Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In S_(N)1 reaction of (S)-2 bromobutane with water Two subsitution products are formed one has the same relative configuration as the reactant and the other has the inverted configuration. This is in most S_(N)1 reactions, the recemic product is non-50:50 mixture i.e, recemization takes place the inverted product is more than 50% . the formation of different composition of the product is due to following stpes involved in S_(N) reactions. R-X "" to R^(+) X^(-) to R^(+) "" "solvent" X^(-) "" to R^(+)+X^(-) {:("Undissociated Molecule", "Intimate ion pair", "solvent-sperated ion pair", "dissociated ions"),(I,II,III,IV):} Which type of intermediate is formed in the reaction of (S)-2 bromobutane with water ?

Answer»

`sp^(3)` HYBRIDIZED
`sp^(2)` hybridized
sp hybridized
A TRANSITION state

Answer :B
2.

In smeltingof iron, which of the following reactions takes place in Blast furnace at 400^(@)C-600^(@)C

Answer»

`CaO_SiO_(2)rarrCaSiO_(3)`
`2FeS+3O_(2)rarr 2Fe+SO_(2)`
`FeO+SiO_(2)rarr FeSiO_(3)`
`Fe_(2)O_(3)+3COrarr 2Fe+3CO_(2)`

SOLUTION :In blast furnace at `400-600^(@)C` for the smelting of iron, FOLLOWING reaction TAKES place `Fe_(2)O_(3)+3COrarr 2Fe+3CO_(2)`
3.

In smelting of iron, which of thefollowing reactions takes place in blast furnace at 400^(@)C-600^(@) C ?

Answer»

`CaO+SiO_(2) to CaSiO_(3)`
`2FeS+3O_(2) to 2Fe+SO_(2)`
`FeO+SiO_(2) to FeSiO_(3)`
`Fe_(2)O_(3)+3CO to 2Fe+3CO_(2)`

ANSWER :D
4.

In smelting process the impurities of an ore is removed by

Answer»

ADDITION of flux
levigation
addition of slag
liquation

Solution :To REMOVE GANGUE
5.

In smelting of iron, reactions takes place in Blast furnace at 400^(@)C-600^(@)C is

Answer»

`CaO + SiO_(2) rarr CaSiO_(3)`
`2FES + 3O_(2) rarr 2Fe + SO_(2)`
`FeO + SiO_(2) rarr FeSiO_(3)`
`Fe_(2)O_(3) + 3CO rarr 2Fe + 3CO_(2)`

Answer :D
6.

In Slapter's rule, the correct arrangments of electron are according to the extent of their screening

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`(1S, 2S), 2p`
`(1s), (2s, 2p)`
`(1s), (2s), (2p)`
NONE of these

ANSWER :B
7.

In SIO_2, each silicon atom is covalently bonded in a tetrahedral manner to four oxygen and each oxygen atom in turn is covalently bonded to another two silicon atoms giving a three dimensional network solid.Find the total number of atoms comprising each ring forming the three dimensional network solid .

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SOLUTION :
8.

In simple ionic crystals_____or______types of arrangement are generally -present.

Answer»

SOLUTION :CCP or HCP
9.

In SiF_(6)^(2-) and SiCl_(6)^(2-) which one is known and why

Answer»

`SiF_(6)^(2-)` because of SMALL size of F
`SiF_(6)^(2-)` because of large size of F
`SiCl_(6)^(2-)` because of small size of Cl
`SiCl_(6)^(2-)` because of large size of Cl

Solution :In `SiF_(6)^(2-)` and `SiCl_(6)^(2-),SiF_(6)^(2-)` is KNOWN due to the small size of F ATOMS. The small six F atoms F atoms can be easily accommodated around SI atom to form `SiF_(6)^(2-)` while in `SiCl_(6)^(2-)`, six large Cl atoms cannot be accommodated around Si atom.
10.

In silver extraction process Zn displaces Ag from its

Answer»

AG(CN) salt
`[NAAG(CN)_(2)]` salt
`Na_(2)[Ag(CN)_(2)]` salt
`[Ag(CN)_(4)]^(-2)` complex

Answer :B
11.

In silicon dioxide:

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each silicon atom is surrounded by four OXYGEN atoms and each oxygen atom is BONDED atoms and each oxygen atom is bonded to TWO silicon atoms.
each silicon atom is surrounded by two oxygen atoms and each oxygen atom is bonded to two silicon atoms.
silicon atom is bonded to two oxygen atoms.
there are double BONDS between silicon and oxygen atoms.

Solution :Silicon dioxide is a network solid in which each `Si` atom is tetrahedrally surrounded by 4 oxygen atoms.
12.

