
Alcohol into starch
Starch into alcohol
Starch into sugar

Answer :D
16.

S_(8) molecule is present in

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Rhombie SULPHUR
MILK of sulphur
Colloidal sulphur
PLASTIC sulphur

Answer :A
17.

S_(2)O_(3)^(2-) + MnO_(4)^(-) + H_(2)O rarr MnO_(2) + S_(2)O_(4)^(2-) + OH^(-). What are the coefficients of S_(2)O_(3)^(2-) and MnO_(4)^(-) in the balance equation ?

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ANSWER :`3S_(2)O_(3)^(2-)` and `8MnO_(4)^(-)`
18.

S_(2) molecule in vapour state is paramagnetic due to the presence of unpaired electrons is

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Bonding `sigma` ORBITALS
ANTI bonding `sigma ^(**)` ORBITAL
Anti bonding `PI^(**)` orbitals
Bonding `pi` orbitals

Answer :C
19.

S^(2-) Cannot be tested with

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`BaCl_2` solution
lead ACETATE solution
sodium nitroprusside
dil. `H_2SO_4` test.

Solution :`S^(2-)` do not GIVE WHITE ppt. with `BaCl_2` (AQ).
20.

S^(2-) " and" SO_(3)^(2-) can be distinguished by :

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`(CH_(3)CO O)_(2) Pb`
`Cr_(2)O_(7)^(2-)// H^(+)`
`Na_(2)[Fe (CN)_(5)NO]`
`Zn + " dil." H_(2)SO_(4)` FOLLOWED by `(CH_(3)CO O)_(2)Pb`

Answer :A::B::C
21.

S^(2-) and SO_(3)^(2-) canbe distinguished by using

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`(CH_(2)COO)_(2)Pb`
`Na_(2)[FE(CN)_(5)NO]`
`CO_(2)O_(7)^(2-)` solution
`CaCI_(2)`

Answer :a,b,d
22.

S^(2-) and SO_(3)^(2-) can be distinguihsed by using

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`(CH_(3)COO)_(2)Pb`
`Na_(2)[Fe(CN)_(5)NO]`
both (a) and (b)
None of these

Solution :`S^(2-)+(CH_(3)COO)_(2)Pb underset("BLACK ppt.")(PBS DARR) +2CH_(3)COO^(-)`
`S^(2-)+Na_(2)[Fe(CN)_(5)NO]tounderset("violet ppt.")([Fe(CN)_(5)NOS]^(4-))+2Na^(+)`
HENCE, they are distinguished by both the REAGENTS as only `S^(2-)` gives precipitate with these reagents.
23.

S^(2–) and SO_(3)^(2–) can be distinguished by using:

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`(CH_(3)COO)_(2)Pb`
` Na_(2)[FE(CN)_(5)NO]`
`Cr_(2)O_(7)^(2–)`
`CaCl_(2)`

Answer :A::B::D
24.

S_(1): 2Se_(2)Cl_(2)rarr SeCl_(4)+3Se S_(2) : Dioxides like MnO_(2), PbO_(2) do not form H_(2)O_(2) with dilute acids but they evolve oxygen with concentrated H_(2)SO_(4). S_(3) : Sodium thiosulphate with FeCl_(3) solution develops a pink or violet colour which soon vanishes. S_(4) : White precipitate of PbS_(2)O_(3) get soluble when boiled with water.

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FTTT
TFTT
FFTT
TTTF

Answer :D
25.

S_(1):(HPO_(3))_(n) can be prepared by heating phosphorous acid and bromine in a sealed tube. S_(2) : dry iodine reacts with ozone and formed yellow solid, I_(4)O_(9) S_(3) : B sulphur is stable below 369 K.

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FTF
TTF
TTT
TFF

Answer :B
26.

S_1:The species [CuCl_4]^(2-) exists but [C ul_4]^(2-) does not. S_2:[RhCl(Ph_3P)_3] and [Ni(CO)_4] both are tetrahedral and diamagnetic. S_3:N(Me)_3 and N(SiMe_3)_3 are isostructural

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T T F
T F F
F T F
T T T

Solution :`S_1`:`I^(-)` ion is a STRONGER reducing agent than `CL^(-)` ion. It reduces `CU^(2+)` to `Cu^(+)` ion.
`S_2:`Both diamagnetic but `[NI(CO)_4]` is tetrahedral and `[RhCl(Ph_3P)_3]` is a square planar.
27.

S, T and U are the aqueous chlorides of the elements X, Y and Z respectively. X, Y and Z are in the same period of the periodic table. U gives a white precipitate with NaOH but this white precipitate dissolves as more NaOH is added. When NaOH is added to T, a white precipitate forms which does not dissolve when more base is added. S does not give precipitate with NaOH. Which of the following statements are correct?

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The three elements are metals
The electronegativity decreases fro X to Y to Z.
X, Y and Z could be SODIUM, magnesium and aluminium respectively
The FIRST ionization INCREASES fro X to Y to Z.

Answer :A::C
28.

S rarr G + F Time " "t " "prop Rotation of Glucose & Fructose r_(t)" " r_(prop) Find k.

