Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Reaction of one molecule of HBr with one molecule of 1,3-butadiene at 40^@ C gives predominantly

Answer»

3-bromobutane under KINETICALLY CONTROLLED conditions
1-bromo-2-butene under thermodynamically controlled conditions
3-bromobutane under thermodynamically controlled conditions
1-bromo-2-butene under kinetically controlled conditions

Answer :B
Discussion
2.

Reaction of one molecule of HBr wit one moleculae 1,3-butadiene at 40^(@)Cgives predominnantly

Answer»

3-bromobutene under kinetically CONTROLLED CONDITIONS
1-bromo-2-butene under thermodynamically controlled conditions
3-bromobutene under thermodynamically controlled conditions
1-bromo-2-butene under KINETIC controlled conditions

Answer :B
Discussion
3.

Reaction of nitrous acid on 1^@ aliphatic amines in cold will give :

Answer»

A DIAZONIUM SALT
An ALCOHOL
A NITRILE
A dye

Answer :B
Discussion
4.

Reaction of methyl bromide with aqueous sodium hydroxide involves ………………….

Answer»

RACEMISATION
`S_(N^(1))` mechanism
inversion of configuration
`S_(N^(2))` mechanism

Answer :D
Discussion
5.

Reaction of methyl bromide with aqueous sodium hydroxide involves

Answer»

RECEMISATION
`S_(N)1` MECHANISM
inversion of CONFIGURATION
`S_(N)2` mechanism

Solution :The order of reactivity of `S_(N)2` reaction reaction is methyl `gt1^(@)gt2^(@)gt3^(@)` and reaction is concerted and configuration of carbon is invferted.
Discussion
6.

Reaction of m-dinitro benzene with (NH_(4))_(2)S_(x) gives

Answer»




Solution :`(NH_(4))_(2)` SX reduces ONE of `NO_(2)+ONH_(2)`
Discussion
7.

Reaction of KMnO_4 in neutral or very weakly acidic solution can be represented as

Answer»

`MnO_(4)^(-) + 2H_2O+3e^(-) RARR MnO_(2) + 4OH^(-)`
`2MnO_(4)^(-) + 2OH^(-) rarr 2MnO_(4)^(2-) + 1//2O_2 + H_2O`
`MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr MN^(2+) + 4H_(2)O`
`MnO_(4)^(-)+ e^(-) rarr MnO_(4)^(2-)`

ANSWER :A
Discussion
8.

Reaction of hydrogen bromoide with propene in the absence of peroxide is a/an

Answer»

FREE radical addition
nucleophilic addition
ELECTROPHILIC SUBSTITUTION
electrophilic addition

ANSWER :D
Discussion
9.

Reaction of HNO_(3) withI, S, P and C gives respectively

Answer»

`HIO_(3), H_(2)SO_(4), H_(3)PO_(4)` and `CO_(2)`
`HIO_(3), H_(2)SO_(4), H_(3)PO_(3)` and `CO_(2)`
`I_(2)O_(5), H_(2)SO_(4), H_(3)PO_(4) and CO`
`I_(2)O_(5), SO_(2), P_(2)O_(5)` and `CO_(2)`

SOLUTION :`10 HNO_(3) + I_2 overset(DELTA)(rarr) 2HIO_3 + 10 NO_2+ 4H_2O`
`6HNO_3 + S overset(Delta)(rarr)H_2SO_4 + 6NO_2 + 2H_2O`
`20 HNO_3 + P_(4) overset(Delta)(rarr) 4H_3PO_4 + 20 NO_2 + 4H_2O`
`4HNO_3 + C overset(Delta)(rarr)CO_2 + 4NO_2 = 2H_2O`
Discussion
10.

Reaction of HI si easiest with

Answer»

`CH_(3)OH`
`CH_(3)CH_(2)OH`
`(CH_(3))_(2)CHOH`
`(CH_(3))_(3)COH`

ANSWER :D
Discussion
11.

Reaction of HBr with propene in the presence of peroxide gives

Answer»

Allyl bromide
n-propyl bromide
Isopropyl bromide
3-bromo propane

Solution :The formation of n-propyl bromide in presence of peroxide can be explained as follows .
Step-1:peroxide undergo FISSION togive free radicals `R-O-O-R to 2 -R-overset(.)O`
Step-2:HBr COMBINES with free radical to form BROMINE free radical `R-overset.O+HBr to R-OH+overset.Br`
Step-3:`Boverset.r` attacks the double BOND of the alkene to form a more stable free radical

Step-4:More stable free radical attacks the HBr
`CH_3-dotCH-CH_2-Br+HBr to underset"n-propyl bromide"(CH_3CH_2CH_2Br+Br)`
Step-5: `Bdotr+Bdotr to Br_2`
Discussion
12.

