Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Rusting of iron is a fast reaction.True / False

Answer»

SOLUTION :very SLOW
2.

Rusting of iron is a _____ reaction.

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SOLUTION :very SLOW
3.

Rusting of iron is a chemical reaction . The reaction is :

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Analysis
Displacement
Oidation of Fe
Double decomposition

Answer :C
4.

Rusting of iron becomes quicker in saline medium. Explain.

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Solution :Saline MEDIUM has extra salts such as sodium chloride dissolved in water. This means that it has a GREATER concentration of ELECTROLYTE than ordinary medium. The ions present will favour the formation of more electrochemical CELLS and will thus promote rusting or CORROSION.
5.

Rusting of iron in moist air involves:

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LOSS of ELECTRONS by Fe
GAIN of electrons by Fe
Neither gain nor loss of electrons
Hydration of Fe

Answer :A
6.

Rust is a mixture of

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`FEO and FE(OH)_(2)`
`FeO and Fe(OH)_(3)`
`Fe_(2)O_(3) and Fe(OH)_(3)`
`Fe_(3)O_(4) and Fe(OH)_(3)`.

SOLUTION :Rust is a MIXTURE of `Fe_(2)O_(3)` and `Fe(OH)_(3)`.
7.

Rust is a mixture of ________.

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`Fe_(2)O_(3)+FE(OH)_(3)`
`Fe+H_(2)O+O_(2)`
`FeO+Fe(OH)_(3)`
`Fe+Fe(OH)_(3)`

ANSWER :A
8.

Rust is

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`FeO+FE(OH)_(2)`
`Fe_(2)O_(3)`
`Fe_(2)O_(3)+Fe(OH)_(2)`
`Fe_(2)O_(3) and Fe(OH)_(3)`

Solution :Rust is `Fe_(2)O_(3) and Fe(OH)_(3)`
9.

Rust is mixture of:

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`FEO` and `Fe(OH)_3`
`FeO` and `Fe(OH)_2`
`Fe_2O_3` and `Fe(OH)_3`
`Fe_2O_4` and `Fe(OH)_3`

ANSWER :C
10.

Rust is a mixture of :

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`Fe_2O_3cdotxH_2O`
`FeOcdotxH_2O`
`Fe_3O_4cdotxH_2O`
`Fe_2O_3`

ANSWER :A
11.

Ruby is aluminium oxide (Al_(2)O_(3)) containing about 0.5-1% Cr^(3+) ions (d^(3)), which are randomly distributed in positions normally occupied by Al^(3+) choose the only incorrect statement :

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`Cr^(3+)` is incorporated into the alumina lattice as octahedral chromium (III) complexes
d-d transitions at these CENTRES give rise to colour
In Emarald, `Cr^(3+)` ions occupy octahedral sites in the mineral beryl `(Be_(3)Al_(2)Si_(6)O_(18))`
The ABSORPTION bands seen in the Emarlad, shift to longer wavelength, namely yellow-red and blue, causing Ruby to transmit light in green region.

Solution :(d) The absorption bonds seen in the Ruby, shift ot longer wavelength, namely yellow-red and blue, causing EMERALD ot transmit light in green region.
12.

Ruby is alumina containing 1% chromic salt. Discuss the type of complex involved in the colour.

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Solution :OCTAHEDRAL COMPLEX with `d^(3)` configuration of `CR^(3+)`
13.

Rubber plating and chrome tanning of leather are based upon:

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Electro-osmosis
Tyndall effect
Electrophoresis
Brownian motion

Answer :C
14.

Ruby copper is:

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`Cu_2O`
`CU(OH)_2`
`CuCl_2`
`Cu_2Cl_2`

ANSWER :A
15.

Rubberlatex is which type of emulsion

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OIL in oil
WATER in oil
oil in water
SOLID in water

SOLUTION :Oil in water
16.

Rubber latex is which type of emulsion

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OIL in oil TYPE 
WATER in oil type 
oil in water type 
SOLID in water type

Answer :C
17.

