Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Order of radioactive disintegration reaction is……

Answer»

zero
first
second
third

Answer :B
Discussion
2.

Order of paramagnetic character among following elements is/are:

Answer»

`MngtFegtCr`
`FegtZngtCr`
`CrgtFegtZn`
`CrgtMngtFe`

ANSWER :C::D
Discussion
3.

Order of nucleophilicity of oxygen containing nucleophiles

Answer»

`RO^(-) GT OH^(-) gt ROH gt H_2O`
`H_2O gt ROH gt OH^(-) gt RO^-`
`RO^(-) gt ROH gt OH^(-) gt H_2O`
`H_2O gt OH^(-) gt RO^(-)gt ROH`

ANSWER :A
Discussion
4.

Order of hydrolysis for the following ltBrgt (I) RCOCl (II) RCOOR (III) RCONH_(2) ltBrgt (IV) (RCO)_(2)O

Answer»

IgtIVgtIIgtIII
IgtIIgtIIIgtIV
IgtIIIgtIIgtIV
IVgtIIIgtIIgtI

Solution :Of all the acid DERIVATIVES, acid chlorides, i.e., `CH_(3)COCl` is most reactive.
the order of REACTIVITY of acid derivatives DECREASES in the following order.
`RCOCl gt (RCO)_(2)O gt RCOOR gt RCONH_(2)`
Discussion
5.

Order of nucleophilicity of halide ions in aprotic solvent

Answer»

`I^(-) gt BR^(-)gt Cl^(-) gt F^-`
`F^(-) gt Br^(-) gt Cl^(-) gt I^-`
`F^(-) gt Cl^(-) gt Br^(-) gt I^-`
`I^(-) gt Cl^(-) gt Br^(-) gt F^(-) `

ANSWER :C
Discussion
6.

Order of esterification of alcohols is

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`3^(@) gt 2^(@) gt 1^(@)`
`2^(@) gt 3^(@) gt 1^(@)`
`1^(@) gt 2^(@) gt 3^(@)`
none of these.

ANSWER :C
Discussion
7.

Order of base strength of the compounds :-

Answer»

IV GT II gt I gt III
III gt II gt IV gt I
II gt III gt IV gt I
II gt III gt I gt IV

Solution :
.
Discussion
8.

Order of a reaction is the power of its concentration which appears in the ________ equation.

Answer»

SOLUTION :RATE LAW
Discussion
9.

Order of acidity of alcohol is

Answer»

`1^@` GT `2^@` gt `3^@`
`3^@` gt `2^@`gt `1^@`
`1^@` gt `3^@` gt `2^@`
`3^@` gt `1^@` gt `2^@`

ANSWER :A
Discussion
10.

Order of a reaction is decided by

Answer»

PRESSURE
Temperature
Molecularity
Relative CONCENTRATION of REACTANTS

Solution :Order ofa reaction is decided by relative concentration of reactants
Discussion
11.

Order of a reaction is decided by…….

Answer»

PRESSURE
temperature
molecularity
relative CONCENTRATION of reactants.

Answer :D
Discussion
12.

Order of a reaction can not be obtained

Answer»

EXPERIMENTALLY
from stoichiometry of the reaction
if the reactants are GASES
if the reactants are in different PHYSICAL STATES

Solution :Order of a reaction can not be obtained from the balanced chemicalequationof the reaction. It is an experimental quantity.
Discussion
13.

Order of a reaction can be zero.

Answer»
Discussion
14.

Order of a reaction can be

Answer»

fractional
ZERO
INTEGER
all the above

Solution :ORDER of REACTION can be zero, integer or fractional.
Discussion
15.

Order H_(3)PO_(4) gt H_(2)SO_(4) gt HNO_(3) gt HCl is correct for :-

Answer»

ACIDIC nature
Basic strength
Viscosity
Oxidation state

Solution :`underset(3OH)overset(H_(3)PO_(4))(HO-underset(OH)underset(|)overset(O)overset(||)P-OH)""underset(2OH)overset(H_(2)SO_(4))(HO-underset(O)underset(||)overset(O)overset(||)S-OH)""underset(OH)overset(HNO_(3))(HO-underset(O)underset(DARR)N=O)"" underset("No OH")(HCl)`
Discussion
16.

Order of a reaction can be 0, 1, 2, 3, or even a ___________ .

Answer»

SOLUTION :FRACTION
Discussion
17.

Order of a chemical reaction.

