Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In solid state PCl_(5) is a ........ .

Answer»

covalent solid
OCTAHEDRAL structure
IONIC soled with `[PCl_(6)]^(+)` octahedral and `[PCl_(4)]^(-)` tetrahedral
ionic solid with `[PCl_(4)]^(+)` tetrahedral and `[PCl_(6)]^(-)` octahedral

Solution :Ionic solid with `[PCl_(4)]^(+)` tetrahedral and `[PCl_(6)]^(-)` octahedral.
2.

In solid state PCl_(15)is a............

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Covalent SOLID
Octahedral structure
Ionic solid with [`PCl_6]^+` octahedral and `[PCl_4]^-` tetrahedral.
Ionic solid with `[PCl_4]`+ tetrahedral and `[PCl_6]^-` octahedral.

Solution :Due to weak P-Cl axial bond, in solid STATE `PCl_5` EXISTS as `[PCl_4]+ [PCl_6]^(-)` to attain stability.
`2PC_(5) to [PCl_(4)]^(+) + [PCl_(6)]^(-)`
3.

Aluminium chloride exists as a dimer, Al_(2)Cl_(6) in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :

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`AL^(3+) +3Cl^(-)`
`[Al(H_(2)O)_6]^(3+)+3Cl^(-)`
`[Al(OH)_6]^(3-)+3HCL`
`Al_(2)O_(3)+6HCL`

Answer :B
4.

In solid state, PCI_5, is a

Answer»

COVALENT SOLID
OCTAHEDRAL structure
ionic solid with `[PCl_6]^(+)` octahedral and `[PCl_4]^-` TETRAHEDRA
ionic solid with `[PCl_4]^+` tetrahedra and `[PCl_6]^-` octahedra

Answer :D
5.

In solid N_(2)O_(3) and solid N_(2)O_(5),N-O hybridization in cationic part are respectively:

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`SP^(2)` and `sp`
`sp` and `sp^(2)`
`sp` and `sp`
NONE of these

Solution :SOLID `N_(2)O_(3) (NO^(-)NO_(3)^(-))`
6.

In solid PCl_(5) exist as

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`PCl_(3)`
`PCl_(4)^(+)`
`PCl_(6)^(-)`
`PCl_(4)^(+) and PCl_(6)^(-)`

ANSWER :D
7.

In solid cyclic form of SO_(3), each sulphur atom is surrounded by …… oxygen atoms

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4
3
5
6

Answer :A
8.

Intramolecular hydrogen bonding is found in :

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IONIC
VAN DER waals'
Metallic
Covalent

Answer :B
9.

In solid CuSO_4.5H_2O,copper is coordinated to:

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4 WATER molecules
5 water molecules
1sulphate molecule
1 water molecule

Answer :A
10.

In solid CuSO_(4).5H_(2)O copper is coordinated to

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4 WATER molecules
5 water molecules
1 sulphate
1 water molecule

Solution :FOUR water molecules are coordinated to COPPER.
11.

In solid CuSO_(4).5H_(2)O

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Five molecules of `H_(2)O` are COORDINATE bonded to `Cu^(2+)`
`Cu^(2+)` ion is coordinate bonded to four water molecules
One `H_(2)O` MOLECULE is H-bonded
It has four type of bonds : Ionic, covalent, coordinate and H-bond

Solution :(c) `CuSO_(4)overset("heat")underset("strongly")rarr underset("black")(CuO)+SO_(3)`
(b) Is not possible `because CL^(Theta)` is not a reducing agent
Is CORRECT because `I^(-)` is a reducing agent
`2CuSO_(4)+4KIrarr Cu_(2)I_(2)+I_(2)+K_(2)SO_(4)`
12.

in solid CuSO_4 .5H_2O copper is co-ordinated to:

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4 WATER molecules
5 water molecules
One SULPHATE molecule
One water molecule

Answer :A
13.

In solid argon, the atoms are held together by:

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Ionic bonds
Hydrogen BOND
van der WAALS' forces
Hydrophobic

Answer :C
14.

In sodium tetrafluorooxochromate (…...),Na_3[Cr(O)F_4]- the left out place should be filled with which of the following Roman numerals:

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`VI`
`III`
`IV`
NONE of 1hese

Answer :B
15.