In Siemen's ozoniser, 60% O_(2) is covered to ozone. How many moles of ozone will be obtained from 10 mole of O_(2)?

Answer»


ANSWER :4
13.

In sickle cell anaemia, the basis of malfunction of haemoglobin molecules is

Answer»

reduced affinity for oxygen
incorrect secondary structure
substitution of glutamic acid residue by valine
faulty binding of the heme group

Solution :The genetically based disease sickle - cell anemia results from a single amino acid error in the `BETA`-chain of haemoglobin. In normal haemoglobin, position 6 has a glutamicacid residue, whereas in sickle - cell haemoglobin position 6 is occupied by valine. Red blood cells (ERYTHROCYTES) containing haemoglobin with this amino acid residue error tend to become crescent shaped ("sickle") when the partial pressure of oxygen is low, as it is in venous blood. These distorted cells are more difficult for the heart to pump through small capillaries. They may even block capillaries by clumping TOGETHER, at other times the red cells may even split open. CHILDREN who INHERIT genetic trait from their parents suffer from a severe form of the disease and usually do not live past the age of two.
14.

In SHE, platinum act as

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Adsorbate
Adsorbent
Adsorbate
Adsorbent

Solution :Hydrogen GAS is adsorbed on the SURFACE of PLATINUM PLATE. Therefore, platinum platinum acts as adsorbent.
15.

In shaving soaps rapid drying is prevented by adding

Answer»

Rosin
Glycerol
Borax
Finely DIVIDED sand

Answer :B
16.

In SF_(6) molecule, is formed in n^(th) excited state of 's'. What is n ?

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SOLUTION :
17.

In SF_4, S atom is ........... hybridized.

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`sp^(3)`
`sp^(3)d`
`sp^(3)d^(2)`
`DSP^(2)`

ANSWER :B
18.

In several experiments on the kinetics of reaction A+B to Products, it is observed that i) On doubling the initial concentration of A, the rate was increased by four times and ii) On doubling the initial concentration of B, the rate was increased by two times.The correct statementis

Answer»

the reaction is first order in and second order in B
the reaction is first order in both the reactants
the rate equation is `(DX)/(DT)=k[A]^0[B]`
the over all order of the reaction is three

Solution :The rate law of the reaction `A + B to` PRODUCTS, as determined from its KINETICS is,
`(dx)/(dt) =k[A]^2[B]` So the overall order of the reaction is 2+ 1 = 3.
19.

In Serpeck's process, byproduct obtained in the purification of bauxite is

Answer»

`Al_(2)O_(3)`
`N_(2)`
`NH_(3)`
none of the above

ANSWER :C
20.

In separate 0.1 M aqueous solution of each of the following salts, which one will record the highest pH value?

Answer»

SODIUM carbonate
Ammonium chloride
Sodium nitrate
Potassium acetate

Answer :A
21.

In serpek's process, by product obtained in the purification of bauxite is:

Answer»

`Al_2O_3`
`N_2`
`NH_3`
None

Answer :C
22.

In SeF_6 selenium is:

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spd-hybridised
`d^2 sp^3`hybridised
`sp^3 d^2`-hybridised
`dsp^3`-hybridised

Answer :C
23.

In second group, H_2 S is passed in the presence of dil. HCl because

Answer»

HCl checks INCOMPLETE precipitation of HIGHER GROUP RADICALS
HCl checks precipitation of sulphur
both (a) and (b)
none of these

Solution :Due to common ion effect , the ionization of `H_2 S` is suppressed by HCl and only II group basic radicals are precipitated . Higher GROUPS are not precipitated.
24.

In second period of the periodic table, ionisation energy follows the order:

Answer»

`NE GT F gt O gt N gt C gt B gt Be gt Li`
`Ne gt F gt N gt C gt O gt Be gt B gt Li`
`Li gt B gt Be gt C gt O gtN gt F gt Ne`
`Ne gt F gt N gt O gt C gt Be gt B gt Li`

Answer :D
25.

In SCN ligand if N is attached to central atom, the name of ligand is:

Answer»

Thiocyanato-N
Cyanato-N
Thipcyanato-S
Cyanato-S

Answer :A
26.

In SCl_(2) the central atom involves

Answer»

`SP^(3)` hybridization
`sp^(3)d` hybridization
`sp^(2)d^(2)` hybridization
`DSP^(2)` hybridization

ANSWER :A
27.

In sample of excited hydrogen atoms, electron make transition from n = 2 to n = 1. Emitted quanta strike on a metal of work functio [phi]4.2 ev. Calculate the wavelength (in Å) associated with ejected electrons having maximum kinetic energy.

