Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the following reaction sequnce:underset(C_(6)H_(5)Cl_(2))(I)overset(KOH(aq))(to)(II)overset((i)CH_(3)MrBr)underset((ii)H_(2)"O/"H^(+))(to)(III)overset(anhy.ZnCl_(2)+conc.HCl)(to)"giventurbidite immediately" Thecompounds 1 is :

Answer»

`underset(CL)underset(|)(C)H_(2)-underset(Cl)underset(|)(C)H-CH_(3)`
`underset(Cl)underset(|)(C)H_(2)-CH_(2)-underset(Cl)underset(|)(C)H_(3)`
`CH-underset(Cl)underset(|)(C)H-CH_(2)-CH_(3)`
`CH_(3)-underset(Cl)underset(|)OVERSET(Cl)overset(|)(C)-CH_(3)`

Solution :
2.

In the clathrates of xenon with water, the nature of bonding between xenon and water molecules is:

Answer»

COVALENT
HYDROGEN bonding
Co-ordinate
Dipole-induced dipole

Answer :D
3.

In the chromyl chloride test, the reagent used is

Answer»

`K_(2)CrO_(4)`
`K_(2)Cr_(2)O_(7)+NaOH`
`K_(2)Cr_(2)O_(7)+H_(2)SO_(4)`
`(NH_(4))_(2)Cr_(2)O_(7)`

Solution :INFORMATIVE
4.

In the following reaction the compound Z is

Answer»

BENZOIC acid
Benzaldehyde
Acetophenone
Benzene

Answer :B
5.

In the chromyl chloride test, the reagent used is:-

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`K_(2)CrO_(4)`
`CrO_(3)`
`K_(2)Cr_(2)O_(7)`
`(NH_(4))_(2)Cr_(2)O_(7)`

ANSWER :C
6.

In the following reaction, the compound Z is

Answer»

BENZOIC acid
BENZALDEHYDE
ACETOPHENONE
BENZENE .

Solution :
7.

In the chorination of isobutane (2-methyl propane) the major product is

Answer»

`CH_(3)CH_(2)CH_(2)Cl`
`CH_(3)CH(CH_(3))CH_(2)Cl`
`CH_(3)CH_(2)CH(CH_(3))Cl`
`(CH_(3))_(3)C Cl`

Solution :The rate of substraction of hydrogen follows the order `3^(@) H gt 2^(@) gt H gt 1^(@)`H, which parallels the STABILITY of free radicals. In otherwords , the order of reactivity OFH is `3^(@) H gt 2^(@) gt 1^(@)H`.
`(CH_(3))_(2)CHCH_(3) +Cl_(2) overset(U.V."LIGHT") to (CH_(3))_(2)C ClCH_(3)+HCL`
8.

In the following reaction sequences V and W are respectively

Answer»




ANSWER :A
9.

In the chlorination reaction of propane, mixture of products are obtained. How many isomers, the mixture contains

Answer»

2
3
4
5

Answer :C
10.

In the following reaction sequence, which of the following steps is wrong?

Answer»

Step 3
Step 2
Step 1
None of these

Solution :Step 3 is wrong . The LAST step will first brominate the DOUBLE BOND. THUS, the productswill be
11.

In the nitration of benzene ,the attacking reagent is ______.

Answer»

`NO_2`
`NO_2^-`
`NO_2^+`
none

Answer :`CI^+`
12.

In the following reaction sequence, the compound J is an intermediate. Ioverset((CH_(3)CO)_(2)O)underset(CH_(3)COONa)rarroverset((i)H_(2),Pd//C)underset({:((ii)SOCl_(2)),((iii)"anhyd. AlCl"_(3)):})(rarr) 'J' (C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and a positive Baeyer's test. The compound K is

Answer»




SOLUTION :The COMPOUND 'K' OBTAINED from compound 'J' as FOLLOWS :
13.

In the chemical sense digestion is basically

Answer»

Hydrolysis
Anabolism
Hydrogenation
Dehydrogenation

Answer :A
14.

In the following reaction sequence, the correct structures of E, F and G are

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ANSWER :C
15.

In the chemical reaction, the compounds 'A' and 'B' respectively are …..