In sodium nitroprusside the oxidation number, coordination number and EAN of iron are respectively. [If your answer is 1, 2, 24 then write the answer as 1224]

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SOLUTION :`overset(+2)(Na_(2))[overset(+2)(Fe)(CN)_(5)overset(+1)(NO)]`
EAN=26-2+12=36
16.

In sodium hydride, oxidation state of sodium is :

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ZERO
`+1`
`-1`
`+2`

ANSWER :B
17.

In sodium nitroprusside, The oxidation number coordination No. and effective atomic number of iron are respectively:

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`+3, 6, 36`
`+2, 6, 36`
` +3, 3, 36`
`6, +3, 35`

Answer :B
18.

In sodium fusion tests why excess of sodium is taken?

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Solution :If sulphur and nitrogen both are present SODIUM thiocyanate (NACNS) MAY be PRODUCED this may GIVE a red coloration with `Fe^(3+)` but will not respond to tests for cyanide or sulphide ions. With excess of sodium the thiocyanate if formed will be decomposed like this `NaCNS+2Na to NaCN+Na_(2)S`.
19.

In sodium fusion test of roganilc compound, the nitrogen of a organic compound is converted into [If only C,H,N are present

Answer»

`NaCN`
`NaNH_(2)`
`NaNO_(2)`
`Na_(3)N`

Solution :`Na+CNtoNaCN`
(B), (c) and (d) are RULED out
20.

In sodium fusion test of organic compounds, the nitrogen of an organic compound is converted to :

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SODIUM cyanide
Sodamide
Sodium nitrite
Sodium nitrate

Answer :A
21.

In SOCl_2, the Cl-S-Cl and Cl-S-O bond angles are

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`130^(@)` and `115^(@)`
`106^(@)` and `96^(@)`
`107^(@)` and `108^(@)`
`96^(@)` and `106^(@)`

Answer :D
22.

In sodium extract test of organic compounds, the nitrogen of an organic compound is converted into:

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SODAMIDE
SODIUM cyanide
Sodium nitrite
Sodium nitrate

Answer :B
23.

In SOCl_(2), the Cl-S-Cl and Cl-S-O bond angles are

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`130^(@) and 115^(@)`
`106^(@) and 96^(@)`
`107^(@) and 108^(@)`
`96^(@) and 106^(@)`

Solution :`SOCl_(2)` has one S = O double BOND and two S-Cl single bonds.
Hybridization of `S = (1)/(2) [1 XX 6 (S) + 0 (=0) + 2 xx 1 (Cl) ] = 4`
Thus, S is `sp^(3)`-hydridized. Since `SOCl_(2)` has only three `sigma`-bonds, therefore, it has one lone pair and hence its shape is pyramidal. Further, since `pi`- electrons of the S = O bond are more polarized, therefore, they repel the bond pair of S-Cl bonds. In other words, Cl-S-O bond angle `(106^(@))` is larger than Cl-S-Cl bond angle `(96^(@))`. Hence, option (d) is correct.
24.

In SOCl_(2) and SO_(2)Cl_(2)

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The OXIDATION STATE of sulphuris different
The HYBRIDISATION state of sulphur is same
The shapes of both `SOCl_(2) and SO_(2)Cl_(2)`are same
The Cl-S-Cl angle in both `SOCl_(2) and SO_(2)Cl_(2)` is same

SOLUTION :`{:("+4,-2,=2","-2,-1"),(SOCl_(2),SO_(2)Cl_(2)),(x-2-2=0,x-4-2=x-6=0),(x-4=0,x=+4,x=+6):}`
25.

In SOCI_(2) , the CI-S-CI and CI-S-O bond angles are

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`130^@` and `115^@`
`106^@ and 96^@`
`107^@ and 108^@`
`96^@ and 106^@`

ANSWER :D
26.

In SO_(3),ZX- atoms undergoes ………..hybridisation.

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SOLUTION :`SP^(2)`
27.

In SO_(3), a double bond arises between S and O is due to …………………overlapping.

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SOLUTION :`ppi-dpi`
28.

