Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Indicate the correct answer out of the following for the below reaction. NH_(4)Cl + H_(2)O

Answer»

The reaction is not favoured by the ADDITION of KOH.
The reaction is favoured by the addition of `NH_(4)OH`.
The reaction is not favoured by the addition of HYDROGEN ion
The reaction is favoured by the addition of hydrogen ion.

Solution :Ionic FORM of the reaction is
`NH_(4)^(+) + H_(2)O
2.

Indicate the complex ion which shows geometrical isomerism :

Answer»

`[Cr(H_(2)O)_(4)Cl_(2)]^(+)`
`[Pt(NH_(3))_(3)Cl]^(+)`
`[CO(NH_(3))_(6)]^(3+)`
`[Co(CN)_(5)(NC)]^(3-)`

Answer :A
3.

Indicate the colour of compound Z formed in the given reaction , C_(6)H_(5)NO_(2)overset(Fe//HCl)rarrXunderset(273k)overset(HNO_(2))rarrY overset(C_(6)H_(5)OH)rarrZ.

Answer»

ORANGE
RED
BLUE
Yellow

Solution :
4.

Indicate the complex ion which shows geometrical isomerism

Answer»

`[CR(H_(2)O)_(4)Cl_(2)]^(+)`
`[Pt(NH_(3))_(3)Cl]`
`[Co(NH_(3))_(6)]^(3+)`
`[Co(CN)_(5)(NC)]^(3-)`

Solution :(a) is of the type `MA_(4)B_(2)` and shows geometrical isomerism.
5.

Indicate the complex ion which shows geometrical isomerism.

Answer»

`[Cr(H_(2)O)_4)Cl_(2)]^(+)`
`[Pt(NH_(3))_(3)CL]`
`[Pt(NH_(3))_(6)]^(3+)`
`[CO(CN)_(5)(NC)]^(3-)`

ANSWER :A
6.

Write basicity of H_3PO_2,H_3PO_3 and H_3PO_4 .

Answer»

Solution :Basicity of `H_3PO_4` IS 3 (Tribasic acid)
Basicity of `H_3PO_3` is 2 (DIBASIC acid )
Basicity of`H_3PO_2` is 1 (monobasic acid)
7.

Indicate more stable carbocation and explain :

Answer»


SOLUTION :N//A
8.

Indicate in which case/cases the spontaneity of a change is favoured when

Answer»

`DELTAG` is +ve
`DELTAH` is -ve
`DeltaS` is +ve
`DeltaS` is `-ve`

ANSWER :B::C::D
9.

Indicate bonds which are cleaved I: In basic contions II: in acidic conditions

Answer»


SOLUTION :N//A
10.

Indicate a chemical reaction involvind a homogenous catalyst.

Answer»

SOLUTION :`2SO_(2)(G)+O_(2)(g) overset(NO(g))to2SO_(3)(g)` (Lead chamber process for MANUFACTURE of sulphuric acid).
11.

India has the world's largest deposite of thorium in the form of

Answer»

Rutile
Magnesite
Lignite
Monazite

Answer :D
12.

Indian salpetre is:

Answer»

`KNO_3`
`NaNO_3`
NACL
`Na_2CO_3`

ANSWER :A
13.

India conducted an underground nuclear test at

Answer»

Tarapur
Narora
Pokhran
Pushkar

Answer :C
14.

Indentigy the set of reagents/reacatns conditins (X) and (Y) in the followingset of transforamtion: CH_(3) - CH_(2) - CH_(2) Br overset((Br))(rarr) underset(Br)underset(|)underset(CH_(3)-CH-CH_(3))underset(darr (Y))("Product")

Answer»

`(X)` = Dilute aqueosu`NaOH, 20^(@)C`
`(Y) = HBr//"acetic"` acid, `20^(@)C`
`(X)` = CONCENTRATED alcholic `NaOH, 80^(@)C`
`(Y) = HBr//"acetic"` acid, `20^(@)C`
`(X)` =Dilue aqueous`NaOH, 20^(@)C`
`(Y) = Br_(2)//CHCl_(3), 0^()c`
`(X)` = Concentrateed alcoholic `NaOH, 80^(@)C`
`(Y) = Br_(2)//CHCl_(3), 0^()c`