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NITROBENZENE and CHLOROBENZENE
Nitrobenzene and fluorobenzene
Phenol and Benzene
Benzene diazonium CHLORIDE and fluorobenzene

Answer :D
16.

In the following reaction sequence, the compound J is an intermediate. Ioverset((CH_(3)CO)_(2)O)underset(CH_(3)COONa)rarroverset((i)H_(2),Pd//C)underset({:((ii)SOCl_(2)),((iii)"anhyd. AlCl"_(3)):})(rarr) 'J' (C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and a positive Baeyer's test. The compound I is

Answer»




Solution :Since the intermadiate 'J' GIVES brisk effervescence on treatment with `NaHCO_(3)`. It must have a -COOH group. Since it gives a positive Baeyer's reagent (decolourisesdilute alkaline `KMnO_(4)`), it should be unsturated in nature. The correponding compound 'I' is benzaldehyde (a). the intermediate 'J' is formed as a RESULT of Perkin's reaction
17.

In the chemical reaction : CH_(3)CH_(2)NH_(2) + CHCI_(3) + 3KOH rightarrow A+B+ 3H_(2)O The compound A and B are respectively

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`CH_(3)CH_(2)CONH_(2) and 3KCI`
`CH_(3)CH_(2)NC+K_(2)CO_(3)`
`CH_93)CH_(2)NC and 3KCI`
`CH_(3)CH_(2)CNB + 3KCI`

ANSWER :C
18.

In the chemical reaction, CH_(3)CH_(2)NH_(2)+CHCl_(3)+3KOHrarr (A)+(B)+3H_(2)O. the compounds (A) and (B) are respectively :

Answer»

`CH_(3)CH_(2)CONH_(2) and 3KCl`
`C_(2)H_(5)NC and K_(2)CO_(3)`
`C_(2)H_(5)NC and 3KCl`
`C_(2)H_(5)CN and 3KCl.`

Answer :C
19.

In the chemical reaction, CH_3CH_2NH_2 + CHCl_3 + 3KOH to (A) + (B) + 3H_2O, the compounds (A) and (B) are respectively

Answer»

`C_2H_5NC` and 3KCL
`C_2H_5CN` and 3KCl
`CH_3CH_2CONH_2` and 3KCl
`C_2H_5NC` and `K_2CO_3`

SOLUTION :This is CARBYLAMINE REACTION.
`CH_3CH_2NH_2 +CHCl_3 + 3KOH to C_2H_5NC + 3KCl + 3H_2O`
20.

In the following reaction sequence, the compound J is an intermediate. I underset(CH_(3)COONa)overset((CH_(3)CO)_(2)O)toJ underset((ii)." "SOCl_(2),(iii)." anhyd. "AlCl_(3))overset((i)." "H_(2),Pd//C)toK J(C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and a positive Baeyer's test. Q. The compound K is

Answer»




Solution :Treatment of compound (J) with `H_(2),Pd//C`, reduces the double bond to give the corresponding saturated acid, i.e., 3-henylpropanoic acid. The saturated acid on treatment with `SOCl_(2)` gives the corresponding acid chloride which upon subsequent treatment with ANHYD. `AlCl_(3)` BRINGS
About CYCLIZATION to give the CYCLIC ketone, (K), i.e., I-indanone.
21.

In the following reaction sequence, the compound J is an intermediate. I underset(CH_(3)COONa)overset((CH_(3)CO)_(2)O)toJ underset((ii)." "SOCl_(2),(iii)." anhyd. "AlCl_(3))overset((i)." "H_(2),Pd//C)toK J(C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and a positive Baeyer's test. Q. The compound I is

Answer»




Solution :Since COMPOUND, J (M.F. `C_(9)H_(8)O_(2)`) gives effervescence with `NaHCO_(3)` and a positive test with BAEYER's reagent, therefore, (J) is an unsaturated acid. Since (J) is obtained by treatment of compound (I) with `(CH_(3)CO)_(2)O` in presence of `CH_(3)COONa`, therefore, compound (I) must be benzaldehyde which UNDERGOES Perkin reaction with `(CH_(3)CO)_(2)O` in presence of `CH_(3)COONa` to FORM cinnamic acid (J) which is an `alpha,beta`-unsaturated acid. thus
22.