Answer»

Solution :The order of a chemical reaction is defined as the number of molecules (or atoms) WHOSE CONCENTRATIONS influence the rate of the chemical reaction.
OR
The order of a chemical reaction is defined as the sum of the POWERS (or exponents) to which the concentration terms of the reactants are raised in the rate LAW expression for the GIVEN reaction.
Discussion
18.

Order and Molecularity of the reaction.

Answer»

Solution :`{:("Order","Molecularity"),("1. Ot is the sum of the exponents to which the concentration TERMS in rate law EXPRESSION are raised.","1. It is the number of molecules (or ATOMS or ions) of the reactants taking parts in the elementary REACTION."),("2. It is experimentally determined and indicates the dependance of concentration of particular reactants.","2. It is theoretical property and indicates the number of molecules of reactant in each step of the reaction."),("3. It may have values which are integer, freactional or zero.","3. It is always an integer."),("4. Its value depends upon experimental conditions.","4. Its value does depends upon experimental conditions."),("5. It is the property of elementary and complex reactions.","5. It is the property of elementary reactions only."):}`
Discussion
19.

Orbital interaction between the sigma bonds of a substituent group and neighbouringp-orbital is known as

Answer»

HYPERCONJUGATION
INDUCTIVE effect
steric effect
dipole-dipole INTERACTIONS.

Answer :A
Discussion
20.

Orbital angular momentum of p-subshell is:-

Answer»

`(3H)/(pi)`
`(6H)/(2pi)`
`(h)/(sqrt(2)pi)`
`(h)/(2pi)`

Answer :C
Discussion
21.

Orbital angular momentum depends upon

Answer»

L VALUES
l+m values
n and l
l and m

Answer :B
Discussion
22.

Orange colouredsodiumcobaltinitrite Na_(3)[Co(NO_(3))_(6)] is used for thedetectionof K^(Theta) whichgives …… pptdue to theformation of pot sod cobaltinitrite K_(2)Na[Co(NO_(2))_(6)]

Answer»

White
Orange
Yellow
Brown

Answer :C
Discussion
23.

"Orange solid"overset(Delta)rarrunderset(gas)"diamagnetic"+underset("residue")"green" underset("solid"(X_(2)))"Orange"overset(Delta)rarrunderset("magnetic(gas)")"para"+underset(("residue"))"green"+underset("(solid)")"yellow" X_(1) and X_(2) are respectively:

Answer»

`Na_(2)Cr_(2)O_(7),K_(2)Cr_(2)O_(7)`
`(NH_(4))_(2)Cr_(2)O_(7),Na_(2)Cr_(2)O_(7)`
`K_(2)Cr_(2)O_(7),(NH_(4))_(2)Cr_(2)O_(7)`
`(NH_(4))_(2)Cr_(2)O_(7),KNO_(3)`

Answer :B
Discussion
24.

Orangecolourof Cr_(2)O_(7)^(2-)ioncharges toyellowin alkaliand yellowsolutionturnsout orangeon adding H^(+) ions.Explainwhy ?

Answer»

Solution :(i)Whenorangesolutioncontaining`Cr_(2) O_(7)^(2-)` ION is treatedwith analkali a YELLOWSOLUTION of `Cr_(2)O_(4)^(2-)` is obtained .
(ii)Similarly when `H^(+) ` ionsare addedto yellowsolutionan orangesolutionof `Cr_(2)O_(7)^(2-) ` isobtaineddue tointerrconversion.
Discussion
25.

Orangecolourcompoundis obtainedwhenbenzenediazonium chlorideand what .

Answer»




ANSWER :B
Discussion
26.

Oral contraceptive drugs contain

Answer»

Mestanol
Norethin drone
Equinal
Barbutyric ACID

SOLUTION :NORETHINDRONE is ORAL CONTRACEPTIVE
Discussion
27.

Option with correctly matched reactant and product is/are :

Answer»

`"C"Cl_(3)-underset(O)underset(||)C-H underset(Delta)OVERSET(Ooverset(ϴ)H)rarr "C"Cl_(3)-COO^(ϴ)+"C"Cl_(3)-CH_(2)-OH`


ANSWER :B::C
Discussion
28.

Optically pure (S)-(+)-2bromo octane [alpha]_(D)^(25^(@)C)=+36^(@), react with aqueous NaOH in acetone to give optically pure (R)-(-)-2-octanol [alpha]_(D)^(25^(@)C) =-10.3^(@). With partially racemized bromo compound whose [alpha]_(D)^(25^(@)C)=30^(@), the [alpha]_(D)^(25^(@) of the alcohol product is - 6.0^(@). Calculate the percentage of frontside attack :

Answer»

`15%`
`85%`
`30%`
`58%`

SOLUTION :N//A
Discussion
29.