Rubber latex is

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Emulsion of polyhydrocarbon droplets in an aqueous solution 
Milk white suspension of crude rubber in `C Cl_(4)` 
TRUE solution of crude rubber in WATER 
True solution of crude rubber in ALCOHOL 

Answer :A
18.

Rubber is heated with sulphur and the process is known:

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Galvanization
Vulcanization
Bessemerization
Sulphonation

Answer :B
19.

Rubber is a natural polymer obtained from the bark of rubber trees vuclanisation improves elasticity of rubber. What is vulcanisation?

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SOLUTION :HEATING RUBBER with SULPHER is KNOWN as vuclanisation
20.

Rubber is a solidsol

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SOLUTION :Solidfoam
21.

Rubber is a natural polymer obtained from the bark of rubber trees Name the monomer of natural rubber

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SOLUTION :ISOPRENE (2-methyl I-I, 3 BUTADIENE)
22.

Rubber foms colloidal solution with ................

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SOLUTION :BENZENE
23.

Rubber is a ......... colloid.

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LYOPHOBIC 
Multi-molecular 
ASSOCIATED 
LYOPHILIC 

SOLUTION :Lyophilic
24.

Ru and Os have highest oxidation state in which compounds? Explain with example.

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Solution :(i) Ru and Os have +8 as the highest oxidation STATE.
(ii) The highest oxidation state of 4d and 5d elements are FOUND in their compounds with the higher electronegative elements like O, F and Cl. For example: `RuO_(4), OsO_(4)`
25.

Replacement of Cl of Chlorobenzene to give phenol requires drastie conditions, but Cl of 2, 4 -dinitro chlorobenzene is readily replaced. This is because,

Answer»

`-NO_(2)` group makes the ring electron RICH at ORTHO and para positions
`-NO_(2)` group withdraws electrons from meta position
`-NO_(2)` DONATES electron at meta position
`-NO_(2)` with drows electrons from ortho and para positions.

Solution : `:NO_(2)` withdraws w electrons from the carbon bearing chlorine group making the C-Cl bond WEAK
26.

R.R.D. sir had a great interest in performing the experiment when he used to study at IT BHU. Once He saw the dissociation of PCl_5and concluded that it was 40% dissociated at 4 atm. Calculate the pressure at which he will see 80% dissociation of PCl_5, temperature remaining the same ?

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SOLUTION :(0.43 ATM)
27.

Round up upto three significant figures : (i) 34.216 (ii) 10.4107 (iii) 0.04597 (iv) 2808

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SOLUTION :`"(i) 34.2(II) 10.4(III) 0.0460(IV) 2810"`
28.

Rotational energy levels of diatomic molecules are well described by the formula E_(J)=BJ(J+1), where J is the rotational quantum number of the molecule and B its rotational constant. B is related to the reduced mass mu and the bond length R of the molecule through the equation B=h^(2)/(8pi^(2)muR^(2)). In general, spectroscopic transitions appear at photon energies which are equal to the energy difference between appropriate states of a molecule (hv=DeltaE). The observed rotational transitions occur between adjacent rotational levels, hence DeltaE=E_(J+1)-E_(J)=2B(J+1). Consequently, successive rotational transitions that appear on the spectrum (such as the one shown here) follow the equation h(Deltaupsilon)=2B. By inspecting the spectrum provided, determine the following quantities for ^(2) C ^(p)C with appropriate units (a) Deltaupsilon (b) B (c) R

Answer»


Answer :{:a) For example : `DeltaV=1150-1035=115 GHz`
{:b) `B=(hDeltav)/(2)=(6.63xx10^(-34)xx115'xx10^(9))/(2)=3.81xx10^(-23) J`
{:c) `mu=(m(C)xxm(O))/(m(CO))=(12xx16)/(28)=6.86 a.u.=1,14 xx10^(-26) kg`
For interatomic distance R:
`R=(H)/(2pisqrt(2muB))=(3.63xx10^(-34))/(2xx3.14sqrt(2xx1.14xx10^(-26)xx3.81xx10^(-23)))=1.13xx10^(-10) m =1.13 Å`
29.