In the following reaction sequence, the compound J is an intermediate. I overset((CH_(3)CO)_(2)O)underset(CH_(3)COONa)rarr J overset((i)H_(2),Pd//C)undersetunderset((iii)"anhyd".AICI_(3))((ii)SOCI_(2))rarrK J(C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and positive Baeyer's test. The compound I is

Answer»




Solution :`underset(I)(Ph)-CHOoverset((CH_(3)CO)_(2)O)underset(CH_(3)COONa)RARR underset(J)(Ph-CH=CH-COOH)`
`overset(H_(2)-PDLC)rarr Ph-CH_(2)-CH_(2)-COOH`
`overset(SOCI_(2))rarr Ph-CH_(2)-CH_(2)-underset(O)underset(||)(C )-CI`
23.

In the change [Cu(H_(2)O)_(6)]^(2+)overset(HCl)rarr [CuCl(H_(2)O)_(5)]^(+), the colour changes from

Answer»

BLUE to GREEN
blue to PINK
pink to green
pink to blue

ANSWER :B
24.

In the cell Zn|Zn^(2+)||Cu^(2+)|Cu, the negative electrode is

Answer»

Cu
`Cu^(2+)`
`ZN`
`Zn^(2+)`

Solution :In the CELL `Zn|Zn^(2+)||Cu^(2+)|Cu` the negative ELECTRODE always written on left side while CATHODE on right side.
25.

In the following reaction sequence, the compound J is an intermediate. I overset((CH_(3)CO)_(2)O)underset(CH_(3)COONa)rarr J overset((i)H_(2),Pd//C)undersetunderset((iii)"anhyd".AICI_(3))((ii)SOCI_(2))rarrK J(C_(9)H_(8)O_(2)) gives effervescence on treatment with NaHCO_(3) and positive Baeyer's test. The compound K is

Answer»




Solution :`UNDERSET(I)(Ph)-CHOoverset((CH_(3)CO)_(2)O)underset(CH_(3)COONa)rarr underset(J)(Ph-CH=CH-COOH)`
`OVERSET(H_(2)-PDLC)rarr Ph-CH_(2)-CH_(2)-COOH`
`overset(SOCI_(2))rarr Ph-CH_(2)-CH_(2)-underset(O)underset(||)(C )-CI`
26.

In the cell represented by Pb_(s) |Pb^(2+) (1M) ||Ag^(+)(1M) |Ag_(s) the reducing agents is

Answer»

Pb
`Pb^(2+)`
AG
`Ag^(+)`

SOLUTION :`Pb(s)| Pb^(2+) (1M) ||Ag^(+)(1M)| Ag_(s)`
The compound losing `e^(-)` is called reducing agent.
`Pb to Pb^(2+) + 2E^(-)`
27.

In the cell Zn|Zn^(2+)(1M)||H^(+)(1M)|H_(2(g))|Pt Zn electrode is replaced by Cu electrode. Thecell potential will ____________.

Answer»

increases
decreases
remain the same
BECOME double

Answer :B
28.

In the following reaction sequence The compound I is

Answer»

`CH_3-OVERSET(CL)overset(|)UNDERSET(Cl)underset(|)C-CH_3`
`Cl-underset(Cl)underset(|)CH-CH_2-CH_3`
`underset(Cl)underset(|)CH_2-underset(Cl)underset(|)CH-CH_3`
`underset(Cl)underset(|)CH_2-CH_2-underset(Cl)underset(|)CH_2`

ANSWER :A
29.

In the following reaction sequence, the amount of D (in g) formed from to moles of acetophenone is.......... (Atomic weights in g mol^(-1) : H = 1, C = 12, N = 14, O = 16, Br = 80. The yield (%) corresponding to the product in each step is given in the parenthesis)

Answer»


ANSWER :495
30.

In the cell representation (+) represents

Answer»

SALT bridge
phase boundary
cathode
anode

Answer :B
31.

In the following reaction sequence, product I, J and L are formed. K represents a reagent The structure of product L is

Answer»




Solution :`H_(2), Pd//BaSO_(4)`, quinoline is a well known reagent. In ROSENMUND's reaction (conversion of acyl halide). `H_(2), Pd,BaSO_(4)` is known as Lindlar's reagent and reduces TRIPLE bond SYN addition giving cis PRODUCT. Reagent has simultaneous action because usually the reaction is not selective-follows free RADICAL mechanism.
32.