Solution :`RX overset(X)(rarr) "Alkene" overset(Y)(rarr) "Isomer of RX"`
For `X`, the conditions given are:
`{:(a,b,c,d),(Dil.aq.,CONC. Alcoholic,Dil.aq.,Conc. Alcoholic),(NaOH,NaOH,NaOH,NaOH),(20^@C,80^@C,20^@C,80^@):}`
So conditions (a) and (c) are same and not required becuase in aq. `NAOH. SN^(2)` reaction will OCCUR to give `ROH`.
[So condtions for `E2`ELIMINATION is conc. alcoholic
`NaOH` at `80^(@)C` (Conditions (b) and (d) are same.)]
For `Y` conditions given are:
`{:(a,b,c,d),(HBr//"acetic".,HBr//"acetic",Br_(2)//CHCl_(3),Br_(2)//CHCl_(3)),("acid","acid",,),(at20^@C,at20^@C,at0^@C,at0^@):}`
Conditions (c) and (d) are not required becuase they do not give the desiredproduct.
Only condition for `(Y)` is `(a)` or `(b)`
But for `(X)` is as in `(b)`, and conditionfor `(Y)` as in `(b)`.
15.

Indentify the true statement(s)

Answer»

A catalyst is chemically unchanged at the end of a REACTION
A catalyst MAY appear in the kinetic rate equation of the reaction
A catalyst will not affect the composition of an EQUILIBRIUM mixture
A catalyst cannot cause a non-spontaneous `(DeltaG gt 0)` reaction to proceed

Answer :A::B::C::D
16.

Indentify the following ions by a simple test forming complex compound : (i)Cu^(2+)(ii)Ni^(2+)(iii)Fe^(3+)(iv)Co^(2+)

Answer»

Solution :(i) ` Cu^(2+) ` solution with excesses of AMMONIA solution, `NH_(4)OH` FROMS a deep BLUE coloured complex.
` underset(ap)(Cu^(2+)) + 4NH_(4)OH_(aq) to [Cu(NH_(3))_(4)]^(2+) + 4H_(2)O`
(b) ` Cu^(2+)` with potassium hexacyanoferrate (II) forms red - brown PRECIPITATE which is a complex, ` Cu_(2) [Fe(CN)_(6)]`
` 2Cu^(2+) + K_(4)[Fe(CN)_(6)] to Cu_(2)[Fe(CN)_(6)]`
red brown
(ii) `Ni^(2+)`with dimethylgloxine (DMG) in ammonical alcoholic solution forms rosy-red precipitate of a complex.
` (##NVT_21_CHE_XII_C18_E01_001_S01.png" width="80%">
(iii) (a) ` Fe^(3+) ` with `K_(4)[Fe (CN)_(6)]`forms prussian blue compound of deep blue colour .
` Fe^(3+) + K_(4)[Fe(CN)_(6)] to overset(III""II )(K[Fe(CN)_(6))] + 3K^(+)`
prussian blue
(b) ` Fe^(3+) ` with ammonium thiocyanate `NH_(4)SCN` forms deep red compound .
` Fe^(3+) + 3NH_(4)SCN to underset("deep red")(Fe(SCN)_(3)) + 3NH_(4)^(+)`
17.

Indentify (A),(B),(C), (D) and (E) in the following shcemes and write their structure

Answer»


ANSWER :A::C
18.

Indentify (A) to (E). a. 1,3- Butadience + BrCCl_(3) + "Preoxide" rarr (A) b. RCH = CH_(2) + CCl_(4) overset("Peroxide")(rarr) (B) + (C) c. 1- Octene + CHCl_(3) overset("Peroxide")(rarr) (D) 1- Octene + CbrCl_(3) overset("Peroxide")(rarr) (E)

Answer»

SOLUTION :a. This is RADICAL ADDITION which typically gives mainly the `1,4-` adduct.

Prodouct `(C)` can be obtained by thecombinationof TWO intermedicate free radicals.
`R dot(C) HCH_(2) CCl_(3) + RCH(Cl)dot(C) H_(2)`



19.