In S_(N)l ( substitution nucleophilie unimolecular) reaction, the racemisation takes place, It is due to

Answer»

inversion of configuration
relention of configuration
both (a) and (b)
NEITHER (a) nor (b)

Solution :In `S_(N)1` mechanism, the INTERMEDIATE FORMED is carbocation. As carbocation is planar thus the incoming nucleophilecan ATTACK from either side. Thus, both retention and inversion takes place RESULTING in racemisation.
29.

In reactions the incorrect order of reactivity of nucleophies is

Answer»

` I^(-) gt Br ^(-) gt CL^(-) gt F^(-) `
` CH_3 O^(-) gt CH_3 OH`
` RS ^(-) I^(-) gt CN^(-)NH_3 gt Cl^(-) `
` F^(-) gt Cl ^(-) gt Br ^(-) I^(-) `

ANSWER :D
30.

In SO_(2) two oxygen atoms are linked to the sulphur atom through double bonds. The two pi bonds are

Answer»

<P>both `p _(PI) -p_(pi)`
both `p_(pi) -d _(pi)`
both `d_(pi)-d_(pi)`
ONE `d _(pi)-p_(pi)` one `p_(pi)-p_(pi)`

ANSWER :D
31.

In S_(N)2 reactions, the correct order of reactivity for the following compounds : CH_(3)Cl,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCland(CH_(3))_(3)C Cl is :

Answer»

`CH_(3)Clgt(CH_(3))_(2)CHClgtCH_(3)CH_(2)Clgt(CH_(3))_(3)C Cl`
`CH_(3)ClgtCH_(3)CH_(2)Clgt(CH_(3))_(2)CHClgt(CH_(3))_(3)C Cl`
`CH_(3)CH_(2)ClgtCH_(3)Clgt(CH_(3))_(2)CHClgt(CH_(3))_(3)C Cl`
`(CH_(3))_(2)CHClgtCH_(3)CH_(2)ClgtCH_(3)Clgt(CH_(3))_(3)C Cl`

Solution :Rate of `S_(N)2` REACTION depends on stearic crowding of alkyl HALIDE. THEREFORE, the ORDER of reactivity is :
`CH_(3)ClgtCH_(3)CH_(2)Clgt(CH_(3))_(2)CHClgt(CH_(3))_(3)C Cl`
32.

In S_(N)2 reactions, the correct order of reactivity for the following compounds :CH_(3)Cl, CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl and (CH_(3))_(3)C Cl is :

Answer»

`CH_(3)CH_(2)CL GT CH_(3)Cl gt (CH_(3))_(2)CHCL gt (CH_(3))_(3)C Cl`
`(CH_(3))_(2)CHCl gt CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3))_(3)C Cl`
`CH_(3)Cl gt (CH_(3))_(2)CHCl gt CH_(3)CH_(2)Cl gt (CH_(3))_(3)C Cl`
`CH_(3)Cl gt CH_(3)CH_(2)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)C Cl`

Answer :D
33.

In S_(N^(2)) reactions, the correct order of reactivity for the compounds CH_(3)Cl,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl and (CH_(3))_(3)C Cl is:

Answer»

`CH_(3)Cl gt (CH_(3))_(2) CHCL gt CH_(3)CH_(2)Cl gt (CH_(3))_(3) C Cl`
`CH_(3)Cl gt CH_(3)CH_(2)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3) C Cl`
`CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)C Cl`
`(CH_(3))_(2) CHCl gt CH_(3)CH_(2) Cl gt C H_(3)Cl gt (CH_(3))_(3)C Cl`

Solution :It is an example of `S_(N^(2))` REACTION. The order of reactivity is inversely proportional to the STERIC hindrance offered by the alkyl groups.
34.

In SN_(2) reactions, the correct order of reactivity for the following compounds ? CH_(3)CI,CH_(3)CH_(2)CI,(CH_(3))_(3)CHCI"and"(CH_(3))_(3)"CCI" is

Answer»

`CH_(3)CH_(2)Cl GT CH_(3) Cl gt (CH_(3) )_(2)CHCl gt (CH_(3) )_(3)"CCl"`
`(CH_(3) )_(2)CHCl gt CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3) ) _(3)"CCl"`
`CH_(3)Cl gt (CH_(3) )_(2)CHCl gt CH_(3)CH_(2)Cl gt (CH_(3) )_(3)`CCl
`CH_(3)Cl gt CH_(3)CH_(2) Cl gt (CH_(3) )_(2)CHCl gt (CH_(3) )_(3) `CCl

Solution :`S_(N)^(2)`
Reactivity of `SN^(2) prop (1)/("Steric HINDRANCE ")`
ORDER of reactivity towards `S_(N)^(2)` .
`CH_(3)CIgtCH_(3)-CH_(2)-CI gt (CH_(3))_(2)CH-CI gt(CH_(3))_(3) C-CI`
35.

