1.

Reaction of HBr with propene in the presence of peroxide gives

Answer»

Allyl bromide
n-propyl bromide
Isopropyl bromide
3-bromo propane

Solution :The formation of n-propyl bromide in presence of peroxide can be explained as follows .
Step-1:peroxide undergo FISSION togive free radicals `R-O-O-R to 2 -R-overset(.)O`
Step-2:HBr COMBINES with free radical to form BROMINE free radical `R-overset.O+HBr to R-OH+overset.Br`
Step-3:`Boverset.r` attacks the double BOND of the alkene to form a more stable free radical

Step-4:More stable free radical attacks the HBr
`CH_3-dotCH-CH_2-Br+HBr to underset"n-propyl bromide"(CH_3CH_2CH_2Br+Br)`
Step-5: `Bdotr+Bdotr to Br_2`


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