Increasing value of spin only magnetic moments of :- (I) [Fe(CN)_(6)]​^( 4–) (II) [Fe(CN)_6]^(​ –3)(III) [Cr(NH_(3))_(6)]​ ^(3+)(IV) [Ni(H_(2)O)_(4)]​^( 2+ )

Answer»

I LT II lt III lt IV
IV lt III lt II lt I
II lt III lt I lt IV
I lt II lt IV lt III

ANSWER :D
20.

Indentifiy the incorrect statement regarding chemical equlibrium

Answer»

It can be attained from EITHER side
`Q_(c)=K_(c)` at EQULIBRIUM
Equlibreium is achieved when the REACTANT and product concentration become equal
Presence of catalyst influences the POSITION of equlibrium

ANSWER :C
21.

Increasing the temperature of an aqueous solution wil case

Answer»

DECREASE in molality
decrease in molarity
decrease in mole fraction
decrease in % (WW).

Solution :An increase in temperature INCREASES the volume of the solution and THUS decreases its molarity.
22.

Increasing the temperature of an aqueous solution will cause

Answer»

DECREASE in molality
decrease in molarity
decrease in MOLE fraction
decrease in `%` w/w.

SOLUTION :On increasing the TEMPERATURE, volume of the solution increases. Hence molarity decreases.
23.

Increasing the temperature of an aqueous solution will cause -

Answer»

DECREASE in molality
decrease in molarity
decrease in MOLE fraction
decrease in % (w/w)

ANSWER :B
24.

Increasing the adsorbing power iof an adsorbent by suddividing it is called ……… of the solid adsorbent.

Answer»

SOLUTION :ACTIVATION
25.

Increasing order of thermal stability is :

Answer»

`BeCO_(3)ltMgCO_(3)ltCaCO_(3)ltK_(2)CO_(3)`
`K_(2)CO_(3)ltMgCO_(3)ltCaCO_(3)ltBeCO_(3)`
`BeCO_(3)ltMgCO_(3)ltK_(2)CO_(3)ltCaCO_(3)`
`MgCO_(3)ltBeCO_(3)ltCaCO_(3)ltKCO_(3)`

ANSWER :A
26.

Increasing pK_(a) values of o-, and p- cresols is

Answer»

<P>`o LT p lt m`
`m lt p = o`
`m lt o lt p`
`p lt o lt m`

ANSWER :B
27.

Increasing order of strength of oxyacids of chlorine is:

Answer»

`HClOltHClO_2ltHClO_3ltHClO_4`
`HClO_4ltHClO_2ltHClOltHClO_3`
`HClOltHClO_2ltHClO_3ltHClO_4`
None

Answer :C
28.

Increasing order of stability of the +2 oxidation of the ions?

Answer»

`CA^(2+)LTBA^(2+)ltSr^(2+)`
`PB^(2+)ltGe^(2+)ltSn^(2+)`
`Ge^(2+)ltSn^(2+)ltPb^(2+)`
`Cu^(2+_,TAU^(2+)ltAg^(2+)`

Answer :C
29.

Increasing order of stability among the three main conformations (i.e, eclipse, anit, gauche) of 2-fluroethanol is

Answer»

ECLIPSE, GAUCHE, ANTI
gauche, eclipse, anti
eclipse, anti, gauche
anti, gauche, esclipse

Answer :C
30.

Increasing order of stability among the three main conformations of 2-Fluroethanol is :

Answer»

ECLIPSE, GAUCHE, ANTI
gauche, eclipse, anti
eclipse, anti, gauche
anti, gauche, esclipse

Answer :C
31.

Increasing order of stability among the three main conformation (i.e., eclipse,anti,gauche) of 2-fluoroethanol is:

Answer»

ECLIPSE,GAUCHE,ANTI
gauche,eclipse,anti
eclipse,anti,gauche
anti,gauche,eclipse

Answer :C
32.

Increasing order of solubility is

Answer»

`CaCO_(3),KHCO_(3),NaHCO_(3)`
`NaHCO_(3),KHCO_(3),CaCO_(3)`
`KHCO_(3),NaHCO_(3),CaCO_(3)`
`CaCO_(3),NaHCO_(3),KHCO_(3)`

Solution :`CaCO_(3) lt NaHCO_(3) lt KHCO_(3)` is the INCREASING order of solubility.
33.