In S_(N)2 reactions, the correct order of reactivity for the following compounds: CH_(3)CI,CH_(3)CH_(2)CI,(CH_(3))_(2)CHCI and (CH_(3))_(2)C CI is:

Answer»

`CH_(3)CL GT (CH_(3))_(2)CHCl gt CH_(3)Cl_(2)Cl gt (CH_(3))_(3)"CC"L`
`CH_(3)Cl gt CH_(3)CH_(2)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)"CC"l`
`CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)"CC"l`
`(CH_(3))_(2)CHCl gt CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3))_(3)"CCl"`

ANSWER :B
36.

In S_(N)2 reactions, the correct order of reactivity for the compounds: CH_(3)CI,CH_(3)CH_(2)CI,(CH_(3))_(2)CHCIand(CH_(3))_(3)C CI-

Answer»

`(CH_(3))_(2)CHCIgtCH_(3)CH_(2)CIgtCH_(3)CIgt(CH_(3))_(3)C CI`
`CH_(3)CIgt(CH_(3))_(2)CHCIgtCH_(3)CH_(2)CIgt(CH_(3))_(3)C CI`
`CH_(3)CIgtCH_(3)CH_(2)CIgt(CH_(3))_(3)C CI`
`CH_(3)CH_(2)CIgtCH_(3)CIgt(CH_(3))_(2)CHCIgt(CH_(3))_(3)C CI`

Solution :In case of `S_(N)2` mechanism, stric hindrance increases with INCREASE in number of bulky groups attached to the chlorinated carbon ATOM. As a RESULT, the transition state BECOMES lessleading to a very slow reaction, Hence, the order of reactively is:
`underset("methyl")(CH_(3)CI)gtunderset("primary"(1^(@)))(CH_(3)CH_(2)CI)gtunderset("secondary"(2^(@)))((CH_(3))_(2)CHCI)gtunderset("tertiary"(3^(@)))((CH_(3))_(3)C CI)`
37.

In S_(N)2 reaction, the correct order of reactivity for the following compounds: CH_(3)Cl,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl and (CH_(3))_(3)C Cl is

Answer»

`(CH_(3))_(2)CHCl GT CH_(3)CH_(2)CL gt CH_(3)CL gt (CH_(3))_(3)C Cl`
`CH_(3)Cl gt (CH_(3))_(2) CHCl gt CH_(3)CH_(2)Cl gt (CH_(3))_(3)C Cl`
`CH_(3)Cl gt CH_(3)CH_(2)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)C Cl`
`CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)C Cl`

Solution :As the SIZE of the alkyl group increases in the order: `CH_(3),CH_(3)CH_(2),(CH_(3))_(2)CH,(CH_(3))_(3)C`, steric hindrance increases in the same order and hence the reactivity of the corresponding alkyl halides DECREASES in the same order, i.e., option (c) is correct.
38.

In S_(N)^(2) reaction the correct order of reactivity of the following compounds: (i) CH_(3)CI(ii) (CH_(3))_(3) C CI (iii) (CH_(3))_(2) CHCI(iv) CH_(3)CH_(2) - CI

Answer»

I > II > iii > iv
iv > iii > ii > i
I > iv > iii > ii
iv > I > ii > iii

Answer :C
39.

In S_(N^(1)) (substitution, nucleophilic, unimolecular) reaction, the reacemization takes place, it is due to

Answer»

INVERSION of CONFIGURATION
RETENTION of configuration
conversion of configuration
Both A and B

Solution :Inversion and retention of configuration LEAD to RACEMISATION.
40.

In S_(N)1 type mechanism, the intermediate species is :

Answer»

a FREE RADICAL
a carbonium ion
a CARBANION
NONE of these

Answer :B
41.