Optically pure (S)-(+)-2bromo octane [alpha]_(D)^(25^(@)C)=+36^(@), react with aqueous NaOH in acetone to give optically pure (R)-(-)-2-octanol [alpha]_(D)^(25^(@)C) =-10.3^(@). With partially racemized bromo compound whose [alpha]_(D)^(25^(@)C)=30^(@), the [alpha]_(D)^(25^(@) of the alcohol product is - 6.0^(@). Calculate the per cent optical purity of partially racemized bromo compound :

Answer»

`58%`
`83%`
`70%`
`30%`

SOLUTION :N//A
Discussion
30.

Optically active tert alkyl halide given below on hydrolysis gives recemic mixture. Soparation of (d)and (l) form from the recemic mixture is known as resultuion. C_(6)H_(5)-overset(C_(6)H_(13)) overset(|)underset(CH_(3))underset(|)(Br)- overset(HOH)toC_(6)H_(5)C-overset(C_(6)H_(13)) overset(|)underset((X))underset(CH_(3))underset(|)C-OH+HO-overset(C_(6)H_(13)) overset(|) underset((Y))underset(CH_(3)) underset(|)C-C_(6)H_(5) Which of these statements are correct for the given reaction ? 1 Reaction intermediate is carboncation (2) Product formation takes place by formation of TS. (4) There is inversion as well as retention of configuration (4) Reaction is known as hydrolysis, i.e, solvolysis. Of these statements

Answer»

1, 3 and 4 are correct
1, 2 and 3 are correct
3 and 4 are correct
1 and 4 are correct

ANSWER :A
Discussion
31.

Optically active compound is ,

Answer»

2-chloropropane
2-chlorobutane
3-chloropentane
None

Answer :B
Discussion
32.

Optically pure (S)-(+)-2bromo octane [alpha]_(D)^(25^(@)C)=+36^(@), react with aqueous NaOH in acetone to give optically pure (R)-(-)-2-octanol [alpha]_(D)^(25^(@)C) =-10.3^(@). With partially racemized bromo compound whose [alpha]_(D)^(25^(@)C)=30^(@), the [alpha]_(D)^(25^(@) of the alcohol product is - 6.0^(@). Calculate the precentage of racemization :

Answer»

`58%`
`83%`
`70%`
`30%`

SOLUTION :N//A
Discussion
33.

Optically pure 2(S)-butanol is subjected to the following reaction 2 (S) - Butanol underset(Na)(rarr)X overset(CH_1I)(rarr) , which of the following statements is correct for stereo cemical outcome of the reaction

Answer»

The reaction proceeds with INVERSION 
The reaction proceeds with racemisation 
The reaction proceeds with complete retention of configuration 
The reaction LEADS to destruction of chiralily in the MOLECULE 

Answer :C
Discussion
34.

Optically active tert alkyl halide given below on hydrolysis gives recemic mixture. Soparation of (d)and (l) form from the recemic mixture is known as resultuion. C_(6)H_(5)-overset(C_(6)H_(13)) overset(|)underset(CH_(3))underset(|)(Br)- overset(HOH)toC_(6)H_(5)C-overset(C_(6)H_(13)) overset(|)underset((X))underset(CH_(3))underset(|)C-OH+HO-overset(C_(6)H_(13)) overset(|) underset((Y))underset(CH_(3)) underset(|)C-C_(6)H_(5) Which one of the following statements is NOT true for (A) and (B) the above reaction ?

Answer»

(X) and (Y) are enatiomers
Physiscal and CHEMICAL properties of (X) and (Y) are same except TWO physical properties
(X) and (Y) can be separated from the mixture by the use of `CH_(3)-COOH`
(X) and (Y) can be separated by the use of `(CH_(3)-CHOH-COOH`

Answer :C
Discussion
35.

Optically active 'P' has the molecular formula C_(6) H_(12) and catalytic hydrogenation converts into achiral C_(6) H_(14) . The structure of 'P' is -

Answer»




SOLUTION :
Discussion
36.

Optically active (S)-alpha-methoxyacetaldehyde on reaction with MeMgX gave a mixture of alcohols. The major diastereomer 'P' on treatment with MeI//K_(2)CO_(3) gave an optically inactive compound. P is -

Answer»

`i`
`ii`
`iii`
`iv`

Solution :Incorrect question
The STATEMENT OPTICALLY active `(s) - ALPHA -` methoxy ACETALDEHYDE is incorrect.
Discussion
37.