Increasing order of reactivity of the following alkyl halide in the Willamson's synthesis is underset(I)(CH_2=CHCH_2CI), underset(II)(CH_3CH_2CH_2Br),underset(III)((CH_(3))C CH_2Br),underset(IV)(CH_3CH_2CH_2CI)

Answer»

`II lt III lt IV lt I`
`III lt II lt IV lt I`
`IV lt III lt I lt II`
`III lt IV lt II lt I`

SOLUTION :`CH_2=CH-CH_2-CI` ("Allylic and 1^(@)) gt`CH_3CH_2CH_2-Br(1^(@)`and C-Br BOND) gt`CH_3CH_2CH_2-CI(1^(@)and C-CI bond) gt`
`(CH_(3))_(3)CCH_2Br` (Neopentyl bromide, a sterically HINDERED R-X)
34.

Increasing order of reactivity of alkyl halide is

Answer»

`R-FltR-BrltR-O=I`
`R-IltR-BrltR-ClltR-F`
`R-IltR-BrltR-FltR-Cl`
`R-ClltR-FltR-BrltR-I`

Solution :Alkyl iodides are more REACTIVE than other HALIDE because C-I BON is wekae than others,, it ATTACKS easily by REAGENTS.
35.

Increasing order of intermolecular forces of the following polymers is

Answer»

NEOPRENE, PVC, NYLON -6
Nylon, PVC, Neoprene
PVC, Neoprene, Nylon -6
Neoprene, Nylon -6, PVC

Answer :A
36.

The increasing order of the rate of HCN addition of compound a-d is (i) HCHO (ii) CH_(3)COCH_(3) (iii) PhCOCH_(3) (iv) PhCOPh

Answer»

`IV LT ii lt iii lt i`
`iv lt iii lt ii lt i`
`iii lt iv lt ii lt i`
`ILT ii lt iii lt iv`.

ANSWER :B
37.

Increasing order of electronegativity is

Answer»

<P>`BI LT P lt S lt CL`
`P lt Bi lt S lt Cl`
`S lt Bi lt P lt Cl`
`Cl lt S lt Bi lt P`

ANSWER :A
38.

Increasing order of carbon-carbon bond length for the following is : {:(C_(2)H_(4),C_(2)H_(2),C_(6)H_(6),C_(2)H_(6)),((A),"(B)",(C),(D)):}

Answer»

`B LT C lt A lt D`
`C lt B lt A lt D`
`B lt A lt C lt D`
`D lt C lt A lt B`

ANSWER :C
39.

Increasing order of basic nature of NH_(3) (I), CH_(3)NH_(2) (II) "and" C_(6)H_(5)NH_(2) (III) is

Answer»

`III lt I lt II`
` I ltII lt III `
`III lt II lt I`
`I lt III lt II`

SOLUTION :Due to electron-donating inductive effect of alkyl groups and electron-withdrawing RESONANCE effect of `C_(6)H_(5)` ring, aliphatic amines are stronger BASES than `NH_(3)` while aromatic amines are WEAKER bases than `NH_(3)` .Thus, option (a) is correct.
40.

Increasing order of carbon-carbon bond length for the following is : (i) C_(2)H_(4) (ii) C_(2)H_(2) (iii) C_(6)H_(6) (iv) C_(2)H_(6)

Answer»

`BltCltAltD`
`CltBltAltD`
`BltAltCltD`
`DltCltAltB`

SOLUTION :`C_(6)H_(6)(C )` have -C-C and -C`==`C- bonds so benzene has an AVERAGE bond length of two bonds, i.e 1.40 Å.
`C_(2)H_(4)` (A) has bond ,having bond length 1.34 Å.
`C_(2)H_(4)` (B) has`-C-=C` - bond,having bond length 1.21 Å
`C_(2)H_(6)` (D) having bond,having bond length 1.54 Å `THEREFORE` Increasing order of bond length is
`BltAltCltD`
41.

Increasing order of boiling points is:

Answer»

`H_2O GT H_2S gt H_2Se gt H_2Te`
`H_2O gt H_2Te gt H_2Se gt H_2S`
`H_2O gt H_2Se gt H_2Te gt H_2S`
`H_2O gt H_2S gt H_2 TE gt H_2Se`

ANSWER :B
42.