Reaction of gasous fluorine (F_2) with compound X yields a single product Y, whose mass precent composition is 61.7% F and 38.3% Cl.Calculate Delta_fH^@ (in kJ/mol) for the synthesis of Y using following information 2ClF(g)+O_2(g)toCl_2O(g)+OF_2(g) DeltaH^@=205.6 kJ 2ClF_3(g)+2O_2(g)toCl_2O(g)+3OF_2(g) DeltaH^@=533.0 kJ Delta_f -I^@(OF_2, g)=24.7 kJ/mol

Answer»


Solution :`DeltaH_f^@=139`
no. of moles `overset(Cl)(38.7/35.5=1.09)oversetF(61.7/19=3.42)`
Simplest RELATIVE ratio 1:3
So, product Yis `CiF_3` & compound X is CIF
For the synthesis of Y reaction is `F_2(G)+CIF(g)toCIF_3(g)`
`1//2Cl_2O(g)+3//2OF_2(g)toCIF_3(g)+O_2(g) " " DeltaH^@=-533.0//2 KJ implies -266.5 kJ`
`CIF(g)+1//2O_2(g)to1//2Cl_2O(g)+1//2OF_2" " DeltaH^@=205.6//2 kJ implies 102.8 kJ`
`(F_2(g)+1/2O_2(g)toF_2O(g) " " DeltaH^@=24.7 kJ)/(CIF(g)+F_2(g)toCIF_3(g) " "Delta_fH^@=-139kJ//mol `
Discussion
13.

Reaction of glucose with (CH_3CO)_2O suggest that

Answer»

pentahydroxy aldehyde
hydrate of carbon
pentahydroxy ketone
an hexahydric aldehyde

Answer :A
Discussion
14.

Reactionof ethylformatewith excessof CH_(3)Mglfollowed by hydrolysis gives .

Answer»

n-propyl ALCOHOL
ETHANAL
propanal
isopropyl alcohol

Solution :
Discussion
15.

Reaction of formaldehyde and ammonia gives

Answer»

hexamethylene tetramine
bakelite
urea
triethylene tetramine.

Solution :FORMALDEHYDE reacts with ammonia to form hexamethylene tetramine which is used as a URINARY ANTISEPTIC.
`6HCHO + 4NH_(3) to UNDERSET("Hexamethylene tetramine")((CH_(2))_(6)N_(4)) + 6H_(2)O`
Discussion
16.

Reaction of ferrous salts withKMnO_4 is a:

Answer»

NEUTRALISATION reaction
redox reaction
auto-oxidation reaction
thermal reaction.

Answer :B
Discussion
17.

Reaction of ethylamine with chloroform in alcoholic KOH gives:

Answer»

`C_(2)H_(5)CN`
`C_(2)H_(5)NC`
`CH_(3)CN`
`CH_(3)CN.`

ANSWER :B
Discussion
18.

Reaction of ethyl chloride with sodium leads to :

Answer»

Ethane
PROPANE
n - BUTANE
n - pentane

ANSWER :3
Discussion
19.

Reaction of ethyl amine with alkaline chloroform leads to the formation of carbylamine reaction. This reaction involves the attack of an electrophile on ethyl amine, the electrophile is

Answer»

`H_(3)O^(+)`
`H^(+)`
`RNH_(3)^(+)`
`:C Cl_(2)`

Solution :`HC Cl_(3)OVERSET(OH^(-))rarr :overset(-)C Cl_(3)overset(-Cl^(-))rarr underset("deficient species)")underset("(a neutral electron")underset("DICHLOROCARBENE")( :C Cl_(2))`
Discussion
20.

Reaction of ethyl bromide with sodium cyanide gives a mixture of ethyl cyanide and ethyl isocyanide because :

Answer»

the products are ISOMERIC
`OVERSET(C)N` is an ambident nucleophile
KCN is covalent compound
a rearrangement takes place

Solution :See preparation of alkyl cyanides from alkyl HALIDES.
Discussion
21.

Reaction of ethene with Br_2 in C Cl_4 gives

Answer»

bromoethane
1,2-dibromoethane
1, 1-dibromoethane
1,1,2,2-tetrabromoethane

Answer :B
Discussion
22.

Reaction of etherwith HI is preferredthan HBr because _________.