In the cell reaction Cu(S) + 2 Ag^(+) (aq) to Cu^(2+) (aq) + 2 Ag(s) , E_("cell")^(@) = 0.46 V By doubling the concentration of Cu^(2+) , E_("cell")^(@)is

Answer»

DOUBLED
HALVED
increases but LESS than double
decreases by a small fraction .

SOLUTION :`E_("cell") = E_("cell")^(@) - (RT)/(nF) "ln" ([Cu^(2+)])/([Ag^(+)]^(2))` .
Doubling `[Cu^(2+)]` decreases the EMF by a small fraction .
33.

In the following reaction sequence, product I, J and L are formed. K represents a reagent The structure of J and K respectively are

Answer»




Solution :Bromide is converted into Grignard reagent and further CARBONATION `[(i)CO_(2)(ii)H_(3)O^(+)]` produces CARBOXYLIC acid J.
34.

In the cell , Pt, Sn^(+4)|| Fe^(+3)|Fe^(+2) ,Pt, the cathode half cell reaction is

Answer»

`FE^(+3)+E^(-) to Fe^(+2)`
`Fe^(+3) 3E^(-) to Fe`
`Fe^(+2) +2E^(-) to Fe`
`Fe^(+2) to Fe^(+3)+e`

Answer :A
35.

In the following reaction sequence, CH_(3)CHO overset(Cl_(2))underset(Ca(OH)_(2))(to) X overset(C_(6)H_(5)NH_(2))underset("Alc."KOH)(to) Y Y is

Answer»

`CH_(3)CH = NHC_(6)H_(5)`
`C_(6)H_(5) NHCH_(3)`
`C_(6)H_(5)NC`
`C_(6)H_(5)NCO`

Solution :
36.

In the cell reaction :Ag(s)+Cu^(2+)(aq)+Br^(-)(aq)toAgBr(s)+Cu^(+)(aq)the reduction half reaction is :

Answer»

`Ag^(+)(s)+BR^(-)(AQ)toAgBr(s)`
`Cu^(2+)+e^(-)toCu^(+)`
`Cu^(+)-e^(-)toCu^(2+)`
`Ag(s) TOAG^(+)+e^(-)`.

ANSWER :B
37.

In the following reaction sequence in aqueous solution, the species X,Y and Z, respectively S_(2)O_(3)^(2-)overset(Ag^(+))(rarr)underset("clear solution")(X)overset(Ag^(+))(rarr)underset("white precipitate")(Y)overset("withtime")(rarr)underset(" black precipitate")(Z)

Answer»

`[AG(S_(2)O_(3))_(2)]^(3-), Ag_(2)S_(2)O_(3), Ag_(2)S`
`[Ag(S_(2)O_(3))_(3)]^(5-), Ag_(2)SO_(3), Ag_(2)S`
`[Ag(SO_(3))_(2)]^(3-), Ag_(2)S_(2)O_(2), Ag`
`[Ag(SO_(3))_(3)]^(3-), Ag_(2)SO_(4), Ag`

ANSWER :A
38.

In the catalytic oxidation of ammonia, an oxide is formed which is used in the precipitation of HNO_3. The oxide is

Answer»

NO
`NO_2`
`N_2O_5`
`N_2O_4`

Solution :`4NH_3 + 5O_2 UNDERSET(1100K)OVERSET(PT)(to) 4NO + 6H_2O`
39.

In the Castner process for the extraction of sodium, the anode is made of..... Metal.

Answer»

Copper
Iron
Sodium
Nickel

Answer :D
40.

In the following reaction sequence, (##MBD_HKR_CHE_XII_P02_C16_E07_099_Q01.png" width="80%"> The end product would be useful as :

Answer»

A soap
A fertilizer
An EXPLOSIVE
A DETERGENT

ANSWER :D
41.

In the following reaction sequence, C_(6)H_(5)Br underset(523K)overset(CuCN // "pyridine")to X underset("boil")overset(dil. H_(2)SO_(4))to Y the product Y is

Answer»

benzonitrile
benzene
benzoic acid
benzamide.