Rotation of plane polarized light can be measured by:

Answer»

Manometer
Calorimeter
Polarimreter
Viscometer

Answer :C
30.

Rotation of plane polarised light is measured by

Answer»

Manometer
Polarimeter
Viscometer
Refractometer

SOLUTION :Polarimeter is an instrument USED for measuring the optical rotation. It consists of two Nicol prisms, ONE CALLED the polariser (near the light source) and the other called the analyser (near the EYE). In between the polariser and analyser, a glass tube containing the solution of an optically active compound is placed.
31.

Rotation around the bond (between the underlined atoms) is restricted in :

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`ulC_2H_4`
`H_2ulO_2`
`ulC_2H_2`
`ulC_2H_6`

ANSWER :A::B::C
32.

Rosstingofsulphidesgivesthe gas X as a byproduct .The is a colourless gaswithchoking small of burnt sulphurand cause great damage to respectively ornge as a result of acid rain its aquneous solutionis acidic , acts as a reducing agent and its acid has neverisolated .The gas X is

Answer»

`CO_(2)`
`SO_(3)`
`H_(2)S`
`SO_(2)`

Solution :`S^(2-) + O_(2) overset("Roasting")(to) SO_(2) + 2e^(Theta)`
i. Sulphideson reastingnecverform `SO_(3)` since in is PRODUCED byreacting `SO_(2)` with `O_(2)` in prenceof a catalyat`(PT , or V_(2)O_(3))` and atoptimumtemperature `(720K)` andhighpresence `(2 bar)`

ii. `SO_(2)` and `SO_(2)` bothare COLOURLESS gas but `SO_(2)` has achoking smell of `SO_(2),NO_(2)` and `SO_(2)`from atmosphareafteroxidation and reactionwithwater aremajorcontributor to acid rain
`2SO_(2(G)) + O_(2(g)) + 2H_(2)O_((1)) rarr2H_(2)SO_(4(Aq))`
`2NO_(2(g)) +_O_(2(g)) + 2H_(2)O_((1))RARR 2HNO_(3(aq))`
So `X` bo `SO_(2)` not `SO_(3)`
iii. Aqueoussolution of both `SO_(2)` and `SO_(3)` are acidic `SO_(2)` acts as reducingagent (undergo) oxidationfrom `+4 to +6`oxidation sate) but `SO_(4)` does acts as readicingagent (i.e. it has maximum oxidation sate of `+6)`
So `X` can be `SO_(2)` bot `SO_(2)`
iv `SO_(2)` reacts with `H_(2)O` as given below and `H_(2)SO_(3)` isneverisolated

Hence the anwer is (d), i.e. `SO_(2)`
33.

Rosenmund's reduction is used to prepare

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ALCOHOL
CARBOXYLIC acid
aldehyde
ketones

Answer :C
34.

Rosenmund's reductionconvert

Answer»

carboxylic ACID to aldehyde
ketonone to `2^(@)` - ALCOHOL
ACYL HALIDE to ketone
acyl halide to aldehyde

ANSWER :D
35.

Rosenmund's reductioncarried out by using

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`H_(2)//Ni`
`Na.Hg+H_(2)O`
`LiAlH_(4)`
`Pd-BaSO_(4) +` QUINOLINE

ANSWER :D
36.

Rosenmund reduction of acyl chloride gives :

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an ALCOHOL
a HYDROCARBON
an ESTER
an aldehyde.

Answer :B
37.

Rosenmund reaction can be used to obtain:

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Alkanes
Alkenes
Alcohols
Aldehydes

Answer :D
38.

Rose metal is an alloy of :

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`SN +PB +Bi`
`Sn + CU`
`Sn + SB + Cu`
None of the above

Answer :A
39.