Answer»


ANSWER :5
28.

In salts of polyatomic anion, as polarising power of cation increase, thermal stability of the salt decrease and decomposed species may further undergo redox reaction Q. Water soluble salt(x) was heated into three products A, B and C and B and C are two different paramagnetic gases. A is red in hot condition, then salt(x) is :

Answer»

`Hg(NO_(3))_(2)`
`FeC_(2)O_(4)`
`ZnSO_(4)`
`Pb(NO_(3))_(2)`

SOLUTION :`Pb(NO_(3))_(2) overset(Delta)(to) underset("Red in hot(Litharge)")(PbO)+2NO_(2)(uarr)+underset("Two differentparamagnetic gases")((1)/(2)O_(3))`
`implies Hg(NO_(3))_(2)overset(Delta)(to) Hg+2NO_(2)(uarr)+O_(2)(uarr)`
`implies FeC_(2)O_(4) overset(Delta)(to)FeO+CO(uarr)+CO_(2)(uarr)`
`ZnSO_(4) overset(gt800^(@)C)(to)ZnO+SO_(2)(uarr)+(1)/(2)O_(2)(uarr)`
29.

In salt analysis cations of group I and II precipitated in acidicmedium and therefore the solution remains acidic till group II. But from III group onwards cations precipitates in basic medium and hence filtrate of group II is to be boiled with con HNO_(3) before using it for III group. Which statements is not true for III group precipitate.

Answer»

`(NH_(4))_(2)SO_(4)` cannot be usedin place `NH_(4)Cl`
`NH_(4)NO_(3)` can be used in place of `NH_(4)Cl`
`NH_(4)Cl` must be ADDED in excess before `NH_(4)OH`
`NaOH` DISSOLVES only `Al(OH)_(3)` not `Cr(OH)_(3)` and `FE(OH)_(3)`.

Solution :`NO_(3)^(-)`ion will OXIDIZE `Mn^(2+)` to `Mn^(3+)` and `Mn(OH)_(3)` will precipitate.
30.

In salts of polyatomic anion, as polarising power of cation increase, thermal stability of the salt decrease and decomposed species may further undergo redox reaction Q. Which of the followinng species undergoes non-redox thermal decomposition reaction on heating?

Answer»

`FeSO_(4)`
`SnSO_(4)`
`H_(2)C_(2)O_(4)`
`Na_(2)HPO_(4)`

Solution :`2FeSO_(4) overset(delta)(to)Fe_(2)O_(3)+SO_(2)(uarr)+SO_(3)(uarr)`
`SnSO_(4) overset(Delta)(to)SnO_(2)+SO_(2)(uarr)`
`H_(2)C_(2)O_(4) overset(Delta)(to) CO(uarr)+CO_(2)(uarr)+H_(2)O`
`2Na_(2)P_(2)O_(7)+H_(2)O`
31.

In salt analysis cations of group I and II precipitated in acidicmedium and therefore the solution remains acidic till group II. But from III group onwards cations precipitates in basic medium and hence filtrate of group II is to be boiled with con HNO_(3) before using it for III group. Conc. HNO_(3) is added for proceeding to test III group radicals, because

Answer»

to form NITRATES which gives granular precipitates.
oxidize any remaining `H_(2)S`.
increase IONIZATION of `NH_(4)OH`
CONVERT `Fe^(2+)` ion to `Fe^(3+)` ions.

Solution :In presence of `H_(2)` gas `Fe^(3+)` reduced to `Fe^(2+)` , and therefore to convert it again to `Fe^(3+),HNO_(3)` is added.
32.

In salt analysis cations of group I and II precipitated in acidicmedium and therefore the solution remains acidic till group II. But from III group onwards cations precipitates in basic medium and hence filtrate of group II is to be boiled with con HNO_(3) before using it for III group. The use of Br_(2) and NaOH to group III precipitate facilitates

Answer»

RENDERING Al into SODIUM meta-aluminate
rendering Fe into `Fe(OH)_(2)`
conversion of Cr into soluble sodium chromate
removal of group III ions before starting group IV

Solution :`Cr^(3+)` makes soluble sodium chromate in presence of `Br_(2)//NAOH` to allow precipitation.
33.

In S_(8)each sulphur atom is :-

Answer»

SP hybridised with a planar ring
`sp^(3)` hybridised with a planar ring
`sp^(3)` hybridised with a non-planar ring
`sp^(3)d` hybridised two SULPHUR atoms

Answer :C
34.

In s salt bridge, KCl is used because

Answer»

it is and ELECTROLYTE
KCl is found in pure crystalline state in large deposits
it is a good CONDUCTOR of electricity
it forms a good jelly with agr-agr.