Increasing order of boiling points is: 1) H_2O gt H_2S gt H_2Se gt H_2Te2) H_2O gt H_2Te gt H_2Se gt H_2S3) H_2O gt H_2Se gt H_2Te gt H_2S 4) H_2O gt H_2S gt H_2 Te gt H_2Se

Answer»

`H_2O GT H_2S gt H_2Se gt H_2Te`
`H_2O gt H_2Te gt H_2Se gt H_2S`
`H_2O gt H_2Se gt H_2Te gt H_2S`
`H_2O gt H_2S gt H_2 TE gt H_2Se`

ANSWER :B
43.

Increasing order of acidic character would be

Answer»

`CH_(3)COOH lt H_(2)SO_(4) lt H_(2)CO_(3)`
`CH_(3)COOH lt H_(2)CO_(3) lt H_(2)SO_(4)`
`H_(2)CO_(3) lt CH_(3)COOH lt H_(2)SO_(4)`
`H_(2)SO_(4) lt H_(2)CO_(3) lt CH_(3)COOH`

ANSWER :C
44.

Increasing order of acid strengths of hydrogen halides is:

Answer»

HF`LT`HCL`lt`HBR`lt`HI
HCl`lt`HI`lt`HBr`lt`HF
HCl`lt`HBr`lt`HI`lt`HF
None

Answer :A
45.

Increasing order of acid strength among tert butanol, isopropanol and ethanol is :

Answer»

Ethanol, ISOPROPANOL,tert butanol
Tert butanol,isopropanol, ethanol
Isopropanol, tert butanol, ethanol
Tert butanol, ETHARIOL, isopropanol

Answer :B
46.

Increasing order of acid strength among p-methoxphenol, p-methylphenol and p-nitrophenol is

Answer»

<P> p-nitrophenol,p -METHOXYPHENOL,p-methylphenol
p-methylphenol, p-methoxyphenol, p-nitrophenol
p-nitrophenol, p-methylphenol, p-methoxyphenol
p-methoxyphenol,p-methylphenol, p-nitrophenol.

ANSWER :D
47.

Increasing amoutn of HgI_(2)is added to 1 litre of an aqueous solution containing0.1mole of KI.Which of the following graphs does represent the variation of depression in freezing point of the resulting solution with the amount of HgI_(2)added?

Answer»




Solution :`2KI_(aq)+HgI_(2(s))rarrK_(2)HgI_(4)(aq)or2K^(+)+2I^(-)+HgI_(2(s))rarr2K^(+)+[HgI_(4)]^(2-)` As a RESULT of complex ion formation, THENO. Of mole particles in the solution decreases in the RATIO `4:3`So`DeltaT_(f)`decreases until all the `I^(-)` ions are consumed with`0.05` moles of `HgI_(2)`. The excess of `HgI_(2)`remain insoluble .Hence after `0.05`moles of `HgI_(2)`, the `F.P.` of solution REMAINS constant.
48.

Increasing basic properties of TiO_(2), ZrO_(2) and HfO_(2) are in order :

Answer»

`TiO_(2) LT ZrO_(2) lt HfO_(2)`
`HfO_(2) lt ZrO_(2) lt TiO_(2)`
`HfO_(2) lt TiO_(2) lt ZrO_(2)`
`ZrO_(2) lt TiO_(2) lt HfO_(2)`

ANSWER :A
49.

Increasing amount of solid Hgl_(2) is added to 1 L of an aqueous solution containing 0.1 mol KI. Which fo the following graphs do represent the variation of freezing point of the resulting with the amount of Hgi_(2) added?

Answer»





Solution :When `H_(g)I_(2)` is ADDED to KI:
`HgI_(2)+2KitoK_(2)HgI_(4)`
Mole` 0.05""0.2""0.1""0.05`
`implies`0.05moles ofare REQUIRED for its complete reaction with KI.
Thus, as `HgI_(2)`is being added, number of SOLUTE molecules will decrease causing `DeltaT_(f)`to decrease[Causing `T_(g)`to increase]. When whole of KI has been converted to `K_(2)HgI_(4)` , further addition of `HgI_(2)` doesn’t change the `T_(g)`since it is a sparingly soluble SALT.
50.

Increased blood pressure may be caused by excess secretion of :

Answer»

Thyroxin
Testosterone
Estradiol
Adrenalin

Answer :D