Optically active polyhydroxy aldehydes or ketones are known as

Answer»

AMINO acids 
PROTEINS 
Lipids 
Carbohydrates 

ANSWER :D
Discussion
38.

Optically active isomers but not mirror images are called

Answer»

ENANTIOMERS
MESOMERS
TAUTOMERS
DIASTEREOMERS

ANSWER :D
Discussion
39.

Optically active isomers are also called:

Answer»

Epimers
Anomers
Conformers
Enantiomers

Answer :D
Discussion
40.

Optically active 2-iodobutane on treatment with sodium iodide in acetone gives a product which does not show optical activity. Explain.

Answer»

Solution :Optically ACTIVE 2-iodobutane DISSOCIATED to form iodide ion and the carbocation.
The iodide ion then attacks the flat carbocation from either side resulting in a mixture of two ENANTIOMERIC products in equal amounts, which CONSTITUTES a RACEMIC mixture which does not show optical activity.
Discussion
41.

Optically active 2-iodobutane on treatment wit NaI in acetone gives a product which does not show optical activity. Expalain.

Answer»

Solution :OPTICALLY active 2-iodobutane on treatment with NaI in acetone undergoes racemization and HENCE the product does not show optical activity as explained below:
When optically active 21-iodobutane (I) is treated with `I^(-)` ion, it undergoes WALDEN inversion (`S_(N)2` raction) to give 2-iodobutane (II) which is the enantiomer of (I). Now 2-iodobutane (II) undergoes Walden inversion to give enantiomer (I). As a RESULT of repetition of these two Walden inversion, ultimately a 50:50 mixture of the two enantiomers is obtained
Discussion
42.

Optically active 2-iodobutane on treatment with sodium iodide in acetone gives a product which does not show optical activity. Explain

Answer»

SOLUTION :OPTICALLY ACTIVE 2-iodobutane dissociated to FORM iodide ion and the carbocation. The iodide ion then attacks the flat carbocation from either side resulting in a mixture of two enantiomeric products in equal amounts, which constitutes a racemic mixture which does not show optical activity.
Discussion
43.

Optically active 2-iodobutane on treatment with Nal in acetone gives a product which does not show optical activity. Explain briefly.

Answer»

Solution :There occurs breaking and reforming of C-1 bond. This resutls into two enantiomers which FORM racemic mixture which does not show optical activity due to EXTERNAL compensation.
`H-UNDERSET(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-Ioverset((i)-I^(-))underset((ii)+I^(-))rarrH-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-I+I-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-H`
Discussion
44.

Optically active 2-bromobutane on treatment with NaI in acetone gives a product which does not show optical activity. Explain briefly.

Answer»

SOLUTION :The product OBTAINED after the reaction contain equal amount of both d and l-isomers of 2-iodobutane and this RACEMIC mixture does not show OPTICAL activity due to EXTERNAL compensation.
Discussion
45.

Optical isomers which are non-superimpo sable mirror images of each other are called

Answer»

ENANTIOMERS
DIASTEREOMERS
TAUTOMERS
GEOMETRICAL isomers

Answer :A
Discussion
46.

Optical isomers essentially have

Answer»

SUPER IMPOSABLE MIRROR image
asymetric CARBON atom
nonsuper imposable mirror iamge
symetric carbon atom

Answer :C
Discussion
47.

Optical isomers have A) property of chirality B) almost identical chemical properties C) almost identical physical properties D) similar rotation of plane polarised light

Answer»

A,B,C are CORRECT
B,C,D are correct
A,C,D are correct
A,B,D are correct

Answer :A
Discussion
48.

Optical isomerism not show by :-

Answer»

`Cl-CH=C=CH-CH_(3)`
`CH_(3)CH(Br)CH(Cl)CH_(3)`
`C_(2)H_(5)CH(Br)CH_(2)CH_(3)`
`CH_(3)-CH=CH-CH(OH)CH_(3)`

Answer :C
Discussion
49.

Optical isomers differ in

Answer»

CHEMICAL properties
molecular formulae
physical properties
optical properties

Answer :D
Discussion
50.

Optical isomerism is exhibited by (ox = oxalate anion, en = ethylene diamine)

Answer»

`cis-[CrCl_(2)(o x)_(2)]^(3-)`
`[Co(en)_(3)]^(3+)`
trans-`[CrCl_(2)(o x)_(2)]^(3-)`
`[Co(o x)(en)_(2)]^(+)`

Solution :trans-isomers (c ) has a plane of SYMMETRY and hence does not SHOW optical isomerism.
Discussion