Solution :(a,C,d) are correct.
35.

In Rosenmunds reduction, the action of BaSO_4is.......

Answer»

PROMOTER
CATALYST poison
Positive catalyst
NEGATIVE catalyst

Solution :Catalyst poison
36.

In Rosenmund's reduction reaction .................... is the catalyst and ............. is the catalytic poison.

Answer»

SOLUTION :`PD, BaSO_4`
37.

In Rosenmund reduction, which of the following does not poison the catalyst Pd?

Answer»

a.`BaSO_(4)`
b.S
c.Quinoline
d.Xylene

Solution :All the reagents CONVERT

GROUP to `(-CH_(2)-)` group. So the answer is `(d)`.
38.

In rosenmund reduction, benzoyl chloride in boiling xylene is reduced to benzaldehyde in presence of______.

Answer»

SOLUTION :`H_(2)-Pd//BaSO_(4)`,
39.

In roasting :

Answer»

MOISTURE is removed
non-metals as their volatile oxide are removed
Ore becomes porous
All the above

Solution :Roasting removes easily oxidisable volatile impurities like arsenic (as `As_2O_3`) sulphur (as `SO_2`), phosphorus (as`P_4O_10`) and antimony (as `Sb_2O_3`)
`4M(M=As, SB)+3O_2to2M_2O_3uarr`
`S+O_2toSO_2uarr,P_4+4O_2toP_4O_10uarr`
ORGANIC matter, moisture if present in the ore, ALSO GET expelled and the ore becomes porous .
40.

In Rosenmund reaction, presence of BaSO_(4) acts as ………….for Pd.

Answer»

promoter
moderator
inhibitor
poison

Solution :`BaSO_(4)` retards the activity of Pd and HENCE, acts as catalytic poison. In presence of `BaSO_(4), - COCI` group gets reduced to aldehydic group.
`- COCl underset(Pd//BaSO_(4)) overset (H_(2)) to- CHO`
41.

In RNA, the sugar is ..............but in DNA, it is ...............

Answer»

SOLUTION :RIBOSE, 2- dexyribose
42.

In RN A number of nucleotides are joined together by

Answer»

AMIDE linkage
phosphodiester linkage
peptide linkage
glycosidic linkage

Answer :B
43.

In respect of the equation k = Ae^(-E_(a)//RT) in chemical kinetics , which one of the following statement is correct

Answer»

k is equilibrium constant
A is ADSORPTION factor
`E_(a)` is ENERGY of ACTIVATION
R is Rydberg's constant

SOLUTION :It is Arrhenius equation .
44.

In Reimer-Tiemann reaction, the medium of reaction is

Answer»

acidic
basic
neutral
gas-phase

Answer :B
45.

In Reimer-Tiemann formylation reaction, molecular weight of phenol increases by

Answer»

27
28
29
30

Answer :B
46.

In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the from of an equation.

Answer»
47.

In reference to Freundlich adsorption isotherm, write the expression for adsorption of gases on solids in the form of an equation.

Answer»

Solution :`(x)/(m)=K.p^(1/n)(n gt 1)`
where x is the MASS of the gas adsorbed on mass m of the adsorbent at pressure P. k and n are CONSTANTS which depend UPON the nature of adsorbent and the gas at a PARTICULAR temperature.
48.

In reactin (1), XeF_(6) hydrolysis to form HF and X. In reaction (2), XeF_(6) on partial hydrolysis from HF, Y and Z. The product X,Y,Z respectively, are

Answer»

`XeO_3, XE, XeO_2F_2`
`XeO_3, XeOF_4, XeO_2F_2`
`Xe, XeO_4, XeO_2F_2`
`XeO_3, O_2, XeO_2F_2`

ANSWER :B
49.

In a redox reaction, H_2 O_2 oxidizes K_4 [Fe (CN)_6] into Fe^(3+), CO_(3)^(2-) and NO_(3)^(-) ions in acidic medium, then how many moles of H_2 O_2 will react with 1 mole of K_4 [Fe (CN)_6]

Answer»

5 moles
9 moles
8 moles
30.5 moles

Answer :D
50.

In reaction PCI_5 (g) hArr PCI_3(g)+CI_2(g) at 27^@Cand density was 0.5 gm/cc when reaction was not started . What will be the partial pressure of PCI_3 at equilibrium ? The CI_2 present at equilibrium when reacts with the excess of benzene in presence of a Lewis acid produces 56.2 gm of monochloro benzene only K_c =1.66 xx10^(-1)

Answer»

<P>

SOLUTION :`P_(PCI_3)=0.04 ATM`