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SOLUTION :`K=(1)/(t)" In "(r_(OO))/((r_(oo)-r_(1)))`
29.

S-S bond is not present in

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PYRO SULPHUROUS ACID
Dithionic acid
Dithionous acid
Pyro SULPHURIC acid

ANSWER :D
30.

S-O-O-S bond present in which of the following oxyacid is

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`H_(2)SO_(4)`
`H_(2)S_(2)O_(6)`
`H_(2)S_(2)O_(8)`
`H_(2)S_(2)O_(7)`

ANSWER :C
31.

S is a well known pain killer which of the following is 'R' ?

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`CH_(3)-overset(O)overset(||)(C)-NH_(2)`
`CH_(3)-overset(O)overset(||)(C)-O-overset(O)overset(||)(C)-CH_(2)`
`CH_(3)-overset(O)overset(||)(C)-H`
`CH_(3)-overset(O)overset(||)(C)-CH_(3)`

Answer :B
32.

S+(3)/(2)O_(2)rarrSO_(3)+2 x kcalSO_(2)+(1)/(2)O_(2)rarrSO_(3)+y kcalFind out the heat of formation of SO_(2)

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`2X - y`
`2x + y`
`x + y`
`2x//y`

SOLUTION :Substract EQUATION (II) from (i).
33.

S+3//2O_2rarrSO_3 + 2x kcal SO_2+ 1/2O_2rarrSO_3 + y kcal: The heat of formation of SO_2 is :

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y-2x
(2x+y)
(x+y)
2x-y

Answer :A
34.

S+2Cl_(2) to X overset(H_(2)O)to Y+HCl, Y to Z+H_(2)O. Oxidation state of S in 'Z' is

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`+1`
`+4`
`+6`
`+2`

ANSWER :D
35.

RX + NaOH_(aq) overset(Delta) to ROH + NaX The above reaction proceed by __________ mechanism.

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NUCLEOPHILIC addition
elimination
ELECTROPHILIC SUBSTITUTION
nucleophilic substitution

ANSWER :D
36.

Rydberg constant is

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A UNIVERSAL constant
Same for all elements
Different for different elements
Is different for LIGHTER ELEMENT but same for heavier elements

Answer :C
37.

RX on heating with NH_3 in sealed tube gives :

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`RNH_2`
`R_2NH`
`R_3N`
All

ANSWER :D
38.

Rutile is seperated from chlonapatite by

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Froth floation method
levigation
electromagnetic seperation method
electrostatic seperation method

Solution :The magnetic impurity RUTILE `(TiO_(2))` can be SEPARATED by using electromagnetic separation method from chlorapatite `(3Ca_(3)(PO_(4))_(2)CaCl_(2)` a non magnetic MATERIAL.
39.

Rutile is an ore of:

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Ti
Zr
Mn
V

Answer :A
40.

Rutherford's scattering experiment led to the discovery of

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Nucleus
Distribution of ELECTRONS AROUND the nucleus
Presence of neutrons in the nucleus
Both (1) and (3)

ANSWER :A
41.

Rutherford's experiment, which established the nuclear model of the atom, used a beam of

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`beta`-particles, which impinged on a METAL FOIL and GOT absorbed
`gamma`-rays, which impinged on a metal foil and ejected electrons
helium ATOMS, which impinged on a metal foil and got scattered
helium NUCLEI, which impinged on a metal foil and got scattered

Answer :D
42.

Ruthenium carbonyl is:

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`RU(CO)_4`
`Ru(CO)_5`
`Ru(CO)_8`
`Ru(CO)_6`

ANSWER :B
43.

Ruthenium carbonyl is

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 `Ru(CO)_(4)` 
`Ru(CO)_(5)`
`Ru(CO)_(8)`
`Ru(CO)_(6)`

ANSWER :B
44.

Rusting or iron is catalysed by which of the following

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Fe
`O_(2)`
Zn
`H^(+)`

Solution :Rusting of iron is CATALYSED by `[H^(+)]`.
45.

Ruthenium carbonyl is :

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RU(CO)_4`
Ru(CO)_5`
`Ru(CO)_8`
`Ru(CO)_6`

Answer :B
46.

Rusting on iron needs

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DRY air
Air and WATER
Distilled water and CARBON dioxide
Oxygen and carbon dioxide

Answer :B
47.

Rusting of iron is not only on the surface but it eats up iron completely because

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RUST PENETRATES into iron
rust further REACTS with Fe-atoms in the bulks
water and AIR PENETRATE into iron
rust is a non-sticking compound

Solution :Rust is brittle.
48.

Rusting of iron is quicker in saline water than in orderinary water. Give reason.

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Solution :In saline water, the presence of `Na^(+) and Cl^(-)` ions increases the conductance of the solution in CONTACT with the METAL SURFACE. This accelerates the formation of `Fe^(2+)` ion and HENCE that of rust, `Fe_(2)O_(3).xH_(2)O`
49.

Rusting of iron is catalysed by which of the following ?

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FE
`O_2`
`ZN`
`H^+`

ANSWER :D
50.

Rusting of iron is an ................. Process.

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SOLUTION :ELECTRO CHEMICAL