Answer»

HI is strongerthan HBr <BR>HI giveshigherconcentrationof oxonium ION
`I^-` is a betternuclophile in `S_N2` REACTION than the `Br^(-)` ion
all of these

Answer :D
Discussion
23.

Reaction of dimethyl ether with cold HI is

Answer»

`E^2` REACTION
`SN^1` reaction
`E^1` reaction
`SN^2` reaction

Answer :D
Discussion
24.

Reaction of cyclohexanone with dimethylamine in the presence of catalytic amount of an acid forms a compound if water during the reaction is continuously removed. The compound formed is generally known as

Answer»

an amine
an imine
an anemine
a SCHIFF's BASE

SOLUTION :
Discussion
25.

Primary amines on reaction with alcoholic KOH and chloroform yields

Answer»

Hydrolysis
Reduction
Wurtz reaction
Carbylamine reaction

Answer :D
Discussion
26.

Reaction of Cl_(2) with slaked lime. (only reaction)

Answer»

Solution :`2CA(OH)_(2)+2Cl_(2)rarr CA(Ocl_(2))+CaCl_(2)+2H_(2)O`
Discussion
27.

Reaction of CH_3OCH_2CH_3 is maximum with

Answer»

HF
HCI
HBr
HI

Answer :D
Discussion
28.

Reaction of chloroform with alcoholic KOH in presence of a primary aromatic amine is called:

Answer»

Hydrolysis
Reduction
Wurtz reaction
Carbylamine reaction

Answer :D
Discussion
29.

Reaction of CH_3COOH with CH_3CH_2MgBr yields:

Answer»

An ALKENE
An ester
An ALKANE
A TERTIARY alcohol

Answer :C
Discussion
30.

Reaction of C_(6)H_(5)CH_(2)Br with aqueous sodium hydroxide follows

Answer»

`S_(N)1` mechanism
`S_(N)2` mechanism
Any of the above TWO depending upon the temperature of reaction
Saytzeff rule

SOLUTION :In AQUEOUS `NaOH, C_(6)H_(5)CH_(2)Cl` readily undergoes ionization to form benzyl cation, `C_(6)H_(5)CH_(2)^(+)` and hence its undergoes hydrolysis by `S_(N)1` mechanism.
Discussion
31.

Reaction of carbonyl compound with one of the following reagents involves nucleophilic addition followed by elimination of water. The reagent is followed bhy elimination of water. The reagent is

Answer»

HYDRAZINE in PRESENCE of FEEBLY ACIDIC solution
hydroxyanic acid
sodium HYDROGEN sulphite
Grignard reagent

Answer :A
Discussion
32.

Reaction of carboxylic acids with hydrazoic acid in presence of conc. H_(2)SO_(4) gives______with the evolution of CO_(2) and _____

Answer»

SOLUTION :PRIMARY amines, `N_(2)` GAS
Discussion
33.

Reaction of C_(6)H_(5)CH_(2)Br with aqueous sodium hydroxide follows_______.

Answer»

`S_(N)1` mechanism
`S_(N)2` mechanism
Any of the above two DEPENDING upon the temperature of reaction
saytzeff rule

Solution :In AQUEOUS NaOH, `C_(6)H_(5)CH_(2)Cl` readily undergoes IONIZATION to form stable benzyl CATION `(C_(6)H_(5)CH_(2)^(+))`
and hence it undergoes hydrolysis by `S_(N)1` mechanism and form benzyl alcohol as PRODUCT.
Discussion
34.

Reaction of C_(6)H_(5)CH_(2)Br with aqueous sodium hydroxide follows ………..

Answer»

`S_(N)1` mechanism
`S_(N)2` mechanism
Any of the above two depending upon the TEMPERATURE of reaction.
SAYTZEFF rule

Solution :The presence of polar protic solvents such as `H_(2)O` and formation of stable carbocation intermediate follows `S_(N)1` mechanism.
Discussion
35.

Reaction of C_(6)H_(5)CH_(2)Br with aqueous sodium hydroxide follows _____ .

Answer»

`S_(N)1` mechanism
`S_(N)2` mechanism
any of the above TWO DEPENDING upon the temperature of reaction
SAYTZEFF rule

Answer :a
Discussion
36.

Reaction of bromine water with glucose suggest that

Answer»

`1^(@)` ALCOHOLIC GROUP present in GLUCOSE
`2^(@)` alcoholic group present in glucose
aldehyde group present in glucose
cyclic STRUCTURE of glucose

Answer :C
Discussion
37.

Reaction of C_6H_5 CHOwith CH_3NH_2 gives

Answer»

`C_6H_5COOH`
` C_6H_5-N=NCl +2H_2O`
` C_6H_5-CH=N-CH_3`
`C_6H_5NH_2`

ANSWER :C
Discussion
38.