In S_(N^(1)) (substitution, nucleophilic unimolecular) reaction, the racemization takes place. It is due to

Answer»

INVERSION of configuration
retention of configuration
conversion of configuration
both 1 and 2 HALOARENES

ANSWER :D
42.

In S_(N)1 reactions, the order of reactivity of halides is :

Answer»

`3^(@)GT2^(@)GT1^(@)GT` methyl
methyl `gt1^(@)gt2^(@)gt3^(@)`
`3^(@)gt2^(@)gt` methyl `gt1^(@)`
`2^(@)gt1^(@)gt` methyl `gt3^(@)`

Answer :A
43.

In S_N1 reactions, rate of reaction depends on a) Concentration of alkyl halide b) Concentration of nucleophile c) Nature of alkyl halide

Answer»

All
'a' and 'C' only
'a' and 'B' only
'c' only

ANSWER :B
44.

In SN^(1) reaction the hybridisation changes in rate determination step select the correct change among the following

Answer»

from `SP^(3)" to "sp^(2)`
from `sp^(2)" to "sp^(3)`
from sp to `sp^(3)`
from `sp^(2)` to sp

Answer :A
45.

In SN^(1) reaction the first step is the formation of,

Answer»

CARBOCATION
carbanion
free readical
all of these

Answer :A
46.

In S_(N^1) reaction the first step involves the formation of:

Answer»

FREE radical
Carbanion
Carbocation
Final product

Answer :C
47.

In S_(N)1 reaction of (S)-2 bromobutane with water Two subsitution products are formed one has the same relative configuration as the reactant and the other has the inverted configuration. This is in most S_(N)1 reactions, the recemic product is non-50:50 mixture i.e, recemization takes place the inverted product is more than 50% . the formation of different composition of the product is due to following stpes involved in S_(N) reactions. R-X "" to R^(+) X^(-) to R^(+) "" "solvent" X^(-) "" to R^(+)+X^(-) {:("Undissociated Molecule", "Intimate ion pair", "solvent-sperated ion pair", "dissociated ions"),(I,II,III,IV):} In the above reaction the non-50 :50 racemic mixturecontains more amount of

Answer»

original CONFIGURATION
inverted configuration
either of the two
none of the above

Answer :B
48.

In S_(N)1 reaction on chiral centres, there is

Answer»

INVERSION more than retention reading to PARTIAL racemization
100% retention
100% conversion
100% racemization

Solution :Since inversion product EXCEEDS the retention product, THEREFORE, only partial racemization is observed, i.e., option (a) is correct.
49.

In S_(N)1 reaction of (S)-2 bromobutane with water Two subsitution products are formed one has the same relative configuration as the reactant and the other has the inverted configuration. This is in most S_(N)1 reactions, the recemic product is non-50:50 mixture i.e, recemization takes place the inverted product is more than 50% . the formation of different composition of the product is due to following stpes involved in S_(N) reactions. R-X "" to R^(+) X^(-) to R^(+) "" "solvent" X^(-) "" to R^(+)+X^(-) {:("Undissociated Molecule", "Intimate ion pair", "solvent-sperated ion pair", "dissociated ions"),(I,II,III,IV):} the non-50:50 racemic mixture during S_(N) reaction of an alkyl halide is formed due to the attack of the nucleophile on species

Answer»

I
II
III
both II and III

Answer :D
50.

In S_(N)1 reaction of (S)-2 bromobutane with water Two subsitution products are formed one has the same relative configuration as the reactant and the other has the inverted configuration. This is in most S_(N)1 reactions, the recemic product is non-50:50 mixture i.e, recemization takes place the inverted product is more than 50% . the formation of different composition of the product is due to following stpes involved in S_(N) reactions. R-X "" to R^(+) X^(-) to R^(+) "" "solvent" X^(-) "" to R^(+)+X^(-) {:("Undissociated Molecule", "Intimate ion pair", "solvent-sperated ion pair", "dissociated ions"),(I,II,III,IV):} 50 : 50 racemic mixture is formed due to the attack of nucleophil on which intermeidate species of the reaction ?

Answer»

I
II
III
IV

Answer :D