Solution :`C_(6)H_(5)Br underset(523K)overset(CuCN // "PYRIDINE")to underset((X))(C_(6)H_(5)CN) underset("boil")overset(dil. H_(2)SO_(4))to underset(underset((Y))("Benzoic acid"))(C_(6)H_(5)COOH)`
42.

In the case of the alkali metals:

Answer»

The CATION is LESS stable than the atom
The cation is SMALLER than the atom
The cation and the atom have about the same size
The cation is larger than the atom

Answer :B
43.

In the following reaction sequence:

Answer»

REACTION 1
Reaction 2
Reaction 3
Reaction 4

Answer :A
44.

In the case of small cuts, bleeding is stopped by applying potash alum. Here alum act as

Answer»

germicide
coagulating agent
fungicids
disinfectant

Answer :B
45.

In the case of osmosis, solvent molecules move from:

Answer»

HIGHER VAPOUR PRESSURE to LOWER vapour pressure
Higher concentration to lower concentration
Lower vapour pressure to higher vapour pressure
Higher OSMOTIC pressure to lower osmotic pressure

Answer :A
46.

In the followingreaction sequence 'A' is C_(2)H_(5)Ioverset(alc KOH)rarrXunderset(C CI_(4))overset(Br_(2))rarrtYoverset(KCN)rarrZoverset(H_(3)O^(+))rarrA

Answer»

succinic ACID
OXALIC acid
malonic acid
maleic acid

ANSWER :A
47.

In the case of immiscible liquids, the addition of one liquid to another does not after the properties of either liquid. Hence liquid exerts its own vapour pressure independently of the pressure of the other. Since boiling point of any system is the temperature at which its total vapour pressure becomes equal to the prevailing pressure, so by knowing the miscibility of two liquids, we can find out boiling temperature. An immiscible mixture of water and quinoline is prepared and distillation is done. If p_("quinoline")^(@) = 7.9 torr and p_("water")^(@) = 732.04 torr at the boiling point of 98.9^(@)C. Find out the relative masses of water and quinoline in the distillate. If it is given that no of moles of any component in the vapour phase prop its vapour pressure. (Molar mass of water = 18 g/mol and molar mass of quinoline= 129g//mol)

Answer»

`W_("water"): W_("quinoline") : : 13:1`
`W_("water"): W_("quinoline"):: 1:1`
`W_("water") : W_("quinoline") ::1:14`
`W_("Water"):W_("quinoline") :: 7.1:1`

SOLUTION :`(W_("water"))/(W_("quinoline"))=(n_("water"))/(n_("quinoline"))XX(M_("water"))/(M_("quinoline"))`
and `(n_("water"))/(n_("quinoline"))=(p_("water"))/(p_("quinoline"))=(732.04)/(7.9)`
`(W_("water"))/(W_("quinoline"))=(73204)/(790)xx(18)/(129)~=(13)/(1)`.
48.

In thefollowingreaction RX + KCN overset(Delta) towhichof the followingisomericcompoundis formed

Answer»

RCN
RNC
`RNH_(2)`
ROR

Answer :B
49.

In the case of immiscible liquids, the addition of one liquid to another does not after the properties of either liquid. Hence liquid exerts its own vapour pressure independently of the pressure of the other. Since boiling point of any system is the temperature at which its total vapour pressure becomes equal to the prevailing pressure, so by knowing the miscibility of two liquids, we can find out boiling temperature. In which of the following mixtures, vapour pressure of each component is independent of the amount of the other components?

Answer»

MIXTURE of WATER and aniline
Mixture of toluene and benzene
Mixture of water and SULPHURIC acid
Mixture of `N_(2)(g)` and `O_(2)(g)`

Solution :Vapour pressure of each component is INDEPENDENT in the case of IMMISCIBLE liquids (i.e., aniline and water).
50.

In the following reaction: RMgX+HC(OE t)_(3) overset(Ether)to overset(H_(3)O^(+))toP The product 'P' is

Answer»

RCHO
`R_(2)CHOEt`
`R_(3)CH`
`RCH(OE t)_(2)`

Solution :`R-MgX+HC(OE t)_(3) overset("Ether")toR-CH(OEF)_(2) overset(H_(3)O^(+))to R-CH=O+2EtOH`