Rosasting of copper pyrites is done:

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to remove MOISTURE and volatile impurities
to oxidise free sulphur
to decompose pyrites into `Cu_(2)S and FES`
to decompose `Cu_(2)S` into BLISTER copper

Answer :A::B::C
40.

Root of valerian plant contains

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`C_(3) H_(7) COOH`
`C_(2) H_(5) COOH`
`C_(4) H_(9) COOH`
`HCOOH`

Answer :C
41.

Roosting is carried out to

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CONVERT sulphide to oxide and sulphate
remove water of hydration
melt the ORE
remove ARSENIC and sulphur impurities

Solution :In roasting sulphide ore is converted into oxide, sulphate, during roasting moisture `(H_(2)O)` volatile oxides of metals like Se, Sb, As etc are REMOVED
42.

Role of limestone used in re extraction

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OXIDATION of FE ore
REDUCTION of Fe ore
FORMATION of slag
Purification of Fe formed

ANSWER :C
43.

Role of ATP in bioenergetics is

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releasing energy
absorbing energy
transporting energy
conservation of energy

Solution :ATP is an energy rich COMPOUND. The bond between the ribose SUGAR and the first phosphoric acid unit is an ordinary low-energy PHOSPHATE bond (ie., energy is CONSUMED when this bond is broken) but the oxygen phosphorus bonds between the other two phosphoric acid RESIDUES are high energy phosphate bonds (ie., energy is released when these bonds are broken).
44.

ROH cannot be converted into RCl on treatment with KCl, however reaction takens place on treatment with HCl. Explain

Answer»

SOLUTION :`Cl^(-)` is a WEAK nuleophile than `OH^(-)` and hence cannot replace. HOWEVER when Hcl is added, `H^(+)` of HCl protonates on oxygen atom and `H_(2)O` becomes good LEAVING group and gives `R-Cl`
45.

Rochelle salt is

Answer»

AMMONIUM tartarate
SODIUM ammonium tartarate
POTASSIUM ammonium tartarate
sodium tartarate

ANSWER :B
46.

Roasting of sulphides gives the gas X as a byproduct. This is a colourless gas with choking smell of burnt sulphur and causes great damage to respiratiory organs as a result of acid rain. Its aqueous solution is acidic, acts as a reducing agent and its acid has never been isolated. The gas X is

Answer»

`CO_(2)`
`SO_(3)`
`H_(2)S`
`SO_(2)`

Solution :Roasting of sulphides PRODUCES `SO_(2)`,
`{:(""2ZnS + 3O_(2)rarr 2ZnO + underset((X))(2SO_(2))),(2SO_(2)+2H_(2)O+O_(2)rarr 2H_(2)SO_(4)("acid rain")),(""SO_(2)+H_(2)O rarr underset("SULPHUROUS acid")(H_(2)SO_(3))):}`
Sulphurous acid acts as a reducing agent. Being unstable it has NEVER been isolated.
47.

Roasting results in the production of metal in the case of :

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IRON PYRITES
GALENA
CINNABAR
bauxite.

Answer :C
48.

Roasting process is applied to which of the following ores

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Galena
arsenoprites
copperglance
all

Solution :Roasting is the process generally used for low GRADED sulphide ores like Galena (Pbs). Iron PYRITES `(FeS_(2))` and copper GLANCE `(Cu_(2)S)`.
49.

Roasting of sulphide ore is done before smelting

Answer»

to remove moisture and volatile impurities
because SULPHIDE cannot be REDUCED easily as oxide by carbon REDUCTION
to remove earthen impurities
all of the above

Answer :A::B
50.

Roasting os sulphide ore gives the gas (A). (A) is a colourless gas. Aqueous solution of (A) is acidic. The gas (A) is

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`CO_(2)`
`SO_(3)`
`SO_(2)`
`H_(2)S`

Answer :C