Reaction of Br_(2) with Na_(2)CO_(3) in aqueous solution gives NaBr and sodium bormate with evolution of CO_(2) gas. The number of NaBr molecue involved in the balanced chemical equation is ………….

Answer»


SOLUTION :`3Br_(2)+3Na_(2)CO_(3)overset(HOT)rarr 5NaBr+NaBrO_(3)+3CO`
`{:((i),[Br_(2)+overset(Θ)(O)Hoverset("Hot")toBr^(Θ)+BrO_(3)^(Θ)]),("Note:", "In cold it gives"),((ii), [Br_(2)+Ooverset(Θ)Hoverset("Cold")toBr^(Θ)+BRO^(Θ)]):}]` Both are disproportionation reaction
Discussion
39.

Reaction of Br_2 on ethylene in presence of NaCl gives

Answer»

`BrCH_2-CH_2Br`<BR>`ClCH_2-CH_2Br`
Both (a) and (B)
None of these

Solution :`CH_2=CH_2+Br_2overset"NACL"to underset"1,2-dibromoethane"(underset(Br)underset(|)CH_2-underset(Br)underset(|)CH_2)+underset"1-bromo-2-chloroethane"(undersetunderset(Cl)(|)overset2(CH_2)-undersetunderset(Br)(|)overset1(CH_2))`
Discussion
40.

Write the reaction of benzene diazonium chloride with : CuCN

Answer»


ANSWER :T
Discussion
41.

Reaction of benzenediazonium chloride with alkaline phenol gives an azo dye. This is an example of

Answer»

ELECTROPHILIC substitution
nucleophilic substitution
oxidative coupling
a free radical reaction

Solution :See properties of DIAZONIUM salt (C section)
Discussion
42.

Reaction of benzene with Me_3COCl in the presence of anhydrous AlCl_3 gives

Answer»




SOLUTION :It is because of rearrangement during which initially formed acyl CATION LOSES CO to FORM stable tertiary butyl cation
Discussion
43.

Reaction of benzene with Me_(3)"CCOCl" in the presence of anhydrous AlCl_(3) gives

Answer»




Solution :It is because of rearrangement during which INITIALLY formed acyl cation loses CO to form stable TERTIARY butyl cation.
Discussion
44.

Reaction of benzene with Me_3C""COCl in the presence of anhydrous AlCl_3 gives-

Answer»





SOLUTION :In this electrophilic substitution, removel of CO from the electrophile, acylium ion `(Me_(3)Coverset(oplus)(C) = O)` results in a more stable tertiary butyl carbocation `(Me_(3)overset(oplus)(C))`. THUS, `C_(6)H_(5)CMe_(3)` is formed as the product.
Discussion
45.

Reaction of benzene with a mixture of conc.HNO_(3) and ConcH_(2)SO_(4) at about 60^(@)C give nitrobenzene. Nitration of substituted benzenes depends on the nature of the group already present in the ring. Increase of temperature may result in multiple nitration. Which of the following compounds undergo nitration at a rate faster than the other

Answer»

Toluene
Phenol
Benzene
Chlorobenzene

Solution :`+R` GROUPS `UARR E^(+)" SUB "uarr`
Discussion
46.

Reaction of benzene with a mixture of conc.HNO_(3) and ConcH_(2)SO_(4) at about 60^(@)C give nitrobenzene. Nitration of substituted benzenes depends on the nature of the group already present in the ring. Increase of temperature may result in multiple nitration. Nitration of benzene is an

Answer»

Elechphilic addition
Electrophilic substitution
Nucleophilic substitution
Nucleophilic addition

Solution :`E^(+)` SUB REACTION
Discussion
47.

Reaction of anisole with conc. HNO_(3) and conc. H_(2)SO_(4) will give…..

Answer»

PHENOL
ORTHO NITRO ANISOLE
nitro BENZENE
o, p-nitro anisole

Solution :
Discussion
48.

Reaction of aniline with ......... yields C_6H_5N underset(to )= C and the reaction is known as ........ reaction.

Answer»

SOLUTION :`CHCl_3 - KOHcarbylamine
Discussion
49.

Reaction of aniline with benzoyl chloride gives :

Answer»

Benzoin
Benzanilide
Benzanide
None of these

Answer :B
Discussion
50.

Reaction of an acid with a base usually results in the production of

Answer»

`H_3O^+`
`H_2O`
`H^+` and `OH^-` IONS
`OH^-`

ANSWER :B
Discussion